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In Go, how should I put dynamic/user input in maps
func main() {
mapp := make(map[int]string)
for i := 0; i < 5; i++ {
fmt.Scanf("%d %s", &mapp[i], &mapp[i])
}
fmt.Print(mapp)
}
You can't create a key-value pair on a map like that.
What you can do, is store the input in variables, and then create a map key-value pair with the input. Like this:
for i := 0 ; i < 5 ; i++ {
var num int
var text string
fmt.Scanf("%d %s",&num,&text)
mapp[num] = text
}
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I have a raw string which is formed from array of strings like the one defined below
"['a','b','c']"
which i want to convert to proper array of string as below
["a","b","c"]
I am trying this on golang. However, i didn't succeed in getting this done. How this can be accomplished in go
var s = "['a','b','c']"
ss := strings.Split(strings.Trim(s, "[]"), ",")
a := make([]string, len(ss))
for i := range ss {
a[i] = strings.Trim(ss[i], "'")
}
out, err := json.Marshal(a)
if err != nil {
panic(err)
}
fmt.Println(string(out))
// output: ["a","b","c"]
https://go.dev/play/p/kQ0Up06K9zz
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if i have many option to be filter in IF statement, can i use some function like this?
s1 := "lorem ipsum"
sum := 0
for _, v := range s1 {
if string(v) like ("a","i","u","e","o") {
sum+=1
}
}
You can use switch statement.
Switch supports multiple matches
switch string(v) {
case "a","i","u","e","o":
sum+=1
}
Tried it in the playground - https://play.golang.org/p/QRYhEDA7EUZ
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When I try to assign a map key to a function it executes the function. How can I do this without executing the function?
var myslice []int
myslice = append(myslice, 1)
func RemoveIndex(s []string, index int) []string {
return append(s[:index], s[index+1:]...)
}
a["removeIndex"] = removeIndex(myslice, 0)
Just assign the function to the map[string]func([]string,int)[]string's key
func RemoveIndex(s []string, index int) []string {
return append(s[:index], s[index+1:]...)
}
a["removeIndex"] = RemoveIndex
rifn := a["removeIndex"]
rifn(myslice, 0)
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Given such a code:
type Test struct {
V int
}
func (t *Test) t() {
t.V += 1
}
func main() {
t := Test{}
for i := 1; i <= 1000000; i++ {
go t.t()
}
for {
fmt.Println(t.V)
time.Sleep(3 * time.Second)
}
}
I hope it is clear, why do I do this test. And the result is never 1000000. It always prints number less than 1000000.. So, only go channels can I use to solve it ?
Why don't I have 1000000 in result ? How to get 1000000 ?
is access to single variable from routines integrity safe?
No. Everything that is racy is not safe. Under no circumstances. Not if is a single variable, not if accessed by an odd number of goroutines and not on Mondays. Never.
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I'm thinking up about how I find the same characters in one variable looks like this:
var words string = "abab"
and then I want's to eliminate the same characters in that one variable and here's the output to be
Output:
ab
have any solution about this?
One solution can be the use of go map[] to track the taken characters.
sample code:
func main() {
s := "abcdaabcefgahccij"
newS := ""
taken := make(map[rune]int)
for _, value := range s {
if _, ok := taken[value]; !ok {
taken[value] = 1
newS += string(value)
}
}
fmt.Println(newS)
}
Output:
abcdefghij