I am trying to rename a file which is the only file in a directory.
It is a podcast download which changes name each day so I don't know what it is called but it always ends in .MP3
I want to rename it to news.mp3
I have tried the following based on another solution on this site but it appends the news to the file
#!/bin/sh
for file in *.MP3; do
mv "$file" "${file/.MP3/news.mp3}"
done
If it's the only file in the directory you can just write the following command:
mv directory_name/* directory_name/news.mp3
In case there are few files or if dir is empty:
shopt -s nullglob
src="/path/to/dir/with/files"
dst="/destanation/folder"
i=1
cd "$src"
for f in *; do
mv "$f" "$dst/new_name_$((i++))"
done
Related
I have a folder structure like this:
A big parent folder named Photos. This folder contains 900+ subfolders named a_000, a_001, a_002 etc.
Each of those subfolders contain more subfolders, named dir_001, dir_002 etc. And each of those subfolders contain lots of pictures (with unique names).
I want to move all these pictures contained in the subdirectories of a_xxx inside a_xxx. (where xxx could be 001, 002 etc)
After looking in similar questions around, this is the closest solution I came up with:
for file in *; do
if [ -d $file ]; then
cd $file; mv * ./; cd ..;
fi
done
Another solution I got is doing a bash script:
#!/bin/bash
dir1="/path/to/photos/"
subs= `ls $dir1`
for i in $subs; do
mv $dir1/$i/*/* $dir1/$i/
done
Still, I'm missing something, can you help?
(Then it would be nice to discard the empty dir_yyy, but not much of a problem at the moment)
You could try the following bash script :
#!/bin/bash
#needed in case we have empty folders
shopt -s nullglob
#we must write the full path here (no ~ character)
target="/path/to/photos"
#we use a glob to list the folders. parsing the output of ls is baaaaaaaddd !!!!
#for every folder in our photo folder ...
for dir in "$target"/*/
do
#we list the subdirectories ...
for sub in "$dir"/*/
do
#and we move the content of the subdirectories to the parent
mv "$sub"/* "$dir"
#if you want to remove subdirectories once the copy is done, uncoment the next line
#rm -r "$sub"
done
done
Here is why you don't parse ls in bash
Make sure the directory where the files exist is correct (and complete) in the following script and try it:
#!/bin/bash
BigParentDir=Photos
for subdir in "$BigParentDir"/*/; do # Select the a_001, a_002 subdirs
for ssdir in "$subdir"/*/; do # Select dir_001, … sub-subdirs
for f in "$ssdir"/*; do # Select the files to move
if [[ -f $f ]]; do # if indeed are files
echo \
mv "$ssdir"/* "$subdir"/ # Move the files.
fi
done
done
done
No file will be moved, just printed. If you are sure the script does what you want, comment the echo line and run it "for real".
You can try this
#!/bin/bash
dir1="/path/to/photos/"
subs= `ls $dir1`
cp /dev/null /tmp/newscript.sh
for i in $subs; do
find $dir1/$i -type f -exec echo mv \'\{\}\' $dir1/$i \; >> /tmp/newscript.sh
done
then open /tmp/newscript.sh with an editor or less and see if looks like what you are trying to do.
if it does then execute it with sh -x /tmp/newscript.sh
I need make multiple folder having the name from file without extension with this command
for i in *.avi; do mkdir "${i%.*}"; done
I don't know how to mv the related file in the folder made...
Thanks for any help
Thanks. Let's say I want to do a general script to record on Textexpander which ask me for the file extension a sort of this :
echo "Type the suffix of the file follewe by enter:"
read ext
for i in *.ext
do
mkdir "${i%.ext}"
mv "$i" "${i%.ext}"
done
But this is not working.
Use the mv command:
for i in *.avi
do
mkdir "${i%.*}"
mv "$i" "${i%.*}"
done
After much searching and trial and error, I'm unable to do a batch mv or rename on a directory of files. What I'd like to do is move or rename all files in a directory so that the mv'd or renamed file has $date (+ '%Y%d%m') added to the original suffix.
All the original files have unique prefixes but are either .xml or .txt so I'd like to go from org_prefix.org_suffix -> org_prefix.org_suffix.DATE
I've tried this:
$ mv /directory/* /directory/*$(date (+ '%Y%m%d')
but always get /directory/*.actualdate' is not a directory error.
I've tried this:
$ for f in *; do mv $ $f.$(date +'_%m%d%y'); done
but I get mv: cannot stat '$'; No such file or directory
Lastly, I've even tried this:
$ rename 's/*/.test/' *
just to see if I could change all the files to org_prefix.test but nothing happens (no errors, nada, zip)
Any help greatly appreciated.
The proper way to loop through files (and e.g., print their name) in the current directory is:
for file in *; do
echo "$file"
done
How will you append the date? like so, of course:
for file in *; do
echo "$file.$(date +%Y%m%d)"
done
And how are you going to do the move? like so, of course:
for file in *; do
mv -nv -- "$file" "$file.$(date +%Y%m%d)"
done
I've added:
-v so that mv be verbose (I like to know what's happening and it always impresses my little sister to watch all these lines flowing on the screen).
-n so as to no overwrite an otherwise existing file. Safety first.
-- just in case a file name starts with a hyphen: without --, mv would confuse with an option. Safety first.
If you just want to look through the files with extension .banana, replace the for with:
for file in *.banana; do
of for files that contain the word banana:
for file in *banana*; do
and so on.
Keep up with the bananas!
$ mv /directory/* /directory/*$(date (+ '%Y%m%d')
This does not work, because the * is expanded to a list of all files, so after the expansion the command will be something like:
mv /directory/file1 /directory/file2 /directory/file3 /directory/file1_date /directory/file1_date ...
So you have specified many destinations, but the syntax for mv allows only one single destination.
for f in *; do mv $ $f.$(date +'_%m%d%y'); done
Here you forgot the f after the $, that's why you get the error message.
for f in *; do mv $f $f.$(date +'%m%d%y'); done
I think this should work now, but don't forget to quote all the variables!
Finally:
for f in *; do mv "$f" "$f.$(date +'%m%d%y')"; done
Edit: When there are characters directly after a variable, it's good practice to use {} to make clear that they are not part of the variable name:
for f in *; do mv "$f" "${f}.$(date +'%m%d%y')"; done
I'am trying to write simple script that will get files name from one folder and search them in another folder and remove if found them in that folder.
Got two folder like
/home/install/lib
/home/install/bin
/home/install/include
and
/usr/local/lib
/usr/local/bin
/usr/local/include
I want to remove all file's from /usr/local/lib{bin,include} that contains in /home/install/lib{bin,include}. For example having
/home/install/lib/test1
/usr/local/lib/test1
scritp will remove /usr/local/lib/test1. I tried to do it from each separate directory
/home/install/lib:ls -f -exec rm /usr/local/lib/{} \;
but nothing. Can you help me to manage with this simple script?
Create script rmcomm
#!/bin/bash
a="/home/install/$1"
b="/usr/local/$1"
comm -12 <(ls "$a") <(ls "$b") | while read file; do
rm "$b/$file"
done
Then call this script for every pair:
for dir in lib bin include; do rmcomm "$dir"; done
Here's something simple. Remove the echo from the line containing rm to run it after you've ensured it's doing what you want:
#!/bin/bash
dirs[0]=lib
dirs[1]=bin
dirs[2]=include
pushd /home/install
for dir in "${dirs[#]}"
do
for file in $(find $dir -type f)
do
# Remove 'echo' below once you're satisfied the correct files
# are being removed
echo rm /usr/local/$file
done
done
popd
I have a few subdirectories in a given folder, where a file d2.sh~ exists. I want to delete this file via following shell script, which, rather than writing in a .sh file I wrote on terminal, on one line. [Edit: been formatted properly here for clarity]
for i in `ls *`; do
if [ -d $i ]; then
cd $i
rm d2.sh~
cd ..
fi
done
This did not give me any errors but it failed to delete d2.sh~ from the subdirectories. So I want to know what mistake I have made above?
find /some/path -type f -name "d2.sh~" -delete
Your first mistake is trying to parse ls. See this link as to why.
Just use for i in *; do ....
If you need recursion then you need to look to find or if you have Bash 4.X you can do:
shopt -s globstar; for i in **/d2.sh~; do rm "$i"; done