I have a an adress of a dialog form: ...ntityName=opportunity&ObjectId=%wwwww-www-wwww-wwww-wwwwwwww%7d and I want to call this dialog form from a button. I create a button for this and a parameter data in ribbon but and I don't know how to use the parameter data wich the id in the adress:
You can use a javascript Action, you can put any data or parameters you want.
the javascript funtion to use is:
Xrm.Page.data.entity.getId()
Related
I have a Insert form for Account Entity.
Once user create Record, I want to move to another page and show same record as Edit Form.
Does anyone have idea way to achieve this?
You should be able to redirect the user to desired page using OnSuccess of form submission.
On success: Select one of the following options:
Show success message: Requires a message to be displayed to the
user on successful submission of the form. You can also select Hide
form on success to hide the form upon successful submission.
Redirect to webpage: Redirects the user to the selected webpage
in the portal. You must select a webpage from the Redirect to webpage
list.
Redirect to URL: Redirects the user to the specified URL. You
must enter a URL in the Redirect to URL field.
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Out of Box configuration helps!!!
There is a field on "Entity Form" records named "Append Record ID to Query String". This is to configure passing the id of the record to the page after form submission. This screenshot shows it in the Redirect Section in the classic interface
You can do this several ways. What I do, is use Navigate() to go to the new screen, and I pass in a context variable to the new edit screen.
Assuming you're using OnSelect() on a button to call SubmitForm(), you can do the Navigate() call via the OnSuccess() property of the form.
And within Navigate(), you just pass whatever data you need to in order for the next screen to properly bind it to the Edit Form. This is the UpdateContextRecord optional param. You'd have the Edit form take its values from a Context Variable.
Passing variables between screens has been discussed here, as well.
I have a jqGrid with a custom navigation button that looks like this:
The button to the left of the refresh button is my custom button. I am successful in having it execute a $('#bom').trigger('reloadGrid'); but I need to know on the server which button initiated the request. I would like to add the button name to postData. I tried:
$("#bom").jqGrid({postData:{jqgAction:"release"}});
$("#bom").trigger('reloadGrid');
But that does not add the extra field to the request string. postData already has some values in it, and those are unaffected as I see them in the request. I just need to be able to dynamically add an additional field, and don't know how to insert the additional values.
I have found the answer. Instead of using:
$("#bom").jqGrid({postData:{jqgAction:"release"}});
to update postData, I can use:
this.p.postData.jqgAction="release";
I have a hyperlink column in the grid. On clicking the link i have to hide the partialview(grid section) and have to show/load another partialview which is the detail section. Please provide solution
You could use javascript. With jQuery that will correspond to the .toggle() function or the .show()/.hide() functions. So basically you will subscribe to the click event of the link and inside this handler show and hide the respective sections. For this to work you should obviously place those partials inside placeholder divs so that you could show/hide the entire placeholder.
If in addition to showing the partial you need to fetch some fresh information from the server then you could use AJAX to request a controller action that will return the fresh data of the partial view that you will inject into the DOM at the correct placeholder location. In order to send an AJAX request in jQuery you could use the $.ajax() function or directly the .load() function.
Is this possible?
The ajax form's purpose is to serve as a selector for the main form.
Forms cannot be nested.
Btw, you don't need a form for that purpose. Just send AJAX request without any form.
Put a select/set of radio buttons outside the form, assign onchange handler and in it do whatever you want. For example - send AJAX query and modify the form.
Hello sir I am new to the jsp and ajax world. my problem is
If i select one combo option then it should change the other combo options dynamically without submit button press.
for example if i select the country then it should shows their states in other combo.
I am using servlet & JSP and MS-ACCESS as backend. please reply as soon as possible.
THANKING YOU....
You need:
A piece of JSP which returns a string which can be parsed in javascript to create a list of possible combobox items (value, name) to select in the SECOND combobox, based on a VALUE which can be selected in the FIRST combobox
A piece of javascript which receives the onChange event of the FIRST combobox and uses the then selected value to create a XMLHTTP-request to your JSP (at 1)
A piece of javascript which you can pass to the XMLHTTP-request onReadyStateChange event to execute, which reads/parses the parseable string (from 1) and fills the second COMBOBOX with those values
Good luck