A single JSON is posting from Postman and having two entity names as employee and employee address. From that JSON, empName should be stored in first entity and empAddress should be stored in second entity.
How to do this in Spring Boot? I tried to write only Entities.
First Entity:
class Employee{
private int emId;
private String empName;
//Getters;
//Setter;
}
Second Entity:
class EmployeeAddress{
private int emId;
private String empAddress;
//Getters;
//Setter;
}
My JSON: the firt value in JSON need to be stored in first entity and second need to be stored in second entity. How to do this in Spring Boot from controller?
{
"empName": "sam",
"empAddress:"chennai"
}
You need a DTO.
Something like this:
class Employee{
private String empName;
private String empAddress;
}
So, you can return this object as a Json
Related
I'm using spring data mongo. I have a collection within a document that when I add an item to it I would like to assign a new automatically generated unique identifier to it e.g. (someGeneratedId)
#Document(collection = "questionnaire")
public class Questionnaire {
#Id
private String id;
#Field("answers")
private List<Answer> answers;
}
public class Answer {
private String someGeneratedId;
private String text;
}
I am aware I could use UUID.randomUUID() (wrapped in some kind of service) and set the value, I was just wondering if there was anything out of the box that can handle this? From here #Id seems to be specific to _id field in mongo:
The #Id annotation tells the mapper which property you want to use for
the MongoDB _id property
TIA
No there is no out of the box solution for generating ids for properties on embedded documents.
If you want to keep this away from your business-logic you could implement a BeforeConvertCallback which generates the id's for your embedded objects.
#Component
class BeforeConvertQuestionnaireCallback implements BeforeConvertCallback<Questionnaire> {
#Override
public Questionnaire onBeforeConvert(#NonNull Questionnaire entity, #NonNull String collection) {
for (var answer : entity.getAnswers()) {
if (answer.getId() == null) {
answer.setId(new ObjectId().toString());
}
}
return entity;
}
}
You could also implement this in a more generic manner:
Create a new annotation: #AutogeneratedId.
Then listen to all BeforeConvertCallback's of all entities and iterate through the properties with reflection. Each property annotated with the new annotation gets a unique id if null.
I'm setting a server to get a CRUD api from a postgresql Database using JPA. Everytime I want to expose an object from the DB it duplicate the idObject.
When I get an object from the database using springframework and send it after that, it duplicate the idObject like this:
{
"siteId": 3,
"contractId": "1",
"name": "sitenumber1",
"siteIdObject": {
"siteId": 3,
"contractId": "1"
}
}
SiteId and contractId are repeating...
but I want something like that:
{
"siteId": 3,
"contractId": "1",
"name": "sitenumber1"
}
I want to avoid using DTO because I think there is a better way but I don't find it. Since I'm using springFramework for just one or two month I'm maybe forgeting something...
there is the code:
Site code:
#Entity
#IdClass(SiteId.class)
#Table(name = "site", schema="public")
public class Site {
#Id
#Column(name="siteid")
private Integer siteId;
#Id
#Column(name="clientid")
private Integer contractId;
private String name;
#JsonIgnore
#OneToMany(cascade=CascadeType.ALL, mappedBy = "site")
public Set<Device> devices;
//setter, getter, hash, equals, tostring, constructor empty one and full one
SiteId code:
public class SiteId implements Serializable {
private Integer siteId;
private Integer contractId;
// setter, getter, constructor empty and full, hash and equals
Thanks to help :)
Bessaix Daniel
If you are using Spring you might also be using Jackson so if you annotate your SiteIdclass with #JsonIgnoreType it shouldn't be serialized at all when the Site object is serialized.
I am however unsure if this will break your application logic now that the id object is not serialized anymore.
Is possible to get data from jpa/hibernate withou define entity or model in spring boot? if possible, how to? thank you...
Yes its possible
for serverside and database you first read
https://spring.io/guides/gs/relational-data-access/
and for restful ,you must use RequestEntity<> to get a field(s) without a model and send or receive data from JSON.
// Field class is a response and this is not model class
public class Field{
private String name;
//getter and seter
}
#PostMapping("/test")
public void getFields(RequestEntity<Map<String,String>> entity){
Field field = new Field();
field.setName(entity.getBody().get("name"));
System.out.println(field);
}
It is possible to fetch the data without having it mapped to an entity by using nativeQuery and a Tuple class.
List<Tuple> resultList = entityManager
.createNativeQuery("select id as id, street as street, city as city, country as country from address ", Tuple.class
.getResultList();
Tuple firstResult = resultList.get(0);
assertEquals(1L , ((Number) firstResult.get("id")).longValue());
For more information you can read Vlad Mihalcea's blog post
https://vladmihalcea.com/the-best-way-to-map-a-projection-query-to-a-dto-with-jpa-and-hibernate/
I am using Spring Data's Rest Repositories from spring-boot-starter-data-rest, with Couchbase being used as the underlining DBMS.
My Pojo for the object is setup as so.
#Document
public class Item{
#Id #GeneratedValue(strategy = UNIQUE)
private String id;
#NotNull
private String name;
//other items and getters and setters here
}
And say the Item has an id of "xxx-xxx-xxx-xxx" and name of "testItem".
Problem is, that when I want to access the item, I need to be accessible by /items/testItem, but instead it is accessible by /items/xxx-xxx-xxx-xxx.
How do I get use its name instead of its generated id, to get the data.
I found out the answer to my own question.
I just need to override the config for the EntityLookup.
#Component
public class SpringDataRestCustomization extends RepositoryRestConfigurerAdapter {
#Override
public void configureRepositoryRestConfiguration(RepositoryRestConfiguration config) {
config.withEntityLookup().forRepository(UserRepository.class).
withIdMapping(User::getUsername).
withLookup(UserRepository::findByUsername);
}
}
Found the info here, though the method name changed slightly.
https://github.com/spring-projects/spring-data-examples/tree/master/rest/uri-customization
If you want query the item by name and want it perform as querying by id,you should make sure the name is unique too.You cant identify a explicit object by name if all objects have a same name,right?
With jpa you could do it like:
#NotNull
#Column(name="name",nullable=false,unique=true)
private String name;
I've the following domain and needs to return selected field in response to client. How can I achieve that using Spring?
public class Vehicle {
private String vehicleId;
private Long dateCreated;
private String ownerId;
private String colourCode;
private String engineNumber;
private String transmission;
//getters & setters
}
My objective is to return only colourCode and transmission fields to client request. I've read about DTO and seems like I can achieve my objective with DTO but I don't find any good example how to implement it. Is DTO is the correct way to achieve my objective ?
Basically you just create VehicleDTO class with parameters you need
public class VehicleDTO {
private String colourCode;
private String transmission;
//getters and setters
}
and then in your code you construct VehicleDTO from your Vehicle class. Fortunately, we have BeansUtils class from Spring, that uses reflection to copy properties of one object to another, because you do not want to repeat logic for copying properties for every object. So it would be something like:
BeanUtils.copyProperties(v1, dto);
At the end your return VehicleDTO in your response instead of Vehicle
You can return IVehicle interface which exposes your properties of choice
public interface IVehicle {
String getTransmission();
String getColourCode();
}
and your Vehicle implents it
public class Vehicle implements IVehicle{ }
There are various ways you can achieve what you want.
You can add relevant usecase / APi specific DTO for the resource.
e.g. If your API return the vehical general details you may want to expose some level of details,
public class VehicleDetailsDTO {
private String colourCode;
private String transmission;
private String engineNumber; //more
//getters and setters
}
You can then either use BeanUtils or Dozzer to convert your Vehical resource to transportable object like your DTO.
BeanUtils : http://commons.apache.org/proper/commons-beanutils/
Dozzer : http://dozer.sourceforge.net/documentation/mappings.html
Assuming you use JSON as output format and Jackson as serialization engine (default in Spring MVC), you can tell Jackson to not serialize null properties. Now you just need to populate the properties you need and can return the original business object.