Laravel: find posts from current user - laravel

I´ve cloned this sample app: https://github.com/codekerala/laravel-and-vue.js-spa-Recipe-Box
In RecipeController there's an index function that returns all posts (or recipes in this case). I need to get only recipes added by the current logged in user.
public function index()
{
$currentuser = Auth::id();
$recipes = Recipe::where('user_id', '=', $currentuser)
->get(['id', 'name', 'image']);
return response()
->json([
'recipes' => $recipes
]);
}
When trying this, my recipes array is empty, but no other errors from what I can see. I can hardcode value 1 instead of $currentuser and it returns all recipes that are made by user # 1.
I am declaring use Auth;, but am new to the Laravel framework, maybe someone could give any assistance?
Using Laravel 5.4.15

There might be any problem in Auth::user() please check it.
Add the following in your controller
use Illuminate\Support\Facades\Auth;
And add a constructor
public function __construct()
{
$this->middleware('auth');
}
public function index()
{
$currentuser = Auth::user();
dump($currentuser);
$recipes = Recipe::where('user_id', '=', $currentuser->id)
->get(['id', 'name', 'image']);
return response()
->json([
'recipes' => $recipes
]);
}

I think there is problem in your current user. You are not able to retrieve user id
Just use this statement.
$current_user = \Auth::user()->id;

Related

Laravel - Get array with relationship

I have an ajax call that returns an array:
$reports = Report::where('submission_id', $submissionID)
->where('status', 'pending')
->get(['description','rule']);
return [
'message' => 'Success.',
'reports' => $reports,
];
From this array, I only want to return the fields 'description' and 'rule'. However I also want to return the owner() relationship from the Report model. How could I do this? Do I have to load the relationship and do some kind of array push, or is there a more elegant solution?
You can use with() to eager load related model
$reports = Report::with('owner')
->where('submission_id', $submissionID)
->where('status', 'pending')
->get(['id','description','rule']);
Note you need to include id in get() from report model to map (owner) related model
you will have probably one to many relationship with Reports and owners table like below
Report Model
public function owner() {
return $this->belongsTo('App\Owner');
}
Owner Model
public function reports() {
return $this->hasMany('App\Report');
}
your controller code
$reports = Report::with('owner')->
where('submission_id', $submissionID)->where('status', 'pending')->get()
return [
'message' => 'Success.',
'reports' => $reports,
];
This is what I ended up going with:
$reports = Report::
with(['owner' => function($q)
{
$q->select('username', 'id');
}])
->where('submission_id', $submissionID)
->where('status', 'pending')
->select('description', 'rule','created_by')
->get();
The other answers were right, I needed to load in the ID of the user. But I had to use a function for it to work.

How to queue the logics in controller

I have used two logic in my controller in my laravel project
public function multiStore()
{
$user = User::create([
'name'=>$request->name,
'email'=>$request->email,
'password'=>Hash::make($request->name),
]);
$post = MyPost::create([
'name'=>$request->post_name,
'body'=>$request->post_body,
]);
return redirect()->to('/admin/home);
}
Is it possible to make like if user is created successfully only then the post will be created so that I can use post created by user relationship
I have tried something like if condition but it is not working
You can try the code bellow , I assume you have a user_id field in posts table since you mentio9ned a relation ship. This is not the best way but i try to keep things simple, so I just edited the code.
Note : make sure you listed all the table fields in protected $fillable in your model before using Create()
public function multiStore()
{
$user = User::create([
'name'=>$request->name,
'email'=>$request->email,
'password'=>Hash::make($request->name),
]);
if($user){
$post = MyPost::create([
'user_id' => $user->id
'name'=>$request->post_name,
'body'=>$request->post_body,
]);
}
return redirect()->to('/admin/home);
}
Enclose your query in database transaction
https://laravel.com/docs/5.8/database#database-transactions
Either you can:
DB::transaction(function() {
Model::create();
AnotherModel::create();
});
Or you can use the following to find and catch error...
DB::beginTransaction();
// Your queries here...
// Model::create();
// AnotherModel::create();
DB::commit();

Laravel 5.6 - Using model functions in ModelFactory

I am working with Laravel 5.6 and found myself a weird problem while extending the functionality of my project.
Right now i need to create two new models: order and item. It was quite easy to fill the items table with dummy data using Faker and Laravel Factories/Seeders. The biggest problem is while working with the order model.
This little fellow is related to a company with a foreign key named company_id and user with a foreign key named seller_id. The company field is okay, the trouble is behind my seller_id
This seller needs a role related to the company my factory will randomly pick for it because the user is not related to the company (directly) and i can't just look for it with a company_id.
In order to get all the users "related" to my company, i've created the next function on my Company model:
public function users()
{
$roles = $this->roles;
$users = [];
foreach ($roles as $role) {
foreach ($role->users as $user) {
$user->makeHidden(['pivot']);
array_push($users, $user);
}
}
$users = array_unique_objects($users);
return $users;
}
btw: I'm using laravel-permissions, a library made by Spatie.
What this functions does is get every role from a company and then it pushes it to an array of users.
This custom helper: array_unique_objects tracks any repeated user on my array and removes them.
That function works find because i've tested on a couple of controllers so i know there is no problem with it. Either way, my OrderFactory.php looks like this:
<?php
use Faker\Generator as Faker;
use App\Models\User;
use App\Models\Company;
$factory->define(App\Models\Order::class, function (Faker $faker) {
$company = Company::get()->random(1);
$users = $company->users();
$user = array_random($users);
return [
'company_id' => $company,
'seller_id' => $user->id,
'code' => strtoupper(str_random(10)),
'description' => $faker->sentence($nbWords = rand(2, 4), $variableNbWords = true),
'created_at' => $faker->dateTimeBetween($startDate = '-1 year', $endDate = 'now', $timezone = null)
];
});
But when i run the php artisan db:seed command, it throws the next error in console:
BadMethodCallException : Method Illuminate\Database\Eloquent\Collection::users does not exist.
at >/home/ironman/Documentos/Sandbox/Proventas/Backend/vendor/laravel/framework/src/Illuminate/Support/Traits/Macroable.php:99
95| */
96| public function __call($method, $parameters)
97| {
98| if (! static::hasMacro($method)) {
99| throw new BadMethodCallException(sprintf(
100| 'Method %s::%s does not exist.', static::class, $method
101| ));
102| }
103|
Exception trace:
1 Illuminate\Support\Collection::__call("users", [])
/home/ironman/Documentos/Sandbox/Proventas/Backend/database/factories/OrderFactory.php:10
2 Illuminate\Database\Eloquent\Factory::{closure}(Object(Faker\Generator), [])
/home/ironman/Documentos/Sandbox/Proventas/Backend/vendor/laravel/framework/src/Illuminate/Database/Eloquent/FactoryBuilder.php:274
Please use the argument -v to see more details.
Is there anything I can do to fix this problem? I know that using Laravel Relationships will fix my problem but the specifications of this project says that i have to keep things just as the are.
Your call to
$company = Company::get()->random(1);
does not return a single company. It returns a Collection, which does not have a users dynamic function. Try
$company = Company::get()->random(1)->first();

Property [***] does not exist on this collection instance Laravel eloquent relationship

In my Post Model
public function user()
{
return $this->belongsTo('App\User');
}
And in the User Model
public function posts()
{
return $this->hasMany('App\Post');
}
Now I am trying to get the comments of a specific user
$user= User::where('name', 'like', '%Mat%')->first();
return $user->posts->comment;
But it shows
Property [comment] does not exist on this collection instance.
The user has many posts which therefore returns a collection, you will need to loop over this to get your comments out. I.e.
$user = User::where('name', 'like', '%Mat%')->first();
$user->posts->each(function($post) {
echo $post->comment;
});
See the documentation on Laravel Collections
I think you can try this :
$user= User::with('post')->where('name', 'like', '%Mat%')->get();
$postComment = array();
foreach($user->post as $post){
$postComment = $post->comment;
}
return $postComment;
Hope this help for you !!!
If you want to have all comments you can use the following code:
$comments = [];
$user = User::where('name', 'like', '%Mat%')->with(['post.comment' => function($query) use (&$comments) {
$comments = $query->get();
}])->first();
return $comments;
Property [comment] does not exist on this collection instance.
The above error occurs because the Posts function returns a collection. Now you will have to traverse through each element of the collection.
Since, you are returning $user->posts()->comment, I am assuming you need it in the form of an array and don't have to simply echo them out, one by one. So you can store them all in an array & then process it whatever whay you like.
$comments = array();
$user->posts()->each(function $post){
$comments = $post->comment;
}
return $comments;
For greater insight, into this collection function read:
https://laravel.com/docs/5.4/collections#method-each

Laravel 5.4 - route model binding condition

I have implemented route model binding as follows:
Route:
Route::get('property/{property}', 'PropertyController#view');
Controller:
public function view(Property $property)
{
$data = compact([
'property'
]);
return view('property.view', $data);
}
This works great. However I want to add a condition to the Property model to check that active = 1. How and where do I do this?
You can register an explicit binding. Add the code below to RouteServiceProvider. This will be applied to the model binding when the segment is property.
Route::bind('property', function ($id) {
return \App\Property::where('id', $id)
->where('active', 1)
->firstOrFail();
});
If you need this condition to be applied globally for every result then you can add a global scope instead. https://laravel.com/docs/5.4/eloquent#global-scopes

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