I have implemented a basic role system that uses a table 'role_user'.
On my user model I have a few methods that check the roles, one of them is:
public function isStaff()
{
foreach ($this->roles()->get() as $role)
{
if ($role->id == 3)
{
return true;
}
}
return false;
}
How can I use this method when I am querying users?
This query here:
return User::where('name', 'like', "%".$request->name."%")
->orWhere('email', 'like', "%".$request->name."%")
->whereDoesntHave('Teams', function ($query) use($teamId) {
$query->whereId($teamId);
})
->with('teams')
->get();
Currently returns all users, but I only wish to return users that have a role of 3 (isStaff)
You can using Scopes With Laravel instead of multiple methods to check for different methods.
public function scopeRole($query, $flag)
{
return $query->where('role', $flag);
}
and then
$users= User::role(3)->get();
check the reference tutorial for Creating Dynamic Scopes
it's better to do condition
return User::where('name', 'like', "%".$request->name."%")
->orWhere('email', 'like', "%".$request->name."%")
->whereDoesntHave('Teams', function ($query) use($teamId) {
$query->whereId($teamId);
})
->whereHas('roles', function($q) use ($role_id){
$q->where('id',$role_id);
})
->with('teams')
->get();
or also you can create a method for above query and based on param reurn result
You can have a scope called staff in your User model, then use that to narrow down your result:
public function scopeStaff($query, $roll_id = 3)
{
return $query->where('role_id', '=', $roll_id)
}
So when checking (with the model) for staff roles, you can improve the function that does that:
public function isStaff($role_id = 3)
{
return $this->role_id = $role_id ? $this : false;
}
Therefore, when using the query builder you can use the first method to narrow the result to those with the specified id, as you can see the default is 3 but will change to any value you give:
$staff_users = User::staff()->get();
Then the other one for verifying if a matched user model is a staff:
$user = User::find(1);
$is_staff = $user->isStaff(); //false or returns the same model
Hope this helps
Related
I have a Restaurant Model, each restaurant has a Contact Model,
and each Contact is related to a City Model:
Restaurant.php:
public function contact()
{
return $this->hasOne('App\Contact','rest_id');
}
Contact.php:
public function restaurant()
{
return $this->belongsTo('App\Restaurant','rest_id','id');
}
public function city()
{
return $this->belongsTo('App\City');
}
City.php:
public function contacts()
{
return $this->hasMany('App\Contact');
}
now, what I want to do is search the restaurant names, alongside city names.
my controller code for searching is like this:
// the purpose of this condition is to keep the query empty until applying desired filters
$data = Restaurant::where('id', '=', '0');
$cityRest=$request->cityRest ;
if (!empty($cityRest)) {
$nameFilter = Restaurant::where('name', 'like', "%$cityRest%");
$contactFilter = Restaurant::whereHas('contact', function ($contact) use ($cityRest) {
$contact->where('address', 'like', "%$cityRest%");
$contact->whereHas('city', function ($city) use ($cityRest) {
$city->where('cityName', 'like', "%$cityRest%");
});
});
$data = $data->union($nameFilter);
$data = $data->union($contactFilter);
}
$data->get();
when searching for restaurant name,the results are returned correctly,but when searching for city names nothing is returned, although there is restaurants with contact models that has a city???
You have to use a orWhereHas instead of a whereHas.
With the whereHas you are searching for restaurants where the contact.address AND the city.name match your input.
By using the orWhereHas you are searching for restaurants where the contact.address OR the city.name match your input.
The AND and OR operators are used to filter records based on more than one condition:
The AND operator displays a record if all the conditions separated by AND are TRUE.
The OR operator displays a record if any of the conditions separated by OR is TRUE.
source
Try this:
$contactFilter = Restaurant::whereHas('contact', function ($contact) use ($cityRest) {
$contact->where('address', 'like', "%$cityRest%");
$contact->orWhereHas('city', function ($city) use ($cityRest) {
$city->where('cityName', 'like', "%$cityRest%");
});
});
You are searching "%$cityRest%" as string.
I think it should be like this:
Restaurant::where('name', 'like', "%".$cityRest."%");
I am working on laravel 5.5 project
i have four tables as following:-
1- Subject model (has following relations)
public function types()
{
return $this->belongsToMany('App\Types');
}
public function areas()
{
return $this->belongsToMany('App\Area');
}
public function articles()
{
return $this->hasMany('App\Article');
}
2- Area and Types has many to many relation with Subject model
public function subjects()
{
return $this->belongsToMany('App\Subjects');
}
3- Article has 1 to many relation with Subject
public function subjects()
{
return $this->belongsTo('App\Subjects');
}
The below controller will search for subject by keyword, select type or area and return value as json using toJson() and return results to view:-
public function search(Request $request)
{
//start search//
$get_Subjects = new Subject();
$get_Subjects = $get_Subjects ->newQuery();
if($request->term != '')
{
$get_Subjects->with('articles')->whereHas('articles', function ($query) use ($request){
$query->where('title', 'LIKE', '% '.$request->term.' %')
->orwhere('abstract', 'LIKE', '% '.$request->term.' %')
->orwhere('fullCitation', 'LIKE', '% '.$request->term.' %');
})
->where(function($query) use ($request){
$query->where('name', 'LIKE', '%'.$request->term.'%');
});
}if($request->area != '28')
{
// search for the selected area
$get_Subjects->with('areas')->whereHas('areas', function($query) use ($request){
$query->where('area_id', $request->area);
});
}
if($request->type!= '36')
{
// search for the selected types
$get_Subjects->with('types')->whereHas('types', function($query) use ($request){
$query->where('type_id', $request->type);
});
}
$subjects = $get_Subjects->tojson();
return View::make('public.search', compact('subjects'));
}
the issue is when i search by keyword the returned json only include related articles, and if i search by area i only get related areas()
while if i did not use json and access variable from blade i can access all related models even though it is the same query
i tried to use load() but it did not work
any help will be valuable
============Update===========
i tried using load() as follow
$subjects= $get_subjects->get();
$subjects= $subjects->load('articles', 'areas', 'types')->tojson();
when search by keyword, the json does have related relations
but they are empty
when search by area or type, the json does have related relation
which mean if i search in the subject table only which is the 1st case i wont get related model with it
please need your help
Have you tried adding the ->get() method before the ->toJson() method?
$subjects = $get_Subjects->get()->toJson();
get() will run the query and return models. toJson() should then work as you expect.
Update
I would write your code like this to start with. (I haven't tested this).
It seems like you are using the whereHas the wrong way. The subject table should have the area_id and type_id fields, so whereHas isn't needed... this might not be the case, but it seems like it should be based on the info you provided.
public function search(Request $request)
{
$get_Subjects = new Subject();
$get_Subjects = $get_Subjects ->newQuery();
$with = [];
if($request->term != '') {
$with[] = 'articles';
$subjects = $get_Subjects->whereHas('articles', function ($query) use ($request){
$query->where('title', 'LIKE', '% '.$request->term.' %')
->orwhere('abstract', 'LIKE', '% '.$request->term.' %')
->orwhere('fullCitation', 'LIKE', '% '.$request->term.' %');
})
->where('name', 'LIKE', '%'.$request->term.'%');
}
if($request->area != '28') {
$with[] = 'areas';
$get_Subjects->where('area_id', $request->area);
}
if($request->type!= '36') {
$with[] = 'types';
$get_Subjects->where('type_id', $request->type);
}
$subjects = $get_Subjects->with($with)->get()->toJson();
return View::make('public.search', compact('subjects'));
}
In my Post Model
public function user()
{
return $this->belongsTo('App\User');
}
And in the User Model
public function posts()
{
return $this->hasMany('App\Post');
}
Now I am trying to get the comments of a specific user
$user= User::where('name', 'like', '%Mat%')->first();
return $user->posts->comment;
But it shows
Property [comment] does not exist on this collection instance.
The user has many posts which therefore returns a collection, you will need to loop over this to get your comments out. I.e.
$user = User::where('name', 'like', '%Mat%')->first();
$user->posts->each(function($post) {
echo $post->comment;
});
See the documentation on Laravel Collections
I think you can try this :
$user= User::with('post')->where('name', 'like', '%Mat%')->get();
$postComment = array();
foreach($user->post as $post){
$postComment = $post->comment;
}
return $postComment;
Hope this help for you !!!
If you want to have all comments you can use the following code:
$comments = [];
$user = User::where('name', 'like', '%Mat%')->with(['post.comment' => function($query) use (&$comments) {
$comments = $query->get();
}])->first();
return $comments;
Property [comment] does not exist on this collection instance.
The above error occurs because the Posts function returns a collection. Now you will have to traverse through each element of the collection.
Since, you are returning $user->posts()->comment, I am assuming you need it in the form of an array and don't have to simply echo them out, one by one. So you can store them all in an array & then process it whatever whay you like.
$comments = array();
$user->posts()->each(function $post){
$comments = $post->comment;
}
return $comments;
For greater insight, into this collection function read:
https://laravel.com/docs/5.4/collections#method-each
stuck on a form that allows the user to enter a value into a choice of two fields. I can query the database using one field but want to add more range to database queries. With the following code below when i try to access the page to query it just shows me a white screen.
public function index()
{
$data = $request->all();
if(!empty($data['pstoreNum']))
{
$pstoreNum = $data['pstoreNum'];
$result = DB::table('perfumes')->where('StoreNumber','=',$pstoreNum)
->get();
return view('perfumes',compact('result'));
}
else if(!empty($data['pweekNum']))
{
$pweekNum = $data['pweekNum'];
$result = DB::table('perfumes')->where('WeekNumber','=',$pweekNum)
->get();
return view('perfumes',compact('result'));
}
}
My routes file simple calls the index function. Any help would be appreciated.
You can add query functions within your query like so
public function index(Request $request)
{
$data = $request->all();
$result = \DB::table('perfumes')->where(function($query) use ($data) {
if(!empty($data['pstoreNum'])) {
$query->where('StoreNumber', '=', $data['pstoreNum']);
}
if(!empty($data['pweekNum'])) {
$query->where('WeekNumber', '=', $data['pweekNum']);
}
})->get();
return view('perfumes',compact('result'));
}
You can then use the one query and add multiple wheres on various conditions.
https://laravel.com/docs/5.2/queries#advanced-where-clauses
In Laravel we can setup relationships like so:
class User {
public function items()
{
return $this->belongsToMany('Item');
}
}
Allowing us to to get all items in a pivot table for a user:
Auth::user()->items();
However what if I want to get the opposite of that. And get all items the user DOES NOT have yet. So NOT in the pivot table.
Is there a simple way to do this?
Looking at the source code of the class Illuminate\Database\Eloquent\Builder, we have two methods in Laravel that does this: whereDoesntHave (opposite of whereHas) and doesntHave (opposite of has)
// SELECT * FROM users WHERE ((SELECT count(*) FROM roles WHERE user.role_id = roles.id AND id = 1) < 1) AND ...
User::whereDoesntHave('Role', function ($query) use($id) {
$query->whereId($id);
})
->get();
this works correctly for me!
For simple "Where not exists relationship", use this:
User::doesntHave('Role')->get();
Sorry, do not understand English. I used the google translator.
For simplicity and symmetry you could create a new method in the User model:
// User model
public function availableItems()
{
$ids = \DB::table('item_user')->where('user_id', '=', $this->id)->lists('user_id');
return \Item::whereNotIn('id', $ids)->get();
}
To use call:
Auth::user()->availableItems();
It's not that simple but usually the most efficient way is to use a subquery.
$items = Item::whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
})
->get();
If this was something I did often I would add it as a scope method to the Item model.
class Item extends Eloquent {
public function scopeWhereNotRelatedToUser($query, $user_id)
{
$query->whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
});
}
}
Then use that later like this.
$items = Item::whereNotRelatedToUser($user_id)->get();
How about left join?
Assuming the tables are users, items and item_user find all items not associated with the user 123:
DB::table('items')->leftJoin(
'item_user', function ($join) {
$join->on('items.id', '=', 'item_user.item_id')
->where('item_user.user_id', '=', 123);
})
->whereNull('item_user.item_id')
->get();
this should work for you
$someuser = Auth::user();
$someusers_items = $someuser->related()->lists('item_id');
$all_items = Item::all()->lists('id');
$someuser_doesnt_have_items = array_diff($all_items, $someusers_items);
Ended up writing a scope for this like so:
public function scopeAvail($query)
{
return $query->join('item_user', 'items.id', '<>', 'item_user.item_id')->where('item_user.user_id', Auth::user()->id);
}
And then call:
Items::avail()->get();
Works for now, but a bit messy. Would like to see something with a keyword like not:
Auth::user()->itemsNot();
Basically Eloquent is running the above query anyway, except with a = instead of a <>.
Maybe you can use:
DB::table('users')
->whereExists(function($query)
{
$query->select(DB::raw(1))
->from('orders')
->whereRaw('orders.user_id = users.id');
})
->get();
Source: http://laravel.com/docs/4.2/queries#advanced-wheres
This code brings the items that have no relationship with the user.
$items = $this->item->whereDoesntHave('users')->get();