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I'm making a program in Go for guessing a random number. I'm having issues with a for loop.
I can't stop the for loop from continuously iterating.
How do i break out of the loop once a condition is satisfied.
for loop == true {
//fmt.Println("read number", i, "/n")
if i == ans {
fmt.Println("well done")
}
if i != ans {
fmt.Println("Nope")
fmt.Scan(i)
}
You need to break out of the loop:
for {
fmt.Scan(i)
if i == ans {
fmt.Println("well done")
break
}
if i != ans {
fmt.Println("Nope")
}
}
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I am a newbie in Golang and now I have a requirement to change a value inside the if statement.
Here is my dummy code.
package main
func main() {
a := "hi"
pull_enable := true
switch a {
case "hi":
image_list := []float32{
0,
2,
}
for image:=0; image<len(image_list); image++{
if image == 0 {
pull_enable = true
break
}
}
}
}
I define a variable pull_enable outside of switch statement, and I want to change this variable value in the if statement, but when I built it, it encountered an issue below.
# command-line-arguments
pull_enable declared but not used
I am wondering how I can fix this issue. Is there any idea?
package main
import "fmt"
func main() {
a := "hi"
pullEnable := true
switch a {
case "hi":
image_list := []float32{
0,
2,
}
for image := 0; image < len(image_list); image++ {
if image == 0 {
pullEnable = true
break
}
}
}
fmt.Println(pullEnable)
}
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if i have many option to be filter in IF statement, can i use some function like this?
s1 := "lorem ipsum"
sum := 0
for _, v := range s1 {
if string(v) like ("a","i","u","e","o") {
sum+=1
}
}
You can use switch statement.
Switch supports multiple matches
switch string(v) {
case "a","i","u","e","o":
sum+=1
}
Tried it in the playground - https://play.golang.org/p/QRYhEDA7EUZ
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Given such a code:
type Test struct {
V int
}
func (t *Test) t() {
t.V += 1
}
func main() {
t := Test{}
for i := 1; i <= 1000000; i++ {
go t.t()
}
for {
fmt.Println(t.V)
time.Sleep(3 * time.Second)
}
}
I hope it is clear, why do I do this test. And the result is never 1000000. It always prints number less than 1000000.. So, only go channels can I use to solve it ?
Why don't I have 1000000 in result ? How to get 1000000 ?
is access to single variable from routines integrity safe?
No. Everything that is racy is not safe. Under no circumstances. Not if is a single variable, not if accessed by an odd number of goroutines and not on Mondays. Never.
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In Go, how should I put dynamic/user input in maps
func main() {
mapp := make(map[int]string)
for i := 0; i < 5; i++ {
fmt.Scanf("%d %s", &mapp[i], &mapp[i])
}
fmt.Print(mapp)
}
You can't create a key-value pair on a map like that.
What you can do, is store the input in variables, and then create a map key-value pair with the input. Like this:
for i := 0 ; i < 5 ; i++ {
var num int
var text string
fmt.Scanf("%d %s",&num,&text)
mapp[num] = text
}
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I'm thinking up about how I find the same characters in one variable looks like this:
var words string = "abab"
and then I want's to eliminate the same characters in that one variable and here's the output to be
Output:
ab
have any solution about this?
One solution can be the use of go map[] to track the taken characters.
sample code:
func main() {
s := "abcdaabcefgahccij"
newS := ""
taken := make(map[rune]int)
for _, value := range s {
if _, ok := taken[value]; !ok {
taken[value] = 1
newS += string(value)
}
}
fmt.Println(newS)
}
Output:
abcdefghij