In the following table I want Supp_ID that have same rate for same combination of Product and RouteCode
So, I should get all the rows except the first row.
Supp_ID Product RouteCode Rate
25sdf-1 PROD1 2-00 0.0436
302qq-6 PROD1 1-00 0.0815
30wqa-6 PROD1 1-00 0.0815
20xdf-1 PROD1 3-00 0.0936
28xdf-1 PROD1 3-00 0.0936
You could use a Window function to help out here:
SELECT *
FROM (SELECT supp_id, product, routecode, rate,
count(*) OVER (PARTITION BY rate, Supp_Id, Product) as count_of_shared_rate
FROM table) t1
WHERE count_of_shared_rate > 1
Related
I have a huge amount stock data. We are tracking every day stock level amount. My purpose is to get query which take records only when the amount is change:
Sample:
Desired result:
Try this query with subquery:
Select date_id, product,warehouse,amount
From
(
Select
date_id, product, warehouse, amount,
lag(amount) over (partition by product, warehouse order by date_id) amount_prev
From TABLENAME
) x
Where amount <> amount_prev
It's an exercise that is not solved in the book in which I am studying.
The goal is to find the seller who has had the highest number of sales per month,
during all the months for which there is registered information. The problem is that I do not know how to divide tuples into periods of one month.
First table is:
Table Sellers
Id_seller
Name_Product
And the other one is:
Table Product
Name_Product
View_datetime
Budget
What did i do?
I made this query:
SELECT id_seller FROM(SELECT id_seller, COUNT(id_seller)
FROM SELLERS INNER JOIN PRODUCT
ON SELLERS.name_product = PRODUCT.name_product
GROUP BY id_seller HAVING COUNT(id_seller)>= 1
ORDER BY 2 DESC)
WHERE ROWNUM = 1;
The query returns me the seller that most sales has done, but not "per month since there are records" as the statement asks. Any ideas? I'm so lost...
The idea is to compare the total sales of each salesman in this month (sysdate), with those of a month ago, two months ago ... so long as there are older records. And get the maximum from each seller. And then you print the seller with more sales from the previous list. If a seller sells 400 products this month(April, the sysdate), but another seller sold in October last year 500, the result would be the second seller . That's what I do not know how to do.
Thanks ^^
You could try this query
select MonthName, id_seller, max(TotalSales) from (
select to_char(sysdate, 'Month') MonthName, sellers.id_seller, count(sellers.id_seller) TotalSales
from sellers inner join product
on sellers.name_product = product.name_product
group by to_char(view_datetime, 'Month'), sellers.id_seller
) tab
group by MonthName, id_seller
There are a few points to make...
The tables are weird. I assume your table sellers would better be called sales, right?
In this example, having count... >= 1 is a no-op. Count could only be 0 if there were no rows at all, in which case there would be no row in the group- by output. You can just leave this count away, here.
To get the sales per month, just add the month to the group by. I.e. group by id_seller, To_date(view_datetime,'YYYYMM').
This is what I get previously from another SQL code:
Customer Id week_ending Purchase Id Price
1234 2/28/2015 8604220 15
1234 2/28/2015 8604220 13.75
1234 2/28/2015 8604220 12.95
1234 2/28/2015 8604220 18.95
567890 8/15/2015 6376243 5.15
567890 8/15/2015 6376243 0.89
567890 8/15/2015 6376243 3.99
567890 8/15/2015 6376243 2.3
1234 1/24/2015 8824241 0.99
1234 1/24/2015 8824241 3.99
1234 1/24/2015 8824241 3.89
Now I want to sum the price by Purchase ID since it is unique for every of our customer's order but I don't want my SQL to think and sum it by Customer ID (since each customer could order multiple times with multiple Purchase ID). Following is my code that I wrote but I'm afraid that it would sum them by customer_id. How do I avoid this mistake of double accounting? Thanks in advance!
WITH example AS(SELECT
customer_id
,MAX(nvl(promised_arrival_day, ship_day)) OVER (PARTITION BY purchase_id) AS ship2_day
,purchase_id
,SUM(price) AS order_size
FROM
my_table
GROUP BY
customer_id
,MAX(nvl(promised_arrival_day, ship_day)) OVER (PARTITION BY customer_purchase_id)
,purchase_id)
SELECT
example.customer_id
,TO_CHAR(example.ship2_day + (7-TO_CHAR(example.ship2_day,'d')),'MM-DD-YYYY') AS week_ending
,example.purchase_id
,example.order_size
FROM
example;
Just
SELECT customer_id, purchase_id, sum(price)
FROM your_table
GROUP BY customer_id, purchase_id
Each record will be counted only once. It doesn't do any "double accounting" as you say.
You will get one record for each unique combination of customer_id/puchase_id in your data.
Looking at your data, I would do something like.
with tbl as(
-- query by which you are getting dataset in example
)
select customer_id,purchase_id, sum(price) as total_price from tbl
group by purchase_id,customer_id
So I have a table called rentalqueue(queue_id,customer_id,movie_title,etc.) I also have a sequence on the queue_id as such:
CREATE SEQUENCE rentalqueue_seq
MINVALUE 100
MAXVALUE 300
START WITH 100
INCREMENT BY 1
NOCACHE;
Lets say I insert several movie titles into rentalqueue for a given customer from a movie table. How can I implement a trigger(assumption), so that I can designate the very last movie added in the queue? Assume I add 5 movies over lets say a couple days, each with a different timestamp.
I suggest you modify your sequence so that the maxvalue is something like 99999999. You can select the last movie added for a customer like this:
select *
from (
select *
from rentalqueue
where customer_id = :p_customer_id
order by queue_id desc)
where rownum = 1
Or, if you have a date_added field (or something similar), like this:
select *
from (
select *
from rentalqueue
where customer_id = :p_customer_id
order by date_added desc)
where rownum = 1
I need create following "numeric distribution" report in OBIEE :
item name,
count(distinct item_id by item_name),
count(distinct item_id by item_name)/count(distinct item_id)
(third column should be percent of count distinct by item name / count distinct by total)
How to get total count distinct ? I'm stuck and i will be appreciate any help.
The result should be:
Item 1 , 10, 50%
Item 2 , 20, 100%
where total number of customers is 20, and 10 od them buy Item_1, and 20 of them buy Item_2
Click on Measure in Pivot table then click on 'show Data as'>Percent of>Column.
Thats it