I'm having trouble with the line
F := UTL_FILE.FOPEN('my_directory', 'MyCSV.csv', 'R');
After previously running
CREATE DIRECTORY my_directory AS 'C:\Users\timfo\eclipse-workspace\CSVCreation';
which succeeds. The error I'm getting is
ORA-29280: invalid directory path
ORA-06512: at "SYS.UTL_FILE", line 41
ORA-06512: at "SYS.UTL_FILE", line 478
ORA-06512: at line 9
29280. 00000 - "invalid directory path"
*Cause: A corresponding directory object does not exist.
*Action: Correct the directory object parameter, or create a corresponding
directory object with the CREATE DIRECTORY command.
but I've made sure that the user has permission with
grant create any directory to TimGraupner2;
CREATE DIRECTORY my_directory AS 'C:\Users\timfo\eclipse-workspace\CSVCreation';
grant read on directory my_directory to TimGraupner2;
and all those succeeded. I've tried entering the full directory path in the FOPEN line, and that didn't work either. What's going on?
Related
Most of the answers I've seen are for Linux. Windows permissions have an element of black magic about them. This is Windows Server 2016.
I created the d:\data\transfer\sirius\ directory on the Oracle database server.
As SYSDBA I do the following:
create or replace directory SIRIUS_DIR as 'd:\data\transfer\sirius\';
grant read,write on directory SIRIUS_DIR to SIRIUS;
Then on another server, in a SQL*Plus session as the SIRIUS user, I run:
DECLARE myFile utl_file.file_type;
BEGIN
myFile := utl_file.fopen('SIRIUS_DIR ', 'random.txt', 'w', 32000);
END;
/
Which gives:
ERROR at line 1:
ORA-29283: invalid file operation
ORA-06512: at "SYS.UTL_FILE", line 536
ORA-29283: invalid file operation
ORA-06512: at "SYS.UTL_FILE", line 41
ORA-06512: at "SYS.UTL_FILE", line 478
ORA-06512: at line 3
How to proceed?
Figured it out. You need to grant full access to the ORA_INSTALL group to the directory in question on the database. According to the Oracle configuration docs:
The ORA_INSTALL group contains all the Oracle Home Users for all
Oracle homes on the server.
Thanks to this kindly blogger for his solution.
I am currently trying to import a database using DBMS_DATAPUMP in PL/SQL using the following script.
DECLARE
h1 NUMBER;
BEGIN
h1 := DBMS_DATAPUMP.OPEN('IMPORT', 'FULL', NULL, DBMS_SCHEDULER.generate_job_name, 'LATEST');
DBMS_DATAPUMP.ADD_FILE(handle => h1, filename => 'EXAMPLE6.DMP', directory => 'DUMP');
DBMS_DATAPUMP.START_JOB(h1);
dbms_datapump.detach(h1);
END;
/
Everytime I execute this code, I get the following error message.
ERROR in line 1:
ORA-39001: invalid argument value
ORA-06512: in "SYS.DBMS_SYS_ERROR", line 79
ORA-06512: in "SYS.DBMS_DATAPUMP", line 4929
ORA-06512: in "SYS.DBMS_DATAPUMP", line 5180
ORA-06512: in line 5
I already googled the error, but the answer mostly consisted of checking if the directory was already created and if the user had read and write access to the directory.
I also tried the impdp tool just as an experiment, to see if I could execute imports that way.
impdp pdb2 directory="DUMP" dumpfile="EXAMPLE6.DMP"
Based on the user I am executing impdp as, I get different error messages.
As a user with all privileges granted:
ORA-39001: invalid argument value
ORA-39000: bad dump file specification
ORA-39155: error expanding dump file name "C:\Users\...\EXAMPLE6.DMP"
ORA-48128: opening of a symbolic link is disallowed
As the sysdba user:
ORA-39002: invalid operation
ORA-39070: unable to open the log file
ORA-39087: directory name DUMP is invalid
As I already said, the directory does exist on my drive, I created the directory called DUMP in Oracle and granted read and write access to my user.
All help would be appreciated and I would be happy to clarify if I wrote something confusing!
Edit:
Output of select directory_name, directory_path from dba_directories;
DIRECTORY_NAME
--------------------------------------------------------------------------------
DIRECTORY_PATH
--------------------------------------------------------------------------------
DUMP
C:\Users\Nemanja\Desktop\oraclePLS
I forgot to mention, that the Oracle service has complete access to the specified Windows directory.
OWNER SYS
DIRECTORY_NAME ME
DIRECTORY_PATH \\172.16.20.11\Mad\
begin
vSFile := utl_file.fopen('ME','20170405.csv','R');
IF utl_file.is_open(vSFile) THEN
LOOP
i am getting error :
ORA-29283: invalid file operation ORA-06512: at "SYS.UTL_FILE", line 536 ORA-29283: invalid file operation ORA-06512: at "MADHUR.MSP_UPD_DAILYSALESFRMSAP", line 28 ORA-06512: at line 1
29283. 00000 - "invalid file operation"
*Cause: An attempt was made to read from a file or directory that does
not exist, or file or directory access was denied by the
operating system.
*Action: Verify file and directory access privileges on the file system,
and if reading, verify that the file exists.
Your error tells you exactly what the problem is:
*Cause: An attempt was made to read from a file or directory that does
not exist, or file or directory access was denied by the
operating system.
and what to do to fix it:
*Action: Verify file and directory access privileges on the file system,
and if reading, verify that the file exists.
So you specify:
DIRECTORY_PATH \\172.16.20.11\Mad\
are you able to actually access \\172.16.20.11\Mad\ with your oracle user?
if not, then you need to grant read, write on directory to user and also check OS permissions for your user to that path.
but also consider doing a network share to drive letter, instead of UNC path.
The reason for getting such issue is that you dont have read or write permission to the directory.
Run the below query to see if you have read and write priviledges:
SELECT *
FROM all_tab_privs
WHERE table_name = 'your_directory name';
If you find dont have any access then grant read and write privs.
SQL>CREATE OR REPLACE DIRECTORY dir1 as '/opt/oracle/';
SQL>GRANT READ,WRITE on dir1 to <Required user>; (if you want to give access to particular user)
OR
SQL>GRANT READ,WRITE on dir1 to PUBLIC; (if you want to give access to all users then give access to public)
I was learning PL/SQL and I have been getting this error as "invalid file operation since long"
The code is as follows:
SET SERVEROUTPUT on;
CREATE or replace directory DESKTOP as 'C:\Users\Gadre\Desktop';
declare
v1 varchar2(32767);
f1 utl_file.file_type;
begin
f1 :=utl_file.fopen('DESKTOP','test.docx','r');
dbms_output.put_line('HELLO WORLD');
end;
The error is:
Error report:
ORA-29283: invalid file operation
ORA-06512: at "SYS.UTL_FILE", line 536
ORA-29283: invalid file operation
ORA-06512: at line 5
29283. 00000 - "invalid file operation"
*Cause: An attempt was made to read from a file or directory that does
not exist, or file or directory access was denied by the
operating system.
*Action: Verify file and directory access privileges on the file system,
and if reading, verify that the file exists.
The file does exist surely. Plus I am through admin access so I think I do have privileges.
Following is my query to insert xml file
INSERT INTO sampletagtable VALUES ( 1 , XMLType(bfilename('xmldir3', 'book.xml') , nls_charset_id('AL32UTF8') ));
Before that I have created the xmldir3 by the following query,
CREATE OR REPLACE DIRECTORY xmldir3 AS '/opt/user/nishanth/xmldir';
Here /opt/user/nishanth is a directory in my linux os.
book.xml is inside that specified directory.
I am getting the following error,
SQL Error: ORA-22285: non-existent directory or file for FILEOPEN operation
ORA-06512: at "SYS.XMLTYPE", line 296
ORA-06512: at line 1
22285. 00000 - "non-existent directory or file for %s operation"
*Cause: Attempted to access a directory that does not exist, or attempted
to access a file in a directory that does not exist.
*Action: Ensure that a system object corresponding to the specified
directory exists in the database dictionary, or
make sure the name is correct.
You created the directory as xmldir3, which is an unquoted identifier so it'll be upper-case in the data dictionary. But then you refer to it in lower-case. You need to use:
bfilename('XMLDIR3', 'book.xml')
You can check the actual directory name by querying the all_directories view:
SQL> CREATE OR REPLACE DIRECTORY xmldir3 AS '/opt/user/nishanth/xmldir';
Directory created.
SQL> SELECT directory_name, directory_path FROM all_directories;
DIRECTORY_NAME DIRECTORY_PATH
------------------------------ ----------------------------------------
XMLDIR3 /opt/user/nishanth/xmldir
...