Reading a text file and constructing a matrix from it - pascal

I need to construct a matrix; a number of columns and rows are also in the first row of the matrix, I'll make an example so its more clearer.
4 3
1 2 3
5 6 7
9 10 8
1 11 13
Where m=4 (number of rows) and n=3 (number of columns)
This is an example of a text file. Is something like this even possible?
Program Feb;
const
max=100;
type
Matrix=array[1..max,1..max] of integer;
var datoteka:text;
m,n:integer;
counter:integer;
begin
assign(datoteka,'datoteka.txt');
reset(datoteka);
while not eoln(datoteka) do
begin
read(datoteka, m);
read(datoteka, n);
end;
repeat
read eoln(n)
until eof(datoteka)
write (m,n);
end.
My code isn't a big help, cause I don't know how to write it.

First, have a look at the code I wrote to do the task, and then look at my explanation below.
program Matrixtest;
uses
sysutils;
var
NoOfCols,
NoOfRows : Integer;
Source : TextFile;
Matrix : array of array of integer;
FileName : String;
Row,
Col : Integer; // for-loop iterators to access a single cell of the matrix
Value : Integer;
begin
// First, construct the name of the file defining the matrix
// This assumes that the file is in the same folder as this app
FileName := ExtractFilePath(ParamStr(0)) + 'MatrixDef.Txt';
writeln(FileName); // echo it back to the screen so we can see it
// Next, open the file
Assign(Source, FileName);
Reset(Source);
read(Source, NoOfRows, NoOfCols);
writeln('Cols: ', NoOfCols, 'Rows: ', NoOfRows);
SetLength(Matrix, NoOfCols, NoOfRows);
readln(source); // move to next line in file
// Next, read the array data
for Row := 1 to NoOfRows do begin
for Col := 1 to NoOfCols do begin
read(Source, Value);
Matrix[Col - 1, Row - 1] := Value;
end;
end;
// Display the array contents
for Row := 1 to NoOfRows do begin
for Col := 1 to NoOfCols do begin
writeln('Row: ', Row, ' contents', Matrix[Col - 1, Row - 1]);
end;
end;
Close(Source); // We're done with the file, so close it to release OS resources
readln; // this waits until you press a key, so you can read what's been displayed
end.
In your program, you can use a two-dimensional array to represent your matrix. Free Pascal supports multi-dimensional arrays; see https://wiki.lazarus.freepascal.org/Multidimensional_arrays for more information.
This is a complex task, so it helps to know how to do more basic things like reading an array of a size known at compile-time from a text file.
The wrinkle in this task is that you are supposed to read the dimensions (numbers of rows and columns) of the matrix at run-time from the file which contains the matrix's contents.
One inefficient way to do this would be to declare the matrix array with huge dimensions, larger than anything you would expect in practice, using the type of array declaration in the Wiki page linked above.
A better way is to use dynamic arrays, whose dimensions you can set at run-time. To use this, you need to know:
How to declare a dynamic array in Free Pascal
How to set the dimensions of the array at run-time, once you've picked them up from your matrix-definition file (hint: SetLength is the way to do this)
The fact that a Free Pascal dynamic array is zero-based
The easiest way of managing zero-based arrays is to write your code (in terms of Row and Column variables) as if the matrix were declared as array[1..NoOfRows, 1..NoOfColumns] and subtract one from the array indexes only when you actually access the array, as in:
Row := 3;
Column := 4;
Value := Matrix[Row - 1, Column - 1];

Related

Create var inside a for loop PLSQL ORACLE 11G

i have a function that puts a number in a var (var1). if var1 = 3 then create 3 new variables and assign a value for later send that values in an out type. I don't know how can i do, my code is something like this where "pos" acts like an INSTR() that i know its each 13 chars. And "newvar||var1" is because i want my vars names be newvar1, newvar2, newvar3, etc.:
FOR n IN 1..var1
LOOP
pos NUMBER(4):= 0;
newvar||var1 NUMBER(3);
newvar||var1 := SUBSTR(TO_NUMBER(numberInsideString), 1, 1+pos);
pos := pos+13;
END LOOP;
My question is, how a person who really know PLSQL would do that, im learning PLSQL please help. thank you.
What you want to try to do suggests that you need a one dimensional array in order repeatedly to assign new values for each iteration within the loop. One of the types in OWA package such as vc_arr(composed of VARCHAR2 data type values) is handy to define an array.
Coming to the code, you can start with moving the variables into the declaration section, and write such a simple code as a sample exercise
SET serveroutput ON
DECLARE
pos INT := 0;
numberInsideString VARCHAR2(100):='as12df34sdg345apl8976gkh4f11öjhöh678u7jgvj';
newvar OWA.vc_arr;
BEGIN
FOR n IN 1..3
LOOP
newvar(n) := SUBSTR(numberInsideString, 1, 1+pos);
pos := pos+5;
Dbms_Output.Put_Line(newvar(n));
END LOOP;
END;
/
a
as12df
as12df34sdg

How to find the biggest number from a txt file?

I have to find out the biggest number from a txt file. Numbers are for example:
9 8 7 6 5
Someone told me, that it should works, but it didn't, and I have no clue how to work with file bcs.
program file;
uses crt;
var i,count,help:integer;
numb:array [1..9] of integer;
f:text;
begin
clrscr;
assign(f,'file1.txt');
reset(f);
readln(f,count);
for i:=1 to count do
readln(f,numb[i]);
close(f);
for i:=2 to count do
begin
if (numb[i-1] < numb[i]) then
help:=numb[i-1];
numb[i-1]:=numb[i];
numb[i]:=help;
end;
for i:=1 to count do
begin
write(numb[i]);
end;
readln;
end.
If you only want to know the highest number, you can use a running maximum while reading the numbers in the file.
As a user you don't have to know how many numbers there are in the file. The program should determine that.
I wrote a little test file, called file1.txt:
9 8 7 6 3 11 17
32 11 13 19 64 11 19 22
38 6 21 0 37
And I only read the numbers, comparing them with Max. That is all you need.
No need to read the data into an array and
no need to (try to) sort the data. You only want the highest number, right?
And there is also no need for the user to know or enter the number of numbers in the text file.
program ReadMaxNumber;
uses
Crt;
var
Max, Num: Integer;
F: Text;
begin
ClrScr;
Assign(F, 'file1.txt');
Reset(F);
Max := -1;
while not Eof(F) do
begin
Read(F, Num);
if Num > Max then
Max := Num;
end;
Close(F);
Writeln('Maximum = ', Max);
Readln;
end.
When I run this, the output is as expected:
Maximum = 64
There are a few mistakes in the code provided:
The program name is file. The program name cannot be a keyword;
You read from the file the variable count, but the actual value cannot be found in the file, so count=0. For this reason, the for loop which reads the data from the file is never executed. You either read it from a file or from the keyboard (in the solution below, I chose the second option);
You use readln when you read from the file. readln moves the cursor on the next line after it reads the data. This means that only the first number, 9, is stored into numb. Replace readln with read;
At the second for loop, you say that if ... then. If you want all the three instructions to be executed (and I think you do, because it's an exchange of values), put them between begin and end. Otherwise, only the first instruction is executed if the condition is true, the others are always been executed;
The method to determine the maximum is an overkill. Better if you take a variable, max, which initially gets the value of the first element in the array, then you cycle in the remaining values to see if a value is higher than max.
The final code looks like this:
program file1;
uses crt;
var i,count,help, max:integer;
numb:array [1..9] of integer;
f:text;
begin
clrscr;
assign(f,'file1.txt');
reset(f);
writeln('Please input a number for count :');
readln(count);
for i:=1 to count do
read(f,numb[i]);
close(f);
max:=numb[1];
for i:=2 to count do
if numb[i]>max then
max:=numb[i];
write('The result is: ',max);
readln;
end.

Ada thread to pass auto random generated data to a procedure

How would i go about creating a procedure that is a thread which continuously passes automatic random generated data within a specified range.
I currently would have to manually enter in each bit of data in the console using this procedure below. I want to creatre a procedure that when running is able to pass data to this procedure as if it was being typed into the console itself.
procedure Analyse_Data is
Data : Integer;
begin
DT_Put_Line("Data input by user");
loop
DT_Get(Data,"Data must be taken as a whole number");
exit when (Data >=0) and (Data <= Maximum_Data_Possible);
DT_Put("Please input a value between 0 and ");
DT_Put(Maximum_Data_Possible);
DT_Put_Line("");
end loop;
Status_System.Data_Measured := Data_Range(Data);
end Analyse_Data;
I havent included the specification files (.ads)
I am new to Ada and any help would be appreciated.
Use an instance of Discrete_Random to generate some number of random data values in the desired range:
subtype Valid_Range is Natural range 0 .. Maximum_Data_Possible;
package Some_Value is new Ada.Numerics.Discrete_Random(Valid_Range);
G : Some_Value.Generator;
…
procedure Generate is
N : Valid_Range;
begin
for I in 1 .. Count loop
N := Some_Value.Random(G);
Put(N);
end loop;
end;
Save the values to a file:
./generate > test_data.txt
Feed that file to your program using I/O redirection from the command line:
./analyse_data < test_data.txt
The exact details will depend on you actual program. See this related Q&A regarding empty lines in standard input.

Transpose a string in Pascal

I'm very new to Pascal and still learning much. I have to write a code that :
Takes input of a string
Split the string into two characters each (Snippet)
Use the Snippet to get an index from an array
Transpose the Snippet to a certain value
If Index + Transpose is larger than the length of the Array, return nothing
If not, append the transposed Snippet to a result string
Return the transposed string
I can only write 1 through 3, the rest is still a blur for me. Helps are appreciated.
(And I also want to improve it without many for loops. Any thoughts?)
program TransposeString;
var
melody : Array[1..24] of String[2] = ('c.', 'c#', 'd.', 'd#', 'e.', 'f.', 'f#', 'g.', 'g#', 'a.', 'a#', 'b.', 'C.', 'C#', 'D.', 'D#', 'E.', 'F.', 'F#', 'G.', 'G#', 'A.', 'A#', 'B.');
songstring, transposedstring : String;
transposevalue : byte;
function Transpose(song : String; transposevalue : byte): String;
var
songsnippet : String[2];
iter_song, iter_index, index : byte;
begin
for iter_song := 1 to length(song) do
begin
if iter_song mod 2 = 0 then continue;
songsnippet := song[iter_song] + song[iter_song + 1]; //Split the string into 2 characters each
for iter_index := 1 to 24 do
begin
if melody[iter_index] = songsnippet then
begin
index := iter_index; //Get Index
break;
end;
end;
//Check Transpose + Index
//Transpose Snippet
//Append Snippet to Result String
end;
end;
begin
readln(songstring);
readln(transposevalue);
transposedstring := transpose(songstring, transposevalue);
writeln(transposedstring);
end.
As a starter for you to work from, rather than just spoon-feeding an answer:
You have the index of the snippet (note) in index. Assuming the notes are in order you need to return the note from the array positions above it, so
result := result + melody[iter_index + transposevalue];
You need to check the length of the array before trying to read from it, otherwise it'll crash (step 5). This is just an if statement.
I wouldn't worry too much about for loops - 2 deep nesting isn't that bad. If you wanted to split it out a bit then GetTransposedNote(const note:string): string; could be split out as a new function.
Things you may want to think about are:
What if you can't find the note in the array?
Do you want to be case-sensitive
What if the input string has an odd number of characters?
You are most of the way there already, though.

Three Dimension Array Display Table

I know how the two dimensions array works in pascal, [rows, columns].
How the three or more dimensions works? Please help, thanks.
a[rows, columns, ???]
A one dimensional array is declared as array[lowIndex..HighIndex] of <type>, as in
intArray: array[0..9] of integer;
A two dimensional array is simply an array containing an array, as in:
twoDim: array[0..9,0..9] of integer;
You reference it using the indexes:
twoDim[0,0] := 1;
twoDim[0,1] := 2;
A three dimensional array simply extends the two dimensional, as in this declaration:
threeDim: array[0..9,0..9,0..9] of integer;
You also use it with the indexes, in the same way:
threeDim[0,0,0] := 1;
threeDim[9,0,1] := 12;
As far as what to call the individual dimensions, use names that mean something related to the purpose they serve. For instance, if I was keeping an array of hourly readings for something each day over the period of a week for four weeks, I could declare the array as:
Readings: array[1..4,1..7,1..24] of integer;
I could then declare variables to name the indexes:
var
Week, Day, Hour; Integer;
I could then reference the three dimensions of the array easily. To initialize them all to zero, for instance, I could do something like this:
for Week := 1 to 4 do
for Day := 1 to 7 do
for Hour := 1 to 24 do
Readings[Week, Day, Hour] := 0;

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