Pass specific id to model and take data from database using codeigniter? - codeigniter

My controller method like below
public function index($book_id) {
print_r($book_id);
}
I will get the id from view. View like below
I need to get specific row according id on model how can I do that if I use query in controller its not working
If I use like below in controller it gives something else as result
public function index($book_id) {
print_r($book_id);
$this->db->select('*');
$this->db->from('books')->where('book_id', $book_id);
$query = $this->db->get();
print_r($query);
}
but if I use same query in model with hard coded id for testing it gives the expected out put
Please help me with this

You don't need to include "/index" in anchor tag href as controller default method will be index if found. And "print_r($book_id)" should be "echo $book_id" as $book_id is variable not array.
Please try this code (either in model/controller):
$query = $this->db->get_where('books', array('book_id' => $book_id));
$result = $query->row_array();
print_r($result);

Related

Variable inside laravel query builder is always null

Im trying to find the users that has commented the product this way:
public function getUserToRate(Product $product)
{
$userIds = DB::table('product_ratings')->where('product_id', $product->id)->pluck('user_id');
return $userIds;
}
But the thing is that $product->id is null. This is what comes out if I do:
DB::table('product_ratings')->where('product_id', $product->id)->toSql():
select * from `product_ratings` where `product_id` = ?
Why is my $product->id null? I have checked and the model exists, but I cant seem to use it inside the query builder.
Can anyone lend me a hand? Thanks
I don't think you need a product model. So ignore Route Model binding like Product $product. Instead you can use your $oroductId. And query the UserIds like this:
public function getUserToRate( $productId)
{
$userIds = ProductRating::where('product_id', $productId)->pluck('user_id');
return $userIds;
}

Looking up model in Laravel after returning array of objects in Controller

I am trying to do something I've never done before in Laravel and cannot figure out how to do it.
I have the following code in my Controller:
public function show($id)
{
//Get application for drug
$application = PharmaApplication::where('ApplNo', $id)->first();
//Get all products for given application (i.e. the different quantities and forms drug comes in)
$product = PharmaProduct::where('ApplNo', $id)->get();
foreach($product as $product){
$product->ProductNo;
}
//Get Marketing Status for drug
$marketingStatus = DB::table('pharma_marketing_statuses')
->where('ApplNo', $id)
->where('ProductNo', $product->ProductNo)
->get();
//Lookup marketing status Description
$marketingStatusDescription = PharmaMarketingSatusLookup::where('MarketingStatusID', $marketingStatus->MarketingStatusID);
return view('profiles.drug', compact('application', 'product', 'marketingStatus', 'marketingStatusDescription'));
}
I am trying to accomplish the following:
Get the application for a drug - this part of my code works
Return an array of objects for the products (i.e. 7 products that belong to one application). I can do this but get stuck going to the next part.
Next, I have to use the array of objects and search a table with the following columns: MarketingStatusID, ApplNo, ProductNo. I know how to query this table and get one row, but the problem is I have an array that I need to search. I imagine I have to use a loop but don't know where.
Finally, I use the MarketingStatusID to retrieve the MarketingStatusDescription which I will know how to do.
I am also getting an error message that says:
Class 'App\Http\Controllers\profiles\PharmaMarketingSatusLookup' not found
In my Controller, I have use App\PharmaMarketingStatusLookup; so I am not sure why it is searching the Controllers folder
You have a typo in your class
From PharmaMarketingSatusLookup change to PharmaMarketingStatusLookup
App\Http\Controllers\profiles\PharmaMarketingStatusLookup
USE whereIn
use App\PharmaApplication;
use App\PharmaProduct;
use App\PharmaMarketingSatusLookup;
public function show($id)
{
$application = PharmaApplication::where('ApplNo', $id)->first();
$products = PharmaProduct::where('ApplNo', $id)->get();
$productid = array();
foreach($products as $product){
$productid[] = $product->ProductNo;
}
$marketingStatus = DB::table('pharma_marketing_statuses')
->where('ApplNo', $id)
->whereIn('ProductNo', $productid)
->get();
$marketingStatusDescription = PharmaMarketingSatusLookup::where('MarketingStatusID', $marketingStatus->MarketingStatusID);
return view('profiles.drug', compact('application', 'product', 'marketingStatus', 'marketingStatusDescription'));
}

how to display name from database in laravel

i want to display data from my database
controller
public function generatePDF(Request $request)
{
$id = Auth::user()->id;
$name = User::select("NAME")->where("id", $id)->get();
$pdf = PDF::loadView('generatePDF', ['name'=>$name]);
return $pdf->stream('generatePDF.pdf');
}
blade
<h2>{{name}}</h2>
result
[{"NAME":"name_from_database"}]
can i display without [{"name":}], so just the value of data (name_from_database) ?
Simple use find like this
$name = User::find($id)->name;
Or direct from auth
$name = \Auth::user()->name;
To get logged in user id you can use \Auth::id()
you can use:
$user_id = User::findOrFail($id)->first();
$name=$user_id->name;
test the laravel log file:
\Log::info($name);
Use first() instead of get(), because get() will return an array and first() will return the object.
DRY Code line no.1 and no.2. simple use:
$name = auth()->user()->name;
to get the name of the currently authenticated user.
Send $name to you view is fine
$pdf = PDF::loadView('generatePDF', ['name' => $name]);
Correct your code in blade file
{{ name }} -> {{ $name }}
I hope this might help you. :)
Hello Aldi Rostiawan,
$nameGet = User::select("NAME")->where("id", $id)->get();
$nameFirst = User::select("NAME")->where("id", $id)->first();
Here in both line of code the difference is only Get and First.
Get method returns an Array of objects. So for example if the query apply on many records then the code will give you many objects in an array. Or if query will be true for only one record then also it will return an array with one object.
If you know that id is primary key of he table then only one record will be fetched then you can use First function instead if Get method.
First function always return an Object. In case if query apply on many records then also first method will return you only first record as an Object.
And it seems that you have required an Object only.
You should try this:
Controller
public function generatePDF(Request $request)
{
$id = Auth::user()->id;
$rsltUser = User::where("id", $id)->first();
$pdf = PDF::loadView('generatePDF', ['rsltUser'=>$rsltUser]);
return $pdf->stream('generatePDF.pdf');
}
blade
<h2>{{$rsltUser->name}}</h2>
use VALUE() to display name only.
in your case:
<h2>{{$rsltUser->value('name')}}</h2>
your name variable is an array containing a single object with a NAME attribute .. so to diplay that value, you should change your script to
<h2>{{name[0]['NAME']}}</h2>

Getting ID from url and using it in CRUD controller laravel

I need to add orders to existing customers. From my customers.show view I use the following to visit the order form.
href="{{action('OrderController#create', $customer['id'])}}
The link of the page looks like:
/orders/create?2f10f8a0-30b9-11e8-8711-dd477b141226
I've been using the following route::get to no avail to be able to use this ID in my resource controller for Orders
Route::get('orders/create/{id}', 'OrderController#create');
Basically need to be able to to something along the lines of below to be able to show customer details while displaying the create order form as well but getting stuck on best way to pass the id through for the current customer
public function create(){
$customer = Customer::find($id)
return view('orders.create', compact('customer'));
}
With Laravel, you just need to add the parameters you specified in the route as function parameters, like below:
public function create($id){
$customer = Customer::find($id)
return view('orders.create', compact('customer'));
}
You are not passing the $id argument in the create function.
Change it to:
public function create( $id ){
$customer = Customer::find($id)
return view('orders.create', compact('customer'));
}

codeigniter pass variable from controller to model

simple issue I presume.
My controller is getting the if to display from the url using $this->uri->segment(3). This will always be a single value. I am putting this in an array to pass to the model with:
$customerid = array(
'id' => $this->uri->segment(3)
);
The controller syntax is below:
function confirm_delete_customer()
{
$data['title']="Confirm Customer Deletion";
$customerid=array(
'id'=>$this->uri->segment(3)
);
//query model to get data results for form
$data=array();
if($query=$this->model_master_data->get_customer_records_to_delete()){
$data['records']=$query;
$this->load->view("master_data/view_master_data_header",$data);
$this->load->view("master_data/view_master_data_nav");
$this->load->view("master_data/view_content_master_data_confirm_customer_deletion",$data);
$this->load->view("master_data/view_master_data_footer");
}
I am then trying to access this array value and pass it to my model to process. If I hard code the array into the model it works as per below syntax:
Model - Manual Syntax is:
function get_customer_records_to_delete()
{
$query = $this->db->get_where('customers', array('id'=>43));
return $query->result();
}
if I try replace this with the array from my controller it fails with error:
Undefined variable: customerid
idea of model that I want to get working:
function get_customer_records_to_delete()
{
$query = $this->db->get_where('customers', $customerid);
return $query->result();
}
I have a feeling it is something small. however is this the best way to get a single record from the database in order to output to a view?
Thanks in advance for the assistance.
The best way to do that is:
function confirm_delete_customer()
{
$data=array();
$data['title']="Confirm Customer Deletion";
$customerId = $this->uri->segment(3);
//Prevent SQL injections
if(!is_numeric($customerId) || empty($customerId)) {
show_error("Bad Request");
}
$query = $this->model_master_data->get_customer_records_to_delete($customerId);
if ($query){
$data['records']=$query;
$this->load->view("master_data/view_master_data_header",$data);
$this->load->view("master_data/view_master_data_nav");
$this->load->view("master_data/view_content_master_data_confirm_customer_deletion",$data);
$this->load->view("master_data/view_master_data_footer");
}
}
and then you can simply call:
function get_customer_records_to_delete($customerId)
{
$query = $this->db->get_where('customers', array('id'=>$customerId));
return $query->result();
}
at your model.
You need to pass the value as an argument to the function so it can access it.
Ex:
get_customer_records_to_delete($customerid)
{
// now $customerid is accessible
$query = ....;
return $……;
}
You should heavily rely on function parameters. Grab the customer id from the controller and send it to the model. Moreover, you can use row() to get a single result from the database.
Controller:
function confirm_delete_customer(){
$data['title']="Confirm Customer Deletion";
$customerid=$this->uri->segment(3);
//query model to get data results for form
$data=array();
if($query=$this->model_master_data->get_customer_records_to_delete( $customerid)) //you are sending customer id as a parameter here
$data['records']=$query;
$this->load->view("master_data/view_master_data_header",$data);
$this->load->view("master_data/view_master_data_nav");
$this->load->view("master_data/view_content_master_data_confirm_customer_deletion",$data);
$this->load->view("master_data/view_master_data_footer");
}}
Model
function get_customer_records_to_delete($customerid)
{
$query = $this->db->get_where('customers', array("id"=>$customerid)); //you are using the customer id sent from the controller here
return $query->row(); //this will return a single row
}
Old thread but the answer is to declare the variable as "public" in the controller (i.e. public $customerid;), in which case it'll be available to your model. In some cases it's probably safer to explicitly pass as an argument. However, when you have several variables, it's useful to have the option to declare them instead.

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