Bash For Loop With If & Elif Logic Broken - bash

Question

I've been playing with bash scripting for 40'ish days with 0 experience so forgive me if my code looks like crap. I have a script that will take the configured NTP servers out of the /etc/ntp.conf file (/root/ntp.conf for testing)
NTPSRVCounter=1
echo "--- NTP Configuration ---"
echo " "
while read -r line; do
if [ $NTPSRVCounter == 1 ] ; then
echo "Primary NTP: $line"
SEDConfiguredNTP1="$(echo $line | sed 's/\./\\./g')"
((NTPSRVCounter++))
echo " "
else
SEDConfiguredNTP2="$(echo $line | sed 's/\./\\./g')"
echo "Secondary NTP: $line"
echo ""
fi
done < <(grep -o -P '(?<=server ).*(?= iburst)' /root/ntp.conf)
And asks you if you want to change it with a case statement:
echo "Do you wish to change it? [Y/n]"
NTPSRVCounter2=1
read opt
case $opt in
Y|y) read -p "Enter in your primary NTP server: " -e -i '0.debian.pool.ntp.org' UserInputNTP1
read -p "Enter in your secondary NTP serer: " -e -i '1.debian.pool.ntp.org' UserInputNTP2
for NTP in "$UserInputNTP1" "$UserInputNTP2" ; do
is_fqdn "$NTP"
if [[ $? == 0 && $NTPSRVCounter2 == 1 ]] ; then
SEDUserInput1=$(echo $UserInputNTP1 | sed 's/\./\\./g')
((NTPSRVCounter2++))
elif [[ $? == 0 && $NTPSRVCounter2 == 2 ]] ; then
SEDUserInput2=$(echo $UserInputNTP2 | sed 's/\./\\./g')
sudo sed -i "s/$SEDConfiguredNTP1/$SEDUserInput1/g" /root/ntp.conf
sudo sed -i "s/$SEDConfiguredNTP2/$SEDUserInput2/g" /root/ntp.conf
else
echo "Fail!!! :-( "
fi
done
;;
N|n) return 0
;;
*) echo "I don't know what happened, but, eh, you're not supposed to be here."
;;
esac
The problem is with the "elif" statement and the function "is_fqdn" on the second run of the function. If I put "bash -x" on the script and run it, I see "is_fqdn" returning 0 on both runs of the function, but the elif statement "$?" is coming up as 1 instead of 0.
The two functions used are below. Have to validate NTP addresses as either valid domain names or I.P. addresses, right? :)
is_fqdn() {
hostname=$1
if [[ "$hostname" =~ ^[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$ ]]; then
valid_ip "$hostname"
elif [[ "$hostname" == *"."* && "$hostname" != "localhost." && "$hostname" != "localhost" ]] ; then
return 0
else
return 1
fi
host $hostname > /dev/null 2>&1 || return 1
}
valid_ip(){
local stat=1
local ip=$1
if [[ $ip =~ ^[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$ ]]; then
OIFS=$IFS
IFS="."
ip=($ip)
IFS=$OIFS
[[ ${ip[0]} -le 255 && ${ip[1]} -le 255 && ${ip[2]} -le 255 && ${ip[3]} -le 255 ]]
stat=$?
fi
return "$stat"
}

Answer 1

The condition in your if sets the value of $?, and that is what's used by the condition in the elif part, not the return value of is_fqdn. You need to save the value if you want to use it in multiple places:
is_fqdn "$NTP"
is_fqdn_rv=$?
if [[ $is_fqdn_rv == 0 && $NTPSRVCounter2 == 1 ]] ; then
SEDUserInput1=$(echo $UserInputNTP1 | sed 's/\./\\./g')
((NTPSRVCounter2++))
elif [[ $is_fqdn_rv == 0 && $NTPSRVCounter2 == 2 ]] ; then
SEDUserInput2=$(echo $UserInputNTP2 | sed 's/\./\\./g')
sudo sed -i "s/$SEDConfiguredNTP1/$SEDUserInput1/g" /root/ntp.conf
sudo sed -i "s/$SEDConfiguredNTP2/$SEDUserInput2/g" /root/ntp.conf
else
echo "Fail!!! :-( "
fi