I have 2 groovy class files under one rootProject. I want to run just one of them without running the other one. How can I do that using intellij command line and command prompt. Right now when I run the rootProject both files run one after the other. Is there any setting required build.gradle file then please explain hoow can I do that as I am very new to gradle and don't know much about it. Thanks!
If you have only those two groovy scripts (and there is nothing to compile etc.), you do not need Gradle to run it at all. From command line call
groovy <filename>.groovy
To run the script directly from Gradle Script, use
new GroovyShell().run(file('somePath'))
Yes you can create intellij config to run your script.
Follow these steps:
1) Edit configuration
2) Add new Groovy configuration
3) Browse you script
4) Run your script
Related
So I have a Jenkins job wherein as part of the build.
I run one script which creates a folder in the workspace say "test"
so the script runs fine and creates the folder test.
After this, I have a maven command wherein I want to access this test folder(as an argument) I am trying it as $workspace/test
but it's not working.
Can anyone guide if i am missing anything here
Can you give us more information - maybe code snippets?
I'm not sure what you mean with 'maven command' and '$workspace/test'
If you want use a variable in a pom.xml like:
<path>${workspace}</path>
you will have to assign it in the properties:
<workspace>...location...</workspace>
Otherwise you can use maven preassigned variables like
${basedir}/
I need to execute groovy script with gradle, but the thing is that these scripts are located in external directory (let's say it's Desktop). I've heard, that in previous versions of Gradle (currently working on 3.2.1) it was not possible, since it is not part of the gradle project. I wonder if it is possible now, or do I have to copy all these scripts into some folder located in gradle project, to execute it.
User story:
I found script in external directory (based on some properties passed to console) - I have absolute path to the script
Now I want to execute this script (build.gradle) without copying it into my gradle project
I'm pretty green with gradle and I hope I made my point clear.
Thanks for help and every attempt :)
Is that what you're looking for? To run the script clone the repository, navigate to 42556631/project folder and run the command:
gradle -b ../script/build.gradle clean build
yes you need to move build.gradle file into project/Build Script folder and then run it.
Along the lines of this answer (which works for me, BTW) and the javadocs, I tried
gradle.startParameter.consoleOutput = org.gradle.api.logging.configuration.ConsoleOutput.Rich
in my ~/.gradle/init.gradle. However, I still need --console=rich to get color output. Why?
Tested with Gradle 2.14.1 and 3.2.1.
Terminal is cygwin urxvt with TERM variable set to rxvt-unicode-256color.
Since Gradle 4.3 you can use org.gradle.console property in gradle.properties:
org.gradle.console=rich
A new console verbose mode will print outcomes of all tasks (like UP-TO-DATE) like Gradle 3.5 and earlier did. You can set this via --console=verbose or by a new Gradle property org.gradle.console=(plain rich verbose).
I am not sure if you can force the rich console from a gradle script, as the detection happens likely before the script is interpreted.
NativeServices class provides the integration with the console. If you look at the source code, there are two messages possibly printed in log:
Native-platform terminal integration is not available. Continuing with fallback.
Unable to load from native-platform backed ConsoleDetector. Continuing with fallback.
The latter might give you more information why. Try running the gradle script with --debug. You will likely find out that you are missing a native library that is either not available in cygwin or it is, but is not on library path.
I believe it works when you specify the rich console from the command line, because gradle forces the colours even though the console doesn't indicate it supports them.
Does it work if you don't use the cygwin console in Windows native command line or maybe GitBash?
There is a workaround how you can make this work. You can create an alias in cygwin that will always add the --console=rich.
If you are using gradle wrapper, you can edit the gradlew script and add the command line parameter. To make it automated, you can change the wrapper task to alter your script in the doLast part.
Create a file called gradle.properties inside your ~/.gradle/ folder.
Inside gradle.properties, add the line org.gradle.console=rich.
Each builds will run under --console=rich automatically because the new gradle.properties will be merged with the gradle.properties of your project.
If your project's gradle.properties contains the same tag as the local file, your project's will be used overriding the local file's
If you are on Linux/Mac set
alias gradle='gradle --console rich'
in your ~/.bashrc.
In Gradle Wrapper, add the following line:
org.gradle.console=rich
to ./gradle.properties in the root folder, where the gradlew script is located.
I have a single script in a project in intellij that I want to run in my mac terminal. I can run the script but I am getting errors where it can't find the JAR files I added as a module. There are a lot of dependencies, so I was wondering how can I add my intellij project settings to calling my groovy script. Right now all I have is this:
groovy CreateReport.groovy
Turns out all you need to do is dump your libraries into the GROOVY_HOME/lib directory, where GROOVY_HOME is where you have defined your groovy environment variables to be.
http://dustinwhitney.blogspot.com/2008/03/groovy-classpath.html
I have used the STS(Spring Tool Suite) to create a compiled groovy script which exists as a file on windows called Test.class. I am able to right click on the file in STS and execute it which works well.
However - I want to be able to execute the script on the windows command line, so far I have tried various ways but have not been successful. I have tried the following...
java -cp C:\Users\MyName\springsource\sts->
3.1.0.RELEASE\plugins\org.codehaus.grails.bundle_2.1.1\content\lib\
org.codehaus.groovy\groovy-all\jars\groovy-all-1.8.8.jar Test.class
But that does not work it gives me an error --> Error: Could not find or load main class Test.class
Any Pointers?
You are trying to run a test case, so you really ned to be launching junit and ass this test as the test to run.
The easiest thing to do is to download a distribution of groovy, unzip, and run:
groovy Test.groovy
Step 1
In STS(Spring Tool Suite) ,Create a Groovy Class e.g. Customer.groovy file. Specify a Package Name e.g. com.customer. In the main method put in code to validate the code is being called e.g. println ‘test’.
Step 2
Go to your command line (Windows use command prompt). Switch\cd to the ROOT directory of your project. Execute the command below.
Step 3
execute java -cp C:\Users\Profile\springsource\sts-3.1.0.RELEASE\plugins\org.codehaus.grails.bundle_2.1.1\content\lib\org.codehaus.groovy\groovy-all\jars\groovy-all-1.8.8.jar;. com.customer.Customer
The code should run.
V Important
If like me, you do not have a class and you only have a groovy script then in step#3 specify the Groovy script name without the suffix.
Test is naked? (without package name?) try this.
java -cp C:\Users\MyName\springsource\sts-> 3.1.0.RELEASE\plugins\org.codehaus.grails.bundle_2.1.1\content\lib\ org.codehaus.groovy\groovy-all\jars\groovy-all-1.8.8.jar;. package.Test
Pay attention to ;. and package name.