Hello sir I am new to the jsp and ajax world. my problem is
If i select one combo option then it should change the other combo options dynamically without submit button press.
for example if i select the country then it should shows their states in other combo.
I am using servlet & JSP and MS-ACCESS as backend. please reply as soon as possible.
THANKING YOU....
You need:
A piece of JSP which returns a string which can be parsed in javascript to create a list of possible combobox items (value, name) to select in the SECOND combobox, based on a VALUE which can be selected in the FIRST combobox
A piece of javascript which receives the onChange event of the FIRST combobox and uses the then selected value to create a XMLHTTP-request to your JSP (at 1)
A piece of javascript which you can pass to the XMLHTTP-request onReadyStateChange event to execute, which reads/parses the parseable string (from 1) and fills the second COMBOBOX with those values
Good luck
Related
Is there a good visual tutorial that takes through the various steps on how to create radio buttons in Apex 19.2? This tutorial Creating a Classic Report having radio button on each row helped me and I’m looking for a similar one..
In my case, I would like to add a radio button to each row of my classic report which when selected would add some of the informations selected by the radio button in a text field in the same page.
Any advice is much appreciated.
Thank you
Install Sample Reporting application on your APEX instance (preferably on apex.oracle.com as Dan suggested).
Navigate to the Classic Report page.
Change the query to the report to the following:
select rowid,
ID,
PROJECT,
TASK_NAME,
START_DATE,
END_DATE,
STATUS,
ASSIGNED_TO,
COST,
BUDGET,
apex_item.radiogroup(1,TASK_NAME) ACTION
from EBA_DEMO_IR_PROJECTS
where (nvl(:P3_STATUS,'0') = '0' or :P3_STATUS = status)
Note the added column "ACTION" which consists of the apex_item.radiogroup with TASK_NAME value. Let's assume that this is the value that you want to pass to another page item.
Open that column's attribute under Page Designer and disable "Escape special characters" attribute and add a CSS Class (e.g. mycolumn)
Create a Page Item (e.g. P3_NEW).
Now add the following Dynamic Action
Event > Click
Selection Type > jQuery Selector
jQuery Selector > #classic_report .mycolumn input
Your true action will be of the type Set Value and the Set Type is JavaScript Expression with the following code:
this.triggeringElement.value
Your affected element is P3_NEW and disable Fire on Initialization
I have created JQGrid.
I have put the Data in cell and one html Link in cells.
OnClick of that link I need to open JQGrid Specific popUp.Popup have one combobox .I'll select one option and click submit button and that data needs to be appear in clicked cell.
Thanks
The construction which you suggest seems me too complex. Probably you can consider to use more simple user interface?
Nevertheless you can just use setCell method to set new contain of the cell of the grid.
We have a dropdown list column in ASP.NET MVC 3.0 WebGrid. User will select a item from that list for each row.
When i click on submit I need to capture the selected value for each row.
Can anyone please give me a sample code for doing this from controller.
Thanks in advance
You can make a column with DropDownList control using a html helper:
grid.Column("List", header: "List", format: #<text>#Html.DropDownList("selection", someItems)</text>)
Then put the whole grid in a "form" statement, which refers to "Save" action in your controller, and create that "Save" action method like this:
public ActionResult Save(string[] selection) {
[...]
}
Why don'y you give telerik.mvc grid a try. It's super smooth and handles such scenarios pretty well. Moreover the effort is pretty less in setting it up.
You can download it as a nuget package.
Examples are here http://demos.telerik.com/aspnet-mvc/grid
I have a grid control displaying data about a Company. I want one column to be "Employee". On click on the any cell of "Employee" column I want to pop up the one Form called "Employee Details" and would like to feel the data.
How can I do this?
As I understand the modal form on click of a jqgrid cell deals with data only related to that row. I want to show different data on the pop up form, i.e. other than the grid data.
Pl help.
Shivali
Probably you can use unobtrusive links in the column (see this and this answers). The advantage of this technique is that instead of typical links you can define any custom action on click on the link. The look of the link can be defined by CSS, but it seems to the that the link can show the user better as other HTML elements, that the user can click on it.
Alternative you can use a button in the column with respect of the custom formatter, but with the same technique as described before you can free define which action will be done on the click.
Inside of the click event with the parameter 'e' you have e.currentTarget as the DOM element of <a> for the link or <input> or <button> if you use buttons in the grid column. To find the row id you can use var row = $(e.currentTarget).closest("tr.jqgrow") or var row = $(e.target).closest("tr.jqgrow") to find the <tr> element. The row id will be row[0].id.
I would like to implement a dropdownlist with some listedItems.After that I want for every selected item to be connected to a new aspx page(i.e. if I select meat I want to have a new aspx page that will contain some information about the meat). Does anybody have any ideas? Thanks,
Naim
Set the Value of your ListItem to the URL you want to redirect to when the item is selected. When the user selects the value, simply redirect to that URL.
This can be done in either Javascript or serverside. I'd prefer doing it in javascript to avoid the extra server roundtrip.