What is the equivalent query of laravel on this? - laravel

This is the native sql:
$sql = "Select count(name) from users Where email = 't#t.com' and user_id = 10";
I have this laravel code:
$checker = Customer::whereEmailAndUserId("t#t.com",10)->count("name");
Is this a correct way to do it in laravel?

You have to use where helper function and pass an array of checks. For example in your code it will be:
$checker = Customer::where([
['email', '=', 't#t.com'],
['user_id' '=', '10']
])->count();
Note: Please use the appropriate column name as it in table.

Assuming Customer model represents table users, you'll get query with eloquent like this:
Customer::where('email', 't#t.com')->where('user_id', 10)->select(\DB::raw('count(name)'))->get();

The option you are trying is incorrect
here is the right option
$users = \App\Customer::where('email','t#t.com')
->where('user_id',10)
->count()
Explanation of above code
App\Customer is the Model class and I am trying to read records where email = 't#t.com you can use various comparison operators like <,> and so on and you can also use the same function to for string pattern matching also
Eg.
$users = \App\Customer::where('email','%t.com')
->where('user_id',10)
->count()
You can use the same where function for Null Value test also
Eg.
$users = \App\Customer::where('email','=', null)
->where('user_id',10)
->count()
The above where clause will be converted to is null test of the SQL
You can read more here

Related

Laravel JOIN with JSON string

I have two tables in Laravel, one is the comment table, and the second is the users table. In the comment table, I have this type of data.
For this comment table, I want to match the tags column's userid in JSON, so how can we join that userid with the user's table? here is what I tried, but that is not working as expected.
$messages = TopicComment::where('user_id', $currentUserId)
->join("users", "users.id", "=", "users.id")
->(function ($query) {
$query->whereJsonContains('tags.userid', users.id);
})
->
->get()->toArray();
with this package you can create a relation via a json field
https://github.com/staudenmeir/eloquent-json-relations
First, there seem to be a number of errors in your code.
Judging from the DB schema, there is no user_id column in your comments table and so, ::where('user_id', $currentUserId) will not work.
A similar issue occurs in your join statement. You're joining on "users.id","=","users.id" which is the same column in the same table.
There's no method called in the line with function($query). Ideally, should be a where clause.
Correct usage of whereJsonContains would be:
$query->whereJsonContains('tags', ['userid' => $currentUserId]);
Rouge arrow after that line.
And so, your final result after correcting the changes should look like:
use Illuminate\Support\Facades\DB;
...
$messages = TopicComment::join('users', 'users.id', DB::Raw("CAST(comments.tags->'$.userid' AS UNSIGNED)"))
->where(function ($query) use ($currentUserId) {
$query->whereJsonContains('tags', ['userid' => $currentUserId]);
})
->get()
->toArray();
I think the only way to extract is to use json tables.
DB::select(DB::raw("
SELECT document_types.*, jst.name
FROM document_types,
JSON_TABLE(settings, '$[*]' COLUMNS (
`userid` int(11) PATH '$.userid',
`name` varchar(255) PATH '$.name'
)) jst
inner join users on jst.userid = users.id WHERE users.id = :id"
,['id' => $currentUserId]))->get()
credit: https://dba.stackexchange.com/questions/306938/extract-json-object-inside-of-an-json-array-then-search-base-on-id
Unfortunately I don't have json functions on my mysql so the code will probably fail, maybe at least it'll help get you on the right track.
You can try this way...
eg:
<?php
$comments = DB::table('topic_comments')
->join('users', 'users.id', '=', 'topic_comments.tags->userid')
->select('topic_comments.*', 'users.name')
->get();

How to select min and max in laravel

I want to convert this code in laravel.
SELECT MAX(date_start) AS DateStart,MIN(date_end) AS DateEnd FROM DBTest
And I try this code
$data = DB::table('DBTest')
->select(max('date_start'), min('date_end')))
->get();
Return Error: max(): When only one parameter is given, it must be an array
I am using laravel 5.2, and SQLyog as database
I am confuse in syntax please help me
You can't use functions in select statement, but you can use raw SQL :
$data = DB::table('DBTest')
->select(\DB::raw('MIN(date_start) AS DateStart, MAX(date_end) AS DateEnd'));
->get();
You can do it like this:
For the max start date:
max = DB::table('DBTest')->select('date_start')->orderBy('date_start', 'desc')->first();
For min end date:
min = DB::table('DBTest')->select('date_end')->orderBy('date_end', 'asc')->first();
You have to use something called selectRaw method in Laravel in order to achieve this result. Chaining method like ->max('columnA')->min('columnB') will not work. So, here is the solution:
$data = DB::table('DBTest')
->selectRaw('MAX(date_start) AS DateStart, MIN(date_end) AS DateEnd')->get();
Try MIN() and MAX() functions in the sql query.
$data = DB::table('DBTest')
->select(\DB::raw('MIN(date_start) AS startDate, MAX(date_end) AS endDate'));
->get();

How to use search value contain in array field using eloquent in Laravel

I'm working on laravel array serialize. Below is serialize in controller.
public function CreateSave(CreateTestTopicRequest $request){
...code..
$testtopic->class_room_id = $request->classroom;
$testtopic->roomno = serialize($request->roomno);
...code..
}
Then, roomno will be saved to database like.
a:2:{i:0;s:1:"1";i:1;s:1:"2";}
I would like to get result. For example class_room_id = 1 and roomno only contain in roomno array. I may use command to get all as below.
$testtopics = TestTopic::where('class_room_id',1)->get();
But, I do not know to get record only class_room_id = 1 and roomno contain in array. Any advice or guidance on this would be greatly appreciated, Thanks
You can use like search in json fields
TestTopic::where('class_room_id',1)->where('roomno', 'like', '%"id": 1%')->first()
When checking for an array of values the whereIn method can be used:
$roomno = 'a:2:{i:0;s:1:"1";i:1;s:1:"2";}';
$testtopics = TestTopic::where('class_room_id',1)
->whereIn('roomno', unserialize($roomno))
->get();
Multiple where statements can be combined by passing an array:
$roomno = 'a:2:{i:0;s:1:"1";i:1;s:1:"2";}';
$users = TestTopic::where([
['class_room_id', '=', '1'],
['roomno', '=', $roomno],
])->get();

How to Join same table in laravel

I wan to wirte a join query to connect same table, and without ON, but when i write it in laravel without on it is showing error
$key = DB::table('api_keys as ak')
->join('api_keys as bk','')
->where('ak.api_key', $api_key)->where('ak.user_id',0)
->pluck('api_key');
want to build the below query,
SELECT * FROM `api_keys` as ak
JOIN `api_keys` as bk
WHERE ak.`api_key`=$akey
and ak.`user_id`=$auser
and bk.`user_id`=$bsuer
and bk.`api_key`=$bkey
You must provide an ON clause for the join. More about where ON clauses are required can be found in this answer.
You can view the generated query using toSql() on a QueryBuilder object:
echo $key = DB::table('api_keys as ak')
->join('api_keys as bk','')
->where('ak.api_key', $api_key)->where('ak.user_id',0)
->toSql();
Which in your case returns:
select * from `api_keys` as `ak` inner join `api_keys` as `bk`
on `` `` where `ak`.`api_key` = ? and `ak`.`user_id` = ?
In your case it isn't totally clear what you are trying to achieve, but you might consider joining on api_key or the primary key of the api_keys table, if that is different:
$key = DB::table('api_keys as ak')
->join('api_keys as bk','ak.api_key', '=', bk.api_key)
->where('ak.api_key', $api_key)->where('ak.user_id',0)
->pluck('api_key');
DB::table('registerusers as a')
->join('registerusers as b', 'a.id', 'b.refer_id')
->where('a.username', 'b.username')
->where('b.id', 'a.refer_id')
->value('b.id');
without using on clause in laravel query builder you can use following
$key = DB::table(DB::raw('api_keys as ak, api_keys as bk'))
->where('ak.api_key', '=', $api_key)
->where('ak.user_id','=',0)
->where('ak.PK','=','bk.PK')
->pluck('ak.api_key')
where PK references to your table's primary key.
result will in your case.
select * from api_keys as ak, api_keys as bk where ak.api_key= 'api_key_value' and ak.user_id = 0 and ak.PK = bk.PK
I solved this by creating my own class and starting out with a base query which I modify to apply the join (using Laravel's joinSub function) as follows:
public function __construct()
{
$this->query = DB::table('question_responses as BASE');
}
public function applyFilter($questionId, $questionValue) {
$filterTableStr = 'filter_table_'.$questionId;
$filterIdStr = 'filter_id_'.$questionId;
$filterQuery = DB::table('question_responses AS '.$filterTableStr)
->select('survey_response_id AS '.$filterIdStr)
->where($filterTableStr.'.question_short_name', $questionId)
->where($filterTableStr.'.value', $questionValue);
$resultTableStr = 'result_table_'.$questionId;
$this->query = $this->query
->joinSub($filterQuery, $resultTableStr, function($join) use ($resultTableStr, $filterIdStr) {
$join->on('BASE.survey_response_id', '=', $resultTableStr.'.'.$filterIdStr);
});
}
After applying my required filters I can just call $this->query->get() as normal to obtain the result.
The important part was to make sure that each resulting table and join fields has unique names.
With this method I can apply unlimited filters to my base query.

how to make query with substr in eloquent (laravel 4)?

I have this query:
select substr(id,1,4) as id
from meteo.a2012
group by substr(id,1,4)
I just want to take first 4 numbers to my id row, but I'm trying to do in eloquent, how I do?
Thanks.
You need to use raw expressions so you can use special functions like that.
Model::select(DB::raw('substr(id, 1, 4) as id'))->groupBy(DB::raw('substr(id, 1, 4)'))->get();
Where Model is your Eloquent model you want to run the query on.
G'day
I was able to do it like this in Laravel
$data = DataModel::selectRaw("SUBSTRING_INDEX(EMAIL_COLUMN, '#', 1) as 'alias'")->get();
As a result, I get the alias name (address) from the mail address#domain.net
$ids = Model::get(['id']);
foreach ($ids as $str)
{
$str->id =substr($str->id,1,4);
}
return $ids;

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