I have two tables that I want to run joint query on using the value of two date time columns, I have products table and sync_status tables, I want to return all products with updated_at date time greater than synced_at date time.
DB::table('products')
->join('sync_statuses', function ($join) {
$join->on('products.product_number', '=', 'sync_statuses.product_number')
->where('products.updated_at', '>', 'sync_statuses.synced_at')
->whereNull('products.deleted_at');
})
->select('products.product_number');
This SQL represents what I am trying to achieve using Eloquent:
SELECT products.product_number
FROM products
JOIN push_statuses
ON products.product_number = statuses.product_number
AND (
statuses.synced_at IS NULL
OR products.updated_at > statuses.synced_at
)
You have to use on() instead of where() to compare columns:
->on('products.updated_at', '>', 'sync_statuses.synced_at')
This worked for me:
DB::table('products')
->join('statuses', function ($join) {
$join->on('products.product_number', '=', 'statuses.product_number')
->where(DB::raw('products.updated_at'), '>=', DB::raw('statuses.synced_at'))
->whereNull('products.deleted_at');
})->select('products.product_number');
I needed to use DB::raw('products.updated_at') to reference each date time column in the where() clause.
Related
i has raw query in laravel like this
public function getPopularBook(){
$book = DB::select("
with totalReview as(
SELECT r.book_id , count(r.id)
FROM review r
GROUP BY r.book_id
)
SELECT *
from totalReview x
left JOIN (
SELECT b.*,
case when ((now() >= d.discount_start_date and now() <= d.discount_end_date) or (now() >= d.discount_start_date and d.discount_end_date is null)) then (b.book_price-d.discount_price)
ELSE b.book_price
end as final_price
FROM discount d
right JOIN book b
on d.book_id = b.id
) as y
on x.book_id = y.id
ORDER BY x.count DESC, y.final_price ASC
LIMIT 8"
);
return $book;
}
so when i want to return a paginate, it doesn't work so can i convert this to query build to use paginate
This is a very un-optimized raw query in itself. You are performing too many Join in Subquery just to sort by price
i'm assuming the database table:
books[ id, name, price ]
reviews[ id, book_id ]
discounts[ id, book_id, start_date, end_date, discount_price]
Look how easy it is if you just use Eloquent:
Book::withCount('reviews')->orderBy('reviews_count')->get();
this will give you all the Books order by number of reviews
now with the final price, this can be a bit tricky, let's take a look at a query when we don't consider discount time
Book::withCount('reviews')
->withSum('discounts', 'discount_price') //i'm assuming a book can have many discount at the same time, so i just sum them all
->addSelect(
DB::raw('final_price AS (books.price - discounts_sum_discount_price)')
)
->orderBy('reviews_count', 'asc') // =you can specify ascending or descending
->orderBy('final_price', 'desc') //in laravel chaining multiple orderBy to order multiple column
->get();
I dont even need to use Subquery!! But how do we actually only add the "active" discount?, just need to modify the withSum a bit:
Book::withCount('reviews')
->withSum(
[
'discounts' => function($query) {
$query->where('start_date', '<=', Carbon::now())
->where('end_date', '>=', Carbon::now())
}
],
'discount_price'
)
->addSelect(
DB::raw('final_price AS (books.price - discounts_sum_discount_price)')
)
->orderBy('reviews_count', 'asc') // =you can specify ascending or descending
->orderBy('final_price', 'desc') //in laravel chaining multiple orderBy to order multiple column
->get();
and it is done
What about pagination? just replace the get() method with paginate():
Book::withCount('reviews')
->withSum(['discounts' => function($query) {
$query->where('start_date', '<=', Carbon::now())->where('end_date', '>=', Carbon::now())
}],'discount_price')
->addSelect(DB::raw('final_price AS (books.price - discounts_sum_discount_price)')) //just format to be a bit cleaner, nothing had changed
->orderBy('reviews_count', 'asc')
->orderBy('final_price', 'desc')
->paginate(10); //10 books per page
WARNING: this is written with ELoquent ORM, not QueryBuilder, so you must define your relationship first
my sqlfiddle eample
Hello there,
according to the above sqlfiddle example;
I have a table A where the products are listed and a table B with different prices for different periods associated with these products.
Here I show these prices according to the date the user has chosen. There is no problem.
However, if the user has not selected a date, I cannot show the price of the period closest to today by default.
In the example I gave, the sql query does this successfully, but I cannot write it successfully in the form of laravel query. Or as an Eloquent orm query
How can I do that?
$query->select(['tableA.*', 'tableB.start_date', 'tableB.end_date', 'tableB.price'])
->join('tableB', function($join) {
$join->on('tableA.id', '=', 'tableB.pro_id');
})->where(function($sq) use ($postFrom) {
$sq->when($postFrom[0]=='0', function ($syq) {
$syq->whereRaw('DAYOFYEAR(curdate()) <= DAYOFYEAR(tableB.end_date)');
}, function ($stq) use ($postFrom) {
$stq->whereDate('tableB.start_date', '<=', $postFrom[0])
->whereDate('tableB.end_date', '>=', $postFrom[0]);
});
})->orWhere(function($ssq) use ($postTo) {
$ssq->whereDate('tableB.start_date', '<=', $postTo[0])
->whereDate('tableB.end_date', '>=', $postTo[0]);
})->groupBy('tableA.id')->orderBy('tableB.price', $sortDirection);
note1: $postFrom and $postTo are the start and end dates from the user. If the user did not submit a date, $postFrom is displayed as 0.
note2: I show the default price when the $postFrom[0] == '0' condition is met.
note3: The '2021-03-07' value in the sqlfiddle example is used for example instead of the dynamic present value.
note4: According to this query, it takes the price value of the first period as default. But that's not what I want.
note5: I can't use 'joinSub' because Laravel version is 5.5.
note6:In the example I want to convert to Laravel Query form, the sql query that works without any problems:
select `tableA`.*, `tableB`.`start_date`, `tableB`.`end_date`, `tableB`.`price`
from `tableA`
right join(
SELECT id, start_date, end_date, pro_id, price, DATEDIFF(`tableB`.`end_date`, '2021-03-07') diff
FROM `tableB` GROUP BY id order by diff asc
) `tableB` on `tableA`.`id` = `tableB`.`pro_id` where (date(`end_date`) >= '2021-03-07')
group by `tableA`.`id` order by `price` desc
This is an equivalent query of your query. I haven't executed.
If Laravel Version is greater then 5.5
$query1 = DB::table('tableB')
->selectRaw("id, start_date, end_date, pro_id, price, DATEDIFF(end_date, '2021-03-07') AS diff")
->groupBy('id')->orderBy('diff','ASC');
TableA::select('tableA.*', 'tableB.start_date', 'tableB.end_date', 'tableB.price')
->joinSub($query1, 'tableB', function ($join)
{
$join->on('tableA.id', '=', 'tableB.pro_id');
})
->whereDate('tableB.end_date','>=','2021-03-07')
->groupBy('tableA.id')->orderBy('price','DESC')->get();
For Laravel 5.5
TableA::select('tableA.*', 'tableB.start_date', 'tableB.end_date', 'tableB.price')
->join(DB::raw("(SELECT id, start_date, end_date, pro_id, price,
DATEDIFF(`tableB`.`end_date`, '2021-03-07') diff
FROM `tableB` GROUP BY id order by diff asc) table2 "), function ($join)
{
$join->on('tableA.id', '=', 'table2.pro_id');
})
->whereDate('table2.end_date','>=','2021-03-07')
->groupBy('tableA.id')->orderBy('price','DESC')->get();
I want to retrieve data from 4 different table using laravel eloquent with multiple criteria.
an Overview of my table;
table 1
id
name
table 2
id
name
year
table1_id
table 3
id
name
description
table2_id
table 4
id
name
quarter
table3_id
below are their relations
table 1
hasMany -> table 2
table 2
belongsTo ->table1
HasMany->table2
table 3
belongsTo ->table2
HasMany->table3
table 4
belongsTo ->table3
I'd like to fetch the data by resource show with two parameters
and i tried this
$Report = Table1::whereHas('tabke1', function($query){
$query->where('year', 'like','%'.$year.'%');
})
->with('table2')->whereHas('table3', function($query){
$query->where('quarter', 'like', '%'.$quarters.'%');
})
->get();
but im receiving syntax error.
How can I retrieve the data from multiple table with multiple filter?
i tried this table query to understand more what i expect
SELECT `table1`.*, `table2`.*, `table3`.*, `table4`.*
FROM `table1`, `table2`, `table3`, `table4`
WHERE ((`table2`.* year = 2019) AND (`table4`.* quarter = 1))
I reckon there are two queries to achieve the results.
The first query is something like:
Table1::whereHas('table2', function ($query) {
$query->where('year', 2019);
})
->whereHas('table2.table3.table4', function ($query) {
$query->where('quarter', 1);
})
->get();
The second query is something like:
Table1::select('table1.*')
->join('table2', 'table1.id', '=', 'table2.table1_id')
->join('table3', 'table2.id', '=', 'table3.table2_id')
->join('table4', 'table3.id', '=', 'table4.table3_id')
->where('table2.year', 2019)
->where('table4.quarter', 1)
->distinct()
->get();
Regarding performance, I prefer the second query.
I am using laravel 5.3 and I have some left join query with error in laravel query method.
This is my normal query
SELECT bran.branchName,sch.schoolName From m_schoolbranch bran
LEFT JOIN m_students stu ON stu.schoolNo=bran.schoolNo AND stu.branchNo=bran.branchNo
LEFT JOIN m_school sch ON sch.schoolNo=stu.schoolNo where stu.userNo='0000000001';
And this is my new laravel Query
DB::table('m_schoolbranch')
->join('m_students', 'm_schoolbranch.schoolNo', '=', 'm_students.schoolNo')
->join('m_students', 'm_schoolbranch.branchNo', '=', 'm_students.branchNo')
->join('m_school', 'm_schoolbranch.schoolNo', '=', 'm_school.schoolNo')
->select('m_school.schoolName', 'm_schoolbranch.branchName')
->where('m_students.userNo',$userNo)
->get();
In these query I need to match two column in table m_students so I put like this
->join('m_students', 'm_schoolbranch.branchNo', '=', 'm_students.branchNo')
But i show error...
Tables in the query need to have unique names, otherwise the DB has no way of knowing which m_schoolbranch should be used when evaluating m_schoolbranch.schoolNo.
You could use unique table aliases in your join statements but I recommend using multiple conditions on the join. Just like you use in your original SQL query. See here: https://stackoverflow.com/a/20732468/4437888
DB::table('m_schoolbranch')
->join('m_students', function($join)
{
$join->on('m_schoolbranch.schoolNo', '=', 'm_students.schoolNo');
$join->on('m_schoolbranch.branchNo', '=', 'm_students.branchNo');
})
->join('m_school', 'm_schoolbranch.schoolNo', '=', 'm_school.schoolNo')
->select('m_school.schoolName', 'm_schoolbranch.branchName')
->where('m_students.userNo',$userNo)
->get();
I have the following working for laravel paginate
$query = DB::table('clients')
->leftJoin('radusergroup', 'clients.username', '=', 'radusergroup.username')
->leftJoin('recharge', 'clients.username', '=', 'recharge.soldto');
I want to join some values from two tables radusergroup and recharge. radusergroup always return one row as it has only one row stored whereas recharge table return multiple rows. I want only one row returned from recharge table which is latest entry.
Right now its return all the possible rows from recharge table and showing it on paginated view.
This is Laravel Official documentation
DB::table('clinets')
->leftJoin('radusergroup', 'clients.username', '=', 'radusergroup.username')
->leftJoin('recharge', function ($leftJoin) {
$leftJoin->on('clients.username', '=', 'recharge.soldto')
->where('recharge.create_date', '=', DB::raw("(select max(`create_date`) from recharge)"));
})
->get();
this is the case if you have create_date column in your table, if you haven't got it I strongly recommend to create that column.