plsql CSV file reading and write - oracle

Question

OWNER SYS
DIRECTORY_NAME ME
DIRECTORY_PATH \\172.16.20.11\Mad\
begin
vSFile := utl_file.fopen('ME','20170405.csv','R');
IF utl_file.is_open(vSFile) THEN
LOOP
i am getting error :
ORA-29283: invalid file operation ORA-06512: at "SYS.UTL_FILE", line 536 ORA-29283: invalid file operation ORA-06512: at "MADHUR.MSP_UPD_DAILYSALESFRMSAP", line 28 ORA-06512: at line 1
29283. 00000 - "invalid file operation"
*Cause: An attempt was made to read from a file or directory that does
not exist, or file or directory access was denied by the
operating system.
*Action: Verify file and directory access privileges on the file system,
and if reading, verify that the file exists.

Answer 1

Your error tells you exactly what the problem is:
*Cause: An attempt was made to read from a file or directory that does
not exist, or file or directory access was denied by the
operating system.
and what to do to fix it:
*Action: Verify file and directory access privileges on the file system,
and if reading, verify that the file exists.
So you specify:
DIRECTORY_PATH \\172.16.20.11\Mad\
are you able to actually access \\172.16.20.11\Mad\ with your oracle user?
if not, then you need to grant read, write on directory to user and also check OS permissions for your user to that path.
but also consider doing a network share to drive letter, instead of UNC path.

Answer 2

The reason for getting such issue is that you dont have read or write permission to the directory.
Run the below query to see if you have read and write priviledges:
SELECT *
FROM all_tab_privs
WHERE table_name = 'your_directory name';
If you find dont have any access then grant read and write privs.
SQL>CREATE OR REPLACE DIRECTORY dir1 as '/opt/oracle/';
SQL>GRANT READ,WRITE on dir1 to <Required user>; (if you want to give access to particular user)
OR
SQL>GRANT READ,WRITE on dir1 to PUBLIC; (if you want to give access to all users then give access to public)