I am trying to find out how I can take a piece of data (being delivered to me in a .txt file in a single column) which will contain a number, anywhere from 1-999999 and read each digit and store each one into a separate variable to use later. I am new to Freemarker so I haven't had much in the way of manuals or documentation to go on, and I am not even sure its a While loop I need to complete this.
If you want to print the number with images as digits, then just add the number to the data-model (let's say with name miles and value 6756), and then for example define a FreeMacro macro:
<#macro numberAsImages n>
<#local s = n?c>
<#list 0 ..* s?length as i>
<img href="cid:digit${s[i]}" alt="${s[i]}"><#t>
</#list>
</#macro>
which later you can use as:
<#numberAsImages miles />
which will print this:
<img href="cid:digit6" alt="6"><img href="cid:digit7" alt="7"><img href="cid:digit5" alt="5"><img href="cid:digit6" alt="6">
Note that ?c should only be used if n is not a string already, but a number (which is what it should be, i.e., generally, you should parse a number coming from a .txt before putting it into the data-model).
Related
I'm working on a Scrabble assignment and I'm trying to assign values to letters. Like in Scrabble, A, E, I, O, U, L, N, S, T, R are all equal to 1. I had some help in figuring out how to add the score up once I assign values, but now I'm trying to figure out how to assign values. Is there a way to create one variable for all the values? That doesn't really make sense to me.
I was also thinking I could do an if-else statement. Like if the letter equals any of those letters, value = 1, else if the letter equals D or G, value = 2 and so on. There are 7 different scores so it's kind of annoying and not efficient, but I'm not really sure what a better way might be. I'm new to programming, a novice, so I'm looking for advice that takes my level into account.
I have started my program by reading words from a text file into an arraylist. I successfully printed the arraylist, so I know that part worked. Next I'm working on how to read each character of each word and assign a value. Last, I will figure out how to sort it.
it's me from the other question again. You can definitely do an if-statement, but if I'm not wrong Scrabble has 8 different values for letters, so you would need 8 “if”s and also since there are around 25 letters (depending on language) you would have to handle all 25 some way in the if-statements which would be quite clunky in my opinion.
I think the best option is to use a Hash-table. A hash-table is basically like a dictionary where you look up a key and get a value. So I would add each letter as a key and keep the corresponding value as the value. It would look like this:
//initialize empty hash map
Hashtable<String, Integer> letterScores = new Hashtable<>();
//now we can add values with "put"
letterScores.put("A",1)
letterScores.put("B",3)
letterScores.put("X",8)
//etc
To access an element from the hash table we can use the "get"-method.
//returns 1
letterScores.get("A")
So when looping through our word we would essentially get something like this to calculate the value of the word:
int sumValue = 0;
for(int i =0; i < word.length(); i++)}
sumValue += letterScores.get(word.charAt(i))
}
For each character we grab the value entry from the letterScores hash table where we have saved all our letter's corresponding values.
I have to be honest that I don't quite understand Lua that well yet. I am trying to overwrite a local numeric value assigned to a set table address (is this the right term?).
The addresses are of the type:
project.models.stor1.inputs.T_in.default, project.models.stor2.inputs.T_in.default and so on with the stor number increasing.
I would like to do this in a for loop but cannot find the right expression to make the entire string be accepted by Lua as a table address (again, I hope this is the right term).
So far, I tried the following to concatenate the strings but without success in calling and then overwriting the value:
for k = 1,10,1 do
project.models.["stor"..k].inputs.T_in.default = 25
end
for k = 1,10,1 do
"project.models.stor"..j..".T_in.default" = 25
end
EDIT:
I think I found the solution as per https://www.lua.org/pil/2.5.html:
A common mistake for beginners is to confuse a.x with a[x]. The first form represents a["x"], that is, a table indexed by the string "x". The second form is a table indexed by the value of the variable x. See the difference:
for k = 1,10,1 do
project["models"]["stor"..k]["inputs"]["T_in"]["default"] = 25
end
You were almost close.
Lua supports this representation by providing a.name as syntactic sugar for a["name"].
Read more: https://www.lua.org/pil/2.5.html
You can use only one syntax in time.
Either tbl.key or tbl["key"].
The limitation of . is that you can only use constant strings in it (which are also valid variable names).
In square brackets [] you can evaluate runtime expressions.
Correct way to do it:
project.models["stor"..k].inputs.T_in.default = 25
The . in models.["stor"..k] is unnecessary and causes an error. The correct syntax is just models["stor"..k].
I'm trying to create a random number generator in Lua. I found out that I can just use math.random(1,100) to randomize a number between 1 and 100 and that should be sufficient.
But I don't really understand how to use the randomize number as variables in the script.
Tried this but of course it didn't work.
$randomCorr = math.random(1,100);
http.request_batch({
{"POST", "https://store.thestore.com/priceAndOrder/selectProduct", headers={["Content-Type"]="application/json;charset=UTF-8"}, data="{\"ChoosenPhoneModelId\":4,\"PricePlanId\":\"phone\",\"CorrelationId\":\"$randomCorr\",\"DeliveryTime\":\"1 vecka\",\"$$hashKey\":\"006\"},\"ChoosenAmortization\":{\"AmortizationLength\":0,\"ChoosenDataPackage\":{\"Description\":\"6 GB\",\"PricePerMountInKr\":245,\"DataAmountInGb\":6,\"$$hashKey\":\"00W\"},\"ChoosenPriceplan\":{\"IsPostpaid\":true,\"Title\":\"Fastpris\",\"Description\":\"Fasta kostnader till fast pris\",\"MonthlyAmount\":0,\"AvailiableDataPackages\":null,\"SubscriptionBinding\":0,\"$$hashKey\":\"00K\"}}", auto_decompress=true},
{"GET", "https://store.thestore.com/api/checkout/getproduct?correlationId=$randomCorr", auto_decompress=true},
})
In Lua, you can not start a variable name with $. This is where your main issue is at. Once the $ is removed from your code, we can easily see how to refer to variables in Lua.
randomCorr = math.random(100)
print("The random number:", randomCorr)
randomCorr = math.random(100)
print("New Random Number:", randomCorr)
Also, concatenation does not work the way you are implying it into your Http array. You have to concatenate the value in using .. in Lua
Take a look at the following example:
ran = math.random(100)
data = "{\""..ran.."\"}"
print(data)
--{"14"}
The same logic can be implied into your code:
data="{\"ChoosenPhoneModelId\":4,\"PricePlanId\":\"phone\",\"CorrelationId\":\""..randomCorr.."\",\"DeliveryTime\":\"1 vecka\",\"$$hashKey\":\"006\"},\"ChoosenAmortization\":{\"AmortizationLength\":0,\"ChoosenDataPackage\":{\"Description\":\"6 GB\",\"PricePerMountInKr\":245,\"DataAmountInGb\":6,\"$$hashKey\":\"00W\"},\"ChoosenPriceplan\":{\"IsPostpaid\":true,\"Title\":\"Fastpris\",\"Description\":\"Fasta kostnader till fast pris\",\"MonthlyAmount\":0,\"AvailiableDataPackages\":null,\"SubscriptionBinding\":0,\"$$hashKey\":\"00K\"}}"
Or you can format the value in using one of the methods provided by the string library
Take a look at the following example:
ran = math.random(100)
data = "{%q}"
print(string.format(data,ran))
--{"59"}
The %q specifier will take whatever you put as input, and safely surround it with quotations
The same logic can be applied to your Http Data.
Here is a corrected version of the code snippet:
local randomCorr = math.random(1,100)
http.request_batch({
{"POST", "https://store.thestore.com/priceAndOrder/selectProduct", headers={["Content-Type"]="application/json;charset=UTF-8"}, data="{\"ChoosenPhoneModelId\":4,\"PricePlanId\":\"phone\",\"CorrelationId\":\"" .. randomCorr .. "\",\"DeliveryTime\":\"1 vecka\",\"$$hashKey\":\"006\"},\"ChoosenAmortization\":{\"AmortizationLength\":0,\"ChoosenDataPackage\":{\"Description\":\"6 GB\",\"PricePerMountInKr\":245,\"DataAmountInGb\":6,\"$$hashKey\":\"00W\"},\"ChoosenPriceplan\":{\"IsPostpaid\":true,\"Title\":\"Fastpris\",\"Description\":\"Fasta kostnader till fast pris\",\"MonthlyAmount\":0,\"AvailiableDataPackages\":null,\"SubscriptionBinding\":0,\"$$hashKey\":\"00K\"}}", auto_decompress=true},
{"GET", "https://store.thestore.com/api/checkout/getproduct?correlationId=" .. randomCorr, auto_decompress=true},
})
There is something called $$hashKey also, in the quoted string. Not sure if that is supposed to be referencing a variable or not. If it is, it also needs to be concatenated into the resulting string, using the .. operator (just like with the randomCorr variable).
I'm executing a template with 2 parallel arrays (same size) and I want to list items from both arrays in parallel, how do I use index inside of range?
this obviously doesn't work:
{{range $i, $e := .First}}$e - {{index .Second $i}}{{end}}
One of the predefined global template functions is index.
index Returns the result of indexing its first argument by the
following arguments. Thus index x 1 2 3 is, in Go syntax,
x[1][2][3]. Each indexed item must be a map, slice, or array.
So you are on the right track. The only issue is that you are not accounting for the fact the dot has been reassigned within the range block.
So you need to get back to the original dot, for that we have the following
When execution begins, $ is set to the data argument passed to Execute, that is, to the starting value of dot.
So (assuming there is nothing else going on in your template) you should be able to do:
{{range $i, $e := .First}}$e - {{index $.Second $i}}{{end}}
Personally though, I would create a template function called zip that accepts multiple slices and returns a slice of each pair of values. It would look cleaner in your template and probably get reused somewhere.
I need help with the following H.W. problem. I have done everything except the instructions I numbered. Please help!
A furniture manufacturer makes two types of furniture—chairs and sofas.
The cost per chair is $350, the cost per sofa is $925, and the sales tax rate is 5%.
Write a Visual Basic program to create an invoice form for an order.
After the data on the left side of the form are entered, the user can display an invoice in a list box by pressing the Process Order button.
The user can click on the Clear Order Form button to clear all text boxes and the list box, and can click on the Quit button to exit the program.
The invoice number consists of the capitalized first two letters of the customer’s last name, followed by the last four digits of the zip code.
The customer name is input with the last name first, followed by a comma, a space, and the first name. However, the name is displayed in the invoice in the proper order.
The generation of the invoice number and the reordering of the first and last names should be carried out by Function procedures.
Seeing as this is homework and you haven't provided any code to show what effort you have made on your own, I'm not going to provide any specific answers, but hopefully I will try to point you in the right direction.
Your first 2 numbered items look to be variations on the same theme... string manipulation. Assuming you have the customer's address information from the order form, you just need to write 2 separate function to take the parts of the name and address, take the data you need and return the value (which covers your 3rd item).
To get parts of the name and address to generate the invoice number, you need to think about using the Left() and Right() functions.
Something like:
Dim first as String, last as String, word as String
word = "Foo"
first = Left(word, 1)
last = Right(word, 1)
Debug.Print(first) 'prints "F"
Debug.Print(last) 'prints "o"
Once you get the parts you need, then you just need to worry about joining the parts together in the order you want. The concatenation operator for strings is &. So using the above example, it would go something like:
Dim concat as String
concat = first & last
Debug.Print(concat) 'prints "Fo"
Your final item, using a Function procedure to generate the desired values, is very easily google-able (is that even a word). The syntax is very simple, so here's a quick example of a common function that is not built into VB6:
Private Function IsOdd(value as Integer) As Boolean
If (value Mod 2) = 0 Then 'determines of value is an odd or even by checking
' if the value divided by 2 has a remainder or not
' (aka Mod operator)
IsOdd = False ' if remainder is 0, set IsOdd to False
Else
IsOdd = True ' otherwise set IsOdd to True
End If
End Function
Hopefully this gets you going in the right direction.