Bash loop to read line by line and create folder by line index - bash

Question

I am trying to do the following in a bash file:
mybash.sh myinputfile.txt myloopfile.csv
Create a for loop, that reads myloopfile.csv line by line, and then creates a folder which will take the line number as the folder name prefixed to "folder", ex. folder1, folder2...
and then inside this folder$i create a folder called input and another called output.
write the line$i content into a file called myline.txt and put this file inside the folder$i/input
and copy the file myinputfile.txt that i will pass as a parameter to the bash file inside the folder$i/input as well.
and then run my personal script that takes two arguments:
python myscript.py -i ./folder$i/input -o ./folder$i/output
and done!
myfile.csv
101,1001,10012,100121
102,101213,11122.1,12.15
103,122.15,155.2,1515.54
104,154.4,4551.1,454
what I currently have:
#!/bin/bash
while IFS='' read -r line || [[ -n "$line" ]]; do
mkdir ./folder$line
echo "$line" >> Folder$line/input/myline.txt;
cp myinputfile.txt Folder$line/input
python myscript.py -i ./folder$i/input -o ./folder$i/output
done < "$1"
the problem is that I can't get the line index to pass it as a suffix to the folder name, so I currently get the line content.and I don't know how to read the two files from the arguments that i pass to the mybash.sh.

Answer 1

Use a counter to keep track of line numbers:
#!/bin/bash
input_file=$1
csv_file=$2
count=1
while IFS= read -r line || [[ -n "$line" ]]; do
input_dir="./folder$count/input"
output_dir="./folder$count/output"
mkdir -p "$input_dir" "$output_dir"
printf '%s\n' "$line" > "$input_dir/myline.txt"
cp "$input_file" "$input_dir"
python myscript.py -i "$input_dir" -o "$output_dir"
((count++))
done < "$csv_file"