Gradle task to create a zip archive of a directory - gradle

Question

I have a gradle task to create a zip archive of a directory.
The gradle task is:
task archiveReports(type: Zip) {
from '/projects/Reports/*'
archiveName 'Reports.zip'
}
When I am running the command 'gradle archiveReports', its showing the build is successful. However, no zip file is getting created.
Am I missing something here?

Answer 1

I figured out a way for this:
Its working for me now.
task myZip(type: Zip) {
from 'Reports/'
include '*'
include '*/*' //to include contents of a folder present inside Reports directory
archiveName 'Reports.zip'
destinationDir(file('/dir1/dir2/dir3/'))
}

Answer 2

With Gradle 6.7,
task packageDistribution(type: Zip) {
archiveFileName = "my-distribution.zip"
destinationDirectory = file("$buildDir/dist")
from "$buildDir/toArchive"
}
Note : archiveName is deprected.

Answer 3

With Kotlin DSL
tasks.register<Zip>("packageDistribution") {
archiveFileName.set("my-distribution.zip")
destinationDirectory.set(layout.buildDirectory.dir("dist"))
from(layout.buildDirectory.dir("toArchive"))
}
With Groovy
tasks.register('packageDistribution', Zip) {
archiveFileName = "my-distribution.zip"
destinationDirectory = layout.buildDirectory.dir('dist')
from layout.buildDirectory.dir("toArchive")
}
Taken from the official docs

Answer 4

Just in case anyone will come here to find out how to zip your project e.g. to use it as an AWS lambda zip, here you go:
tasks {
val zipTask by register("createZip", Zip::class) {
from(processResources)
from(compileKotlin)
archiveFileName.set("app.zip")
into("lib") {
from(configurations.runtimeClasspath)
}
}
build {
dependsOn(zipTask)
}
}