I am implementing a diff package generation task in my project's gradle build from the git command line output. Currently I have a method which will give me a list of changed files from git diff --name-only. What I would like to do is create a directory structure in a new directory which matches the paths of each file. For example: inputting the string repo/dir/file.java would create in an output directory if not already created and inside it the directories head/repo/dir with the current file.java and prev/repo/dir with the previous file.java.
My current plan is to split the string repo/dir/file.java on the forward slash, and create directories until the last element of the split result, then write the file there. but nothing I have been able to come up with in gradle is nice or clean. I am wondering if there is a nicer way to create directories from a string like that.
My current plan is to split the string repo/dir/file.java on the forward slash, and create directories until the last element of the split result
Rather than splitting your string manually, you could try using File.mkdirs():
File newDirectoryStructureParent = new File('some/path/to/parent/dir')
def s = 'repo/dir/file.java'
def newContainer = new File(s, newDirectoryStructureParent).getParent()
newContainer.mkdirs()
everyone
In this part of my code you can just work around Path not File!
At the first you can define Path and second need check that path exist or not, if not mkdirs can make it ;)
Its help when you unknown about that path exist or not /
File fullPath = new File('/tmp/Test1')
if (!fullPath.exists())
fullPath.mkdirs()
Related
I have very little experience with the command line and I'm trying to do something very complicated (to me).
I have a directory with A LOT of subfolders and files in them. All file names contain the parent folder name, e.g.:
Folder1
data_Folder1.csv
other_file_Folder1.csv
Folder2
data_Folder2.csv
other_file_Folder2.csv
In another folder (all in one directory), I have a new version of all the data_FolderX.csv files and I need to replace them in the original folders. I cannot give them another name because of later analyses. Is there a way to replace the files in the original folders with the new version, in the command line?
I tried this Replacing a file into multiple folders/subdirectories but didn't work for me. Given that I have many .csv files in the derectories, I don't want to replace them all, so I don't think I should do it based on the file extension. I would also like to note that the name "FolderX" contains several other _, so in principal, I want to replace the .csv file starting with data in the FolderX.
Can anyone help?
Thanks in advance!
Given the following text file which contains a list of directories, how would you automatically generate the file path if it doesn't exist.
apache/bin/
apache/build/
apache/error/include
apache/htdocs/images/
apache/icon/small
python/bin
python/include/python2.7
lib/pkconfig
lib/python2.7/bsddb/test
lib/python2.7/compiler
lib/python2.7/ctypes/macholib
lib/python2.7/ctypes/test
For example, from the root/start directory, if the line reads apache/bin/, I want to check if the folder apache exists, if it doesn't, then I create it.
After that I want to cd into it, check if the file bin exists, if it doesn't then I create it. Then before moving into the new line, I want to move back into the root directory (i.e. move up two levels).
How would I accomplish this in Bash?
I am looking for a way to add File(s) to an existing directory that has a random name as part of a Visual Studio Setup Project and I hoped someone might be able to help me solve this puzzle please.
I have been attempting to obtain the discovered path property of the directory using a Launch Condition; Unfortunately this method returns the full file path including the filename, which cannot be used as a directory property.
The directory in question takes the form [AppDataFolder]Company\Product\aaaaaaaaaaaa\
where aaaaaaaaaaaa is a random installation string.
Within the Launch Condition Setup I check for the directory's existence by searching for a file that would appear inside it,
Search Target Machine
(Name): File marker
Filename: sample.txt
Folder: [AppDataFolder]Company\Product\
Property: DIRFILE
Launch Condition
(Name): File marker exists
Condition: DIRFILE
In the Setup Project I add the file I wish to insert, with the details
Condition: DIRFILE
Folder: 'Installation folder'
Then in File System Setup I add a new folder entry for the random directory aaaaaaaaaaaa
(Name): Installation folder
Condition: DIRFILE
DefaultLocation: [DIRFILE]\..\ *Incorrect*
Property [DIRLOCATION]
As you can see the installer detects the existence of the marker file but, instead of placing my file at the same location, when using [DIRFILE] the installer would incorrectly try and insert it INTO the file;
This is because the file path was returned
[AppDataFolder]Company\Product\aaaaaaaaaaaa\sample.txt
where I instead need the directory path
[AppDataFolder]Company\Product\aaaaaaaaaaaa
Therefore I was wondering if it was possible to return the directory the file was found in from Search Target Machine (as opposed to the file location of the file), if I could extract the directory path by performing a string replace of the filename on the file location DIRFILE within the DefaultLocation field in File System Setup, or if perhaps there is even another method I am missing?
I'm also very interested in a simple solution for this, inside the setup project.
The way I did solve it was to install the files to a temporary location and then copy them to the final location in an AfterInstall event handler. Not a very elegant solution! Since it no longer care about the user selected target path I removed that dialog. Also I needed to take special care when uninstalling.
public override void OnAfterInstall(IDictionary savedState)
{
base.OnAfterInstall(savedState);
// Get original file folder
string originDir = Context.Parameters["targetdir"];
// Get new file folder based on the dir of sample.txt
string newDir = Path.GetDirectoryName(Context.Parameters["dirfile"]);
// Application executable file name
// (or loop for all files on the path instead)
string filename = "ApplicationName.exe";
// Move or copy the file
File.Move(Path.Combine(originDir, filename), Path.Combine(newDir, filename)));
}
I am creating files from within Ruby scripts and adding stuff to them. But where are these files stored that I am creating?
I'm very new to this, sorry!
The files are created at whatever location you specified. For instance:
f = File.new("another_test.txt","w+")
that will create the file in the current working directory. You specify the path along with the file name. For example:
f = File.new("~/Desktop/another_test.txt","w+") # will create the file on the desktop.
For more details, check the File documentation.
Updated:
Included mu is too short correction.
I have to use bash scripting to copy files from one folder to another. If the destination folder has a file with the same name but older timestamp, it should not copy. Only newer files should be copied. I could have used cp -u, but I was asked not to use it. Essentially I have to use the test command testing for "ot". Please let me know how could this be done. I believe two for loops one to read the files in the source and one for the destination directories can be used and the the time stamp compared. The problem is that both for loops produce the absolute path names along with the file name. So not sure how to compare them
Thanks
You can profit from the parameter substitution:
for file in "$folder1"/* ; do
filename=${file##*/} # Remove everything to the last slash.
Or, you can change the directory:
cd "$folder1"
for file in * ; do
## you have to use full or relative path to $folder2 here