Ruby - How is MatchData object created without .new? - ruby

I'm creating a class (say, Bar) for an object to be returned by a method of another class (say, Foo#bar), pretty much MatchData object is returned by Regexp#match.
But the class MatchData does not have .new!
I know I don't need to imitate MatchData implementation, but I'd like to understand it and know how to do it when I find it interesting. Suppose I don't want clients creating Bar objects unless by calling Foo#bar.
Questions:
Internally, how is MatchData object created without .new?
How can I implement it (imitating MatchData or not)?

The MatchData.new method is being explicitly undefined:
rb_cMatch = rb_define_class("MatchData", rb_cObject);
rb_define_alloc_func(rb_cMatch, match_alloc);
rb_undef_method(CLASS_OF(rb_cMatch), "new"); // <- here
You can do the same in pure Ruby via undef_method:
class Bar
class << self
undef_method :new
end
def initialize
#bar = '123' # <- for demonstration purposes
end
end
Trying to call Bar.new will now result in an error:
Bar.new #=> undefined method `new' for Bar:Class (NoMethodError)
To create a new instance without a new method, you can call allocate manually (and maybe initialize, too):
bar = Bar.allocate #=> #<Bar:0x007f9eba047cd8>
Bar.send(:initialize) #=> "123"
bar #=> #<Bar:0x007fd8e0847658 #bar="123">
(send is needed because initialize is private)

Let me start with that you shouldn't. It's arubyic to go out of your way to constraint users to do what they want to do even if it's not public interface. A more idiomatic approach would be make it more explicit that it's not part of the public interface. You can do that by making the class private:
class RegexMockery
class MatchDataMockery
def initialize(whatever)
puts "I'm being created #{whatever}"
end
def [](_)
'42'
end
end
private_constant :MatchDataMockery
def match(string)
MatchDataMockery.new(string)
end
end
match_result = RegexMockery.new.match('foo')
# I'm being created foo
# => #<RegexMockery::MatchDataMockery:0x007fe990de2ed0>
match_result[0] # => '42'
RegexMockery::MatchDataMockery # !> NameError: private constant RegexMockery::MatchDataMockery referenced
But if you insist on people hating you, save the method, undef it and call it whenever you want to create instances:
class Foo
def initialize(whatever)
puts "Now you see me #{whatever}"
end
def brag
puts "I can create Foos and you can't!!!1!!"
end
end
class Bar
foos_new = Foo.method(:new)
Foo.singleton_class.send :undef_method, :new
define_method(:sorcery) do
foos_new.call('bar').brag
end
end
Bar.new.sorcery
# Now you see me bar
# I can create Foos and you can't!!!1!!
Foo.new # !> NoMethodError: undefined method `new' for Foo:Class

Related

Default method for Ruby class

Is there a way to specify a class method such that when the object is used as if it were a function, that method is called? Something like this:
class MyClass
def some_magic_method(*args)
# stuff happens
end
end
# create object
myob = MyClass.new
# implicitly call some_magic_method
myob 'x'
You could write a command class and make use of a ruby shortcut
class MyClass
def self.call(text)
puts text
end
end
MyClass.('x')
Here MyClass.() defaults to the call class method.
As mentioned by #CarySwoveland in the comments you can use method_missing. A basic example is as follows:
class MyClass
def method_missing(method_name, *args)
if method_name.match?(/[xyz]/)
send(:magic_method, args.first)
else
super
end
end
def magic_method(a)
a = 'none' if a.nil?
"xyz-magic method; argument(s): #{a}"
end
end
myob = MyClass.new
myob.x #=> "xyz-magic method; argument(s): none"
myob.x(1) #=> "xyz-magic method; argument(s): 1"
myob.y #=> "xyz-magic method; argument(s): none"
myob.z #=> "xyz-magic method; argument(s): none"
This captures all methods named x, y or z. Our else branch sends all other undefined methods to the original method_missing:
myob.v #=> test.rb:7:in `method_missing': undefined method `v' for
#<MyClass:0x000000021914f8> (NoMethodError)
#from test.rb:25:in `<main>'
What methods you capture is up to you and is determined by the regex /[xyz]/ in this case.
Key methods: BasicObject#method_missing, Object#send. For further info check out this question, read Eloquent Ruby by Russ Olsen (from which this answer references)
You meant to invoke some class' instance method when the object is invoked as a function. This is already supported: instance method call gets called when you "invoke" an object via the functional invocation method () (for more details, see here How do I reference a function in Ruby?).
class C
def call(x)
puts "Called with #{x}"
end
end
obj = C.new
obj.(88) # Called with 88 => nil
obj (88) # NoMethodError: undefined method `obj' for main:Object
If you do want the latter syntax, a horrible trick is the following one (but works only at the top-level, unless you carry along the bindings):
module Kernel
def method_missing(name,*args)
obj = begin
TOPLEVEL_BINDING.local_variable_get(name)
rescue
nil
end
return super if obj.nil?
obj.send :call, *args
end
end
obj = C.new
obj 88 # Called with OK => nil
This example also wants to communicate that you should always keep in mind
who is the receiver of your method calls, and what syntaxes are available for calling methods (especially when you leave out dots and parentheses).
class D
def obj; C.new end
def f
#(obj) 88 # BAD
(obj).(88)
#obj() 88 # BAD
obj().(88)
end
end
The point is that you do not actually have functions, but methods that get called on objects. If you omit the receiver of a method call, the receiver defaults to self, the current object. But in your example, myob does not appear as an explicit receiver (since there is not following dot as in myob.), hence the current object is looked for a method myob.

Why am I getting 'private method new' error only inside a class method definition

I have this Ruby code where I try to implement the Singleton pattern manually:
class A
#a = A.new
def self.instance
p 'initialized'
#a
end
private_class_method :new
end
A.instance #=> prints 'initialized'
Unfortunately, the object will be created before A.instance is even called. To avoid this, I thought of changing the code:
class A
#a = nil
def self.instance
p 'initialized'
#a ||= A.new
end
private_class_method :new
end
A.instance
I get "private method `new' called for A:Class (NoMethodError)" error though. This is very puzzling, why do I get this error in the second example and not in the first? The only difference is that in the second example .new is called in a class method definition. I deliberately put private_class_method on the bottom so this kind of error is prevented (putting it on the top will give the error for both examples). Btw, I'm aware this will work if I change #a from being a class instance variable to a class variable (to start with ##). I don't understand why this would work, since I know instance variables are relative to SELF and SELF is the class, both where I initialize #a to nil and where I lazy instantiate it in self.instance.
Here is a strange thing.
A.new doesn't work because you should call private method only directly, so you should use explicit new call.
In the other hand new call is something like implicit self.new but self.new will raise an exception like A.new. And this is the strange part I don't understand
class A
def self.instance
p 'initialized'
# ok
new
# should be ok but it is not
self.new rescue p("error self.new: #{$!}")
# should fail
A.new rescue p("error A.new: #{$!}")
end
private_class_method :new
end
A.instance
# "initialized"
# "error self.new: private method `new' called for A:Class"
# "error A.new: private method `new' called for A:Class"
PS: http://weblog.jamisbuck.org/2007/2/23/method-visibility-in-ruby
You can't use explicit receiver with private methods
SO: Understanding private methods in Ruby

Ruby: NoMethodError, but why?

I was working on a simple Pi Generator while learning Ruby, but I kept getting NoMethodError on RubyMine 6.3.3, so I decided to make a new project and new class with as simple as possible, and I STILL get NoMethodError. Any reason?
class Methods
def hello (player)
print "Hello, " << player
end
hello ("Annie")
end
And the error I get is:
C:/Users/Annie the Eagle/Documents/Coding/Ruby/Learning Environment/methods.rb:5:in `<class:Methods>': undefined method `hello' for Methods:Class (NoMethodError)
You have defined an instance method and are trying to call it as a method of a class. Thus you need to make the method hello a class method, not an instance method of the class Methods.
class Methods
def self.hello(player)
print "Hello, " << player
end
hello("Annie")
end
Or, if you want to define it as instance method then call it as below :
class Methods
def hello(player)
print "Hello, " << player
end
end
Methods.new.hello("Annie")
You're trying to call an instance method as a class method.
Here's some code that illustrates the difference between the two in ruby:
class Person
# This is a class method - note it's prefixed by self
# (which in this context refers to the Person class)
def self.species
puts 'Human'
# Note: species is OK as a class method because it's the same
# for all instances of the person class - ie, 'Bob', 'Mary',
# 'Peggy-Sue', and whoever else, are ALL Human.
end
# The methods below aren't prefixed with self., and are
# therefore instance methods
# This is the construct, called automatically when
# a new object is created
def initialize(name)
# #name is an instance variable
#name = name
end
def say_hello
puts "Hello from #{#name}"
end
end
And now try it out, calling the methods...
# Call a class method...
# We're not referring to any one 'instance' of Person,
Person.species #=> 'Human'
# Create an instance
bob = Person.new('Bob')
# Call a method on the 'Bob' instance
bob.say_hello #=> 'Hello from Bob'
# Call a method on the Person class, going through the bob instance
bob.class.species #=> 'Human'
# Try to call the class method directly on the instance
bob.species #=> NoMethodError
# Try to call the instance method on the class
# (this is the error you are getting)
Person.say_hello #=> NoMethodError
You've created an instance method, but you're calling a class method. In order to call hello("Annie"), you have to make an instance of Methods. For instance:
class Methods
def self.hello(player)
print "Hello, " << player
end
end
my_method = Methods.new
my_method.hello("Annie")
This would output Hello, Annie
By defining a method with def method_name args you are defining a instance method that will be included in every object of that class, but not in the class itself.
On the other hand, by def self.method_name args you will get a class method that will be directly in the class, without the need of instanciate an object from it.
So If you have this:
Class Test
def self.bar
end
def foo
end
end
You can execute the instance method this way:
a = Test.new
a.foo
And as for the class one should be:
Test.foo

Method chaining in ruby

I want to build an API client that has an interface similar to rails active record. I want the consumers to be able to chain methods and after the last method is chained, the client requests a url based on the methods called. So it's method chaining with some lazy evaluation. I looked into Active Record but this is very complicated (spawning proceses, etc).
Here is a toy example of the sort of thing I am talking about. You can chain as many 'bar' methods together as you like before calling 'get', like this:
puts Foo.bar.bar.get # => 'bar,bar'
puts Foo.bar.bar.bar.get # => 'bar,bar,bar'
I have successfully implemented this, but I would rather not need to call the 'get' method. So what I want is this:
puts Foo.bar.bar # => 'bar,bar'
But my current implementation does this:
puts Foo.bar.bar #=> [:bar, :bar]
I have thought of overriding array methods like each and to_s but I am sure there is a better solution.
How would I chain the methods and know which was the last one so I could return something like the string returned in the get method?
Here is my current implementation:
#!/usr/bin/env ruby
class Bar
def get(args)
# does a request to an API and returns things but this will do for now.
args.join(',')
end
end
class Foo < Array
def self.bar
#q = new
#q << :bar
#q
end
def bar
self << :bar
self
end
def get
Bar.new.get(self)
end
end
Also see: Ruby Challenge - Method chaining and Lazy Evaluation
How it works with activerecord is that the relation is a wrapper around the array, delegating any undefined method to this internal array (called target). So what you need is to start with a BasicObject instead of Object:
class Foo < BasicObject
then you need to create internal variable, to which you will delegate all the methods:
def method_missing(*args, &block)
reload! unless loaded?
#target.send(*args, &block)
end
def reload!
# your logic to populate target, e.g:
#target = #counter
#loaded = true
end
def loaded?
!!#loaded
end
To chain methods, your methods need to return new instance of your class, e.g:
def initialize(counter=0)
#counter = counter
end
def bar
_class.new(#counter + 1)
end
private
# BasicObject does not define class method. If you want to wrap your target
# completely (like ActiveRecord does before rails 4), you want to delegate it
# to #target as well. Still you need to access the instance class to create
# new instances. That's the way (if there are any suggestion how to improve it,
# please comment!)
def _class
(class << self; self end).superclass
end
Now you can check it in action:
p Foo.new.bar.bar.bar #=> 3
(f = Foo.new) && nil # '&& nil' added to prevent execution of inspect
# object in the console , as it will force #target
# to be loaded
f.loaded? #=> false
puts f #=> 0
f.loaded? #=> true
A (very simple, maybe simplistic) option would be to implement the to_s method - as it is used to "coerce" to string (for instance in a puts), you could have your specific "this is the end of the chain" code there.

Ruby: relationship between two methods with same name, one is 'super' to the other

In the the following tea timer code, there's a 'start' method inside SleepTimer, which calls 'notify.'
def start
sleep minutes * 60
notifier.notify("Tea is ready!")
end
If you look at the code below, you'll see that there's a notify method in the class StdioUi as well as a notify method in module UiWithBeep. The start method shown above calls the notify method in module UiWithBeep, which then, via 'super,' calls the notify method in class StdioUi. (The effect is that "BEEP!" is heard before "Tea is ready".) However, I don't understand why notifier.notify calls the notify method in module UiWithBeep rather than in class StdioUi.
First Question: how does it know to go to the one 'notify' over the other.
SecondQuestion And, although I understand super, what establishes the relationship so that notify in class StdioUi is 'super' to the other notify. Can you please explain
Tea Timer
class TeaClock
attr_accessor :timer
attr_accessor :ui
def initialize(minutes)
self.ui = StdioUi.new
self.timer = SleepTimer.new(minutes, ui)
init_plugins
end
def init_plugins
puts "init plugins"
#plugins = []
::Plugins.constants.each do |name|
#plugins << ::Plugins.const_get(name).new(self)
end
end
def start
timer.start
end
end
class StdioUi
def notify(text)
puts text
end
end
SleepTimer = Struct.new(:minutes, :notifier) do
def start
sleep minutes * 60
notifier.notify("Tea is ready!")
end
end
module Plugins
class Beep
def initialize(tea_clock)
tea_clock.ui.extend(UiWithBeep)
end
module UiWithBeep
def notify(*) #gets called by notifier.notify("Tea is ready")
puts "BEEP!"
super #calls notify in class StdioUi
end
end
end
end
t = TeaClock.new(0.01).start
The Book: I keep recommending this excellent book, Metaprogramming Ruby. I was consulting it while composing this answer.
So, here you extend an object with a module. In Ruby it's called Object Extension. In simple cases it all works as expected, like this one:
module Foo
def hello
puts "foo"
end
end
class Bar
end
bar = Bar.new
bar.extend Foo
bar.hello
# >> foo
Things get complicated when there are class' own methods involved. Here's a simplified version of your snippet that exhibits the same behaviour.
module Foo
def hello
puts "foo"
super
end
end
class Bar
def hello
puts 'bar'
end
end
bar = Bar.new
bar.extend Foo
bar.hello
# >> foo
# >> bar
When you call a method in ruby, the interpreter has to first find a method to call. This is called Method Lookup. Now, when you define an instance method, in reality it's a method on class object, not that instance. So, method lookup goes like this for first snippet:
1) bar instance => method hello not found here
2) Bar class => method hello found
When you extend an object, however, methods are injected into instance's eigenclass. It's a special "hidden" class, unique for each instance. And in reality method lookup goes through it first. First snippet again:
1) bar instance => method hello not found here
2) bar's eigenclass => method hello not found here
3) Bar class => method hello found
Now it should be clear why Foo.hello is called instead of Bar.hello: because it appears earlier in the method lookup process!
1) bar instance => method hello not found here
2) bar's eigenclass => method hello found
I may have made a few mistakes but this is roughly what happens.
each class has a property called ancestors that represents the inheritance chain. ruby walks through the list of inherited behavior and looks for matching methods. if it finds one, it calls it with the given parameters. if you call super it looks for the next match.
1.9.3-p194 :003 > String.class.ancestors
=> [Class, Mocha::ClassMethods, Module, NewRelic::Agent::MethodTracer::InstanceMethods, NewRelic::Agent::MethodTracer::InstanceMethods::TraceExecutionScoped, NewRelic::Agent::MethodTracer::ClassMethods, NewRelic::Agent::MethodTracer::ClassMethods::AddMethodTracer, Mocha::ModuleMethods, ActiveSupport::Dependencies::ModuleConstMissing, Object, FactoryGirl::Syntax::Vintage, Metaclass::ObjectMethods, Mocha::ObjectMethods, PP::ObjectMixin, JSON::Ext::Generator::GeneratorMethods::Object, ActiveSupport::Dependencies::Loadable, FriendlyId::ObjectUtils, Kernel, BasicObject]

Resources