I have write shell script to find the particular filename in the directory and create list file to copy the filenames automatically in that list file. But my script is not working list file is not created automatically. I don't know the issue in my script.
Scripts='/app/file'
SrcFiles='/app/file/Mainfiles'
cd "$SrcFiles"
touch SOURCE.LIST
chmod 777 SOURCE.LIST
cd "$Scripts"
cd "$SrcFiles"
for f in *.csv
do
cp -v "$f" /app/file/Mainfiles/SOURCE.LIST/"${f%.csv}"
done
Please try below
search_dir="/app/file/Mainfiles"
for entry in "$search_dir"/*
do echo "$(basename $entry)" >> "/app/file/Mainfiles/SOURCE.LIST"
done
Related
I am trying to rename a file which is the only file in a directory.
It is a podcast download which changes name each day so I don't know what it is called but it always ends in .MP3
I want to rename it to news.mp3
I have tried the following based on another solution on this site but it appends the news to the file
#!/bin/sh
for file in *.MP3; do
mv "$file" "${file/.MP3/news.mp3}"
done
If it's the only file in the directory you can just write the following command:
mv directory_name/* directory_name/news.mp3
In case there are few files or if dir is empty:
shopt -s nullglob
src="/path/to/dir/with/files"
dst="/destanation/folder"
i=1
cd "$src"
for f in *; do
mv "$f" "$dst/new_name_$((i++))"
done
New to shell scripting, just wanted to understand how to write a shell script to create a tar file whenever a particular directory gets modified.
When we say modification, its like new files got added/removed to/from that particular directory.
Tarfile should be something like nameofDir_timestamp.tar
find path/to/dir -mtime 10m exec tar -cvf {} ;
Assuming you have bash installed, you could do this
#!/usr/bin/env bash
dirname='folder'
dirlastmod='folder-last-modified'
[[ ${dirlastmod} -nt ${dirname} ]] && exit
timestamp=$(date '+%s')
tar -cvf "${dirname}_${timestamp}.tar" "${dirname}"
touch "${dirlastmod}"
and add it to a cronjob.
This will check if the directory folder is newer than the file folder-last-modified, and exit if it's not. If it is, it will create a tar file of the directory folder, and use touch to update/create the timestamp on the folder-last-modified file.
I need make multiple folder having the name from file without extension with this command
for i in *.avi; do mkdir "${i%.*}"; done
I don't know how to mv the related file in the folder made...
Thanks for any help
Thanks. Let's say I want to do a general script to record on Textexpander which ask me for the file extension a sort of this :
echo "Type the suffix of the file follewe by enter:"
read ext
for i in *.ext
do
mkdir "${i%.ext}"
mv "$i" "${i%.ext}"
done
But this is not working.
Use the mv command:
for i in *.avi
do
mkdir "${i%.*}"
mv "$i" "${i%.*}"
done
I'am trying to write simple script that will get files name from one folder and search them in another folder and remove if found them in that folder.
Got two folder like
/home/install/lib
/home/install/bin
/home/install/include
and
/usr/local/lib
/usr/local/bin
/usr/local/include
I want to remove all file's from /usr/local/lib{bin,include} that contains in /home/install/lib{bin,include}. For example having
/home/install/lib/test1
/usr/local/lib/test1
scritp will remove /usr/local/lib/test1. I tried to do it from each separate directory
/home/install/lib:ls -f -exec rm /usr/local/lib/{} \;
but nothing. Can you help me to manage with this simple script?
Create script rmcomm
#!/bin/bash
a="/home/install/$1"
b="/usr/local/$1"
comm -12 <(ls "$a") <(ls "$b") | while read file; do
rm "$b/$file"
done
Then call this script for every pair:
for dir in lib bin include; do rmcomm "$dir"; done
Here's something simple. Remove the echo from the line containing rm to run it after you've ensured it's doing what you want:
#!/bin/bash
dirs[0]=lib
dirs[1]=bin
dirs[2]=include
pushd /home/install
for dir in "${dirs[#]}"
do
for file in $(find $dir -type f)
do
# Remove 'echo' below once you're satisfied the correct files
# are being removed
echo rm /usr/local/$file
done
done
popd
I wrote this piece of code this morning.
The idea is, a text file (new.txt) has the details about the directory structure and the files in the directory.
Read new.txt, create the same directory structure at a destination directory (here it is /tmp), copy the source files to the corresponding destination directory.
Script
clear
DEST_DIR=/tmp
for file in 'cat new.txt'
do
mkdir -p $file
touch $file
echo 'ls -ltr $file'
cp -rf $file $DEST_DIR
find . -name $file -type f
cp $file $DEST_DIR
done
Contents of new.txt
Test/test1/test1.txt
Test/test2/test2.txt
Test/test3/test3.txt
Test/test4/test4.txt
The issue is, it executes the code, creates the directory structure, but instead of creating it at the end, it creates directories named test1.txt, test2.txt, etc. I have no idea why this is happening.
Another question: For Turbo C, C++, there is an option to check the execution flow? Is there something available in Unix, Perl and shell scripting to check the execution flow?
The script creates these directories because you tell it to on the line mkdir -p $file. You have to extract the directory path from you filename. The standard command for this is dirname:
dir=`dirname "$file"`
mkdir -p -- "$dir"
To check the execution flow is to add set -x at the top of your script. This will cause all lines that are executed to be printed to stderr with "+ " in front of it.
you might want to try something like rsync