What is start faster by ignoring the start-up file? - shell

What is different between /bin/tcsh and /bin/tcsh -f ?
I create environment variables before I run a script. How does 'f' effect ?

The documentation for tcsh has the answer you are looking for:
When a command to be executed is found not to be a builtin command the
shell attempts to execute the command via execve(2). Each word in the
variable path names a directory in which the shell will look for the
command. If the shell is not given a -f option, the shell hashes the
names in these directories into an internal table so that it will try
an execve(2) in only a directory where there is a possibility that the
command resides there. This greatly speeds command location when a
large number of directories are present in the search path. This
hashing mechanism is not used: ... 2. If the shell was given a -f argument.

Related

Running executables without ./ or bash or source

I am learning the basics of bash and linux. To execute a script, I could type...
bash script1
or
source script1
or
./script1
The first two will run without chmod u+x and the last one requires it.
From my understanding, bash tries to run things in a subshell so it doesn't mess things up. When I add bash before the filename, it's executed in a subshell. source is just a way of telling the computer to run it in the current shell. I'm not sure why these don't require the execute permission though.
./ is pretty straightforward. However, I've seen people run scripts without the ./. One told me I could do this by doing something with PATH. I completely don't understand this PATH thing.
Can someone explain in the easiest way possible?
On
bash script1
you are executing bash (the one that needs execution permission) to read and process script1 (which needs read permission).
On
source script1
you are telling the current bash to read the file and process it as if it were typed on the current shell, so the current bash reads the script (read permission) and executes every line.
Finally, on
./script1
you are telling bash to try to run a file called ./script1, so it checks if it is executable (execute permission on ./script1) and passes this file to the kernel to be executed. The kernel opens the file and acts as needed (if it have a shebang line, it uses whatever is given, if it finds it is an ELF object, it prepares the binary in memory...).
Regarding PATH, check some documentation and come back with specific doubts, if any.
PATH is environmental variable. It is a list containing all directories that will be searched when you issue a command. So if your PATH is defined as PATH=/bin:/usr/bin these two dirs will be searched, if you redefine it as export PATH=./:$PATH it will also add current directory to search list.

How can I store and execute the command "export PATH=$PREFIX/bin" from a script?

I would like to write a script that has several commands of the kind
> export PATH=$PREFIX/bin
Where
> $PREFIX = /home/usr
or something else. Instead of typing it into the the Shell (/bin/bash) I would run the script to execute the commands.
Tried it with sh and then with a .py script having the line,
> commands.getstatusoutput('export PATH=$PREFIX/bin')
but these result into the error "bad variable name".
Would be thankful for some ideas!
If you need to adjust PATH (or any other environment variable) via a script after your .profile and equivalents have been run, you need to 'dot' or 'source' the file containing the script:
. file_setting_path
source file_setting_path
The . notation applies to all Bourne shell derivatives, and is standardized by POSIX. The source notation is used in C shell and has infected Bash completely unnecessarily.
Note that the file (file_setting_path) can be specified as a pathname, or if it lives in a directory listed on $PATH, it will be found. It only needs to be readable; it does not have to be executable.
The way the dot command works is that it reads the named file as part of the current shell environment, rather than executing it in a sub-shell like a normal script would be executed. Normally, the sub-shell sets its environment happily, but that doesn't affect the calling script.
The bad variable name is probably just a complaint that $PREFIX is undefined.
Usually a setting of PATH would look something like
export PATH=$PATH:/new/path/to/programs
so that you retain the old PATH but add something onto the end.
You are best off putting such things in your .bashrc so that they get run every time you log in.

"Command not found" inside shell script

I have a shell script on a mac (OSX 10.9) named msii810161816_TMP_CMD with the following content.
matlab
When I execute it, I get
./msii810161816_TMP_CMD: line 1: matlab: command not found
However, when I type matlab into the shell directly it starts as normal. How can it be that the same command works inside the shell but not inside a shell script? I copy-pasted the command directly from the script into the shell and it worked ...
PS: When I replace the content of the script with
echo matlab
I get the desired result, so I can definitely execute the shell script (I use ./msii810161816_TMP_CMD)
Thanks guys!
By default, aliases are not expanded in non-interactive shells, which is what shell scripts are. Aliases are intended to be used by a person at the keyboard as a typing aid.
If your goal is to not have to type the full path to matlab, instead of creating an alias you should modify your $PATH. Add /Applications/MATLAB_R2014a.app/bin to your $PATH environment variable and then both you and your shell scripts will be able to simply say
matlab
This is because, as commenters have stated, the PATH variable inside of the shell executing the script does not include the directory containing the matlab executable.
When a command name is used, like "matlab", your shell looks at every directory in the PATH in order, searching for one containing an executable file with the name "matlab".
Without going into too much detail, the PATH is determined by the shell being invoked.
When you execute bash, it combines a global setting for basic directories that must be in the PATH with any settings in your ~/.bashrc which alter the PATH.
Most likely, you are not running your script in a shell where the PATH includes matlab's directory.
To verify this, you can take the following steps:
Run which matlab. This will show you the path to the matlab executable.
Run echo "$PATH". This will show you your current PATH settings. Note that the directory from which matlab is included in the colon-separated list.
Add a line to the beginning of your script that does echo "$PATH". Note that the directory from which matlab is not included.
To resolve this, ensure that your script is executed in a shell that has the needed directory in the PATH.
You can do this a few ways, but the two most highly recommended ones would be
Add a shebang line to the start of your script. Assuming that you want to run it with bash, do #!/bin/bash or whatever the path to your bash interpreter is.
The shebang line is not actually fully standardized by POSIX, so BSD-derived systems like OSX will happily handle multiple arguments to the shebanged executable, while Linux systems pass at most one argument.
In spite of this, the shebang is an easy and simple way to document what should be used to execute the script, so it's a good solution.
Explicitly invoke your script with a shell as its interpreter, as in bash myscript.sh or tcsh myscript.sh or even sh myscript.sh
This is not incompatible with using a shebang line, and using both is a common practice.
I believe that the default shell on OSX is always bash, so you should start by trying with that.
If these instructions don't help, then you'll have to dig deeper to find out why or how the PATH is being altered between the calling context and the script's internal context.
Ultimately, this is almost certainly the source of your issue.

How to run a TCL script from shell script?

I am new to TCL scripting and shell scripting. I want to invoke a TCL script from the shell script. I have tried as below.
#!/bin/sh
for i in {1..5}
do
my_script
test_script
done
If I run the script, it is throwing error as follows,
./sample.sh: line 5: my_script: command not found
./sample.sh: line 5: test_script: command not found
Can anyone help me out with this ?
Thanks in advance.
If they cannot be found in your $PATH you have to provide a path to your scripts, e.g.:
./my_myscript # current directory
/path/to/test_script # absolute path
If you haven't made your script executable (with chmod +x) then you need to use:
tclsh my_script.tcl
Or maybe tclsh8.5 /path/to/script.tcl or many variations on that.
If you have made the script executable, check that the directory containing the script is on your PATH (if not, use the full filename of the script or adjust your PATH) and that you've got a suitable #! line. The usual recommended one is:
#!/usr/bin/env tclsh8.5
as that will search your path for the tclsh8.5 executable instead of hard-coding it.
From man tclsh. I guess the second block answers your question.
If you create a Tcl script in a file whose first line is
#!/usr/local/bin/tclsh
then you can invoke the script file directly from your shell if you mark the file as executable. [...]
An even better approach is to start your script files with the following three lines:
#!/bin/sh
# the next line restarts using tclsh \
exec tclsh "$0" ${1+"$#"}
This approach has three advantages over the approach in the previous paragraph [...]
You should note that it is also common practice to install tclsh with its version number as part of the name.This has the advantage of allowing multiple
versions of Tcl to exist on the same system at once, but also the disadvantage of making it harder to write scripts that start up uniformly across different versions of Tcl.

How to run my own programm using command in Shell?

I just learned that I could use chmod make myscript.sh executable and the run it as $ ./myscript.sh But how can I attach a custom command to it, like $ connectme [options] ?
You need to do two things:
Give the name you want to use. Either just rename it, or establish a link (hard or symbolic). Make sure the correctly named object has the right permissions.
Make sure it is in you path. But putting "." in you PATH is a bad idea (tm), so copy it to $HOME/bin, and put that in you path.
A completely different approach. Most shells support aliases. You could define one to run your script.
Note: The environment variable PATH tells the shell where to look for programs to run (unless you specify a fully qualified path like /home/jdoe/scripts/myscript.sh or ./myscript.sh), it consists of a ":" seperated list of directories to examine. You can check yours with:
$ printenv PATH
resulting for me in
/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/X11/bin:/usr/X11R6/bin
which are the usual directories for binaries. You can add a new path element with (in /bin/sh and derivatives):
$ export PATH=$PATH:$HOME/bin
in csh and derivatives use
$ setenv PATH $PATH:$HOME/bin
either of which which will result in the shell also searching ~/bin for things to run. Then move your script into that directory (giving ta new name if you want). Check that you execute permissions for the script, and just type its name like any other command.
Fianlly, the use of a ".sh" extension to denote a shell script is for human consumption only. Unix does not care about how you name your script: it is the so-called "shebang" ("#!") on the first line of the script that the OS uses to find the interpreter.
You need to learn about arguments in BASH PROGRAMMING. Here is a good tutorial on them. Check section #4 out.
Basically, you need to use special variables $1, $2, $3 to refer to first, second and third command line arguments respectively.
Example:
$ ./mycript.sh A-Rod
With myscript.sh being:
#!/bin/bash
echo "Hello $1"
Will print:
Hello A-Rod

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