is there any way or method to generate fake string using laravel faker ?
like in laravel we generate string upto 20 chars..
str_random(20);
Faker offers a couple of methods that let you replace placeholders in a given string with random characters:
lexify - takes given string and replaces ? with random letters
asciify - takes given string and replaces * with random ascii characters
numerify - takes given string and replaces # with random digits
bothify - combines the lexify and numerify
You could try to use one of them, depending on the requirements you have for that random string you need. asciify uses the largest set of characters as replacement so using that one makes most sense.
The following will give you a random string of 20 ascii characters:
$faker->asciify('********************')
Alternate for generate string without special chars.
$faker->regexify('[A-Za-z0-9]{20}')
$faker->text($maxNbChars = 50);
$faker->text()
// generates 50 char by default: "Aut quo omnis placeat eos omnis eos."
$faker->text(10);
// generates 10 char by default: "Labore."
All texts seems to be one or more latin pseudo-sentences with spaces and always a dot in the end (of each sentence).
uze Faker\Provider\en_US\Text
<?php
realText($maxNbChars = 200, $indexSize = 2) // "And yet I wish you could manage it?) 'And what are they made of?' Alice asked in a shrill, passionate voice. 'Would YOU like cats if you were never even spoke to Time!' 'Perhaps not,' Alice replied."
Related
I have a long string which contains only decimal numbers with two signs after comma
str = "123,457568,22321,5484123,77"
The numbers in string only decimals with two signs after comma. How I can separate them in different numbers like that
arr = ["123,45" , "7568,22" , "321,54" , "84123,77"]
You could try a regex split here:
str = "123,457568,22321,5484123,77"
nums = str.split(/(?<=,\d{2})/)
print nums
This prints:
123,45
7568,22
321,54
84123,77
The logic above says to split at every point where a comma followed by two digits precedes.
Scan String for Commas Followed by Two Digits
This is a case where you really need to know your data. If you always have floats with two decimal places, and commas are decimals in your locale, then you can use String#scan as follows:
str.scan /\d+,\d{2}/
#=> ["123,45", "7568,22", "321,54", "84123,77"]
Since your input data isn't consistent (which can be assumed by the lack of a reliable separator between items), you may not be able to guarantee that each item has a fractional component at all, or that the component has exactly two digits. If that's the case, you'll need to find a common pattern that is reliable for your given inputs or make changes to the way you assign data from your data source into str.
An action outputs a fixed-length string via Ruby's pack function
clean = [edc_unico, sequenza_sede, cliente_id.to_s, nome, indirizzo, cap, comune, provincia, persona, note, telefono, email]
string = clean.pack('A15A5A6A40A35A5A30A2A40A40A18A25')
However, the data is in UTF-8 as to allow latin/high-ascii characters. The result of the pack action is logical. high-ascii characters take the space of 2 regular ascii characters. The resulting string is shortened by 1 space character, defeating the original purpose.
What would be a concise ruby command to interpret high-ascii characters and thus add an extra space at the end of each variable for each high-ascii character, so that the length can be brought to its proper target? (note: I am assuming there is no directive that addresses this specifically, and the whole lot of pack directives is mind-muddling)
update an example where the second line shifts positions based on accented characters
CNFrigo 539 Via Privata Da Via Iseo 6C 20098San Giuliano Milanese MI02 98282410 02 98287686 12886480156 12886480156 Bo3 Euro Giuseppe Frigo Transport 349 2803433 M.Gianoli#Delanchy.Fr S.Galliard#Delanchy.Fr
CNIn's M 497 Via Istituto S.Maria della Pietà, 30173Venezia Ve041 8690111 340 6311408 0041 5136113 00115180283 02896940273 B60Fm Euro Per Documentazioni Tecniche Inviare Materiale A : Silvia_Scarpa#Insmercato.It Amministrazione : Michela_Bianco#Insmercato.It Silvia Scarpa Per Liberatorie 041/5136171 Sig.Ra Bianco Per Pagamento Fatture 041/5136111 (Solo Il Giovedi Pomeriggio Dalle 14 All Beniservizi.Insmercato#Pec.Gruppopam.It
It looks like you are trying to use pack to format strings to fixed width columns for display. That’s not what it’s for, it is generally used for packing data into fixed byte structures for things like network protocols.
You probably want to use a format string instead, which is better suited for manipulating data for display.
Have a look at String#% (i.e. the % method on string). Like pack it uses another little language which is defined in Kernel#sprintf.
Taking a simplified example, with the two arrays:
plain = ["Iseo", "Next field"]
accent = ["Pietà", "Next field"]
then using pack like this:
puts plain.pack("A10A10")
puts accent.pack("A10A10")
will produce a result that looks like this, where “Next field” isn’t aligned since pack is dealing with the width in bytes, not the displayed width:
Iseo Next field
Pietà Next field
Using a format string, like this:
puts "%-10s%-10s" % plain
puts "%-10s%-10s" % accent
produces the desired result, since it is dealing with the displayable width:
Iseo Next field
Pietà Next field
I have a string that begins with a set start and then is filled to 252 characters by randomly generated letters. (237 random chars - so that the end length is 252 characters)
For the purpose of testing the string starts off with TESTDATAMENDNOW and the rest is random capital letters.
How can I test that the characters are all capital letters
and that the string begins with TESTDATAMENDNOW
I have tried to use regex expressions to define this but I'm not too sure how to get them to work properly, and what I have tried so far seems not to be working.
EDIT: Clarity
expect(string).to match(/\ATESTDATAMENDNOW[A-Z]{237}\z/)
237 because 252 minus the length of "TESTDATAMENDNOW" is 237.
Here's another way that does not use a regex:
str = "TESTDATAMENDNOW"
expect(string[0,str.size]).eq(str)
expect(string.delete("ABCDEFGHIJKLMNOPQRSTUVWXYZ").eq("")
expect(string.size).eq(252)
I am wondering how to make something where if X=5 and Y=2, then have it output something like
Hello 2 World 5.
In Java I would do
String a = "Hello " + Y + " World " + X;
System.out.println(a);
So how would I do that in TI-BASIC?
You have two issues to work out, concatenating strings and converting integers to a string representation.
String concatenation is very straightforward and utilizes the + operator. In your example:
"Hello " + "World"
Will yield the string "Hello World'.
Converting numbers to strings is not as easy in TI-BASIC, but a method for doing so compatible with the TI-83+/84+ series is available here. The following code and explanation are quoted from the linked page:
:"?
:For(X,1,1+log(N
:sub("0123456789",ipart(10fpart(N10^(-X)))+1,1)+Ans
:End
:sub(Ans,1,length(Ans)-1?Str1
With our number stored in N, we loop through each digit of N and store
the numeric character to our string that is at the matching position
in our substring. You access the individual digit in the number by
using iPart(10fPart(A/10^(X, and then locate where it is in the string
"0123456789". The reason you need to add 1 is so that it works with
the 0 digit.
In order to construct a string with all of the digits of the number, we first create a dummy string. This is what the "? is used
for. Each time through the For( loop, we concatenate the string from
before (which is still stored in the Ans variable) to the next numeric
character that is found in N. Using Ans allows us to not have to use
another string variable, since Ans can act like a string and it gets
updated accordingly, and Ans is also faster than a string variable.
By the time we are done with the For( loop, all of our numeric characters are put together in Ans. However, because we stored a dummy
character to the string initially, we now need to remove it, which we
do by getting the substring from the first character to the second to
last character of the string. Finally, we store the string to a more
permanent variable (in this case, Str1) for future use.
Once converted to a string, you can simply use the + operator to concatenate your string literals with the converted number strings.
You should also take a look at a similar Stack Overflow question which addresses a similar issue.
For this issue you can use the toString( function which was introduced in version 5.2.0. This function translates a number to a string which you can use to display numbers and strings together easily. It would end up like this:
Disp "Hello "+toString(Y)+" World "+toString(X)
If you know the length of "Hello" and "World," then you can simply use Output() because Disp creates a new line after every statement.
Dim str as String
str = "30 40 50 60"
I want to count the number of substrings.
Expected Output: 4
(because there are 4 total values: 30, 40, 50, 60)
How can I accomplish this in VB6?
You could try this:
arrStr = Split(str, " ")
strCnt = UBound(arrStr) + 1
msgBox strCnt
Of course, if you've got Option Explicit set (which you should..) then declare the variables above first..
Your request doesn't make any sense. A string is a sequence of text. The fact that that sequence of text contains numbers separated by spaces is quite irrelevant. Your string looks like this:
30 40 50 60
There are not 4 separate values, there is only one value, shown above—a single string.
You could also view the string as containing 11 individual characters, so it could be argued that the "count" of the string would be 11, but this doesn't get you any further towards your goal.
In order to get the result that you expect, you need to split the string into multiple strings at each space, producing 4 separate strings, each containing a 2-digit numeric value.
Of course, the real question is why you're storing this value in a string in the first place. If they're numeric values, you should store them in an array (for example, an array of Integers). Then you can easily obtain the number of elements in the array using the LBound() and UBound() functions.
I agree with everything Cody stated.
If you really wanted to you could loop through the string character by character and count the number of times you find your delimiter. In your example, it is space delimited, so you would simply count the number of spaces and add 1, but as Cody stated, those are not separate values..
Are you trying to parse text here or what? Regardless, I think what you really need to do is store your data into an array. Make your life easier, not more difficult.