Shell script if-else case - shell

I wrote the below script to take input interactively servername and service name. This repeats asking the inputs when y is given as input at the end of the while loop.
key='y';
service='';
serverName='';
while [[ $key == 'y' ]]; do
echo -e "\nEnter serverName : "
read serverName
echo -e "\nEnter Service Name : "
read service
if [[ ! -z "$service" ] && [ ! -z "$serverName" ]]; then
echo -e "startService $serverName $service"
#echo -e " Atleast one input is null"
else
echo -e " Atleast one input is null"
fi
echo -e "Enter y to repeat this step. Enter n to exit :"
read key
done

your while loop condition is wrong correct it like below:-
while [[ '$key' == 'y' ]];
or
while [[ $key == y ]];

Related

Script mask prefix

My code works good:
#!/bin/bash
read -p 'Enter IP address: ' ip_addr
while true; do
read -p 'Enter mask or prefix (ex: 255.255.255.0 or 24): ' mask_or_prefix
# Check if the input is not empty
if [[ -z "$mask_or_prefix" ]]; then
echo "Error: Mask or prefix cannot be empty."
continue
fi
#Check if the input is a mask
if [[ $mask_or_prefix =~ ^[0-9]+\.[0-9]+\.[0-9]+\.[0-9]+$ ]]; then
prefix=$(ipcalc -p $ip_addr $mask_or_prefix| cut -d '=' -f 2)
elif [[ $mask_or_prefix =~ ^[0-9]+$ ]]; then
# Check if the input is a valid number
if [[ $mask_or_prefix -lt 0 || $mask_or_prefix -gt 32 ]]; then
echo "Error: Prefix must be between 0 and 32."
continue
fi
prefix=$mask_or_prefix
else
echo "Error: Invalid input. Please enter a valid mask or prefix (ex: 255.255.255.0 or 24)."
continue
fi
break
done
echo "IP address: $ip_addr"
echo "Prefix: $prefix"
I just wanna copy it

Continue while loop in Bash Script even if a condition fails

#!/bin/bash
var="true"
i=1
while $var
do
read -p "Enter value (true/false): " var
if [[ $var == "true" ]]
then
echo "Iteration : $i"
((i++))
elif [[ $var == "false" ]]
then
echo "Exiting the process"
elif [[ $? -eq 1 ]]
then
echo "Invalid Choice."
echo "Avaialable Choices are true or false"
exit
fi
done
Script is Working Fine. I Enter true the loop will iterate for false the script stops.
I want the script will continue asking "Enter Value" if any other value instead of true or false will be entered.
This would do the same with a more academic syntax:
i=0
while :; do
printf 'Enter value (true/false): '
read -r var
case $var in
true)
i=$((i + 1))
printf 'Iteration : %d\n' $i
;;
false)
printf 'Exiting the process\n'
break
;;
*)
printf 'Invalid Choice.\nAvaialable Choices are true or false\n'
;;
esac
done
You might find this to be a cleaner solution:
i=0
while true; do
read -p "enter value: " myinput
if [[ $myinput = true ]]; then
echo "iteration $i"
i=$((i+1))
elif [[ $myinput = false ]]; then
echo "exiting"
exit
else
echo "invalid input"
fi;
done;
The issue I see with your current code is that it is unclear which command's exit status $? refers to. Does it refer to the echo in the previous elif block? Or the last condition check? Or something else entirely?
I'm new in bash. I tried that:
#!/bin/bash
i=1
while [[ $var != "false" ]]
do
read -p "Enter value (true/false): " var
if [[ $var == "true" ]]
then
echo "Iteration : $i"
((i++))
elif [[ $var == "false" ]]
then
echo "Exiting the process"
elif [[ $? -eq 1 ]]
then
echo "Invalid Choice."
echo "Avaialable Choices are true or false"
fi
done
I changed while $var with while [[ $var ]] because while works like if. It runs the given command. In there it is $var's value.
And I moved exit to first elif expression's end. So if user type false program will exit.

Terminate shell script after three invalid input

Restricting user from trying multiple invalid attempt in shell scripting. I wrote the below script but somehow it's not getting me desire output. I have shared the script and script output both. Kindly help. Here I wanted script to terminate if user tried more than 3 times.
While true
do
echo -n "Enter yes or no"
read opt
case $opt in
yes) break ;;
no) break ;;
*) echo "Invalid input"
while [[ $err -le 3 ]]
do
If [[ $err -le 3 ]]
then
echo "err: $err"
((err++))
break
else
echo "Max limit crossed"
exit 1
fi
done
;;
esac
done
This was a nice question and I had a lot of fun solving it. I have to mention that I'm new to shell programming.
n=0
until [ $n -ge 3 ]
do
read line
if [ "$line" = "XYZ" ]; then
echo "Accepted"
break
else
n=$[$n+1]
echo " trying " $n "times "
fi;
done
This article helped me a lot to solve it.
Try:
#!/bin/bash
ANSWER=
max=3
while true; do
echo "Enter yes or no:"
read -r ANSWER
[[ $ANSWER == "yes" || $ANSWER == "no" ]] && break
echo Invalid Input
ANSWER=
((--max))
[[ $max -le 0 ]] && { echo "Max limit crossed"; exit 1; }
done

Get user input and check it, linux

I am a beginner at unix and I am trying to use a while loop to get a user integer input for 2 numbers, but I need to check if it is an integer and reask if it's not, so I attempted to utilize if statements inside the while loop. I cannot get this to work, what am I doing wrong with the while and if loop?
#! /bin/bash
echo “Enter first number:“
while read number1
do
if[[ $number1 ]] && [ $input -eq $input 2>/dev/null ]
then
echo “$number1”
else
echo "$number1 is not an integer or not defined.Try again”
fi
done
echo “Enter second number:“
while read number2
do
if[[ $number2 ]] && [ $input -eq $input 2>/dev/null ]
then
echo “$number2”
else
echo "$number2 is not an integer or not defined.Try again”
fi
done
If you are trying to get the number and checking it until it becomes integer, Please try the below code.
#!/bin/bash
echo "enter number"
while read number1
do
if ! [[ $number1 =~ ^[0-9]+$ ]]
then
echo "number is not an integer"
else
echo "number is an integer"
exit;
fi
done

Bash For Loop With If & Elif Logic Broken

I've been playing with bash scripting for 40'ish days with 0 experience so forgive me if my code looks like crap. I have a script that will take the configured NTP servers out of the /etc/ntp.conf file (/root/ntp.conf for testing)
NTPSRVCounter=1
echo "--- NTP Configuration ---"
echo " "
while read -r line; do
if [ $NTPSRVCounter == 1 ] ; then
echo "Primary NTP: $line"
SEDConfiguredNTP1="$(echo $line | sed 's/\./\\./g')"
((NTPSRVCounter++))
echo " "
else
SEDConfiguredNTP2="$(echo $line | sed 's/\./\\./g')"
echo "Secondary NTP: $line"
echo ""
fi
done < <(grep -o -P '(?<=server ).*(?= iburst)' /root/ntp.conf)
And asks you if you want to change it with a case statement:
echo "Do you wish to change it? [Y/n]"
NTPSRVCounter2=1
read opt
case $opt in
Y|y) read -p "Enter in your primary NTP server: " -e -i '0.debian.pool.ntp.org' UserInputNTP1
read -p "Enter in your secondary NTP serer: " -e -i '1.debian.pool.ntp.org' UserInputNTP2
for NTP in "$UserInputNTP1" "$UserInputNTP2" ; do
is_fqdn "$NTP"
if [[ $? == 0 && $NTPSRVCounter2 == 1 ]] ; then
SEDUserInput1=$(echo $UserInputNTP1 | sed 's/\./\\./g')
((NTPSRVCounter2++))
elif [[ $? == 0 && $NTPSRVCounter2 == 2 ]] ; then
SEDUserInput2=$(echo $UserInputNTP2 | sed 's/\./\\./g')
sudo sed -i "s/$SEDConfiguredNTP1/$SEDUserInput1/g" /root/ntp.conf
sudo sed -i "s/$SEDConfiguredNTP2/$SEDUserInput2/g" /root/ntp.conf
else
echo "Fail!!! :-( "
fi
done
;;
N|n) return 0
;;
*) echo "I don't know what happened, but, eh, you're not supposed to be here."
;;
esac
The problem is with the "elif" statement and the function "is_fqdn" on the second run of the function. If I put "bash -x" on the script and run it, I see "is_fqdn" returning 0 on both runs of the function, but the elif statement "$?" is coming up as 1 instead of 0.
The two functions used are below. Have to validate NTP addresses as either valid domain names or I.P. addresses, right? :)
is_fqdn() {
hostname=$1
if [[ "$hostname" =~ ^[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$ ]]; then
valid_ip "$hostname"
elif [[ "$hostname" == *"."* && "$hostname" != "localhost." && "$hostname" != "localhost" ]] ; then
return 0
else
return 1
fi
host $hostname > /dev/null 2>&1 || return 1
}
valid_ip(){
local stat=1
local ip=$1
if [[ $ip =~ ^[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$ ]]; then
OIFS=$IFS
IFS="."
ip=($ip)
IFS=$OIFS
[[ ${ip[0]} -le 255 && ${ip[1]} -le 255 && ${ip[2]} -le 255 && ${ip[3]} -le 255 ]]
stat=$?
fi
return "$stat"
}
The condition in your if sets the value of $?, and that is what's used by the condition in the elif part, not the return value of is_fqdn. You need to save the value if you want to use it in multiple places:
is_fqdn "$NTP"
is_fqdn_rv=$?
if [[ $is_fqdn_rv == 0 && $NTPSRVCounter2 == 1 ]] ; then
SEDUserInput1=$(echo $UserInputNTP1 | sed 's/\./\\./g')
((NTPSRVCounter2++))
elif [[ $is_fqdn_rv == 0 && $NTPSRVCounter2 == 2 ]] ; then
SEDUserInput2=$(echo $UserInputNTP2 | sed 's/\./\\./g')
sudo sed -i "s/$SEDConfiguredNTP1/$SEDUserInput1/g" /root/ntp.conf
sudo sed -i "s/$SEDConfiguredNTP2/$SEDUserInput2/g" /root/ntp.conf
else
echo "Fail!!! :-( "
fi

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