How can i solve this query in sql oracle? - oracle

It's an exercise that is not solved in the book in which I am studying.
The goal is to find the seller who has had the highest number of sales per month,
during all the months for which there is registered information. The problem is that I do not know how to divide tuples into periods of one month.
First table is:
Table Sellers
Id_seller
Name_Product
And the other one is:
Table Product
Name_Product
View_datetime
Budget
What did i do?
I made this query:
SELECT id_seller FROM(SELECT id_seller, COUNT(id_seller)
FROM SELLERS INNER JOIN PRODUCT
ON SELLERS.name_product = PRODUCT.name_product
GROUP BY id_seller HAVING COUNT(id_seller)>= 1
ORDER BY 2 DESC)
WHERE ROWNUM = 1;
The query returns me the seller that most sales has done, but not "per month since there are records" as the statement asks. Any ideas? I'm so lost...
The idea is to compare the total sales of each salesman in this month (sysdate), with those of a month ago, two months ago ... so long as there are older records. And get the maximum from each seller. And then you print the seller with more sales from the previous list. If a seller sells 400 products this month(April, the sysdate), but another seller sold in October last year 500, the result would be the second seller . That's what I do not know how to do.
Thanks ^^

You could try this query
select MonthName, id_seller, max(TotalSales) from (
select to_char(sysdate, 'Month') MonthName, sellers.id_seller, count(sellers.id_seller) TotalSales
from sellers inner join product
on sellers.name_product = product.name_product
group by to_char(view_datetime, 'Month'), sellers.id_seller
) tab
group by MonthName, id_seller

There are a few points to make...
The tables are weird. I assume your table sellers would better be called sales, right?
In this example, having count... >= 1 is a no-op. Count could only be 0 if there were no rows at all, in which case there would be no row in the group- by output. You can just leave this count away, here.
To get the sales per month, just add the month to the group by. I.e. group by id_seller, To_date(view_datetime,'YYYYMM').

Related

Finding all matching rows in a 30 day time window

I have a situation where I have a row in a table for each time a customer visits. What I'm trying to do is find those customers who have visited within any given 30 day window and select those visits.
EX: The main focus is just going to be on three rows in the Table: ROW_ID, CUSTOMER_ID, VISIT_DATE (in the date format).
What I'm trying to get is when a customer has visited multiple times within a 30 day span. EX: CUSTOMER_ID #5 visits on the 10/8/2019 and again on 11/1/2019, I would want to see both rows
We could try using exists logic to handle the requirement:
SELECT ROW_ID, CUSTOMER_ID, VISIT_DATE
FROM yourTable t1
WHERE EXISTS (SELECT 1 FROM yourTable t2
WHERE t2.CUSTOMER_ID = t2.CUSTOMER_ID AND
t2.ROW_ID <> t1.ROW_ID AND
ABS(t2.VISIT_DATE - t1.VISIT_DATE) <= 30);
The logic behind the above query reads cleanly as return any customer record where there another record for the same customer such that the two (different) records are within 30 days of each other.

using alias for cast in HIVE

I have a table called loan with loan amount,annual income, year (MMM-YY format) and member id. I am trying to find the highest loan amount in a year along wit annual income and member id details.
I tried to group the highest loan amount by year using the code
select max(cast(loan_amt as int)),issue_d from loan group by issue_d;
then I wanted also to fetch the member id and annual income information so I wrote the following code
but it is giving me error message for using alias for a column which is cast.
Code:
select a.loan_amt,a.member_id,a.annual_inc,a.issue_d
from
(select loan_amt,member_id,annual_inc,issue_d from loan) a
join
(select max(cast(loan_amt as int)) as ml,issue_d from loan group by issue_d) c
where ((a.issue_d=c.issue_d) and (a.loan_amt=a.ml));
What you want to do is rank the records based on the Amount, per Period, then keep only the top 1 record for each Period.
Use one of the analytic functions that are designed exactly for that purpose -- Hive has a pretty good support of the SQL standard on that topic.
Since you don't say what to do about ties (i.e. what if several loans have the same Amount???) I assume you want just one record chosen randomly...
select X, Y, Z, Period, Amount as TopAmount
from
(select X, Y, Z, Period, cast(StrAmt as double) as Amount,
row_number() over (partition by Period order by cast(StrAmt as double) desc) as TmpRank
from WTF
) TMPWTF
where TmpRank =1
If you want all the records with top Amount then replace row_number with rank or dense_rank (the "dense" stuff would make a difference for the top 2, but not for the top 1)

Select Earliest Invoice Date and Max Distribution Line Amount per Supplier

Using Oracle, PSQL, I am trying to figure out the earliest invoice date for each supplier. That would be simple enough, but I am also trying to figure out the max distribution line on the earliest invoice so I can determine what segment of the business the invoice belongs to. Segment is determined by SEGMENT_NUMBER in the example below. I know a sub query or multiple sub queries are needed here with a group by clause but I am at a loss. The syntax below is not even close, but I wanted to provided something for feedback.
SELECT
SUPPLIER_ID,
INVOICE_NUMBER,
SEGMENT_NUMBER,
MIN(INVOICE_DATE) as EARLIEST_INV_DATE,
MAX(DISTRIBUTION_AMOUNT) as MAX_DIST_LINE
FROM INVOICE_DIST
Use Analytical function like RANK().
SELECT SUPPLIER_ID,
INVOICE_NUMBER,
SEGMENT_NUMBER,
INVOICE_DATE,DISTRIBUTION_AMOUNT
(SELECT SUPPLIER_ID,
INVOICE_NUMBER,
SEGMENT_NUMBER,
INVOICE_DATE,DISTRIBUTION_AMOUNT,
RANK() OVER(PARTITION BY SUPPLIER_ID ORDER BY INVOICE_DATE,DISTRIBUTION_AMOUNT DESC) POSITION FROM INVOICE_DIST) TBL WHERE POSITION=1;

Get Shipping State, Zip, and Tax paid on Magento Orders in Date Range

I need to export a list of all orders between dates X & Y that shows the following:
Order ID
State Shipping
Zip Shipped
Sales Tax Collected
Is there an easy query I can run to pull this information from the orders table?
The current X is January 1, 2015; the current Y is March 31, 2015.
I really only need orders shipped TO California (the only state we charge tax), but can filter this out through sorting the exported CSV list later.
Thank you!
You need two tables to get your data, here is the SQL :
SELECT a.increment_id AS 'Order ID', b.region AS 'State Shipping', b.postcode AS 'Zip Shipped', a.base_tax_amount AS 'Sales Tax Collected'
FROM sales_flat_order a
JOIN sales_flat_order_address b
ON a.entity_id = b.parent_id
WHERE a.created_at >= '2015-01-01 00:00:00' AND a.created_at <= '2015-03-31 23:59:59'
GROUP BY a.entity_id
few things need be care:
tax in sales_flat_order table has many fields, I am not sure this is what you looking for
the create_at value you might want to change. In my case, my Magento order created time value is faster 11 hours than my computer time, maybe the timezone issue.
the 'GROUP BY' is for get rid of duplicate rows after select the data from two tables.
Below query will help you:-
You can implement where clause as per your requirement.
SELECT increment_id AS `Order Id` , address.region AS `state` , address.postcode AS `zipcode` , order.base_subtotal_incl_tax AS `tax` FROM sales_flat_order `order` JOIN sales_flat_order_address `address` ON order.entity_id = address.parent_id

How to add one month to month and year

I am working in oracle and new to coding and new to this site so I apologize in advance for the newbie question:
I have a script I am trying to run that will return the sum of next months' sales orders and compare that figure against our budgeted sales forecast. It was working great last month (November) when I set it up but now that it's December, I believe it's having problems figuring out that next month is a new year.
Essentially I just want to sum of our sales order records from the next month and compare that number against our forecast number.
Here is what I have so far (I'm sure I am making lots of grammatical mistakes so please be patient!)
select
"Backlog", "Forecast Amount" , round("Backlog"/"Forecast Amount",4) as "Backlog Percent"
from
(select round(sum(NVL(unit_price,0) *NVL( ship_quan,0)),2) as "Backlog"
from v_backlog_releases
where
(TO_CHAR(V_BACKLOG_RELEASES.PROMISE_DATE,'MM\YYYY') = TO_CHAR(sysdate,'MM\YYYY')+1)),
(select budamount as "Forecast Amount"
from
glbudget,
glperiods
where
glbudget.glperiods_id=glperiods.id and
TO_CHAR(GLPERIODS.START_DATE,'MM') = TO_CHAR(sysdate,'MM')+1)
The system won't let me post images of the output since I am too new. Essentially I should get something that looks like this:
Backlog | Forecast Amount | Backlog Percent
100,000 | 200,000 | .50
The backlog column is just a sum of ship quantities * price for all orders due to ship the following month.
Your issue is that for December TO_CHAR(sysdate, 'MM') + 1 is returning 13 instead of 1 of the next year. Obviously there is no month 13...
Try using ADD_MONTHS(sysdate, 1) instead and handle that result as appropriate. Best advice is to handle dates as dates instead of chars whenever possible.
Update based on comments:
Try using:
EXTRACT(MONTH FROM GLPERIODS.START_DATE) = EXTRACT(MONTH FROM ADD_MONTHS(sysdate, 1))
Documentation: https://docs.oracle.com/cd/B14117_01/server.101/b10759/functions045.htm

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