replace existing object on the stack with default constructed one - c++11

Question

I would like to know the best/correct way to get back to the initial values of an object without playing with delete and new (everything must stay on the stack)
With this 2 classes:
static const int defaultValue{15};
class Foo
{
private:
int val1{defaultValue};
short val2{4};
}
class LongStandingObject
{
public:
void resetFoo(int index);
private:
Foo foos[100];
}
If I need to reset some foos to their default values, what is the best way?
Create reset method in Foo
void Foo::reset()
{
val1 = defaultValue;
val2 = 4;
}
I don't really like the idea to have the values coming from 2 differents places and I do like to have the defaults values in the header next to the variable declaration.
Replace by a locally created Foo
void LongStandingObject::resetFoo(int index)
{
foos[index] = Foo();
}
Am I heading to trouble when the local variable is destroyed?
Use memcpy
void LongStandingObject::resetFoo(int index)
{
Foo foo;
memcpy(foos[index], &foo, sizeof(Foo));
}
Maybe less readable...
Any other method?

Answer 1

Your #2 is just fine, and probably the most legible.
void LongStandingObject::resetFoo(int index)
{
foos[index] = Foo();
}
There are no object lifetime issues here: the assignment operator is called on foos[index] to change its values to match the temporary object materialized from Foo(). That is, the code is exactly equivalent to
{
Foo tmp;
foos[index].val1 = tmp.val1;
foos[index].val2 = tmp.val2;
}
And if optimizations are enabled, almost any compiler will be able to just modify foos[index] directly without actually creating the temporary Foo.
If you do want a Foo::reset() function as well, you can use the same idea for it:
void Foo::reset()
{
*this = Foo();
}
I would avoid using memcpy, since the program would become incorrect if you ever make changes to Foo that make it no longer trivially copyable.

Answer 2

What you can do is to use std::pair on each variable. Initialized with with variable.first = variable.second = value. After, every time you want to update the variable you set: variable.second = new_value. When you want to restore to the original, you set: variable.second = variable.first. You can improve it by writing a macro RestoreDefault(var) to make the code more readable.
For example:
#define RestoreDefault(var) ((var).second = (var).first)
// int val1{180}; // Instead of this line
std::pair<int,int> val1{ 180,180}; // <- this line
val1.second = 456;
RestoreDefault(val1);
If you want to hardcoded block any possibility to re-set later the default value, write:
std::pair<const int,int> val1{ 180,180}; // <- this line
-
Addition: Same principle for array:
class Foo
{
public:
int x = 100;
int y = 200;
};
#define RestoreArrDefault(var) ((var).second.fill((var).first))
// Use:
std::pair<Foo, std::array<Foo, 100>> FooAr, FooAr2;
// You can define different arrays with different defaults:
FooAr.first = { 180,360 }; // <- Customize FooAr defaults
// In that point FooAr default is 180,360 and FooAr2 default is 100,200
FooAr.second[3] = { 2,10 }; // <- Edit FooAr index-3 item
RestoreArrDefault(FooAr); // <- Restore Default