I have a project that has a folder structure like this
blue/folder1
blue/folder2
red/folder3
red/folder4
and in Gradle I would like to tar up these folders individually so that the output looks like:
build/
tar/
blue/
folder1.tar.gz
folder2.tar.gz
red/
folder3.tar.gz
folder4.tar.gz
Is that possible? How would I do this?
apply plugin: 'base'
['blue', 'red'].each { colour ->
file(colour).listFiles().each { File folder ->
if (folder.directory) {
Task tarTask = tasks.create(name: "tar${colour.capitalize()}${folder.capitalize()}", type: Tar) {
from folder
destinationDir = "${buildDir}/${colour}"
archiveName = "${folder}.tar"
}
assemble.dependOn tarTask
}
}
}
Related
I am trying to create multiple jars. I have a certain directory which contains multiple directory. Each directory has its own files(xml and sql). So I am trying to create a jar with a subdirectory name and all the files in it. Those jars will be used for junit test, so I want to create it during configuration phase in advance.
The target directory "../dist" exists outside this project.
ext.createTemplateJar = { sourceDirectory, jarFileName ->
jar {
archiveName = jarFileName
from sourceDirectory
includeEmptyDirs = false
manifest
{
attributes 'Implementation-Title' : VENDOR_NAME
}
}
println "creating a jar for ${jarFileName}"
}
tasks.withType(Jar) {
destinationDir = file("../dist")
}
task generateTemplates {
new File("${projectDir}/templates").eachFile() { file ->
if (file.isFile()) {
return
}
println "template dir is ${file.path}"
createTemplateJar(file.path, "${file.name}.jar")
}
}
When I execute this gradle generateTemplates, it runs fine, but I don't see any jar files created in the destination directory.
It seems something wrong, but I can't tell.
You should create multiple Jar tasks, one for each subdirectory inside ${projectDir}/templates, and have your generateTemplates task do nothing but depend on all of those tasks. For example (I renamed generateTemplates to allJars):
task allJars {
}
file("${projectDir}/templates").eachFile { f ->
def taskName = "jar${f.name.capitalize()}"
tasks.create(name: taskName, type: Jar) {
archiveName = "${f.name}.jar"
destinationDir = file('../dist')
// Configure each JAR however you want
}
allJars.dependsOn taskName
}
Example build:
$ ls templates/
bar baz foo test
$ ./gradlew clean allJars
:clean
:jarBar
:jarBaz
:jarFoo
:jarTest
:allJars
BUILD SUCCESSFUL
Total time: 0.615 secs
$ ls ../dist/
bar.jar baz.jar foo.jar test.jar
I am new to gradle.
I want to create a filename.tar file which includes (filename.war and data/config/*.properties). The war file stays inside build/libs. The requirement is: inside tar file, we need to have folder data/config and all properties files under that folder. The war file stays in the same level with data folder.
Here is what i have,
task tarz(type: Tar) {
archiveName = 'filename'
from 'build/libs','data/config'
include '*.war','*.properties'
destinationDir = file('build/tar')
extension 'tar'
compression = Compression.GZIP
}
this above script is only copy properties files into tar, not the folder.
And the name of the file is 'filename', not 'filename.tar'
Please help me.
here is what i have done
task tarz(type: Tar) {
archiveName = 'aaa.tar'
into ('/'){
from 'build/libs'
include '*.war'
}
into ('data/config'){
from 'data/config'
include '*.properties.*'
}
destinationDir file('build/tar')
extension 'tar'
compression = Compression.GZIP
}
This is my example for Spring Boot App
task tgzTask(type: Tar) {
into('app/') {
from 'build/libs'
include '*.jar'
}
into('app/') {
from 'build/resources/main/banner.txt'
}
into('app/config') {
from 'build/resources/main/config'
from 'build/resources/main/banner.txt'
}
into('app/config/sql') {
from 'build/resources/main/sql'
}
destinationDirectory = file('build/distributions')
extension 'tgz'
compression = Compression.GZIP
}
for more info Tar manual
I have a gradle task to create a zip archive of a directory.
The gradle task is:
task archiveReports(type: Zip) {
from '/projects/Reports/*'
archiveName 'Reports.zip'
}
When I am running the command 'gradle archiveReports', its showing the build is successful. However, no zip file is getting created.
Am I missing something here?
I figured out a way for this:
Its working for me now.
task myZip(type: Zip) {
from 'Reports/'
include '*'
include '*/*' //to include contents of a folder present inside Reports directory
archiveName 'Reports.zip'
destinationDir(file('/dir1/dir2/dir3/'))
}
With Gradle 6.7,
task packageDistribution(type: Zip) {
archiveFileName = "my-distribution.zip"
destinationDirectory = file("$buildDir/dist")
from "$buildDir/toArchive"
}
Note : archiveName is deprected.
With Kotlin DSL
tasks.register<Zip>("packageDistribution") {
archiveFileName.set("my-distribution.zip")
destinationDirectory.set(layout.buildDirectory.dir("dist"))
from(layout.buildDirectory.dir("toArchive"))
}
With Groovy
tasks.register('packageDistribution', Zip) {
archiveFileName = "my-distribution.zip"
destinationDirectory = layout.buildDirectory.dir('dist')
from layout.buildDirectory.dir("toArchive")
}
Taken from the official docs
Just in case anyone will come here to find out how to zip your project e.g. to use it as an AWS lambda zip, here you go:
tasks {
val zipTask by register("createZip", Zip::class) {
from(processResources)
from(compileKotlin)
archiveFileName.set("app.zip")
into("lib") {
from(configurations.runtimeClasspath)
}
}
build {
dependsOn(zipTask)
}
}
I created a simple Gradle build that exports the contents of ./src/main/groovy to a zip file. The zip file contains a folder with the exact same name as the zip file. I cannot figure out how to get the files into the root of the zip file using the distribution plugin.
i.e. gradlew clean distZip produces:
helloDistribution-1.0.zip -> helloDistribution-1.0 -> files
what I would like:
helloDistribution-1.0.zip -> files
My build.gradle file:
apply plugin: 'groovy'
apply plugin: 'distribution'
version = '1.0'
distributions {
main {
contents {
from {
'src/main/groovy'
}
}
}
}
I have attempted to fix the problem by adding into { 'dir' } but to no avail.
Using into '/' seems to do the trick:
contents {
from {
'src/main/groovy'
}
into '/'
}
Unfortunately, penfold's answer did not work for me. Here is the solution I came up with:
task Package(type: Zip) {
from {
def rootScriptFiles = [] // collection of script files at the root of the src folder
new File('src/main/groovy/').eachFile { if (it.name.endsWith('.groovy')) rootScriptFiles.add(it) }
['build/libs/', // build binaries
'src/res/', // resources
rootScriptFiles, // groovy root source files
]
}
baseName = pluginName
}
To copy files into the root of helloDistribution-1.0.zip -> helloDistribution-1.0 -> use
contents {
from {
'some/file'
}
into ''
}
I created a simple Gradle build that exports the contents of ./src/main/groovy to a zip file. The zip file contains a folder with the exact same name as the zip file. I cannot figure out how to get the files into the root of the zip file using the distribution plugin.
i.e. gradlew clean distZip produces:
helloDistribution-1.0.zip -> helloDistribution-1.0 -> files
what I would like:
helloDistribution-1.0.zip -> files
My build.gradle file:
apply plugin: 'groovy'
apply plugin: 'distribution'
version = '1.0'
distributions {
main {
contents {
from {
'src/main/groovy'
}
}
}
}
I have attempted to fix the problem by adding into { 'dir' } but to no avail.
Using into '/' seems to do the trick:
contents {
from {
'src/main/groovy'
}
into '/'
}
Unfortunately, penfold's answer did not work for me. Here is the solution I came up with:
task Package(type: Zip) {
from {
def rootScriptFiles = [] // collection of script files at the root of the src folder
new File('src/main/groovy/').eachFile { if (it.name.endsWith('.groovy')) rootScriptFiles.add(it) }
['build/libs/', // build binaries
'src/res/', // resources
rootScriptFiles, // groovy root source files
]
}
baseName = pluginName
}
To copy files into the root of helloDistribution-1.0.zip -> helloDistribution-1.0 -> use
contents {
from {
'some/file'
}
into ''
}