I will have a table that is full of information that involves other tables (relations). Most of the information in this table will only have the ID's of the referencing related table. If I were to use "products" as an example for this table it may look like this for some of the columns:
id | name | type_id | price_id | location_id | sale_id
----------------------------------------------------------------
1 | prod1 | 1 | 1 | 2 | 4
2 | prod2 | 2 | 1 | 1 | 1
3 | prod3 | 3 | 2 | 6 | 2
4 | prod4 | 1 | 2 | 3 | 4
I'm trying to take this "products" table and dump it out into a list. I would need to look up all of the items in these columns as I dump it out (the relation). I know how to do belongsToMany and hasMany, but I'm not sure how I can do this in one shot with an Eloquent model if I have a "products" model? Should I just make the products table just a pivot table? Can I do it with an Eloquent model or should I use query builder directly? I think if I were to use withPivot it would return the extra columns but the raw ID value from the column. I would need the value lookup from their respective table (the relation).
Tried something like this:
public function productItems(){
return $this->belongsToMany(Product::class)->withPivot(["type_id","price_id",...]);
}
As suggested by #BagusTesa, you should eager load your relations:
$products = Product::with(['type', 'price', 'location'])->get();
That will query for the related models allowing you to access them as model properties:
foreach ($products as $product){
// $product->type;
// $product->price;
// $product->location;
}
Related
I am using laravel eloquent to get the query results. I have two tables below:
users table:
| id | department_id
| 1 | 1
| 2 | 3
| 3 | 2
department table:
| id | name
| 1 | A
| 2 | B
| 3 | C
| 4 | D
| 5 | E
How to get one unassigned ID, not existing department ID, into the users table? Example, 4 & 5 are not yet existing in users table, so how can I get 4 or 5 using an eloquent?
I am thinking of this but this is not correct.
Department::select('department.id as id')
->leftJoin('users', 'users.department_id' ,'department.id')
->pluck('id');
Does anybody know?
Try this
//here you first got all the department which is assigned to user
$assigned_dept = Users::pluck('department_id')->toArray();
$department = array_values($assigned_dept); //output:['1','3','2']
//here you can select department which is not assigned to user with limit
$user = Department::whereNotIn('id',$department)
->limit(1)->get();
hope it works for you..
You can do it like this:
Department::whereNotIn('id', User::pluck('department_id'))->get();
I believe below code will work for you :
Department::select('department.id as id')
->whereNotIn('id', User::whereNotNull('department_id')->pluck('department_id'))
->pluck('id');
From the answers others, there is a problem with the array if department_id is NULL. So, I added whereNotNull and also last() and then the problem is solved. Let me post the answer here:
Department::select('department.id as id')
->whereNotIn('id', User::whereNotNull('department_id')->pluck('department_id'))
->pluck('id')
->last(); // since I only need one row
I have a polymorphic "Relationships" many to many relation that looks like that:
users
id | first_name | last_name
groups
id | group_name
regions
id | region_name
relationships
id | user_id | relationship_id | relationship_type | relationship_level
4 | 13 | 25 | App\Group | Group Manager
5 | 20 | 18 | App\Region | Participant
And the relationship looks like that:
public function regions()
{
return $this->morphedByMany('App\Region', 'relationship')->withPivot('relationship_level')->withTimestamps();
}
public function groups()
{
return $this->morphedByMany('App\Group', 'relationship')->withPivot('relationship_level')->withTimestamps();
}
And vice versa.
When I have an array of IDs, I want to select the relationships that exactly match between the users, this means that all columns (except user_id) match.
And they should only be rows that match among all users. If only 10 out of 12 selected users have the same relationship it should not be included.
If I select 10 users I need to select a pivot record that all those 10 users have (if any).
It doesn't matter if done in eloquent or via the collection after fetching from Database.
I have the following tables:
parts:
id | name
1 | Lock
2 | Light
shelves:
id | name
1 | 1A
2 | 1B
part_shelf
id | part_id | shelf_id | stock
1 | 1 | 1 | 5
2 | 1 | 2 | 10
3 | 2 | 1 | 4
The relations:
In Part model:
public function shelves()
{
return $this->belongsToMany( Shelf::class )->withPivot( 'stock' );
}
In shelf model:
public function parts()
{
return $this->belongsToMany(Part::class)->withPivot('stock');
}
What I would like to do is order all the parts based on the total stock of the pivot table.
What I have tried is the following:
$parts = Part::all(); // This is inside controller
#foreach($parts->shelves()->orderBy('pivot_stock', 'desc') as $part)
#foreach($parts->shelves()->orderBy('part_shelf.stock', 'desc') as $part)
I do know that I can get the total stock for individual parts with:
$part->shelves()->sum('stock')
I just don't know how to approach it for all parts in the foreach-loop.
Also looked at other questions but that didn't really help:
How to order by pivot table data in Laravel's Eloquent ORM
Order by pivot table created_at in Laravel
Laravel 5.4 Eloquent SUM and ORDER BY pivot table column I think is the closest to what I'm looking for
I had similar problem. I had three tables. Players (in my code "Igrac"), tournaments(in my code "Turnir_Piramida"), and players_tournaments pivot table(in my code "Nastup_piramida"). In pivot table was also column point for points for each player in each tournament. And i needed to summarize points from each player and then sort table by sum of points.
I manage to do that with third link you posted. You can see my solution on this link
Background - I'm creating a system where administrators can create arbitrary fields, which are then combined into a form. Users then complete this form, and the values input against each field are stored in a table. However, rather than overwrite the previous value, I plan on keeping each past value as individual rows in the table. I then want to be able to display the contents submitted in each form, but only the most recently submitted value.
Problem
I have a model, Service, that features a belongsToMany relationship with another model, Field. This relationship is defined as:
public function fields()
{
return $this->belongsToMany('App\Field')->withPivot('id', 'value', 'date')->withTimestamps();
}
The intermediary table has 3 values I wish to retrieve, id, value and date.
A Service may have 1 or more Fields, and for each field it may also have more than 1 pivot row. That is, a single Service/Field pairing may have multiple entries in the pivot table with different pivot values. For example:
Table field_service
id | service_id | field_id | value | created_at
------------------------------------------------------
1 | 1 | 1 | lorem | 2018-02-01
2 | 1 | 1 | ipsum | 2018-01-01
3 | 1 | 1 | dolor | 2017-12-01
4 | 1 | 2 | est | 2018-03-10
5 | 1 | 2 | sicum | 2018-03-09
6 | 1 | 2 | hoci | 2018-03-08
What I want is to get either:
A specific row from the pivot table for each Field associated with the Service, or
A specific value from the pivot table for each Field associated with the Service.
For example - in the table above, I would like the Service with ID 1 to have 2 Fields in the relationship, with each Field containing an attribute for the corresponding pivot value. The Fields attached would be specified by the corresponding pivot table entry having the most recent date. Something akin to:
$service->fields()[0]->value = "lorem"
$service->fields()[1]->value = "est"
I feel there's an obvious, 'Laravel'ly solution out there, but it eludes me...
Update
Somewhat unbelievably this is another case of me not understanding windowing functions. I asked a question 7 years ago that is basically this exactly problem, but with raw MySQL. The following raw MySQL basically gives me what I want, I just don't know how to Laravelise it:
SELECT services.name, fields.name, field_service.value, field_service.created_at, field_service.field_id
FROM field_service
INNER JOIN
(SELECT field_id, max(created_at) as ts
FROM field_service
WHERE service_id = X
GROUP BY field_id) maxt
ON (field_service.field_id = maxt.field_id and field_service.created_at = maxt.ts)
JOIN fields ON fields.id = field_service.field_id
JOIN services ON services.id = field_service.service_id
Try this:
public function fields()
{
$join = DB::table('field_service')
->select('field_id')->selectRaw('max(`created_at`) as `ts`')
->where('service_id', DB::raw($this->id))->groupBy('field_id');
$sql = '(' . $join->toSql() . ') `maxt`';
return $this->belongsToMany(Field::class)->withPivot('id', 'value', 'created_at')
->join(DB::raw($sql), function($join) {
$join->on('field_service.field_id', '=', 'maxt.field_id')
->on('field_service.created_at', '=', 'maxt.ts');
});
}
Then use it like this:
$service->fields[0]->pivot->value // "lorem"
$service->fields[1]->pivot->value // "est"
There a able, called 'interests' which hold the id(s) of 'categories' and/or 'brands' that each user has interest in.
To prevent creating two separate tables for user_category_interests and user_brand_interest I added an enum column called type.
Now I can't figure out how should I create a migration in Schema Builder, How to set relations and foreign keys,... to take advantage of using Eloquent methods.
Schema::create('user_interests', function (Blueprint $table) {
$table->increments('id');
$table->enum('type', ['categories', 'brands']);
$table->integer('reference_id')->unsigned();
$table->timestamps();
});
Is there any better way instead of creating two separate tables and models?
P.S. I use laravel 5.4
Brands Table:
id | name
-----------
1 | Adidas
2 | Nike
3 | Puma
Categories Table:
id | name
-----------
1 | Clothes
2 | Luxury
3 | Sport Wear
User_Interests Table:
id | user_id | type | reference_id
-----------------------------------------
1 | 113 | 'brand' | 2
1 | 113 | 'brand' | 3
2 | 113 |'category'| 3
3 | 224 | 'brand' | 1
Yes - read the docs on polymorphic relations.
It works similar to what you have, but you might have columns called interestable_id and interestable_type (you can configure this to something else if you prefer). The interestable_type will literally be the string representation of the referenced class name, like App\Brand or App\Category and interestable_id will be the primary key of that model.
Best part is as it's all done through Eloquent it's already good to go with associations, eager-loading etc.
Edit: I should add that your 3 table setup is still the best way to represent this structure, just making suggestions on the column names you use and how to hook it in with Eloquent.