I have an query, where it returns 1 or more results. After this query, I execute a delete on these tuples.
I think it's my coding failure, but what I'm trying to do is get this select and send it by ID parameter to Delete.
public function TestDelet(AcademicoRequest $request)
{
$academico = new Academico();
$res = $request->all();
$academico->member_id = $res->member_id;
if($res->member_id){
$dados_academicos[] = DB::table('academicos')->where('member_id', $res->member_id)->orderby('id')->get();
$this-> destroy($dados_academicos->Id);
}
}
List I try on postman:
{
"member_id": "1",
}
But, return this is error: Trying to get property of non-object
Hope these suggestions help:
$request->all();
the all() method is returning array format, so you need to change from
$res->member_id
into
$res['member_id']
I'm assuming you are trying to delete one/many rows from database at academicos table
if($res['member_id']){
Academico::where('member_id', $res['member_id'])->delete();
}
Please check values of object array:
dd($dados_academicos)
If you are using laravel with mysql by default it is id not Id and with mongodb it is _id. so use
$this-> destroy($dados_academicos->id);
OR
$this-> destroy($dados_academicos->_id);
OR
$this-> destroy($dados_academicos['Id']);
Related
I am trying to reduce the number of SQL queries executed. I have a post where I want to get the author of that post and list it on the page. To reduce the number of SQL queries, I have the following code:
$posts = Post:all();
$posts->load('user');
$posts->first()->user;
I get the error/notice "Trying to get property 'user' of a non-object". How do I get rid of this error?
Eager loading reduces this operation to just 2 queries
public function example()
{
$posts = Posts::with('user')->get();
foreach ($posts as $post) {
echo $post->user->name;
}
}
The error can be there because of the Post (or the first post) you are trying to access is not related to any of the users. You can try this to avoid the error.
$posts = Post:all();
$posts->load('user');
// Try any one of below.
1) $posts->first()->user ?? '';
2) $posts->first()->user or ''; // in Laravel 5.5 or below
My controller method like below
public function index($book_id) {
print_r($book_id);
}
I will get the id from view. View like below
I need to get specific row according id on model how can I do that if I use query in controller its not working
If I use like below in controller it gives something else as result
public function index($book_id) {
print_r($book_id);
$this->db->select('*');
$this->db->from('books')->where('book_id', $book_id);
$query = $this->db->get();
print_r($query);
}
but if I use same query in model with hard coded id for testing it gives the expected out put
Please help me with this
You don't need to include "/index" in anchor tag href as controller default method will be index if found. And "print_r($book_id)" should be "echo $book_id" as $book_id is variable not array.
Please try this code (either in model/controller):
$query = $this->db->get_where('books', array('book_id' => $book_id));
$result = $query->row_array();
print_r($result);
i want to display data from my database
controller
public function generatePDF(Request $request)
{
$id = Auth::user()->id;
$name = User::select("NAME")->where("id", $id)->get();
$pdf = PDF::loadView('generatePDF', ['name'=>$name]);
return $pdf->stream('generatePDF.pdf');
}
blade
<h2>{{name}}</h2>
result
[{"NAME":"name_from_database"}]
can i display without [{"name":}], so just the value of data (name_from_database) ?
Simple use find like this
$name = User::find($id)->name;
Or direct from auth
$name = \Auth::user()->name;
To get logged in user id you can use \Auth::id()
you can use:
$user_id = User::findOrFail($id)->first();
$name=$user_id->name;
test the laravel log file:
\Log::info($name);
Use first() instead of get(), because get() will return an array and first() will return the object.
DRY Code line no.1 and no.2. simple use:
$name = auth()->user()->name;
to get the name of the currently authenticated user.
Send $name to you view is fine
$pdf = PDF::loadView('generatePDF', ['name' => $name]);
Correct your code in blade file
{{ name }} -> {{ $name }}
I hope this might help you. :)
Hello Aldi Rostiawan,
$nameGet = User::select("NAME")->where("id", $id)->get();
$nameFirst = User::select("NAME")->where("id", $id)->first();
Here in both line of code the difference is only Get and First.
Get method returns an Array of objects. So for example if the query apply on many records then the code will give you many objects in an array. Or if query will be true for only one record then also it will return an array with one object.
If you know that id is primary key of he table then only one record will be fetched then you can use First function instead if Get method.
First function always return an Object. In case if query apply on many records then also first method will return you only first record as an Object.
And it seems that you have required an Object only.
You should try this:
Controller
public function generatePDF(Request $request)
{
$id = Auth::user()->id;
$rsltUser = User::where("id", $id)->first();
$pdf = PDF::loadView('generatePDF', ['rsltUser'=>$rsltUser]);
return $pdf->stream('generatePDF.pdf');
}
blade
<h2>{{$rsltUser->name}}</h2>
use VALUE() to display name only.
in your case:
<h2>{{$rsltUser->value('name')}}</h2>
your name variable is an array containing a single object with a NAME attribute .. so to diplay that value, you should change your script to
<h2>{{name[0]['NAME']}}</h2>
I'm trying to build an app in Laravel 5.3, I want to add additional column data in the pivot table. Following is my code:
My Users model:
public function relations()
{
return $this->belongsToMany('App\Plan')->withPivot('child');
}
My Plan model:
public function relations()
{
return $this->belongsToMany('App\User')->withPivot('child');
}
In my controller I'm fetching the user data from Auth::user(); and for plans and child element I'm getting through request. I want to store this to my pivot table. Following is the code which I tried in my controller:
$user = \Auth::user();
$plan_id = $request->plan_id;
$childid = $request->child_id;
$plan = App\Plan::find($plan_id);
$user->relations()->attach($plan, ['child' => $childid]);
Help me out in this.
You should use attach() like this:
$user->relations()->attach($plan_id, ['child' => $childid]);
Try the save method as:
$user->relations()->save($plan, ['child' => $childid]);
Docs
Both save and attach work. Just that attach will return null while save will return $user object when I try with tinker
simple issue I presume.
My controller is getting the if to display from the url using $this->uri->segment(3). This will always be a single value. I am putting this in an array to pass to the model with:
$customerid = array(
'id' => $this->uri->segment(3)
);
The controller syntax is below:
function confirm_delete_customer()
{
$data['title']="Confirm Customer Deletion";
$customerid=array(
'id'=>$this->uri->segment(3)
);
//query model to get data results for form
$data=array();
if($query=$this->model_master_data->get_customer_records_to_delete()){
$data['records']=$query;
$this->load->view("master_data/view_master_data_header",$data);
$this->load->view("master_data/view_master_data_nav");
$this->load->view("master_data/view_content_master_data_confirm_customer_deletion",$data);
$this->load->view("master_data/view_master_data_footer");
}
I am then trying to access this array value and pass it to my model to process. If I hard code the array into the model it works as per below syntax:
Model - Manual Syntax is:
function get_customer_records_to_delete()
{
$query = $this->db->get_where('customers', array('id'=>43));
return $query->result();
}
if I try replace this with the array from my controller it fails with error:
Undefined variable: customerid
idea of model that I want to get working:
function get_customer_records_to_delete()
{
$query = $this->db->get_where('customers', $customerid);
return $query->result();
}
I have a feeling it is something small. however is this the best way to get a single record from the database in order to output to a view?
Thanks in advance for the assistance.
The best way to do that is:
function confirm_delete_customer()
{
$data=array();
$data['title']="Confirm Customer Deletion";
$customerId = $this->uri->segment(3);
//Prevent SQL injections
if(!is_numeric($customerId) || empty($customerId)) {
show_error("Bad Request");
}
$query = $this->model_master_data->get_customer_records_to_delete($customerId);
if ($query){
$data['records']=$query;
$this->load->view("master_data/view_master_data_header",$data);
$this->load->view("master_data/view_master_data_nav");
$this->load->view("master_data/view_content_master_data_confirm_customer_deletion",$data);
$this->load->view("master_data/view_master_data_footer");
}
}
and then you can simply call:
function get_customer_records_to_delete($customerId)
{
$query = $this->db->get_where('customers', array('id'=>$customerId));
return $query->result();
}
at your model.
You need to pass the value as an argument to the function so it can access it.
Ex:
get_customer_records_to_delete($customerid)
{
// now $customerid is accessible
$query = ....;
return $……;
}
You should heavily rely on function parameters. Grab the customer id from the controller and send it to the model. Moreover, you can use row() to get a single result from the database.
Controller:
function confirm_delete_customer(){
$data['title']="Confirm Customer Deletion";
$customerid=$this->uri->segment(3);
//query model to get data results for form
$data=array();
if($query=$this->model_master_data->get_customer_records_to_delete( $customerid)) //you are sending customer id as a parameter here
$data['records']=$query;
$this->load->view("master_data/view_master_data_header",$data);
$this->load->view("master_data/view_master_data_nav");
$this->load->view("master_data/view_content_master_data_confirm_customer_deletion",$data);
$this->load->view("master_data/view_master_data_footer");
}}
Model
function get_customer_records_to_delete($customerid)
{
$query = $this->db->get_where('customers', array("id"=>$customerid)); //you are using the customer id sent from the controller here
return $query->row(); //this will return a single row
}
Old thread but the answer is to declare the variable as "public" in the controller (i.e. public $customerid;), in which case it'll be available to your model. In some cases it's probably safer to explicitly pass as an argument. However, when you have several variables, it's useful to have the option to declare them instead.