How to get chained data from hive query? - hadoop

I have tableA:
id colA colB(Chained)
1 11 17
2 22 41
3 44 42
4 82 43
5 17 13
6 20 85
7 26 90
8 13 19
9 19 82
I want result set of chained data like below from hive query:
id ChainedCol(from colA) colB
1 11 17
5 17 13
8 13 19
9 19 82
4 82 43


I used a common table expression and do a join to itself based on colA and colB. Then use union to remove duplicates.
with tmp as
( select a.id id_a, a.colA colA_a, a.colB colB_a, b.id id_b, b.colA colA_b, b.colB colB_b
from tbl a
join tbl b
on a.colA=b.colB
)
select id_b id,colA_b colA,colB_b colB
from tmp
union
select id_a,colA_a,colB_a
from tmp;

Related

ORACLE HOW TO GET DATA IN THIS FORMAT

I have a table structure like this in Oracle
Product_ID Product_SKU Product_Zone Product_Price
1 123 Zone1 10
2 123 Zone2 12
3 456 Zone1 13
4 456 Zone2 14
How I can get the result in horizontal format like this
Product_SKU Zone1_Price Zone2_Price
123 10 12
456 13 14
Thanks

Here's a simple, aggregation option:
SQL> with test (product_id, product_sku, product_zone, product_price) as
2 -- sample data
3 (select 1, 123, 'zone1', 10 from dual union all
4 select 2, 123, 'zone2', 12 from dual union all
5 select 3, 456, 'zone1', 13 from dual union all
6 select 4, 456, 'zone2', 14 from dual
7 )
8 select product_sku,
9 max(case when product_zone = 'zone1' then product_price end) zone1_price,
10 max(case when product_zone = 'zone2' then product_price end) zone2_price
11 from test
12 group by product_sku;
PRODUCT_SKU ZONE1_PRICE ZONE2_PRICE
----------- ----------- -----------
123 10 12
456 13 14
SQL>

Select rows with a column value that occurs at least two times and having different values in another column and finally order by updated time

I need to select a column which have same values with exactly three counts and having different values in another column and finally order by updated_time.
For this example below, I need to fetch only the value 15 from column1
column1 column2 updated_time
12 21 2019-01-05 01:36:50.995476
12 21 2018-04-05 01:36:50.995476
12 21 2019-02-05 01:36:50.995476
11 25 2019-03-05 01:36:50.995476
11 25 2019-02-05 01:36:50.995476
11 25 2019-04-04 01:36:50.995476
11 25 2019-05-05 01:36:50.995476
15 27 2019-01-05 01:36:50.995476
15 26 2019-01-05 01:36:50.995476
15 29 2019-02-05 01:36:50.995476
16 29 2019-04-03 01:36:50.995476
17 31 2019-04-03 01:36:50.995476

To get the values of column1 you must group by column1.
same values with exactly three counts
means count(*) = 3, and
having different values in another column
means count(distinct column2) = 3:
select * from tablename
where column1 in (
select column1
from tablename
group by column1
having
count(*) = 3
and
count(distinct column2) = 3
)
order by updated_time

complicated query in ms access 2013

I have two tables:
table1
emp empname mangr mangrname
1 emp1 3 emp3
2 emp2 3 emp3
3 emp3 6 emp6
4 emp4 5 emp5
5 emp5 7 emp7
table 2
emp mngr score
1 3 18
2 3 19
3 6 15
4 5 18
5 7 15
1 6 18
2 6 16
3 7 18
4 3 19
output will be
empname mangrname score_by_mangr mangr_of_mangr score_by_mangr_of_mangr avg_score_by_others
I have been trying using the below query, but its going no where!!!
SELECT UD.emp, UD.empname, UD.mangrname,
(SELECT score FROM TABLE2 WHERE mngr =(SELECT DISTINCT mangr FROM TABLE1 WHERE mangrname=UD.mangrname) ),
AVG(VAL(US.score))
FROM table2 US, table1 UD
WHERE US.EMP_ID=UD.EMP_ID
AND US.mangr=UD.mangr
GROUP BY UD.emp, UD.empname, UD.mangrname;

Fetching the max value from ROWS in pentaho

I have a table structure
ID Col_1 col_2 col_3 col_4
1 34 23 45 32
2 20 19 67 18
3 40 10 76 86
I here want the max value from col_1,col_,col_3,col_4 so my output looks like
ID Col_1 col_2 col_3 col_4 max
1 34 23 45 32 45
2 20 19 67 18 67
3 40 10 76 86 86
any help would be much appreciated.

Use a Modified Java Script Value step with the following code:
var max = Math.max(col_1,col_2,col_3,col_4);

You can use Memory Group By or Group By steps in Pentaho. Use the aggregation method as "Maximum" based on your grouping id.

How to get one query about sales set on default date?

I have two tables, T_TEST and T_DEFAULT_DATE. T_TEST contains date and amount, and T_DEFAULT_DATE contains just P_DATE.
First table T_TEST:
DATE AMOUNT
-------- ----------
01.01.99 77
16.02.99 59
01.01.00 12
15.01.00 32
01.02.00 144
15.02.00 320
16.02.00 521
01.03.00 98
15.03.00 76
16.03.00 33
01.01.01 65
15.01.01 78
01.02.01 95
15.02.01 39
16.02.01 97
02.02.02 63
07.03.02 75
And second table T_DEFAULT_DATE:
P_DATE
--------
16.02.01
What I want to get is two queries established in a single query :
1. what is the amount of sale achieved on the same day last year (- 12 mounths)
2. amount of sales for whole past year (based on table T_DEFAULT_DATE)
3. the amount (sum) for whole mounth (default mounth : 1.2. 2001 - 28.2.2001)
Expected output is :
P_SDLY P_LY P_MS
-----------
521 1236 231
I tryed with add_months(t_default_date.p_date, -12) , but I didn't get expected result. Please help

You can try something like this, assuming that your fields are stored in date columns.
SQL> with t_test(date_, amount) as
2 (
3 select to_date('01.01.99', 'dd.mm.rr'), 77 from dual union all
4 select to_date('16.02.99', 'dd.mm.rr'), 59 from dual union all
5 select to_date('01.01.00', 'dd.mm.rr'), 12 from dual union all
6 select to_date('15.01.00', 'dd.mm.rr'), 32 from dual union all
7 select to_date('01.02.00', 'dd.mm.rr'), 144 from dual union all
8 select to_date('15.02.00', 'dd.mm.rr'), 320 from dual union all
9 select to_date('16.02.00', 'dd.mm.rr'), 521 from dual union all
10 select to_date('01.03.00', 'dd.mm.rr'), 98 from dual union all
11 select to_date('15.03.00', 'dd.mm.rr'), 76 from dual union all
12 select to_date('16.03.00', 'dd.mm.rr'), 33 from dual union all
13 select to_date('01.01.01', 'dd.mm.rr'), 65 from dual union all
14 select to_date('15.01.01', 'dd.mm.rr'), 78 from dual union all
15 select to_date('01.02.01', 'dd.mm.rr'), 95 from dual union all
16 select to_date('15.02.01', 'dd.mm.rr'), 39 from dual union all
17 select to_date('16.02.01', 'dd.mm.rr'), 97 from dual union all
18 select to_date('02.02.02', 'dd.mm.rr'), 63 from dual union all
19 select to_date('07.03.02', 'dd.mm.rr'), 75 from dual
20 ),
21 t_default_date(p_date) as
22 (
23 select to_date('16.02.01', 'dd.mm.rr') from dual
24 )
25 select sum(
26 case
27 when date_ between add_months(trunc(p_date, 'yyyy'), -12)
28 and trunc(p_date, 'yyyy')-1
29 then amount
30 else 0
31 end
32 ) as year,
33 sum( decode (date_, add_months(p_date, -12), amount, 0) ) as day,
34 sum( case
35 when date_ between
36 trunc(p_date, 'MM') and
37 last_day(p_date)
38 then amount
39 else
40 0
41 end
42 ) as month
43 from t_test
44 inner join t_default_date on (date_ between add_months(trunc(p_date, 'yyyy'), -12) and last_day(p_date) );
YEAR DAY MONTH
---------- ---------- ----------
1236 521 231
SQL>
This makes use of add_months to get exactly "one year ago"; if you need "365 days ago" (think of leap years), consider using something like date - 365

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