I have the following ReQL Query which Identifies distinct addresses, but can't seem to add the not() method to get the opposite.
r.db('mydb').table('users').orderBy(r.desc('email')).without('id').distinct()
not operates on booleans. .distinct().not() doesn't modify the distinct operation. It just gets applied applies to its result, which doesn't make much sense.
You could instead do something like this
r.db('mydb').table('users')
.group('email').count().ungroup()
.filter(row => row('reduction').gt(1))('group')
Related
JSONata has the $keys() function which returns all the names associated with an object. I am trying to recursively apply this in order to return all of the object names that exist in a JSON tree.
This example returns the object names in nested arrays.
In an attempt to eliminate the array nesting I came up with this query ... which seems to work fine.
However, when I apply the exact same query to different JSON data as shown here the results are not fully flattened.
Q: What is the proper way to construct this query so that the results are fully flattened?
and/or
Q: What characteristic distinguishes these two datasets to account for the difference in the structure of the results?
OK, I guess I figured this out.
This query uses explicit calls to $map() and $reduce()+$append() to flatten it.
This query accomplishes the same thing using more a standard JSONata dot (.) query notation.
I'm using Solr to run a query on one of our cores. Suppose my documents have two fields: ID, and Name. I also have a separate list of IDs I'm grabbing from a database and passing into the query to boost certain results.
If the document gets returned in the query and the ID is in the list it goes to the top of the results, and if it gets returned in the query and the ID is not in the list then it goes below those that are in the list. The former is from the "boost". My query is something like this -
http://mysolrserver:8983/solr/MyCore/MyQueryHandler?q=Smith&start=0&rows=25&bq=Id%3a(36+OR+76+OR+90+OR+224+OR+391)
I am able to get the boost query working but I need the boosted results to be in alphabetical order by name, then the non boosted results under that also in alphabetical order by name. I need to know what to user for the &sort= parameter.
&sort=score%20desc,Name+asc does not work.
I've looked over a lot of documentation, but I still don't know if this even possible. Any help is appreciated. Thanks!
Solr version is 6.0.1. I am actually using SolrNet to interface with Solr, but I think I can figure out the SolrNet part if I know what the url's &sort= parameter value needs to be.
I figured it out, by doing away with the boost query. I added a sort query using the "exists" function and passing it a sub-query for the ID. The exists returns a boolean value to sort on, then I added the name as a second sort. It works perfect!!
The URL looks like this:
http://mysolrserver:8983/solr/MyCore/MyQueryHandler?q=Smith&start=0&rows=25&sort=exists(query({!v=%27Id:(36+OR+76+OR+90+OR+224+OR+391)%27}))%20DESC,%20Name%20ASC
The closest match to your requirement is the query elevation component[1] .
In your particular case I would first sort my Ids according to my requirements ( sorting them by name for example), then maintain them in the elevate.xml.
At query time you can use the "forceElevation" parameter to force the elevation and then sort the remaining results by name.
[1] https://cwiki.apache.org/confluence/display/solr/The+Query+Elevation+Component
I've got an Entity model (in Mongoid) that I'm trying to search on its keywords field which is an array. I want to do a query where I pass in an array of potential search terms, and any entity that matches any of the terms will pass.
I don't have this working well yet.
But, why I'm asking this question, is that it's more complex. I also DONT want to return any entities that have been marked as "do not return" which I do via a "ignore_project_ids" parameter.
So, when I query, I get 0 results. I was using Bonsai.io. But, I've moved this to my own EC2 instance to reduce complexity/variables on solving the problem.
So, what am I doing wrong? Here are the relevant bits of code.
https://gist.github.com/3405763
You want a terms query rather than a term query - a term query is only interested in equality, whereas a terms query requires that the field match any of the specified values.
Given that you don't seem to care about the query score (you're sorting by another attribute), you'll get faster queries by using a filtered query and expressing your conditions as filters
I got my lucene index with a field that needs to be sorted on.
I have my query and I can make my Sort object.
If I understand right from the javadoc I should be able to do query.SetSort(). But there seems to be no such method...
Sure I'm missing something vital.
Any suggestions?
There are actually two important points. First, the field must be indexed. Second, pass the Sort object into the overloaded search method.
Last time I looked, the docs didn't do a very good job of pointing out the indexing part, and certainly didn't explain why this is so. It took some digging to find out why.
When a field is sortable, the searcher creates an array with one element for each document in the index. It uses information from the term index to populate this array so that it can perform sorting very quickly. If you have a lot of documents, it can use a lot of memory, so don't make a field sortable unless there is a need.
One more caveat: a sortable field must have no more than one value stored in each field. If there are multiple values, Lucene doesn't know which to use as the sort key.
It looks like the actual method you want is e.g. Searcher.search(Query query, Filter filter, int n, Sort sort). setSort is a method of Sort.
I got my lucene index with a field that needs to be sorted on.
I have my query and I can make my Sort object.
If I understand right from the javadoc I should be able to do query.SetSort(). But there seems to be no such method...
Sure I'm missing something vital.
Any suggestions?
There are actually two important points. First, the field must be indexed. Second, pass the Sort object into the overloaded search method.
Last time I looked, the docs didn't do a very good job of pointing out the indexing part, and certainly didn't explain why this is so. It took some digging to find out why.
When a field is sortable, the searcher creates an array with one element for each document in the index. It uses information from the term index to populate this array so that it can perform sorting very quickly. If you have a lot of documents, it can use a lot of memory, so don't make a field sortable unless there is a need.
One more caveat: a sortable field must have no more than one value stored in each field. If there are multiple values, Lucene doesn't know which to use as the sort key.
It looks like the actual method you want is e.g. Searcher.search(Query query, Filter filter, int n, Sort sort). setSort is a method of Sort.