When the user has to edit their profile it shows the id like so Click to see the photo
that is not what I want. I want to replace it with the profile username and remove the edit part. I really hope someone is understanding what I'm asking for. let me show you what I am looking for something like this "localhost/lary/quickstart/public/profile/username"
here is what i have in my code
public function edit($id)
{
$pro=Profile::find($id);
return view('layouts.profileedit')->with('pro',$pro);
}
<span class="glyphicon glyphicon-pencil"></span>
Change your routes file as follows:
Route::resource('profile', 'ProfileController', ['except' => ['edit']]);
Route::get('/profile/{username}', 'ProfileController#edit');
Then change your ProfileController as follows
public function edit($username)
{
$pro=Profile::where('username', $username)->firstOrFail();
return view('layouts.profileedit')->with('pro',$pro);
}
Related
i have this url :
http://127.0.0.1:8000/deliverer/4
i want it like this
http://127.0.0.1:8000/deliverer/
this is my function :
public function show($id)
{
// $userhash->hashids->encode($id);
$user=User::find($id);
return view('deliverer.profile')->with('user',$user);
}
and this is my route
Route::get('deliverer/{id}', 'deliverer\DelivererController#show')->name('profile');
and this in view
<a href="http://127.0.0.1:8000/deliverer/{{ Auth::user()->id }}" >
<i class="nc-icon nc-single-02"></i>
<p>Profile</p>
</a>
Assuming, that what you're trying to accomplish is to view the current authenticated user's profile, then you should follow the steps below:
First you have to modify the route and remove the {id} from the URL, like this:
Route::get('deliverer', 'deliverer\DelivererController#show')->name('profile');
Then, inside the controller you have to remove the $id param from the show() method and change the method to get the id from the authenticated user.
public function show($id)
{
// $userhash->hashids->encode($id);
$user = \Auth::user();
return view('deliverer.profile')->with('user',$user);
}
And of course, you have to remove the Auth::user()->id() from the view route, and perhaps use the named route instead of hardcoding it, like so:
<a href="{{ route('profile') }}">
<i class="nc-icon nc-single-02"></i>
<p>Profile</p>
</a>
I'm assuming you're just trying to hide id's so users can guess the next number or try to pull up records they shouldn't.
Have you looked into UUID's? Example here: (https://dev.to/wilburpowery/easily-use-uuids-in-laravel-45be) That might be a solution.
Also, if you are worried that someone might tamper with URL to pull records, you should look into securing up your models. Do a check to see if the user should have access to that particular record. Many ways to accomplish that.
You can use token or configure a middleware, or as you did you can hash or crypt the id and make the verification after the call
The url will be like that :
http://127.0.0.1:8000/deliverer/?id=aze45a8sd54q
I have two models users and user_profiles
user
id name email
user_prfiles
id user_id fname lname address
this is a one to one relation concept, my doubt is, I add user_profiles details in my table and user table is also good but again the same person login he can view the link of create details which will create user_profiles details of particular user. and my point is when a user fill all of his user profile
the link should not display how can I do that? how to hide the link once the data created? if anyone knows please share the answer..
Can you do something like this?
Code
class User extends Model
{
public function userProfile()
{
$this->hasOne('App\UserProfile');
}
}
class UserProfile extends Model
{
isComplete()
{
// check if all fields is what you expect
}
}
In your view
<h1>User dashboard</h1>
#if(!$user->userProfile || !$user->userProfile->isComplete())
Fill in your profile
#endif
finally I found the answer, in my create page
#if(!Auth::user()->userprofile)
<form>
</form>
#else
<div>already created</div>
#endif
Trying to get property 'userprofile' of non-object (View: E:\Xampp\htdocs\Projects\laravel\Interview\resources\views\layouts\app.blade.php)
I get this error when I did as you say..
#if(!Auth::user()->userprofile || !Auth::user()->userprofile->isComplete())
<a class="nav-link active text-dark" href="/users/create">Add Details</a>
#endif
this is my app.blade.php
my UserProfile.php
public function isComplete()
{
return $this->hasOne(UserProfile::class);
}
I'm trying to open a page from a button, but I need to send the id of the item where the button is in. For context this is a discussion forum page, in the users dash they are shown the forums they can comment on and there is a button on the bottom of each, what I need to send is that forums id, so that when they click on the button it takes them to the correct forum view.
How can I do this?
I'm trying different ways
<el-button type="primary" #click="submit(f.id)">
Answer
</el-button>
submit($id) {
var link = 'comments/' + $id;
this.$inertia.visit('comments/' + $id, {
$id,
});
},
<inertia-link class="el-button el-button--warning"
:href="'comments/' + f.id">
Answer
</inertia-link>
In my routes web.php
Route::resource('comments', 'ReplyController');
Route::get('comments/{id}', 'ReplyController#index');
The index in the controller
public function index($id)
{
$forum = DiscussionForum::where('id', $id)
->with('comment', 'user')->first();
$comment = Reply::with('discussionForum', 'user')
->where('discussion_forum_id', $forum->id)
->orderByDesc('updated_at')->get();
return Inertia::render('Forum/Comment.vue', [
'forum' => $forum,
'comments' => $comment
]);
}
This is not working, the redirect shows me a blank window inside the main page? How can I send the forum id correctly?
The best way to do this is to add a name to the route so:
Route::get('comments/{id}')->name('comments')->uses('ReplyController#index');
Then you can pass your id in the inertia-link in this way:
<inertia-link class="el-button el-button--warning"
:href="route('comments', { f.id })">
Answer
</inertia-link>
This way can be used with Ziggy as mentioned in the docs.
https://inertiajs.com/routing
Use the emit function here: https://v2.vuejs.org/v2/guide/components-custom-events.html
Something like this:
yourMethod() {
this.$emit(
"someName",
this.id
);
}
I'm using this package here in Laravel 5.6 to add likes system in my project.
I have updated the models as per their documentation. However, I'm confused on how to use this package.
I have added tried the following which adds the logged in user to the particular article likes list when he visits the link.
public function show(ArticleCategory $articlecategory, $slug)
{
$categories = ArticleCategory::all();
$article = Article::where('slug', $slug)->first();
$user = User::first();
$user->addFavorite($article);
return view('articles.show', compact('article', 'categories'));
}
And in my user dashboard, I'm able to pull up all the articles which are liked by the user with
$user = Auth::user();
$favoritearticles = $user->favorite(Article::class);
But I'm looking for a functionality where I have a button on the article page where when a logged user clicks on it, he is added to the likes list. I haven't tried this before so stuck at this point.
I replaced
$user->addFavorite($article);
with
$user->toggleFavorite($article);
but that just toggles the favourite list. I mean when I visit the link once, the logged in user is added to the likes list. When I visit the link for the second time, the logged in user is removed from the likes list. The cycle is repeated.
Could anyone explain to me how to achieve the like functionality with a button?
you're almost there,
You have to add a button and on click you will trigger an AJAX request to the server to perform what you want without refreshing the page, here is an example:
First you'll add a button and give it an ID or class:
<button class="like">Like</button>
Then the moment you click on it, you'll call the url which you need to replace with the route to your function,
Then you have to declare a method like so:
public function like($slug)
{
$article = Article::where('slug', $slug)->first();
$user = \Auth::user(); //to get authenticated user...
$user->toggleFavorite($article); // toggle so if u already like it u remove it from the liked table
return response()->json(['status': 1])
}
And of course add the route to your routes.php:
Router::get('like/{slug}',"ArticleController#like");
then add the function (jQuery is used here) to hook the AJAX call
$('.like').on('click', function(){
$.ajax({
type: "GET",
url: 'wwww.example.com/articles/slug',
data: {slug: 'the slug'},
success: function(data){
alert('its done')
},
});
})
Create a form in you article page with a button
<form action="{{url('favorite/{$post->id}')}}" method="post">
#if($post->isFavorited())
<button type="submit">Remove from favorite</button>
#else
<button type="submit">Add to favorite</button>
#endif
</form>
create the favorite route and controller
Router::post('favorite/{id}',"ArticleController#toggleFavorite");
public function toggleFavorite($id) {
$article = ArticleCategory::find($id);//get the article based on the id
Auth::user()->toggleFavorite($article);//add/remove the user from the favorite list
return Redirect::to('article/{$id}');//redirect back (optionally with a message)
}
Hi I am very new to Laravel and MVC frameworks in general and am looking to create a list of links (in a view within a template) that links to some content. I am using this to display a list of nine people and to display their profile description when the link is clicked on. I have created a model of what the page looks like at http://i.imgur.com/8XhI2Ba.png. The portion that I am concerned with is in blue. Is there a way to route these links to something like /about/link2 or /about?link2 while maintaining the same exact page structure but modifying the ‘link content’ section (on the right of the link menu) to show the specific link's content? I would greatly appreciate it if someone could point me in the right direction, as I have literally no clue where to go with this!
There are a couple ways you can go about doing this.
Templates
Create your route.
Im assuming a lot about your app here but hopefully you get the picture. If you need help with anything in particular, be sure to update your question with the code youve tried so it will be easier to help you.
Route::get('about/{page}', function($page)
{
$profile = Profile::where('name', $page)->first();
return View::make('about')->with('profile', $profile);
});
Modify Template.blade.php
Put this line where you wish for About.blade.php to appear.
#yield('content')
Create your view which will extend your template
#extends('Template')
#section('content')
<h2>User Profile</h2>
<ul>
<li>Name: {{ $profile->name }}</li>
<li>Last Updated: {{ $profile->updated_at }}</li>
</ul>
#stop
AJAX
This solution will utilize AJAX to grab the data from the server and output it on the page.
Route for initial page view
Route::get('about', function($page)
{
$profiles = Profile::all();
return View::make('about')->with('profiles', $profiles);
});
Feel free to follow the same templating structure as before but this time we need to add some javascript into the template to handle the AJAX. Will also need to id everything which needs to be dynamically set so we can easily set it with jquery.
#extends('Template')
#section('content')
<h2>Links</h2>
#foreach($profiles as $profile)
{{ $profile->name }}
#endforeach
<h2>User Profile</h2>
<ul>
<li>Name: <span id="profile_name">{{ $profile->name }}</span></li>
<li>Last Updated: <span id="profile_updated_at">{{ $profile->updated_at }}</span></li>
</ul>
<script>
function setProfile(a)
{
$.ajax({
method: 'get',
url: 'getProfile',
dataType: 'json',
data: {
profile: $(a).data('id')
},
success: function(profile) {
$('#profile_name').html(profile.name);
$('#profile_updated_at').html(profile.updated_at);
},
error: function() {
alert('Error loading data.');
}
});
}
</script>
#stop
Route to handle the AJAX request
Route::get('getProfile', function()
{
$profile_id = Input::get('profile');
$profile = Profile::find($profile_id);
return $profile->toJson();
});
Now, the page should not have to reload and only the profile information should be updated.
Making some assumptions here as no code posted and assuming you're using the latest version of Laravel, Laravel 5.
Lets say you have a table in your database named users and you have a Model named Users (Laravel 5 comes with the Users model as default, see app/Users.php). The users will be the base of our data for the links.
Firstly, you want to register a route so you can access the page to view some information. You can do this in the routes file. The routes file can be found here: app/Http/routes.php.
To register a route add the following code:
Route::get('users', ['uses' => 'UserController#index']);
Now what this route does is whenever we hit the URL http://your-app-name/public/users (URL might be different depending on how you have your app set up, i.e. you may not have to include public) in our web browser it will respond by running the index method on the UserController.
To respond to that route you can set up your UserController as so:
<?php namespace App\Http\Controllers;
class UserController extends Controller {
public function index()
{
}
}
Controllers should be stored in app/Http/Controllers/.
Now lets flesh out the index method:
public function index()
{
// grab our users
$users = App\Users::all();
// return a view with the users data
return view('users.index')->with('users');
}
This grabs the users from the database and loads up a view passing the users data.
Here's what your view could look like:
<!DOCTYPE html>
<html>
<head>
<title>Users Page</title>
</head>
<body>
#foreach($users as $user)
<a href="{{ URL::route('user', ['id' => $user->id]) }}">
{{ $user->username }}
</a>
#endforeach
</body>
</html>
The view code will loop through each user from the $users data we passed to the view and create a link to their user page which is different for each user based on their id (their unique identifier in the DB)
Due to the way I've named it, this would be found in app/views/users/index.blade.php - if you save files ending in blade.php you can use Laravel's templating language, blade.
Now you need to finally set up another route to respond to a user page, for example http://your-app-name/public/user/22.
Route::get('user/{id}', ['uses' => 'UserController#show']);
Then add the show method to UserController
public function show($id)
{
// this will dump out the user information
return \App\User::find($id);
}
Hope that helps a little! Wrote most of it off the top of my head so let me know if you get any errors via comment.
This question is very bare, and it is difficult to actually help your situation without you showing any code. Just to point you in the right direction though, here is what you would need.
A Model called People, this is how you will access your data.
A controller. In this controller you will do the following
Get the ID of the profile you want from the functions parameters
Find that persons information e.g. People::find($person_id);
return the profile view with that persons data e.g. return view('profile')->with('person', $person);
In your view you can then use that data on that page e.g. {{ $person->name }}
For the page that needs to display the links to the people you would have a method in your controller which..
Get all the people data e.g. People::all();
Return a view with that data return view('all-people')->with('people', $people);
You will then need a route to access an individual person. The route will need to pass the persons ID into a controller method e.g.
Route::get('get-person/{id}',
[ 'as' => 'get-person',
'uses' => 'PeopleController#getPerson' ]);
You can then use this route in your view to get the links to each person
#foreach($people as $person)
{{$person->name}}
#endforeach
This would produce the list of links you want.