I would require your help to retrieve the selected columns from the oracle query
like
SELECT col1,col2,col3+col4 as col3_4_sum,col5*col6 as col5_6_mul from tab1;
I want to retrieve the below output as
Details
==========
Col1
Col2
Col3+Col4
Col5*Col6
Not the alias ,because this can be easily retrieved from dbms_sql.describe_columns oracle utility ,Can someone suggest some data dictionaries to retrieve this
EDIT :Different forms,but i need a final output column only
Query 2:SELECT col1,col2,col3+col4 as col3_4_sum,col5*col6 as col5_6_mul
FROM (SELECT col1,col2,col3,col4,col5,col6 FROM tab1)
Query3:WITH tab as (SELECT col1,col2,col3,col4,col5,col6 FROM tab1)
SELECT col1,col2,col3+col4 as col3_4_sum,col5*col6 as col5_6_mul
FROM tab;
I hope this is what you looking for.
SELECT trim(regexp_substr('col1,col2,col3+col4,col5*col6', '[^,]+', 1, LEVEL)) str_2_tab
FROM dual
CONNECT BY LEVEL <= regexp_count('col1,col2,col3+col4,col5*col6', ',')+1
/
But the simplest way is using chr(10) to replace the commas:
SELECT REPLACE('col1,col2,col3+col4,col5*col6', ',', chr(10)) str_2_tab FROM dual
Output is the same:
STRING_2_TAB
------------
col1
col2
col3+col4
col5*col6
Good resources to check for Parameters and Arguments:
https://www.techonthenet.com/oracle/functions/regexp_substr.php
https://oracle-base.com/articles/misc/regular-expressions-support-in-oracle#example1
Related
I work on this query and get this error:
Oracle - ORA-01489: result of string concatenation is too long
Some one please help to solve this issue
SELECT LISTAGG(RCRDNUM) WITHIN GROUP (ORDER BY RCRDNUM)
FROM (SELECT (ERR.RCRDNUM || ',') AS RCRDNUM
FROM TABLENAME ERR
INNER JOIN (SELECT UPPER(REGEXP_SUBSTR('No value present for CNTRY_CD column for the record',
'[^,]+', 1, LEVEL)) ERR_MSG
FROM DUAL
CONNECT BY REGEXP_SUBSTR('No value present for CNTRY_CD column for the record',
'[^,]+', 1, LEVEL)
IS NOT NULL) ERRMSG_P
ON (UPPER(ERR.ERRMSG) = ERRMSG_P.ERR_MSG
OR 'No value present for CNTRY_CD column for the record' IS NULL))
If the aggregate list is a string longer than 4000 characters, the string needs to be a CLOB, and you can't use listagg(). However, you can use xmlagg(), which does not have the 4000 character limit. The result must be a CLOB though - and it is cast as CLOB in the solution.
. Here is a proof-of-concept; I will let you adapt it to your situation.
with a (id,val) as (select 10, 'x' from dual union all select 20, 'abc' from dual)
select listagg(val, ',') within group (order by id) as l_agg,
rtrim( xmlcast( xmlagg( xmlelement(e, val || ',') order by id) as clob), ',')
as clob_agg
from a
;
Output
L_AGG CLOB_AGG
---------- ----------
x,abc x,abc
In Oracle's SQL queries, strings (columns of type VARCHAR) are limited to 4000 characters. Obviously, your query creates longer strings and therefore fails. This can easily happen with LISTAGG.
Should your query really return such long strings? If not, you need to work on your query.
If you really need values longer than 4000 characters, you can try to use CLOB instead of VARCHAR by using a custom user-defined aggregation function. Tom Kyte has an example in one of his questions.
I have some tables end with date (YYYYMMDD), some end with HHMMSS:
INVENLEVEL_20160419
INVENLEVEL_20160419_120232 <-optional to exist
INVENLEVEL_20160425
INVENLEVEL_20160426
INVENLEVEL_20160426_032112 <-optional to exist
I need to keep tables within 7 days and drop other INVENLEVEL TABLES.
Expected Results, the following 2 tables deleted:
INVENLEVEL_20160419
INVENLEVEL_20160419_120232
Im able to drop for tables with date, but not the one with HHMMSS.
FOR x IN ( SELECT TABLE_NAME
FROM USER_TABLES
WHERE REGEXP_LIKE(TABLE_NAME, 'INVENLEVEL_[[:digit:]]{8}')
AND TO_DATE(SUBSTR(TABLE_NAME, -8), 'yyyymmdd') <= TRUNC(SYSDATE) - 7
) LOOP
EXECUTE IMMEDIATE 'DROP TABLE ' ||
x.TABLE_NAME ||
' PURGE';
How can i also drop for the table with HHMMSS also? Please note that tables with HHMMSS is optional to exist, means, sometimes we have it, sometime not.
Something like this, perhaps:
with sample_data as (select 'INVENLEVEL_20160419' table_name from dual union all
select 'INVENLEVEL_20160419_120232' table_name from dual union all
select 'INVENLEVEL_20160425' table_name from dual union all
select 'INVENLEVEL_20160426' table_name from dual union all
select 'INVENLEVEL_20160426_032112' table_name from dual union all
select 'NEW_20160426_032112' table_name from dual union all
select 'FRED' table_name from dual)
---- end of mimicking your data; see SQL below
select table_name,
to_date(substr(table_name, 12, 8), 'yyyymmdd') dt
from sample_data
where REGEXP_LIKE(TABLE_NAME, '^INVENLEVEL_[[:digit:]]{8}($|_[[:digit:]]{6})')
and to_date(substr(table_name, 12, 8), 'yyyymmdd') <= trunc(sysdate -7);
TABLE_NAME DT
-------------------------- ----------
INVENLEVEL_20160419 19/04/2016
INVENLEVEL_20160419_120232 19/04/2016
Obviously, you wouldn't need the sample_data subquery - I just used that in order to have data for the SQL to work against. You'd query your user_tables instead.
I amended your regexp to additionally check that it had either reached the end of the string after the 8 digits or there was another underscore followed by 6 digits.
Then I amended your substr to check for the 8 characters from the 12th position, in order to get the date - you have to do it like this, since if you use the end of the string as you had been doing, the date is not necessarily 8 characters from the end.
I have the following query which works fine.
SELECT A.*
FROM
(
SELECT 'ABC','DEF' FROM DUMMY
UNION ALL
SELECT col1,col2 FROM DUMMY
) A;
I want to apply the like key word on the first column returned by the nested query. I tried the following:
SELECT col1, col2
FROM
(
SELECT 'ABC','DEF' FROM DUMMY
UNION ALL
SELECT col1,col2 FROM DUMMY
) A
WHERE COL1 LIKE 'A%';
But the above query did not work. I'm getting the error: ORA-00904: "COL1": invalid identifier.
The fiddle link for the same is as follows: http://sqlfiddle.com/#!4/1c54b/7
Please could anybody guide me on how I can achieve the same?
Edit: I'm also trying to get the columns from the existing table as well.
Thanks in advance.
When using union, column names or aliases have to be matched on both tables.
You can call already defined column names and aliases.
Do not forget define column alias('ABC' as col1)
SELECT col1, col2
FROM
(
SELECT 'ABC' as col1,'DEF' as col2 FROM DUMMY
UNION ALL
SELECT 'GHI' as col1,'JKL' as col2 FROM DUMMY
) A
WHERE COL1 LIKE 'A%';
I think you are trying something like;
SELECT col1, col2
FROM
(
SELECT col1,col2 FROM DUMMY
UNION ALL
SELECT col1,col2 FROM DUMMY2
) A
WHERE col1 LIKE 'A%';
Have a look at another sample from me on here
I'm working in oracle 11g. I've a table with Number as the datatype. For development purpose we have created a staging table with varchar type. Initially data would be loaded in the staging table. We need find out the records that has only number in that column, since the data might contain the noises. Is there any way to find it.
You can select your data with a regexp_like :
SELECT *
FROM your_table t
WHERE REGEXP_LIKE (t.your_colonne, '^[0-9]+$');
The regexp_like function can be used to determine if a value consists of only digits. Here is an example:
with Your_table(your_column) as(
select '123456' from dual union all
select 'a123452' from dual union all
select '01456' from dual union all
select '1j6-d' from dual
)
select your_column
from your_table
where regexp_like(your_column, '^[[:digit:]]+$')
Result:
YOUR_COLUMN
--------------
123456
01456
SQL Fiddle Demo
Oracle:-
I have around 850 records in an table, that need to be assigned UUID.
I am using the following query.
select substr(sys_guid(),1,3)||'-'||
substr(sys_guid(),4,4)||'-'||
substr(sys_guid(),8,4)||'-'||
substr(sys_guid(),13)
from (select sys_guid() as mygid from dual)
I need to generate multiple/850 records in one go.
Any suggestions ?
Should I loop over?
If you really need select, use hierarchical query:
SELECT Substr(mygid,1,3)||'-'||
Substr(mygid,4,4)||'-'||
Substr(mygid,8,4)||'-'||
Substr(mygid,12)
FROM (
SELECT Sys_GUID() AS mygid FROM dual
CONNECT BY Level <= :desired_number_of_records
)
But what's wrong with usual update ?
UPDATE your_tab
SET gid_col = (
SELECT Substr(mygid,1,3)||'-'||
Substr(mygid,4,4)||'-'||
Substr(mygid,8,4)||'-'||
Substr(mygid,12)
FROM( SELECT Sys_Guid() AS mygid FROM dual )
)
Not sure that format is really what you want as you are missing 9 of the 32 characters, buy you could modify the format as needed. Here is an example that shows how to format like XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX:
UPDATE MY_TABLE
SET GUID_COL = (
select regexp_replace((rawtohex(sys_guid()), '([A-F0-9]{8})([A-F0-9]{4})([A-F0-9]{4})([A-F0-9]{4})([A-F0-9]{12})', '\1-\2-\3-\4-\5') as FORMATTED_GUID from dual
)