As I'm new to Unix, can someone help why I get this error?
Error: 0403-057 Syntax error at line 1 : `(' is not expected
Unix server used: AIX servname 1 6 00F635064C00
Script used (to send email alert if day before yesterday source files didn't arrive):
#!/usr/bin/ksh
count=$(sqlplus $PROD_DB #select count(*) from file_audit where (file_name like '%abc%' or file_name like '%dce%') and substr(file_name,17,8)=to_char(to_date(sysdate-2,'DD/MM/YY'), 'yyyymmdd') > asa_file_count.log)
daybefore=`TZ=aaa48 date +%d-%m-%Y`
if [[ $count -lt 20 ]]
then
echo "Alert - Source files are yet to be received for date: $daybefore" | mail -s "Alert : Source data files missing" s#g.com
fi
Parentheses are special to the shell. Your SQL script contains parentheses you don't want the shell to process. However, the shell processes all non-quoted parentheses. Therefore, you can use quotes to prevent the parentheses in your SQL from being interpreted by the shell:
count=$(sqlplus $PROD_DB "#select count(*) from file_audit where (file_name like '%abc%' or file_name like '%dce%') and substr(file_name,17,8)=to_char(to_date(sysdate-2,'DD/MM/YY'), 'yyyymmdd')" > asa_file_count.log)
# ^ and similarly, a closing quote at the end, just before ">asa_file..." .
Now, there is a second issue: you have
count=$(sqlplus ... > asa_file_count.log)
However, I think this means count will always be empty, since the count will go into asa_file_count.log and will not be available to be captured with $(). I believe removing the >asa_file_count.log will probably do what you want:
count=$(sqlplus "$PROD_DB" "<your query>")
(I also put double-quotes around $PROD_DB just in case PROD_DB's value contains any spaces.)
Related
I've the below code which I'm using to retrieve the hive result, storing it in a variable, doing the comparison and then accordingly printing the message using shell script.
count_students=`/usr/bin/hive -e 'select count(*) from student_records.fresher;'`
echo $count_students
if [ $count_students -gt 0 ]; then
echo "There are students to be grouped."
exit 1
else
echo "There are no students to be grouped."
fi
echo "Student count to check for Freshers is completed."
But the code is not returning anything i.e.:
Actual O/P:
-bash: line 2: [: -ge: unary operator expected
There are no students to be grouped.
Also the echo $count_students is not printing anything.
The hive query gives the result as:
admin$ select count(*) from student_records.fresher;
179
Not getting why the hive is not able to return the result. Bcz of that the query is prompting wrong message. Any help/ suggestion will be really helpful. Thanks to the community.
I have a strange problem - possibly I'm just going blind. I have this short script, which replaces the string #qry# in the here-document with a select statement in a file and then pipes it to mysql:
#!/bin/bash
if [[ "$1" == "-h" ]]
then
echo "sqljob [sqlfile] [procnm] [host] [database] [config file]"
echo " sqlfile: text file containing an SQL statement"
echo " procnm: name that will given to the new, stored procedure"
echo " host: hostname of IP address of the database server"
echo " database: the procedure will be created here"
echo " config file: default configuration file with username and password"
exit
fi
infile=$1
procnm=$2
hn=$3
pn=$4
db=$5
mycfg=$6
{
set -o noglob
sed -e "s/#qry#/$(echo $(cat $infile))/g" <<!
drop procedure if exists $procnm;
delete from jobs where jobname="$procnm";
insert into jobs
set
notes="SQL job $procnm",
jobname="$procnm",
parm_tmpl='int';
delimiter //
create procedure $procnm(vqid int)
begin
call joblogmsg(vqid,0,"$procnm","","Executing #qry#");
drop table if exists ${procnm}_res;
create table ${procnm}_res as
#qry#
end//
delimiter ;
!
} | mysql --defaults-file=$mycfg -h $hn -P $pn $db
However, when the select contains *, it expands to whatever is in the directory even though I use noglob. However, it works from the command line:
$ set -o noglob
$ ls *
What am I doing wrong?
Edit
Block Comments in a Shell Script has been suggested as a duplicate, but as you will notice, I need to expand ${procnm} in the here-doc; I just need to avoid the same happening to select *.
I suspect it is because the construct echo (cat). The echo command gets the * from the cat command and the shell in which it runs expands it. In that shell set noglob is not active.
Try leaving the echo away: /$(cat $infile)/, in the end that is the data you need; then there is no extra glob expansion by a shell.
getting issue with echo output.
line=table_name
echo "SELECT CASE WHEN FORMAT_TYPE LIKE '%character%' THEN 'replace(replace(replace('||ATTNAME||',''\'',''\\''),''"'',''\"''),''|'',''\|'') as '||ATTNAME||',' ELSE ATTNAME||',' END FROM _V_RELATION_COLUMN WHERE NAME = '$line' ORDER BY ATTNUM;"
Output I am looking for something like below:
SELECT CASE WHEN FORMAT_TYPE LIKE '%character%'
THEN 'REPLACE(REPLACE(REPLACE('||ATTNAME||',''\'',''\\''),''"'',''\"''),''|'',''\|'') AS '||ATTNAME||','
ELSE ATTNAME||','
END
FROM _V_RELATION_COLUMN WHERE NAME IN ('table_name')
ORDER BY ATTNUM;
But getting there error as
-bash: syntax error near unexpected token `)'
You need to escape the double quotes in your string
Try
echo "SELECT CASE WHEN FORMAT_TYPE LIKE '%character%' THEN 'replace(replace(replace('||ATTNAME||',''\'',''\\''),''\"'',''\\\"''),''|'',''\|'') as '||ATTNAME||',' ELSE ATTNAME||',' END FROM _V_RELATION_COLUMN WHERE NAME = '$line' ORDER BY ATTNUM;"
Note that to print an escape you have to escape the escape.
e.g
If you want \"
You need to type \\\"
Consider this PS1
PS1='\n${_:+$? }$ '
Here is the result of a few commands
$ [ 2 = 2 ]
0 $ [ 2 = 3 ]
1 $
1 $
The first line shows no status as expected, and the next two lines show the
correct exit code. However on line 3 only Enter was pressed, so I would like the
status to go away, like line 1. How can I do this?
Here's a funny, very simple possibility: it uses the \# escape sequence of PS1 together with parameter expansions (and the way Bash expands its prompt).
The escape sequence \# expands to the command number of the command to be executed. This is incremented each time a command has actually been executed. Try it:
$ PS1='\# $ '
2 $ echo hello
hello
3 $ # this is a comment
3 $
3 $ echo hello
hello
4 $
Now, each time a prompt is to be displayed, Bash first expands the escape sequences found in PS1, then (provided the shell option promptvars is set, which is the default), this string is expanded via parameter expansion, command substitution, arithmetic expansion, and quote removal.
The trick is then to have an array that will have the k-th field set (to the empty string) whenever the (k-1)-th command is executed. Then, using appropriate parameter expansions, we'll be able to detect when these fields are set and to display the return code of the previous command if the field isn't set. If you want to call this array __cmdnbary, just do:
PS1='\n${__cmdnbary[\#]-$? }${__cmdnbary[\#]=}\$ '
Look:
$ PS1='\n${__cmdnbary[\#]-$? }${__cmdnbary[\#]=}\$ '
0 $ [ 2 = 3 ]
1 $
$ # it seems that it works
$ echo "it works"
it works
0 $
To qualify for the shortest answer challenge:
PS1='\n${a[\#]-$? }${a[\#]=}$ '
that's 31 characters.
Don't use this, of course, as a is a too trivial name; also, \$ might be better than $.
Seems you don't like that the initial prompt is 0 $; you can very easily modify this by initializing the array __cmdnbary appropriately: you'll put this somewhere in your configuration file:
__cmdnbary=( '' '' ) # Initialize the field 1!
PS1='\n${__cmdnbary[\#]-$? }${__cmdnbary[\#]=}\$ '
Got some time to play around this weekend. Looking at my earlier answer (not-good) and other answers I think this may be probably the smallest answer.
Place these lines at the end of your ~/.bash_profile:
PS1='$_ret$ '
trapDbg() {
local c="$BASH_COMMAND"
[[ "$c" != "pc" ]] && export _cmd="$c"
}
pc() {
local r=$?
trap "" DEBUG
[[ -n "$_cmd" ]] && _ret="$r " || _ret=""
export _ret
export _cmd=
trap 'trapDbg' DEBUG
}
export PROMPT_COMMAND=pc
trap 'trapDbg' DEBUG
Then open a new terminal and note this desired behavior on BASH prompt:
$ uname
Darwin
0 $
$
$
$ date
Sun Dec 14 05:59:03 EST 2014
0 $
$
$ [ 1 = 2 ]
1 $
$
$ ls 123
ls: cannot access 123: No such file or directory
2 $
$
Explanation:
This is based on trap 'handler' DEBUG and PROMPT_COMMAND hooks.
PS1 is using a variable _ret i.e. PS1='$_ret$ '.
trap command runs only when a command is executed but PROMPT_COMMAND is run even when an empty enter is pressed.
trap command sets a variable _cmd to the actually executed command using BASH internal var BASH_COMMAND.
PROMPT_COMMAND hook sets _ret to "$? " if _cmd is non-empty otherwise sets _ret to "". Finally it resets _cmd var to empty state.
The variable HISTCMD is updated every time a new command is executed. Unfortunately, the value is masked during the execution of PROMPT_COMMAND (I suppose for reasons related to not having history messed up with things which happen in the prompt command). The workaround I came up with is kind of messy, but it seems to work in my limited testing.
# This only works if the prompt has a prefix
# which is displayed before the status code field.
# Fortunately, in this case, there is one.
# Maybe use a no-op prefix in the worst case (!)
PS1_base=$'\n'
# Functions for PROMPT_COMMAND
PS1_update_HISTCMD () {
# If HISTCONTROL contains "ignoredups" or "ignoreboth", this breaks.
# We should not change it programmatically
# (think principle of least astonishment etc)
# but we can always gripe.
case :$HISTCONTROL: in
*:ignoredups:* | *:ignoreboth:* )
echo "PS1_update_HISTCMD(): HISTCONTROL contains 'ignoredups' or 'ignoreboth'" >&2
echo "PS1_update_HISTCMD(): Warning: Please remove this setting." >&2 ;;
esac
# PS1_HISTCMD needs to contain the old value of PS1_HISTCMD2 (a copy of HISTCMD)
PS1_HISTCMD=${PS1_HISTCMD2:-$PS1_HISTCMD}
# PS1_HISTCMD2 needs to be unset for the next prompt to trigger properly
unset PS1_HISTCMD2
}
PROMPT_COMMAND=PS1_update_HISTCMD
# Finally, the actual prompt:
PS1='${PS1_base#foo${PS1_HISTCMD2:=${HISTCMD%$PS1_HISTCMD}}}${_:+${PS1_HISTCMD2:+$? }}$ '
The logic in the prompt is roughly as follows:
${PS1_base#foo...}
This displays the prefix. The stuff in #... is useful only for its side effects. We want to do some variable manipulation without having the values of the variables display, so we hide them in a string substitution. (This will display odd and possibly spectacular things if the value of PS1_base ever happens to begin with foo followed by the current command history index.)
${PS1_HISTCMD2:=...}
This assigns a value to PS1_HISTCMD2 (if it is unset, which we have made sure it is). The substitution would nominally also expand to the new value, but we have hidden it in a ${var#subst} as explained above.
${HISTCMD%$PS1_HISTCMD}
We assign either the value of HISTCMD (when a new entry in the command history is being made, i.e. we are executing a new command) or an empty string (when the command is empty) to PS1_HISTCMD2. This works by trimming off the value HISTCMD any match on PS1_HISTCMD (using the ${var%subst} suffix replacement syntax).
${_:+...}
This is from the question. It will expand to ... something if the value of $_ is set and nonempty (which it is when a command is being executed, but not e.g. if we are performing a variable assignment). The "something" should be the status code (and a space, for legibility) if PS1_HISTCMD2 is nonempty.
${PS1_HISTCMD2:+$? }
There.
'$ '
This is just the actual prompt suffix, as in the original question.
So the key parts are the variables PS1_HISTCMD which remembers the previous value of HISTCMD, and the variable PS1_HISTCMD2 which captures the value of HISTCMD so it can be accessed from within PROMPT_COMMAND, but needs to be unset in the PROMPT_COMMAND so that the ${PS1_HISTCMD2:=...} assignment will fire again the next time the prompt is displayed.
I fiddled for a bit with trying to hide the output from ${PS1_HISTCMD2:=...} but then realized that there is in fact something we want to display anyhow, so just piggyback on that. You can't have a completely empty PS1_base because the shell apparently notices, and does not even attempt to perform a substitution when there is no value; but perhaps you can come up with a dummy value (a no-op escape sequence, perhaps?) if you have nothing else you want to display. Or maybe this could be refactored to run with a suffix instead; but that is probably going to be trickier still.
In response to Anubhava's "smallest answer" challenge, here is the code without comments or error checking.
PS1_base=$'\n'
PS1_update_HISTCMD () { PS1_HISTCMD=${PS1_HISTCMD2:-$PS1_HISTCMD}; unset PS1_HISTCMD2; }
PROMPT_COMMAND=PS1_update_HISTCMD
PS1='${PS1_base#foo${PS1_HISTCMD2:=${HISTCMD%$PS1_HISTCMD}}}${_:+${PS1_HISTCMD2:+$? }}$ '
This is probably not the best way to do this, but it seems to be working
function pc {
foo=$_
fc -l > /tmp/new
if cmp -s /tmp/{new,old} || test -z "$foo"
then
PS1='\n$ '
else
PS1='\n$? $ '
fi
cp /tmp/{new,old}
}
PROMPT_COMMAND=pc
Result
$ [ 2 = 2 ]
0 $ [ 2 = 3 ]
1 $
$
I need to use great script bash-preexec.sh.
Although I don't like external dependencies, this was the only thing to help me avoid to have 1 in $? after just pressing enter without running any command.
This goes to your ~/.bashrc:
__prompt_command() {
local exit="$?"
PS1='\u#\h: \w \$ '
[ -n "$LASTCMD" -a "$exit" != "0" ] && PS1='['${red}$exit$clear"] $PS1"
}
PROMPT_COMMAND=__prompt_command
[-f ~/.bash-preexec.sh ] && . ~/.bash-preexec.sh
preexec() { LASTCMD="$1"; }
UPDATE: later I was able to find a solution without dependency on .bash-preexec.sh.
I am writing simple housekeeping script. this script contains following line of codes.This is a sample code i have extracted from the actual code since it is a big file.
#!/bin/bash
ARCHIVE_PATH=/product/file
FunctionA(){
ARCHIVE_USER=user1 # archive storage user name (default)
ARCHIVE_GROUP=group1 # archive storage user group (default)
functionB
}
functionB() {
_name_Project="PROJECT1"
_path_Componet1=/product/company/Componet1/Logs/
_path_Component2=/product/company/Componet2/Logs/
##Component1##
archive "$(_name_Project)" "$(_path_Componet1)" "filename1" "file.log"
}
archive(){
_name= $1
_path=$2
_filename=$3
_ignore_filename=$4
_today=`date + '%Y-%m-%d'`
_archive=${ARCHIVE_PATH}/${_name}_$(hostname)_$(_today).tar
if [ -d $_path];then
echo "it is a directory"
fi
}
FunctionA
When i run the above script , i get the following error
#localhost.localdomain[] $ sh testScript.sh
testScript.sh: line 69: _name_Component1: command not found
testScript.sh: line 69: _path_Component2: command not found
date: extra operand `%Y-%m-%d'
Try `date --help' for more information.
testScript.sh: line 86: _today: command not found
it is a directory
Could someone explain me what am i doing wrong here.
I see the line: _today=date + '%Y-%m-%d'
One error I spotted was resolved by removing the space between the + and the ' like so:
_today=date +'%Y-%m-%d'
I don't see where the _name_Component1 and _name_Component2 variables are declared so can't help there :)
Your variable expansions are incorrect -- you're using $() which is for executing a subshell substitution. You want ${}, i.e.:
archive "${_name_Project}" "${_path_Componet1}" "filename1" "file.log"
As for the date error, no space after the +.
a few things... you are using $(variable) when it should be ${variable}
on the date command, make sure there is no space between the + and the format
and you have name= $1, you don't want that space there