my sqlfiddle eample
Hello there,
according to the above sqlfiddle example;
I have a table A where the products are listed and a table B with different prices for different periods associated with these products.
Here I show these prices according to the date the user has chosen. There is no problem.
However, if the user has not selected a date, I cannot show the price of the period closest to today by default.
In the example I gave, the sql query does this successfully, but I cannot write it successfully in the form of laravel query. Or as an Eloquent orm query
How can I do that?
$query->select(['tableA.*', 'tableB.start_date', 'tableB.end_date', 'tableB.price'])
->join('tableB', function($join) {
$join->on('tableA.id', '=', 'tableB.pro_id');
})->where(function($sq) use ($postFrom) {
$sq->when($postFrom[0]=='0', function ($syq) {
$syq->whereRaw('DAYOFYEAR(curdate()) <= DAYOFYEAR(tableB.end_date)');
}, function ($stq) use ($postFrom) {
$stq->whereDate('tableB.start_date', '<=', $postFrom[0])
->whereDate('tableB.end_date', '>=', $postFrom[0]);
});
})->orWhere(function($ssq) use ($postTo) {
$ssq->whereDate('tableB.start_date', '<=', $postTo[0])
->whereDate('tableB.end_date', '>=', $postTo[0]);
})->groupBy('tableA.id')->orderBy('tableB.price', $sortDirection);
note1: $postFrom and $postTo are the start and end dates from the user. If the user did not submit a date, $postFrom is displayed as 0.
note2: I show the default price when the $postFrom[0] == '0' condition is met.
note3: The '2021-03-07' value in the sqlfiddle example is used for example instead of the dynamic present value.
note4: According to this query, it takes the price value of the first period as default. But that's not what I want.
note5: I can't use 'joinSub' because Laravel version is 5.5.
note6:In the example I want to convert to Laravel Query form, the sql query that works without any problems:
select `tableA`.*, `tableB`.`start_date`, `tableB`.`end_date`, `tableB`.`price`
from `tableA`
right join(
SELECT id, start_date, end_date, pro_id, price, DATEDIFF(`tableB`.`end_date`, '2021-03-07') diff
FROM `tableB` GROUP BY id order by diff asc
) `tableB` on `tableA`.`id` = `tableB`.`pro_id` where (date(`end_date`) >= '2021-03-07')
group by `tableA`.`id` order by `price` desc
This is an equivalent query of your query. I haven't executed.
If Laravel Version is greater then 5.5
$query1 = DB::table('tableB')
->selectRaw("id, start_date, end_date, pro_id, price, DATEDIFF(end_date, '2021-03-07') AS diff")
->groupBy('id')->orderBy('diff','ASC');
TableA::select('tableA.*', 'tableB.start_date', 'tableB.end_date', 'tableB.price')
->joinSub($query1, 'tableB', function ($join)
{
$join->on('tableA.id', '=', 'tableB.pro_id');
})
->whereDate('tableB.end_date','>=','2021-03-07')
->groupBy('tableA.id')->orderBy('price','DESC')->get();
For Laravel 5.5
TableA::select('tableA.*', 'tableB.start_date', 'tableB.end_date', 'tableB.price')
->join(DB::raw("(SELECT id, start_date, end_date, pro_id, price,
DATEDIFF(`tableB`.`end_date`, '2021-03-07') diff
FROM `tableB` GROUP BY id order by diff asc) table2 "), function ($join)
{
$join->on('tableA.id', '=', 'table2.pro_id');
})
->whereDate('table2.end_date','>=','2021-03-07')
->groupBy('tableA.id')->orderBy('price','DESC')->get();
Related
i has raw query in laravel like this
public function getPopularBook(){
$book = DB::select("
with totalReview as(
SELECT r.book_id , count(r.id)
FROM review r
GROUP BY r.book_id
)
SELECT *
from totalReview x
left JOIN (
SELECT b.*,
case when ((now() >= d.discount_start_date and now() <= d.discount_end_date) or (now() >= d.discount_start_date and d.discount_end_date is null)) then (b.book_price-d.discount_price)
ELSE b.book_price
end as final_price
FROM discount d
right JOIN book b
on d.book_id = b.id
) as y
on x.book_id = y.id
ORDER BY x.count DESC, y.final_price ASC
LIMIT 8"
);
return $book;
}
so when i want to return a paginate, it doesn't work so can i convert this to query build to use paginate
This is a very un-optimized raw query in itself. You are performing too many Join in Subquery just to sort by price
i'm assuming the database table:
books[ id, name, price ]
reviews[ id, book_id ]
discounts[ id, book_id, start_date, end_date, discount_price]
Look how easy it is if you just use Eloquent:
Book::withCount('reviews')->orderBy('reviews_count')->get();
this will give you all the Books order by number of reviews
now with the final price, this can be a bit tricky, let's take a look at a query when we don't consider discount time
Book::withCount('reviews')
->withSum('discounts', 'discount_price') //i'm assuming a book can have many discount at the same time, so i just sum them all
->addSelect(
DB::raw('final_price AS (books.price - discounts_sum_discount_price)')
)
->orderBy('reviews_count', 'asc') // =you can specify ascending or descending
->orderBy('final_price', 'desc') //in laravel chaining multiple orderBy to order multiple column
->get();
I dont even need to use Subquery!! But how do we actually only add the "active" discount?, just need to modify the withSum a bit:
Book::withCount('reviews')
->withSum(
[
'discounts' => function($query) {
$query->where('start_date', '<=', Carbon::now())
->where('end_date', '>=', Carbon::now())
}
],
'discount_price'
)
->addSelect(
DB::raw('final_price AS (books.price - discounts_sum_discount_price)')
)
->orderBy('reviews_count', 'asc') // =you can specify ascending or descending
->orderBy('final_price', 'desc') //in laravel chaining multiple orderBy to order multiple column
->get();
and it is done
What about pagination? just replace the get() method with paginate():
Book::withCount('reviews')
->withSum(['discounts' => function($query) {
$query->where('start_date', '<=', Carbon::now())->where('end_date', '>=', Carbon::now())
}],'discount_price')
->addSelect(DB::raw('final_price AS (books.price - discounts_sum_discount_price)')) //just format to be a bit cleaner, nothing had changed
->orderBy('reviews_count', 'asc')
->orderBy('final_price', 'desc')
->paginate(10); //10 books per page
WARNING: this is written with ELoquent ORM, not QueryBuilder, so you must define your relationship first
I'm using Laravel 7. I have a table named assistances witch has some columns and those two columns:
- start_date
- end_date
I'd like to sort data order by the duration between start_date and end_date:
$query = Assistance::join('users', 'assistances.user_id', '=', 'users.id')
->select('assistances.*')
->orderBy('duration between start_date and end_date');
;
How can I do this ?
Please try the following - bare in mind that this is not hugely efficient
DATEDIFF returns the days between two dates. You may also want to use TIMESTAMPDIFF which accepts a first parameter such as 'hour' where you can get more granular control
$query = Assistance::join('users', 'assistances.user_id', '=', 'users.id')
->select('assistances.*')
->orderBy(DB::raw('DATEDIFF(start_date, end_date)'))
->get();
Please also use DB; in your class.
In Laravel 6.18 I'm trying to figure out how to recreate the following Postgres query.
with data as (
select date_trunc('month', purchase_date) as x_month, date_trunc('year', purchase_date) AS x_year,
sum (retail_value) AS "retail_value_sum"
from coins
where user_email = 'user#email.com' and sold = 0
group by x_month, x_year
order by x_month asc, x_year asc
)
select x_month, x_year, sum (retail_value_sum) over (order by x_month asc, x_year asc rows between unbounded preceding and current row)
from data
I know how to build the main part of the query
$value_of_all_purchases_not_sold = DB::table('coins')
->select(DB::raw('date_trunc(\'month\', purchase_date) AS x_month, date_trunc(\'year\', purchase_date) AS x_year, sum(retail_value) as purchase_price_sum'))
->where('user_email', '=', auth()->user()->email)
->where('sold', '=', 0)
->groupBy('x_month', 'x_year')
->orderBy('x_month', 'asc')
->orderBy('x_year', 'asc')
->get();
but how do you build out the with data as ( and the second select?
I need the data to be cumulative and I'd rather do the calculation in the DB than in PHP.
Laravel doesn't have built-in method(s) for common table expression. You may use a third party package such as this - it has a very good documentation. If you don't want to use an external library, then you need use query builder's select method with bindings such as
$results = DB::select('your-query', ['your', 'bindings']);
return Coin::hydrate($results); // if you want them as collection of Coin instance.
I'm looking on how I can have a subquery in Laravel QueryBuilder join with the outer table. For instance, we have a table with Exchange Rates, with a currency and a value_date.
For each currency, we want to be able to fetch the valid exchange rate on a certain valuedate. Since exchange rates do not change on non working days, that means that for saturday and sunday, the value of friday is still valid. A bit of an obvious and standard case.
In SQL, I would query this as follows:
SELECT currency, value_date, rate
FROM exchange_rates er
WHERE value_date = (
SELECT max(value_date)
FROM exchange_rates
WHERE currency = er.currency
AND value_date <= '2019-02-03'
)
This would return a list of all exchange rates (one record for each currency), with the rate that is valid on 2019-02-03, and the associate value date (which would probably be 2019-02-01, since 2019-02-03 is a sunday...)
I have no idea however how I can do this with the Eloquent QueryBuilder without falling back to doing raw sql queries...
$value_date = '2019-02-03';
App\ExchangeRate::where('value_date', function($query) use ($value_date) {
... ??? ...
});
where() can also accept a closure that would allow you to do this:
return ExchangeRate::select('currency', 'value_date', 'rate')
->where('value_date', function($query) {
$query->from('exchange_rates AS er')
->selectRaw('max(value_date)')
->whereColumn('exchange_rates.currency', 'er.currency')
->where('value_date', '<=', '2019-02-03');
})->get();
Here's the output of the query.
Edit: To assign an alias to the outer table, you could do that with the DB Query Builder.
return DB::table('exchange_rates AS alias')
->select('currency', 'value_date', 'rate')
->where('value_date', function($query) {
$query->from('exchange_rates AS er')
->selectRaw('max(value_date)')
->whereColumn('alias.currency', 'er.currency')
->where('value_date', '<=', '2019-02-03');
})->get();
I have two tables that I want to run joint query on using the value of two date time columns, I have products table and sync_status tables, I want to return all products with updated_at date time greater than synced_at date time.
DB::table('products')
->join('sync_statuses', function ($join) {
$join->on('products.product_number', '=', 'sync_statuses.product_number')
->where('products.updated_at', '>', 'sync_statuses.synced_at')
->whereNull('products.deleted_at');
})
->select('products.product_number');
This SQL represents what I am trying to achieve using Eloquent:
SELECT products.product_number
FROM products
JOIN push_statuses
ON products.product_number = statuses.product_number
AND (
statuses.synced_at IS NULL
OR products.updated_at > statuses.synced_at
)
You have to use on() instead of where() to compare columns:
->on('products.updated_at', '>', 'sync_statuses.synced_at')
This worked for me:
DB::table('products')
->join('statuses', function ($join) {
$join->on('products.product_number', '=', 'statuses.product_number')
->where(DB::raw('products.updated_at'), '>=', DB::raw('statuses.synced_at'))
->whereNull('products.deleted_at');
})->select('products.product_number');
I needed to use DB::raw('products.updated_at') to reference each date time column in the where() clause.