i have a script that looks something like
#!/bin/bash$
#x=new value$
#y=old value$
$
export PATH=/xxx/xxx/xxx:$PATH$
$
#get the difference of two files$
diff --side-by-side --suppress-common-lines file.txt file1.txt | tr -d "|,<,>,'\t'" | sed 's/ /:/g' | sed 's/^://' > diff.txt$
cat diff.txt$
$
#get the values$
for i in `cat diff.txt`; do$
plug_x=`echo $i | cut -d ":" -f1`$
echo "the value of jenkins plugin is $plug_x"$
ver_x=`echo $i | cut -d ":" -f2`$
echo "the value of jenkins version is $ver_x"$
plug_y=`echo $i | cut -d ":" -f3`$
echo "the value of db plugin is $plug_y"$
ver_y=`echo $i | cut -d ":" -f4`$
echo "the value of db version is $ver_y"$
if [ -z "$ver_y" ] && [ -z "$ver_x" ] ;$
then $
echo "the plugin is newly added"$
#newly added plugin should be updated in the db$
# mysql -u root -ppassword -h server --local-infile db << EOFMYSQL$
#update the table with the new version$
#EOFMYSQL$
else$
echo "the plugin has changes"$
mysql -u root -ppassword -h server --local-infile db << EOFMYSQL$
insert into table (xxx, xxx) values('$ver_x','$plug_x');$
$
EOFMYSQL $
fi$
done$
but when i run this script it saya
Syntax error: end of file unexpected (expecting "fi")
but the fi is there..i cant figure out why it is throwing the error
this error does not come when i just have echo statements in the script
I would suggest that if you are just running that one query to insert into table, then echo the query and pipe it to the mysql command, that would be (in my opinion) a better and efficient choice.
#!/bin/bash
diff --side-by-side --supress-common-lines test1.txt test2.txt | tr -d "|,<,>,'\t'" | sed 's/ /:/g' | sed 's/^://' > ./diff.txt
for i in `cat ./diff.txt`; do
plug_x=`echo $i | cut -d ":" -f1`
echo "the value of jenkins plugin is $plug_x"
ver_x=`echo $i | cut -d ":" -f2`
echo "the value of jenkins version is $ver_x"
plug_y=`echo $i | cut -d ":" -f3`
echo "the value of db plugin is $plug_y"
ver_y=`echo $i | cut -d ":" -f4`
echo "the value of db version is $ver_y"
if [ -z "$ver_y" ] && [ -z "$ver_x" ]
then
echo "the plugin is newly added"
else
echo "the plugin has changes"
echo "insert into table (xxx, xxx) values('$ver_x','$plug_x')" | mysql -u root -ppassword -h server --local-infile db
fi
done
That should do the job or if you'd like to use While loop, you can certainly do so.
#!/bin/bash
diff --side-by-side --supress-common-lines test1.txt test2.txt | tr -d "|,<,>,'\t'" | sed 's/ /:/g' | sed 's/^://' > ./diff.txt
cat ./diff.txt | while read i
do
plug_x=`echo $i | cut -d ":" -f1`
echo "the value of jenkins plugin is $plug_x"
ver_x=`echo $i | cut -d ":" -f2`
echo "the value of jenkins version is $ver_x"
plug_y=`echo $i | cut -d ":" -f3`
echo "the value of db plugin is $plug_y"
ver_y=`echo $i | cut -d ":" -f4`
echo "the value of db version is $ver_y"
if [ -z "$ver_y" ] && [ -z "$ver_x" ]
then
echo "the plugin is newly added"
else
echo "the plugin has changes"
echo "insert into table (xxx, xxx) values('$ver_x','$plug_x')" | mysql -u root -ppassword -h server --local-infile db
fi
done
Related
I'm currently trying to run a check to download an index file for each entry in a csv, match a last downloaded id to the index and see if it's present. But it is currently only executing the last downloaded id once.
checkIndex() {
for log in $(cat "$2/$3/logs.index")
do
temp=$(echo "$1" | tr -d '\r')
echo "$temp"
if [ $temp == $log ]; then
return 1
fi
done
sed 1d $csvfile | while IFS=, read -r site id key url conf
do
conf=$(echo "$conf" | tr -d '\r')
curr=$(cat "$CONF_DIR$conf/LastKnownDownloadedFileId_curr.txt")
site=$(echo "$site" | tr -d '\r')
id=$(echo "$id" | tr -d '\r')
key=$(echo "$key" | tr -d '\r')
url=$(echo "$url" | tr -d '\r')
index="logs.index"
echo "$site $id $key $url $conf"
if [ ! -d "$TEMPDIR/$site" ]; then
mkdir -p "$TEMPDIR/$site"
fi
wget -q --user=$id --password=$key $url$index -O $TEMPDIR/$site/logs.index
checkIndex $curr $TEMPDIR $site
However the output is something like this
testsite testid testkey https://testurl/ testconf
9248_2147.log vs 9248_2049.log
9248_2050.log
9248_2051.log
9248_2052.log
9248_2053.log
9248_2054.log
9248_2055.log
Sorry all! turns out it was an issue of declaring IFS="," at the top of my script. I was trying to remove unneeded code and after removing IFS="," it worked properly.
I'm completely new to coding and this is my first script. I've been receiving this error from my code and can't seem to figure out what I'm doing wrong.
| LAST NAME | FIRST NAME | JOB | OLD | NEW | MESSAGE
: line 25: syntax error near unexpected token `|'
: line 25: ` else | '
The script is just supposed to read a text file. II've attempted to use gedit to see my mistake and all I've noticed is my JOB= line is discolored.
#!/bin/bash
printf "| % -15s | % -10s | % -6s | % -6s | % -6s | % -40s\n" "LAST NAME" "FIRST NAME" "JOB" "OLD" "NEW" "MESSAGE"
while read line
do
USER ID=` echo $line | cut -d '|' -f1 `
LAST NAME=` echo $line | cut -d '|' -f2 `
FIRST NAME=` echo $line | cut -d '|' -f3 `
JOB=` echo $line | cut -d '|' -f4 `
OLD NICE=` echo $line | cut -d '|' -f5 `
PREFERRED PASSWORD=` echo $line | cut -d '|' -f6 `
FULL NAME="$FIRST_NAME $LAST_NAME"
if [ "$JOB" == "P" ]
then
NEW_NICE=3
elif [ "$JOB" == "S" ]
then
NEW_NICE=6
else |
NEW_ICE=7
fi
test -e /home/$USER_ID
if [ "$?" == "0" ]
then
MESSAGE="$USER_ID already exists"
else
ENCRYPTED_PASSWORD=` echo "$PREFERRED_PASSWORD" | openssl passwd -1 -stdin `
useradd -m -c "$FULL_NAME" -p $ENCRYPTED_PASSWORD $USER_ID
mkdir "/home/$USER_ID/${LAST_NAME}_backup"
chown -r $USER_ID "/home/$USER_ID/${LAST_NAME}_backup"
echo "$USER_ID created"
fi
printf "| % -15s | % -10s | % -6s | % -6s | % -6s | % -40s\n" "$LAST NAME" "$FIRST NAME" "$JOB" "$OLD" "$NEW" "$MESSAGE"
done < test3_data.txt
I have below script to get values from config:
#!/bin/bash
while read -u10 line
do
if echo $line | grep -v -e "^#" -e "^$" | grep -F "=" &>/dev/null
then
varname=$(echo "$line" | cut -f1 -d '=')
export $varname=$(echo "$line" | cut -f2 -d '=')
fi
done 10< ./config
echo $a
My config like below:
a="b"
when at my host, it print a as b, but in container, it print a as "b".
Could anyone know why?
I have created a script that will check to see if a user you provide is logged on and display the duration of the session if logged on. What i need to do now is if no argument (username) is provided when the command is issued, ask for one and have the same results as if you have provided one.
Here is what I have:
name=$(cat /etc/passwd | grep $1 | cut -d':' -f5 | tr ':' ' ' | sed 's/,//' | sed 's/^\([^ ]*\) \([^ ]*\)/\2 \1/' | sort -t' ' -k3,3)
terminal=$(who | grep $1 | cut -d' ' -f3)
loginHour=$(who | grep $1 | cut -c30-31)
loginMin=$(who | grep $1 | cut -c33-34)
loginMins=$((loginHour * 60 + loginMin))
nowHour=$(date +%R | cut -c1-2)
nowMin=$(date +%R | cut -c4-5)
nowMins=$((nowHour * 60 + nowMin))
totalMins=$((nowMins - loginMins))
hoursOn=$((totalMins / 60))
minsOn=$((totalMins % 60))
clear
echo
if [[ $# -eq 1 ]] ; then
grep -q $1 /etc/passwd
if grep -q $1 /etc/passwd ; then
clear
echo
if who | grep $1 > /dev/null ; then
echo "$name" is currently logged on to terminal "$terminal" and has been for "$hoursOn" hour"(s)" and "$minsOn" minute"(s)".
echo
exit 0
else
echo "$name" is NOT currently logged on.
echo
exit 1
fi
else
echo The user you entered is not a valid user on this system.
echo
exit 2
fi
fi
I had an attempt before but was not the desired result so I removed it out of confusion.
if [[ $# -eq 0 ]]
then
read -p "Enter Name: " username
else
username=$1
fi
then replace all subsequent references to $1 by $username
You can also abort if no name given
# : does nothing it just forces the evaluation
: ${1:?"Need to provide name to script"}
I am trying a simple shell script like the following:
#!/bin/bash
up_cap=$( cat result.txt | cut -d ":" -f 6,7 | sort -n | cut -d " " -f 2 | sort -n)
down_cap=$( cat result.txt | cut -d : -f 6,7 | sort -n | cut -d " " -f 6| sort -n)
for value in "${down_cap[#]}";do
if [ $value > 80000 ]; then
cat result.txt | grep -B 1 "$value"
fi
done
echo " All done, exiting"
when I execute the above script as ./script.sh, I get the error:
./script.sh: line 5: [: too many arguments
All done, exiting
I have googled enough, and still not able to rectify this.
You want
if [ "$value" -gt 80000 ]; then
You use -gt for checking if A is bigger than B, not >. The quotation marks I merely added to prevent the script from failing in case $value is empty.
Try to declare variable $value explicitly:
declare -i value
So, with the dominikh's and mine additions the code should look like this:
#!/bin/bash
up_cap=$( cat result.txt | cut -d ":" -f 6,7 | sort -n | cut -d " " -f 2 | sort -n)
down_cap=$( cat result.txt | cut -d : -f 6,7 | sort -n | cut -d " " -f 6| sort -n)
for value in "${down_cap[#]}";do
declare -i value
if [ $value -gt 80000 ]; then
cat result.txt | grep -B 1 "$value"
fi
done
echo " All done, exiting"