Ignore pristinity of the specific field - redux-form

I have a form in which fields are setting up in dropdown menu onChange handler: change() form fields.
Form submit button disabled: pristine || !valid || submitting.
I can try to set up value of dropdown menu field in initialValues in onChange. Is there any other way to ignore field pristinity?

I think you can :
To keep dirty form values when it reinitializes, you can set
keepDirtyOnReinitialize to true
from http://redux-form.com/6.6.3/examples/initializeFromState/
so when you are using
export default reduxForm({
// ...
keepDirtyOnReinitialize: true
})(MyForm);

Related

Delaying Kendo Validation until Submitting the form

I have marked my controls with the Required attribute.
This has caused them to not only error on the lost focus event ( which is good ) but the problem is it won't even let me continue entering values in OTHER columns and controls of the grid on the form until I first type something for the required control.
Is there a way to delay this required validation to when I submit the form?
You can bind the .getKendoValidator(); method to your form which allow you to delay your validation.
You need to set button type ="Submit"
Refer the following line of code :-
var form_validator = $("#form_reg").kendoValidator({
rules: {
/*..*/
},
messages: {
/*..*/
}
}).getKendoValidator();
Also note that as the Validator is attached to a form element,
the validation will be executed automatically when the form is submitted, which in this case is when the button is clicked. Therefore, there is no need to manually call the validate method.
Note:-execute some custom logic, like alert to the user, when form is validated you may use
validate event.

How to remove the default selection checkboxes in ng-grid?

By default multiselection is enabled and ng-grid displays checkboxes on the left side. How to keep multiselection but get rid of the checkboxes?
Set enableRowHeaderSelection to false.
$scope.gridOptions = {
...
enableRowHeaderSelection: false
...
};

How to reset the dropdown value to the old value in jqgrid

I have a simple dropdown with two values.Lets say Staus:active and inactive.
During the onchange event, I want to perfrom some validation and revert back if the validation fails. Thai is if I change from active-inactive and my validation fails, I should change the dropdown back to active.
So far I am able to catch the on change event through the dataevents options of editOptions.
Below is my code, Thanks for the assist.
editoptions:{value:{Y:'Active',N:'Inactive'}, dataEvents:[
{
type: 'change',
fn: function(e) {
alert("inside change trigger");
$grid.setColProp('Status', { editoptions:{value:{Y:'Active',N:'Inactive'}}});
}
}
]}
I also read I have to set recreate form :true. I tried that also.
I would recommend you to consider to make the column non-editable or to readonly/disabled if the validation condition could be checked before editing will be started. It shows the user more clear that the field mayn't be changed.
Alternatively you can get savedRow parameter of jqGrid if you use inline editing mode or cell editing mode (with var savedRows = $(this).jqGrid("getGridParam", "savedRow")). To get the "old" data in case of form editing you can just get the data of selected row by using getGridParam with selrow (or alternatively from the hidden field of the form which have id="id_g". Something like var serRowId = $("#id_g").val();) and by using getRowData/getCell.

jQuery validate plugin with datepicker - invalid date causes datepicker popup on submit

I have a simple MVC3 form that has a date field and client side validation enabled (jquery.validate / jquery.validate.unobtrusive). I've added code to attach a datepicker (jQuery UI) to the date field per the documentation. However, if the datepicker is the last thing I click prior to clicking the submit button and the date field is invalid, it causes the datepicker for that field to automatically show itself. I don't want this. How can I disable?
Edit:
After reviewing the code for the validation plugin, it looks like it tries to manually focus on the last active input control using the focusInvalid() function below:
focusInvalid: function() {
if( this.settings.focusInvalid ) {
try {
$(this.findLastActive() || this.errorList.length && this.errorList[0].element || [])
.filter(":visible")
.focus()
// manually trigger focusin event; without it, focusin handler isn't called, findLastActive won't have anything to find
.trigger("focusin");
} catch(e) {
// ignore IE throwing errors when focusing hidden elements
}
}
},
There appear to be 2 options for dealing with this. One is to set the focusInvalid setting on the validator itself to false. I opted to monkey patch the focusInvalid function instead because it allows me to focus on the FIRST invalid element in the form, not necessarily the last active element.
$('form').data('validator').focusInvalid = function () {
$(this.currentForm).find('.input-validation-error').first().focus();
};
I'd be interested to hear any other approaches to this problem, however.
If acceptable in your case, you could show the datepicker only using a button, using the following datepicker options:
showOn: 'button', showButtonPanel: true, buttonImage: '<your image file>',
buttonImageOnly: true,
buttonText: 'Choose a Date',
If you do it this way the datepicker won't automatically display in case validation fails when submitting the form.

How to set default field values for add form in jqgrid from current row

Add toolbar button is used to add new row to jqgrid.
Add form which appears contains all filed vlaues empty.
How to set add form field values from column values from row which was current/selected when add command was issued ?
json remote data is used. Or if this is simpler, how to call server method passing current/selected row to retrieve default values for add form from server ?
jqgrid contains also hidden columns. If possible values from hidden columns from current row should also sent to add controller if add form is saved.
Update
I tried to use Oleg great suggestion by using
afterShowForm: function(formID) {
var selRowData,
rowid = grid.jqGrid('getGridParam', 'selrow');
if (rowid === null) {
// todo: how to cancel add command here
alert('Please select row');
return;
}
selRowData = grid.jqGrid('getRowData', rowid);
if (selRowData === null) {
alert('something unexpected happened');
return;
}
$('#' + 'Baas' + '.FormElement', formID).val(selRowData.Baas);
}
Application keeps add form open after saving. After first save Baas field is empty. It looks like afterShowForm event runs only once, not after every save. How to fix this so that multiple rows with default values can added without closing add form?
How to cancel or not allow Add command if there is no selected row ?
If you need to make some initialization actions only for Add form you can use at least two approaches:
the usage of defaultValue property as function inside of editoptions. The callback function defaultValue can provide the value for the corresponding field of the Add form based of the data from selected row. For optimization purpose you can read the data from the current selected row once in the beforeInitData callback/event. You can just read the data which you need or make an synchronous call to the server to get the information which you need. The only disadvantage of the usage of defaultValue property is that it uses jQuery.val method to set the default value for all fields of Add form with exception 'checkbox' edittype. For the checkboxs jqGrid set checked property of the checkbox of false, 0, no, off or undefined are not found in the value returned by defaultValue property. So the approach will not work for other edittypes. For example it can fail for the custom edittype.
the usage of beforeShowForm or afterShowForm. Inside of the callback functions you can set any value of the form. You can find the filed of the corresponding column of the grid by id of the field which is the same as the value of name property of the corresponding column.
Like you already knows you can get the id of the current selected row with respect of getGridParam and get the data from the selected row
var selRowData, rowid = grid.jqGrid('getGridParam', 'selrow');
if (rowid !== null) {
// a row of grid is selected and we can get the data from the row
// which includes the data from all visible and hidden columns
selRowData= grid.jqGrid('getGridParam', 'selrow');
}
where grid is jQuery object like $('#list') which selects the main <table> element of the grid.
In the demo you can see how works the first approach described above.

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