$this->db->replace() using where - codeigniter

I'm trying to find something along the lines of insert_or_update (similar to what Laravel offers) in CodeIgniter 3. The closest I have found is $this->db->replace(), but I can't find anything that specifies that it can/can't be used alongside a ->where(). Based on the docs I don't believe this will work since it doesn't list ->where() as an option, but I wanted to double check this as well.
I'm hoping I can do something like...
$data = [...];
$whereSearch = [...];
$this->db->replace($data)->where($whereSearch);

The key here to quote the documentation is
using PRIMARY and UNIQUE keys as the determining factor.
Replace only works based on your keys to replace the values in a table. You might find Does replace into have a where clause? helpful as well.

$this->db->where('column_name',$compared_data);
$this->db->set('column_name',$updated_data);
$this->db->update('table_name');
Would this be what you're looking for?

Related

How to search for a substring (WHERE column LIKE '%foo%')

I'm reading parse API documentation at https://parse.com/docs/rest/guide#queries and can't find how to search by a substring. SQL equivalent would be:
... WHERE column_name LIKE "%foo%"
There's a bunch of options such as &gt, &lt, &in, and similar, but there's no option for LIKE. It's pretty common use case... What am I missing?
We've found something that looks like an undocumented feature.
There's a $regex lookup it's not mentioned in the official API reference. It allows for matching by regular expressions which solved the problem for us.
We believe it should be documented here:
https://parse.com/docs/rest/guide/#queries-query-constraints
But apparently it isn't.
In your case, I think you should follow Parse's tutorial here: http://blog.parse.com/learn/engineering/implementing-scalable-search-on-a-nosql-backend/
It is very helpful in terms of search. The main ideas are:
Separate the texts into single words and store as in array
Then perform search on the new field using containedIn(or $in as in REST API) query.
There's also a question regarding this too: How to make a "like" query in Parse.com
EDIT: New blog link: https://web.archive.org/web/20150416171914/http://blog.parse.com/2013/03/19/implementing-scalable-search-on-a-nosql-backend/

Is it possible to get items from DynamoDB where the primary key ends with a given string?

Is it possible, using the AWS Ruby SDK (or just DynamoDB in general), to get an item or items from a table that uses a primary key only, and where that primary key ends with a certain string?
I haven't come across anything in the docs that explicitly answers this question, either in the ruby ddb docs or the general docs for ddb. I'm not saying the question is not answered, but if it is, I can't find it.
If it is possible, could someone provide an example for ruby or link to the docs where an example exists?
Although #Ryan is correct and this can be done with query, just bear in mind that you're doing a "full-table-scan" here. That might be OK for a one-time job but probably not the best practice for a routine task (and of course not as a part of your API calls).
If your use-case involves quickly finding objects based on their suffix in a specific field, consider extracting this suffix (assuming it's a fixed-size suffix) as another field and have a secondary index on that one. If you want to query arbitrary length suffixes, I would create a lookup table and update it with possible suffixes (or some of them, to save some calls, and then filter when querying).
It looks like you would want to use the Query method on the SDK to find the items your looking for. It seems that "EndsWith" is not available as a comparison operator in the SDK though. So you would need to use CONTAINS and then check your results locally.
This should lead to the best performance, letting DynamoDb do the initial heavy lifting and then further pruning the results once you receive them.
http://docs.aws.amazon.com/sdkforruby/api/Aws/DynamoDB/Client.html#query-instance_method

Path to dynamic object?

I have a system_settings table which has a key and value columns. The key looks something like general.site.something.config and the value is a simple string.
I'd like to have a static class which, upon initialization, reads the settings and caches the values. Furthermore, I'd like to be able to access the settings in an OO way, such as SystemSetting.CACHE.General.Site.Something.Config in order to pull back the value for that key. Basically turning the rows in the table into a tree.
Is there an easy way to do this in Ruby 1.8.7?
TL;DR, No. No easy (read 'built-in') way atleast.
The syntax you want is not the way things happen in Ruby (without over-plumbing, that is). To have a look at the over-plumbing I'm referring to, have a look at the code I wrote for this example that demonstrates some of the desired functionality you want. I wouldn't suggest using it though and that's the same reason I'm not posting it here.

How to uniquly identify an two objects in same page having same url

I Have two objects in same page but with different locations(tabs), I want to verify those objects each a part ...
i cant uniquely any of objects because the have same properties.
These objects clearly are unique to a point because they have completely different text, this means that you will be able to create an object to match only one of them. My suggestion would be to look for the object by using its text property, one of them will always have "Top Ranking" the other you wil need to turn into a regular expression for the text and will be something "Participants (\d+)".
I am assuming that this next answer is unlikely to be possible so saved it for after the answer you are likely to use but the best solution would of course be to get someone with access to give these elements ids for you to search for. This will in the long term be much easier for you to maintain and not using text will allow this test to run in any language.
Manaysah, do these objects have different indexes? Use the object spy and determine which index they have, the ordinal identifier index may be a solution to your problem. You could also try adding an innertext object property if possible, using a wildcard for the number inside the () as it appears dynamic.
try using xpath for the objects...xpath will definitely be different

MongoDB find and remove - the fastest way

I have a quick question, what is the fast way to grab and delete an object from a mongo collection. Here is the code, I have currently:
$cursor = $coll->find()->sort(array('created' => 1))->limit(1);
$obj = $cursor->getNext();
$coll->remove(array('name' => $obj['name']));
as you can see above it grabs one document from the database and deletes it (so it isn't processed again). However fast this may be, I need it to perform faster. The challenge is that we have multiple processes doing this and processing what they have found BUT sometimes two or more of the processes grab the same document therefore making duplicates. Basically I need to make it so a document can only be grabbed once. So any ideas would be much appreciated.
Peter,
It's hard to say what the best solution is here without understanding all the context - but one approach which you could use is findAndModify. This will query for a single document and return it, and also apply an update to it.
You could use this to find a document to process and simultaneously modify a "status" field to mark it as being processed, so that other workers can recognize it as such and ignore it.
There is an example here that may be useful:
http://docs.mongodb.org/manual/reference/command/findAndModify/
Use the findAndRemove function as documented here:
http://api.mongodb.org/java/current/com/mongodb/DBCollection.html
The findAndRemove function retrieve and object from the mongo database and delete it in a single (atomic) operation.
findAndRemove(query, sort[, options], callback)
The query object is used to retrieve the object from the database (see collection.find())
The sort parameter is used to sort the results (in case many where found)
I make a new answer to remark the fact:
As commented by #peterscodeproblems in the accepted answer. The native way to this in mongodb right now is to use the
findAndModify(query=<document>, remove=True)
As pointed out by the documentation.
As it is native, and atomic, I expect this to be the faster way to do this.
I am new to mongodb and not entirely sure what your query is trying to do, but here is how I would do it
# suppose database is staging
# suppose collection is data
use staging
db.data.remove(<your_query_criteria>)
where is a map and can contain any search criteria you want
Not sure if this would help you.

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