Creating a parallel arithmetic operator in an infinite loop in C compiler on Mac Terminal - shell

Question

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
void main (void)
{
while(1) // infinite loop
{
int a, b;
printf("Give me an integer a: ");
scanf("%d",&a);
printf("Give me an integer b: ");
scanf("%d",&b);
sum = &a + &b;
product = &a * &b;
difference = &a - &b;
echo Here is your sum, product, and difference:
printf("Sum: %d + d% = %d.\n", a, b, sum);
printf("Product: %d * d% = %d.\n", a, b, product);
printf("Difference: %d - d% = %d.\n", a, b, difference);
return 0;
}
}
I keep getting a syntax error with my void main (void) on line 6
Using child processes to create 3 parallel processes.

Answer 1

This program has a bunch of problems, and it's not doing anything in parallel:
void main (void)
This will usually compile, but according to the C standard it's not correct. The signature of main() that takes no arguments should be int main(void).
sum = &a + &b;
product = &a * &b;
difference = &a - &b;
You're using the addresses of a and b instead of the values, so you'd always get the same results for sum, product, and difference (except that didn't define the last three.) The correct version should be:
sum = a + b;
product = a * b;
difference = a - b;
echo Here is your sum, product, and difference:
This isn't a C construct, so the compiler will complain about this. Use printf().
return 0;
Although you've indicated that the loop should be infinite, it won't be because you exit the function at the end of the loop.