How to get one query about sales set on default date? - oracle

Question

I have two tables, T_TEST and T_DEFAULT_DATE. T_TEST contains date and amount, and T_DEFAULT_DATE contains just P_DATE.
First table T_TEST:
DATE AMOUNT
-------- ----------
01.01.99 77
16.02.99 59
01.01.00 12
15.01.00 32
01.02.00 144
15.02.00 320
16.02.00 521
01.03.00 98
15.03.00 76
16.03.00 33
01.01.01 65
15.01.01 78
01.02.01 95
15.02.01 39
16.02.01 97
02.02.02 63
07.03.02 75
And second table T_DEFAULT_DATE:
P_DATE
--------
16.02.01
What I want to get is two queries established in a single query :
1. what is the amount of sale achieved on the same day last year (- 12 mounths)
2. amount of sales for whole past year (based on table T_DEFAULT_DATE)
3. the amount (sum) for whole mounth (default mounth : 1.2. 2001 - 28.2.2001)
Expected output is :
P_SDLY P_LY P_MS
-----------
521 1236 231
I tryed with add_months(t_default_date.p_date, -12) , but I didn't get expected result. Please help

Answer 1

You can try something like this, assuming that your fields are stored in date columns.
SQL> with t_test(date_, amount) as
2 (
3 select to_date('01.01.99', 'dd.mm.rr'), 77 from dual union all
4 select to_date('16.02.99', 'dd.mm.rr'), 59 from dual union all
5 select to_date('01.01.00', 'dd.mm.rr'), 12 from dual union all
6 select to_date('15.01.00', 'dd.mm.rr'), 32 from dual union all
7 select to_date('01.02.00', 'dd.mm.rr'), 144 from dual union all
8 select to_date('15.02.00', 'dd.mm.rr'), 320 from dual union all
9 select to_date('16.02.00', 'dd.mm.rr'), 521 from dual union all
10 select to_date('01.03.00', 'dd.mm.rr'), 98 from dual union all
11 select to_date('15.03.00', 'dd.mm.rr'), 76 from dual union all
12 select to_date('16.03.00', 'dd.mm.rr'), 33 from dual union all
13 select to_date('01.01.01', 'dd.mm.rr'), 65 from dual union all
14 select to_date('15.01.01', 'dd.mm.rr'), 78 from dual union all
15 select to_date('01.02.01', 'dd.mm.rr'), 95 from dual union all
16 select to_date('15.02.01', 'dd.mm.rr'), 39 from dual union all
17 select to_date('16.02.01', 'dd.mm.rr'), 97 from dual union all
18 select to_date('02.02.02', 'dd.mm.rr'), 63 from dual union all
19 select to_date('07.03.02', 'dd.mm.rr'), 75 from dual
20 ),
21 t_default_date(p_date) as
22 (
23 select to_date('16.02.01', 'dd.mm.rr') from dual
24 )
25 select sum(
26 case
27 when date_ between add_months(trunc(p_date, 'yyyy'), -12)
28 and trunc(p_date, 'yyyy')-1
29 then amount
30 else 0
31 end
32 ) as year,
33 sum( decode (date_, add_months(p_date, -12), amount, 0) ) as day,
34 sum( case
35 when date_ between
36 trunc(p_date, 'MM') and
37 last_day(p_date)
38 then amount
39 else
40 0
41 end
42 ) as month
43 from t_test
44 inner join t_default_date on (date_ between add_months(trunc(p_date, 'yyyy'), -12) and last_day(p_date) );
YEAR DAY MONTH
---------- ---------- ----------
1236 521 231
SQL>
This makes use of add_months to get exactly "one year ago"; if you need "365 days ago" (think of leap years), consider using something like date - 365