I want to write a script for any name given as an argument and prints the list of paths
to home directories of people with the name.
I am new at scripts. Is there any simple way to do this with awk or egrep command?
Example:
$ show names jakub anna (as an argument)
/home/users/jakubo
/home/students/j_luczka
/home/students/kubeusz
/home/students/jakub5z
/home/students/qwertinx
/home/users/lazinska
/home/students/annalaz
Here is the my friend's code but I have to write it from a different way and it has to be simple like this code
#!/bin/bash
for name in $#
do
awk -v n="$name" -F ':' 'BEGIN{IGNORECASE=1};$5~n{print $6}' /etc/passwd | while read line
do
echo $line
done
done
Possible to use a simple awk script to look for matching names.
The list of names can be passed as a space separated list to awk, which will construct (in the BEGIN section) a combined pattern (e.g. '(names|jakub|anna)'). The pattern is used for testing the user name column ($5) of the password file.
#! /bin/sh
awk -v "L=$*" -F: '
BEGIN {
name_pat = "(" gensub(" ", "|", "g", L) ")"
}
$5 ~ name_pat { print $6 }
' /etc/passwd
Since at present the question as a whole is unclear, this is more of a long comment, and only a partial answer.
There is one easy simplification, since the sample code includes:
... | while read line
do
echo $line
done
All of the code shown above after and including the | is needless, and does nothing, (like a UUoC), and should therefore be removed. (Actually echo $line with an unquoted $line would remove formatting and repeated spaces, but that's not relevant to the task at hand, so we can say the code above does nothing.)
I've written my first script, one in which I want to know if 2 files have the same values in a specific column.
Both files are WEKA machine-learning prediction outputs for different algorithms, hence they have to be in the same format, but the prediction column would be different.
Here's the code I've written based on the tutorial presented in https://linuxconfig.org/bash-scripting-tutorial-for-beginners:
#!/bin/bash
lineasdel1=$(wc -l $1 | awk '{print $1}')
lineasdel2=$(wc -l $2 | awk '{print $1}')
if [ "$lineasdel1" != "$lineasdel2" ]; then
echo "Files $1 and $2 have different number of lines, unable to perform"
exit 1
fi
function quitalineasraras {
awk '$1!="==="&&NF>0'
}
function acomodo {
awk '{gsub(/^ +| +$/, ""); gsub(/ +0/, " W 0"); gsub(/ +1$/, " W 1"); gsub(/ +/, "\t") gsub(/\+\tW/, "+"); print}'
}
function procesodel1 {
quitalineasraras "$1" | acomodo
}
function procesodel2 {
quitalineasraras "$2" | acomodo
}
el1procesado=$(procesodel1)
el2procesado=$(procesodel2)
function pegar {
paste <(echo "$el1procesado") <(echo "$el2procesado")
}
function contarintersec {
awk 'BEGIN {FS="\t"} $3==$8 {n++} END {print n}'
}
unido=$(pegar)
interseccion=$(contarintersec $unido)
echo "Estos 2 archivos tienen $interseccion coincidencias."
I ran all individual codes of all functions in the terminal and verified they work successfully (I'm using Linux Mint 19.2). Script's permissions also have been changed to make it executable. Paste command also is supposed to work with that variable syntax.
But when I run it via:
./script.sh file1 file2
if both files have the same number of lines, and I press enter, no output is obtained; instead, the terminal opens an empty line with cursor waiting for something. In order to write another command, I've got to press CTRL+C.
If both files have different number of lines the error message prints successfully, so I think the problem has something to do with the functions, with the fact that awk has different syntax for some chores, or with turning the output of functions into variables.
I know that I'm missing something, but can't come up with what could be.
Any help will be appreciated.
what could be.
function quitalineasraras {
awk '$1!="==="&&NF>0'
}
function procesodel1 {
quitalineasraras "$1" | acomodo
}
el1procesado=$(procesodel1)
The positional variables $1 are set for each function separately. The "$1" inside procesodel1 expands to empty. The quitalineasraras is passed one empty argument "".
The awk inside quitalineasraras is passed only the script without the filename, so it reads the input for standard input, ie. it waits for the input on standard input.
The awk inside quitalineasraras without any file arguments makes your script seem to wait.
I am trying to collate a series of .csv log files that are named by date (e.g., 2019-02-24.csv). There are a bunch of them, so I'm trying to script the process. I've crafted an AWK script that combines individual files:
awk ' FNR==1 { while (/"_time",PIN,FULLNAME,OFFICE,Acronym,Name/) getline; } 1 { print } ' 2019-01-01.csv >> usage_history.csv
But I am failing when I try to string the AWK commands together with a control loop in BASH:
for i in {01..28}; do echo "awk ' FNR==1 { while (/\"_time\",PIN,FULLNAME,OFFCODE,Acronym,Name/) getline; } 1 { print } ' 2019-01-$i.csv >> user_history.csv"; done
When I run this, it prints out the correct commands to the command line, but the awk scripts are not executed (they only get printed). If I run it without echo, I get errors telling me that the file doesn't exist; though all files are present:
bash: awk ' FNR==1 { while (/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/) getline; } 1 { print } ' 2019-01-01.csv >> user_history.csv: No such file or directory
What am I missing in my loop?
Here is a condensed sample of the command and the error messages:
$ for i in {01..02}; do "awk ' FNR==1 { while (/\"_time\",PIN,FULLNAME,OFFCODE,Acronym,Name/) getline; } 1 { print } ' 2019-01-$i.csv >> user_history.csv"; done
bash: awk ' FNR==1 { while (/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/) getline; } 1 { print } ' 2019-01-01.csv >> user_history.csv: No such file or directory
bash: awk ' FNR==1 { while (/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/) getline; } 1 { print } ' 2019-01-02.csv >> user_history.csv: No such file or directory
Could you please try following.
awk '!/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/' 2019-01-[0-9]*.csv >> user_history.csv
Here following are the points why one could use this approach:
1- Use of for loop and calling awk command in that each time will be a overkill. We should use smart approach when awk could read multiple files then we should sue it.
2- Now comes the getline part which you tried in your code, so if we want to negate any string then simply negate it by using !/string_to_be_skipped/ so it will look for only those lines which are NOT having this string.
3- While mentioning file(multiple files) to single awk command I used 2019-01-[0-9]*.csv why because since you have NOT told if files will be created daily basis or not so in case we give it a loop style and that specific file is NOT present then we will get an error. For an example let's say I use following awk command where I intentionally removed file named(2019-01-02.csv).
awk '........' 2019-01-{01..29}.csv
awk: cannot open 2019-01-02.csv (No such file or directory)
So to avoid these kind of situations I have used 2019-01-[0-9]*.csv where it will only look for files which have digits after 2019-01-0 and will loop NOT run in a loop and complaint us that some xyz etc file is missing.
Try this:
for i in {01..28}; do awk '!/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/' 2019-01-$i.csv >>user_history.csv;done
The commands after do should not be quoted.
And what you were doing essentially equals to ignore the title lines.
The {print} after 1 is unnecessary -- single 1 implies {print}. The 1 is to provide a true.
-- When there's only an expression but no block, the block implies to {print}.
-- And only a regexp equals $0~/regex/, and here I negated it.
If there's no other command inside the loop, you can simplify the loop with one awk command:
awk '!/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/' 2019-01-{01..28}.csv >>user_history.csv
But this one will throw error and stop executing when one of the files not existed.
Another way is:
awk '!/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/' 2019-01-[0-3][0-9].csv >>user_history.csv
This one will only match filenames, instead of loop for them.
It won't stop executing nor throw error, So if there's file missing you wouldn't know. And it will match extra files if exist.
For example it will read 2019-01-34.csv if it exists.
So if you want the warnings (warnings won't affect the results), but don't want the commands to stop, then use the first for loop one.
Pitfalls:
[0-3][1-9] won't match 10,20 and 30, but will match 32 to 39.
[0-9]* will match any longer number, but with 20 to 29 before 3 or likewise, it's string order.
Thanks to #Tiw and #RavinderSingh13 for their guidance. Here is the final awk script that is working well for my case where I have daily files from multiple days, months, and years (only 2018 and 2019 in this case):
awk '!/"_time",PIN,FULLNAME,OFFCODE,Acronym,Name/' 201[8-9]-[0-1][0-2]-[0-3][0-9].csv >> user_history.csv
So I have a file that contains some lines of text separated by ','. I want to create a script that counts how much parts a line has and if the line contains 16 parts i want to add a new one. So far its working great. The only thing that is not working is appending the ',' at the end. See my example below:
Original file:
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
Expected result:
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,xx
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,xx
This is my code:
while read p; do
if [[ $p == "HEA"* ]]
then
IFS=',' read -ra ADDR <<< "$p"
echo ${#ADDR[#]}
arrayCount=${#ADDR[#]}
if [ "${arrayCount}" -eq 16 ];
then
sed -i "/$p/ s/\$/,xx/g" $f
fi
fi
done <$f
Result:
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
,xx
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
,xx
What im doing wrong? I'm sure its something small but i cant find it..
It can be done using awk:
awk -F, 'NF==16{$0 = $0 FS "xx"} 1' file
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,xx
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a
b,b,b,b,b,b
a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,a,xx
-F, sets input field separator as comma
NF==16 is the condition that says execute block inside { and } if # of fields is 16
$0 = $0 FS "xx" appends xx at end of line
1 is the default awk action that means print the output
For using sed answer should be in the following:
Use ${line_number} s/..../..../ format - to target a specific line, you need to find out the line number first.
Use the special char & to denote the matched string
The sed statement should look like the following:
sed -i "${line_number}s/.*/&xx/"
I would prefer to leave it to you to play around with it but if you would prefer i can give you a full working sample.