I have extracted data like below
Name Session CATEGORY HT WT BMI
John SESSION 1 OW 1.5 64.6 28.71
John SESSION 3 OW 1.52 63.2 27.35
Eric SESSION 1 OW 1.48 55.7 25.43
Eric SESSION 3 OW 1.52 55.4 23.98
I would want it in the below format
Name session_1_Category Session_1_height session_1_weight session_1_BMI session_3_Category Session_3_height session_3_weight session_3_BMI
John OW 1.5 64.6 28.71 OW 1.52 63.2 27.35
Eric OW 1.48 55.7 25.43 OW 1.52 55.4 23.98
I'm using oracle database. Please help me with a SQL query to extract data in the above format.
In Oracle, you can use PIVOT:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE TABLE_NAME ( Name, "Session", CATEGORY, HT, WT, BMI ) AS
SELECT 'John', 'SESSION 1', 'OW', 1.5, 64.6, 28.71 FROM DUAL UNION ALL
SELECT 'John', 'SESSION 3', 'OW', 1.52, 63.2, 27.35 FROM DUAL UNION ALL
SELECT 'Eric', 'SESSION 1', 'OW', 1.48, 55.7, 25.43 FROM DUAL UNION ALL
SELECT 'Eric', 'SESSION 3', 'OW', 1.52, 55.4, 23.98 FROM DUAL;
Query 1:
SELECT *
FROM table_name
PIVOT(
MAX( HT ) AS height,
MAX( WT ) AS weight,
MAX( BMI ) AS BMI
FOR "Session" IN (
'SESSION 1' AS Session_1,
'SESSION 3' AS Session_3
)
)
Results:
| NAME | CATEGORY | SESSION_1_HEIGHT | SESSION_1_WEIGHT | SESSION_1_BMI | SESSION_3_HEIGHT | SESSION_3_WEIGHT | SESSION_3_BMI |
|------|----------|------------------|------------------|---------------|------------------|------------------|---------------|
| John | OW | 1.5 | 64.6 | 28.71 | 1.52 | 63.2 | 27.35 |
| Eric | OW | 1.48 | 55.7 | 25.43 | 1.52 | 55.4 | 23.98 |
Here is another solution without using PIVOT tables and will work across platforms-
SELECT NAME
,MAX(CASE WHEN Session = 'SESSION 1' THEN CATEGORY END) AS session_1_Category
,MAX(CASE WHEN Session = 'SESSION 1' THEN HT END) AS Session_1_height
,MAX(CASE WHEN Session = 'SESSION 1' THEN HT END) AS session_1_weight
,MAX(CASE WHEN Session = 'SESSION 1' THEN HT END) AS session_1_BMI
,MAX(CASE WHEN Session = 'SESSION 3' THEN HT END) AS session_3_Category
,MAX(CASE WHEN Session = 'SESSION 3' THEN HT END) AS Session_3_height
,MAX(CASE WHEN Session = 'SESSION 3' THEN HT END) AS session_3_weight
,MAX(CASE WHEN Session = 'SESSION 3' THEN HT END) AS session_3_BMI
FROM YOUR_TABLE
GROUP BY NAME
Related
Oracle - Say you have a table that has a unique key on name, ssn and effective date. The effective date makes it unique. What is the best way to update a current indicator to show inactive for the rows with dates less than the max effective date? I can't really wrap my head around it since there are multiple rows with the same name and ssn combinations. I haven't been able to find this scenario on here for Oracle and I'm having developer's block. Thanks.
"All name/ssn having a max effective date earlier than this time yesterday:"
SELECT name, ssn
FROM t
GROUP BY name, ssn
HAVING MAX(eff_date) < SYSDATE - 1
Oracle supports multi column in, so
UPDATE t
SET current_indicator = 'inactive'
WHERE (name,ssn,eff_date) IN (
SELECT name, ssn, max(eff_date)
FROM t
GROUP BY name, ssn
HAVING MAX(eff_date) < SYSDATE - 1
)
Use a MERGE statement using an analytic function to identify the rows to update and then merge on the ROWID pseudo-column so that Oracle can efficiently identify the rows to update (without having to perform an expensive self-join by comparing the values):
MERGE INTO table_name dst
USING (
SELECT rid,
max_eff_date
FROM (
SELECT ROWID AS rid,
effective_date,
status,
MAX( effective_date ) OVER ( PARTITION BY name, ssn ) AS max_eff_date
FROM table_name
)
WHERE ( effective_date < max_eff_date AND status <> 'inactive' )
OR ( effective_date = max_eff_date AND status <> 'active' )
) src
ON ( dst.ROWID = src.rid )
WHEN MATCHED THEN
UPDATE
SET status = CASE
WHEN src.max_eff_date = dst.effective_date
THEN 'active'
ELSE 'inactive'
END;
So, for some sample data:
CREATE TABLE table_name ( name, ssn, effective_date, status ) AS
SELECT 'aaa', 1, DATE '2020-01-01', 'inactive' FROM DUAL UNION ALL
SELECT 'aaa', 1, DATE '2020-01-02', 'inactive' FROM DUAL UNION ALL
SELECT 'aaa', 1, DATE '2020-01-03', 'inactive' FROM DUAL UNION ALL
SELECT 'bbb', 2, DATE '2020-01-01', 'active' FROM DUAL UNION ALL
SELECT 'bbb', 2, DATE '2020-01-02', 'inactive' FROM DUAL UNION ALL
SELECT 'bbb', 3, DATE '2020-01-01', 'inactive' FROM DUAL UNION ALL
SELECT 'bbb', 3, DATE '2020-01-03', 'active' FROM DUAL;
The query only updates the 3 rows that need changing and:
SELECT *
FROM table_name;
Outputs:
NAME | SSN | EFFECTIVE_DATE | STATUS
:--- | --: | :------------- | :-------
aaa | 1 | 01-JAN-20 | inactive
aaa | 1 | 02-JAN-20 | inactive
aaa | 1 | 03-JAN-20 | active
bbb | 2 | 01-JAN-20 | inactive
bbb | 2 | 02-JAN-20 | active
bbb | 3 | 01-JAN-20 | inactive
bbb | 3 | 03-JAN-20 | active
db<>fiddle here
I have table with following records;
ID | NN | MBL | IC | OTHER
---+-----+------+----+------
1 | 123 | | | ac
2 | | 544 | | dc
3 | | | 524| df
4 |527 | | 124| ff
5 |123 | | | tr // duplicate NN of ID 1
6 | | 544 | | op // duplicate MBL of ID 2
7 | | | 124| ii // duplicate for IC ID 4
When querying with select I need just records with single entry, skipping second occurrence,
select
ID, NN, MBL, IC, OTHER
from
TABLE1 // this should return only one entry of any NN, MBL and IC
How do I get this, I cannot use distinct for multiple columns and I also need ID and OTHER column to display in select query
Expecting result like this:
1 | 123 | | | ac
2 | | 544 | | dc
3 | | | 524| df
4 |527 | | 124| ff
You can use the analytical function ROW_NUMBER() to calculate ranks over each column you want and filter only these rows with rank = 1.
Here is an example:
WITH testdata AS (
SELECT 1 AS ID, 123 AS NN, NULL AS MBL, NULL AS IC, 'ac' AS OTHER FROM DUAL UNION ALL
SELECT 2, NULL, 544 , NULL, 'dc' FROM DUAL UNION ALL
SELECT 3, NULL, NULL, 524 , 'df' FROM DUAL UNION ALL
SELECT 4, 527, NULL, 124, 'ff' FROM DUAL UNION ALL
SELECT 5, 123, NULL, NULL, 'tr' FROM DUAL UNION ALL
SELECT 6, NULL, 544, NULL, 'op' FROM DUAL UNION ALL
SELECT 7, NULL, NULL , 124, 'ii' FROM DUAL
)
SELECT *
FROM(SELECT ID,
NN,
CASE WHEN NN IS NULL THEN 1 ELSE ROW_NUMBER() OVER (PARTITION BY NN ORDER BY ID) END AS NN_RANG,
MBL,
CASE WHEN MBL IS NULL THEN 1 ELSE ROW_NUMBER() OVER (PARTITION BY MBL ORDER BY ID) END AS MBL_RANG,
IC,
CASE WHEN IC IS NULL THEN 1 ELSE ROW_NUMBER() OVER (PARTITION BY IC ORDER BY ID) END AS IC_RANG,
OTHER
FROM testdata
)
WHERE NN_RANG = 1
AND MBL_RANG = 1
AND IC_RANG = 1
;
Hope it helps.
I have Incoming Stock transaction data using Oracle:
ID | DESCRIPTION | PART_NO | QUANTITY | DATEADDED
TR5 | FG | P0025 | 5 | 06-SEP-2017 08:20:33 <-- just now added
TR4 | Test | TEST1 | 8 | 05-SEP-2017 15:11:15
TR3 | FG | GSDFGSG | 10 | 31-AUG-2017 16:26:04
TR2 | FG | GSDFGSG | 2 | 31-AUG-2017 16:05:39
TR1 | FG | GSDFGSG | 2 | 30-AUG-2017 16:30:16
And now I'm grouping that data to be:
TR_ID | PART_NO | TOTAL
TR1 | GSDFGSG | 14
TR4 | TEST1 | 8
TR5 | P0025 | 5 <-- just now added
Query Code:
SELECT MIN(TRANSACTION_EQUIPMENTID) as TR_ID,
PART_NO,
SUM(T.QUANTITY) AS TOTAL
FROM WA_II_TBL_TR_EQUIPMENT T
GROUP BY T.PART_NO
As you can see on that data and query code, I'm show TR_ID using MIN to get first ID on first transaction.
And now I have Outgoing transaction data:
Assume I try to get quantity 8
ID_FK | QUANTITY
TR1 | 8
And now I want to get last ID due to quantity 8 has been consumed
ID | DESCRIPTION | PART_NO | QUANTITY
TR3| FG | GSDFGSG | 10 <-- CONSUMED 4+2+2, TOTAL 8
TR2| FG | GSDFGSG | 2 <-- CONSUMED 2+2, TOTAL 4
TR1| FG | GSDFGSG | 2 <-- CONSUMED 2
As you can see above, TR1, TR2 has been consumed. Now I want the query
SELECT MIN(TRANSACTION_EQUIPMENTID) as TR_ID,
PART_NO,
SUM(T.QUANTITY) AS TOTAL
FROM WA_II_TBL_TR_EQUIPMENT T
GROUP BY T.PART_NO
get the last id is : TR3, due to TR1 & TR2 has been consumed.
How to do that in query?
Take minimum id where growing sum is greater than 8. Use analytic sum():
select min(id) id
from (select t.*,
sum(quantity) over (partition by part_no order by id) sq
from t
where part_no = 'GSDFGSG'
)
where sq >= 8
Test data, output:
create table t(ID varchar2(3), DESCRIPTION varchar2(5),
PART_NO varchar2(8), QUANTITY number(5), DATEADDED date);
insert into t values ('TR4', 'Test', 'TEST1', 8, timestamp '2017-09-05 15:11:15');
insert into t values ('TR3', 'FG', 'GSDFGSG', 10, timestamp '2017-08-31 16:26:04');
insert into t values ('TR2', 'FG', 'GSDFGSG', 2, timestamp '2017-08-31 16:05:39');
insert into t values ('TR1', 'FG', 'GSDFGSG', 2, timestamp '2017-08-30 16:30:16');
insert into t values ('TR5', 'FG', 'GSDFGSG', 3, timestamp '2017-08-31 17:00:00');
Edit:
Add part_no and total columns and group by clause:
select min(id) id, part_no, min(sq) total
from (select t.*,
sum(quantity) over (partition by part_no order by id) sq
from t
where part_no = 'GSDFGSG'
)
where sq >= 8
group by part_no
ID PART_NO TOTAL
--- -------- ----------
TR3 GSDFGSG 14
There is a column in table 'mytable' named 'Description'.
+----+-------------------------------+
| ID | Description |
+----+-------------------------------+
| 1 | My NAME is Sajid KHAN |
| 2 | My Name is Ahmed Khan |
| 3 | MY friend name is Salman Khan |
+----+-------------------------------+
I need to write an Oracle SQL query/procedure/function to list the distinct words in the column.
The output should be:
+------------------+-------+
| Word | Count |
+------------------+-------+
| MY | 3 |
| NAME | 3 |
| IS | 3 |
| SAJID | 1 |
| KHAN | 3 |
| AHMED | 1 |
| FRIEND | 1 |
| SALMAN | 1 |
+------------------+-------+
Word matching should be case-insensitive.
I am using Oracle 12.1.
Let's suppose we would somehow manage to split every description in words.
So, instead of single row with Id = 1 and Description = 'My NAME is Sajid KHAN' we'd have 5 rows like this
ID | Description
--- | ------------
1 | My
1 | NAME
1 | is
1 | Sajid
1 | KHAN
in this form it'd be trivial, something like
select Description, count(*) from data_in_new_form group by Description
So, let's do this using recursive query.
create table mytable
as
select 1 as ID, 'My NAME is Sajid KHAN' as Description from dual
union all
select 2, 'My Name is Ahmed Khan' from dual
union all
select 3, 'MY friend name is Salman Khan' from dual
union all
select 4, 'test, punctuation! it is' from dual
;
with
rec (id, str, depth, element_value) as
(
-- Anchor member.
select id, upper(Description) as str, 1 as depth, REGEXP_SUBSTR( upper(Description), '(.*?)( |$)', 1, 1, NULL, 1 ) AS element_value
from mytable
UNION ALL
-- Recursive member.
select id, str, depth + 1, REGEXP_SUBSTR( str ,'(.*?)( |$)', 1, depth+1, NULL, 1 ) AS element_value
from rec
where depth < regexp_count(str, ' ')+1
)
, data as (
select * from rec
--order by id, depth
)
select element_value, count(*) from data
group by element_value
order by element_value
;
Please notice this version doesn't do anything about punctuation assuming words are separated with spaces.
UPDATE alternative way using hierarchic query
with rec as
(
SELECT id, LEVEL AS depth,
REGEXP_SUBSTR( upper(description) ,'(.*?)( |$)', 1, LEVEL, NULL, 1 ) AS element_value
FROM mytable
CONNECT BY LEVEL <= regexp_count(description, ' ')+1
and prior id = id
and prior SYS_GUID() is not null
)
, data as (
select * from rec
--order by id, depth
)
select element_value, count(*) from data
group by element_value
order by 2 desc
;
This query will work. The ordering of the words may be different. However, frequent words come at the beginning as you have listed.
SELECT word,
COUNT(*)
FROM
(SELECT TRIM (REGEXP_SUBSTR (Description, '[^ ]+', 1, ROWNUM) ) AS Word
FROM
(SELECT LISTAGG(UPPER(Description),' ') within GROUP(
ORDER BY ROWNUM ) AS Description
FROM mytable
)
CONNECT BY LEVEL <= REGEXP_COUNT ( Description, '[^ ]+')
)
GROUP BY WORD
ORDER BY 2 DESC;
I have a table in an Oracle 11g database that looks like this:
ownerid | propertyid | name
--------------------------------------
1 | 1000001 | SMITH MARY
2 | 1000001 | SMITH JOHN
3 | 1000002 | HUGHES JANE
4 | 1000003 | CHEN ALICE
5 | 1000003 | MCCOY ELLIS
I'm trying to group the table on propertyid and pivot the rows to columns so that it looks like this:
propertyid | owner1 | owner2
---------------------------------------------
10001 | SMITH MARY | SMITH JOHN
10002 | HUGHES JANE | <null>
10003 | CHEN ALICE | MCCOY ELLIS
Each property can have between 1 and 3 owners, but I'm only interested in the first two as they appear when ordered on ownerid.
My best solution was to create two subqueries: one of "first" owners and another "second" owners. I used the nth_value function as follows:
-- first owners
select
propertyid,
nth_value(name, 1) over (partition by propertyid order by ownerid) as owner_1
from owners
But this gives me duplicate (although correct) pairs of properties and owners if the total number of owners is greater than 1. In general I feel like there must be a better way of doing this. Does anyone have any ideas?
with
inputs ( ownerid, propertyid, name ) as (
select 1, 1000001, 'SMITH MARY' from dual union all
select 2, 1000001, 'SMITH JOHN' from dual union all
select 3, 1000002, 'HUGHES JANE' from dual union all
select 4, 1000003, 'CHEN ALICE' from dual union all
select 5, 1000003, 'MCCOY ELLIS' from dual
),
prep ( propertyid, name, rn ) as (
select propertyid, name,
row_number() over (partition by propertyid order by ownerid)
from inputs
)
select *
from prep
pivot (max(name) for rn in (1 as owner1, 2 as owner2))
order by propertyid
;
PROPERTYID OWNER1 OWNER2
---------- ----------- -----------
1000001 SMITH MARY SMITH JOHN
1000002 HUGHES JANE
1000003 CHEN ALICE MCCOY ELLIS
3 rows selected.