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Why are explicit lifetimes needed in Rust?
(10 answers)
Semantics of lifetime parameters
(2 answers)
Closed 6 months ago.
I am a beginner in rust, following rust-lang/book.
In it's ch10.3. Validating References with Lifetimes there is a Listing 10-20:
fn main() {
let string1 = String::from("abcd");
let string2 = "xyz";
let result = longest(string1.as_str(), string2);
println!("The longest string is {}", result);
}
fn longest(x: &str, y: &str) -> &str { // <-- ERROR
if x.len() > y.len() {
x
} else {
y
}
}
There are two points they have mentioned :
Rust can’t tell whether the reference being returned refers to x or y. // <-- no need, according to me
We also don’t know the concrete lifetimes of the references that will be passed in, to determine whether the reference we return will always be valid.
In the code below, their is no error (as expected) :
fn main() {
let string1 = String::from("abcd") ;
let string2 = "xyz";
let x: &str = &string1.as_str();
let y: &str = &string2;
let result =
if x.len() > y.len() {
x
} else {
y
};
println!("The longest string is {}", result);
}
Confusion :
Why Rust need to tell whether the reference being returned refers to x or y ?
Silly question, but I want to know...
Edited
Solution :
Suppose that function call is call by customer, and
function as the seller
In snippet one,
Then, function call expect that it will get one of the value, passed in argument, in return (as in snippet one)
But, if seller is biased or accidently give value other than parameters. like -
fn longest(x: &str, y: &str) -> &str {
let z = "Other String";
&z
}
Then, both function call and function both will get error message
But, their is no any mistake of customer.
Therefore, Rust ensure that customer will not get any error, for the mistake of seller, with the help of annotating lifetime parameter.
This is also the reason of, "Why Typescript introduced in Javascript".
In snippet two,
Both customer and seller is the same function
The related question, mentioned below
Why are explicit lifetimes needed in Rust?
In the second snippet, the lifetime used is the shorter of x and y.
But Rust does not do lifetime inference (or any inference at all) across function boundaries. It always requires you to specify explicitly the types and lifetimes involved. Thus, the lifetime that was inferred in the second snippet needs to be specified explicitly in the first.
The most important reason for that is to avoid unintentional breakage. If functions' type would be inferred it would be too easy to break APIs accidentally. Thus Rust by design requires you to specify signatures explicitly.
First Case
Suppose that Rust didn't give an error with your definition of longest(). Then it's possible to use longest() such that the returned address is stored in a variable that has a longer lifetime than the string slices passed in. For example, something like this:
let result: &str;
{
let x = String::from("welcome");
let y = String::from("bye");
result = longest(&x, &y);
} // `x` and `y` go out of scope, so `&x` and `&y` are no longer valid.
// This would be undefined behavior, because the data pointed to
// by `result` is no longer valid.
println!("result: {}", result);
Since result is used after x and y go out of scope, and result points to the data in either x or y, this would lead to undefined behavior. But Rust doesn't allow this; instead, the Rust compiler forces you to make the returned value of longest() has a sufficiently long lifetime.
So if the compiler didn't give an error with how you wrote longest(), then yes in your example there wouldn't be undefined behavior (because x, y, and result all have the same lifetime), but in general certain invocations of longest() and variables subsequently going out of scope could lead to undefined behavior. So to prevent this, Rust forces you to annotate the lifetimes to make sure the returned address has a long enough lifetime.
Second Case
The variables x, y, and result are all cleaned up at the same time when they go out of scope. So the address referenced by result is always valid whether it's the address of x or the address of y. So there's no error.
The "GlobalScope" class defines many fundamental enums like the Error enum.
I'm trying to produce meaningful logs when an error occurs. However printing a value of type Error only prints the integer, which is not very helpful.
The Godot documentation on enums indicates that looking up the value should work in a dictionary like fashion. However, trying to access Error[error_value] errors with:
The identifier "Error" isn't declared in the current scope.
How can I convert such enum values to string?
In the documentation you referenced, it explains that enums basically just create a bunch of constants:
enum {TILE_BRICK, TILE_FLOOR, TILE_SPIKE, TILE_TELEPORT}
# Is the same as:
const TILE_BRICK = 0
const TILE_FLOOR = 1
const TILE_SPIKE = 2
const TILE_TELEPORT = 3
However, the names of the identifiers of these constants only exist to make it easier for humans to read the code. They are replaced on runtime with something the machine can use, and are inaccessible later. If I want to print an identifier's name, I have to do so manually:
# Manually print TILE_FLOOR's name as a string, then its value.
print("The value of TILE_FLOOR is ", TILE_FLOOR)
So if your goal is to have descriptive error output, you should do so in a similar way, perhaps like so:
if unexpected_bug_found:
# Manually print the error description, then actually return the value.
print("ERR_BUG: There was a unexpected bug!")
return ERR_BUG
Now the relationship with dictionaries is that dictionaries can be made to act like enumerations, not the other way around. Enumerations are limited to be a list of identifiers with integer assignments, which dictionaries can do too. But they can also do other cool things, like have identifiers that are strings, which I believe you may have been thinking of:
const MyDict = {
NORMAL_KEY = 0,
'STRING_KEY' : 1, # uses a colon instead of equals sign
}
func _ready():
print("MyDict.NORMAL_KEY is ", MyDict.NORMAL_KEY) # valid
print("MyDict.STRING_KEY is ", MyDict.STRING_KEY) # valid
print("MyDict[NORMAL_KEY] is ", MyDict[NORMAL_KEY]) # INVALID
print("MyDict['STRING_KEY'] is ", MyDict['STRING_KEY']) # valid
# Dictionary['KEY'] only works if the key is a string.
This is useful in its own way, but even in this scenario, we assume to already have the string matching the identifier name explicitly in hand, meaning we may as well print that string manually as in the first example.
The naive approach I done for me, in a Singleton (in fact in a file that contain a lot of static funcs, referenced by a class_name)
static func get_error(global_error_constant:int) -> String:
var info := Engine.get_version_info()
var version := "%s.%s" % [info.major, info.minor]
var default := ["OK","FAILED","ERR_UNAVAILABLE","ERR_UNCONFIGURED","ERR_UNAUTHORIZED","ERR_PARAMETER_RANGE_ERROR","ERR_OUT_OF_MEMORY","ERR_FILE_NOT_FOUND","ERR_FILE_BAD_DRIVE","ERR_FILE_BAD_PATH","ERR_FILE_NO_PERMISSION","ERR_FILE_ALREADY_IN_USE","ERR_FILE_CANT_OPEN","ERR_FILE_CANT_WRITE","ERR_FILE_CANT_READ","ERR_FILE_UNRECOGNIZED","ERR_FILE_CORRUPT","ERR_FILE_MISSING_DEPENDENCIES","ERR_FILE_EOF","ERR_CANT_OPEN","ERR_CANT_CREATE","ERR_QUERY_FAILED","ERR_ALREADY_IN_USE","ERR_LOCKED","ERR_TIMEOUT","ERR_CANT_CONNECT","ERR_CANT_RESOLVE","ERR_CONNECTION_ERROR","ERR_CANT_ACQUIRE_RESOURCE","ERR_CANT_FORK","ERR_INVALID_DATA","ERR_INVALID_PARAMETER","ERR_ALREADY_EXISTS","ERR_DOES_NOT_EXIST","ERR_DATABASE_CANT_READ","ERR_DATABASE_CANT_WRITE","ERR_COMPILATION_FAILED","ERR_METHOD_NOT_FOUND","ERR_LINK_FAILED","ERR_SCRIPT_FAILED","ERR_CYCLIC_LINK","ERR_INVALID_DECLARATION","ERR_DUPLICATE_SYMBOL","ERR_PARSE_ERROR","ERR_BUSY","ERR_SKIP","ERR_HELP","ERR_BUG","ERR_PRINTER_ON_FIR"]
match version:
"3.4":
return default[global_error_constant]
# Regexp to use on #GlobalScope documentation
# \s+=\s+.+ replace by nothing
# (\w+)\s+ replace by "$1", (with quotes and comma)
printerr("you must check and add %s version in get_error()" % version)
return default[global_error_constant]
So print(MyClass.get_error(err)), or assert(!err, MyClass.get_error(err)) is handy
For non globals I made this, though it was not your question, it is highly related.
It would be useful to be able to access to #GlobalScope and #GDScript, maybe due a memory cost ?
static func get_enum_flags(_class:String, _enum:String, flags:int) -> PoolStringArray:
var ret := PoolStringArray()
var enum_flags := ClassDB.class_get_enum_constants(_class, _enum)
for i in enum_flags.size():
if (1 << i) & flags:
ret.append(enum_flags[i])
return ret
static func get_constant_or_enum(_class:String, number:int, _enum:="") -> String:
if _enum:
return ClassDB.class_get_enum_constants(_class, _enum)[number]
return ClassDB.class_get_integer_constant_list(_class)[number]
I am trying to write a code that calculate the size of a list.
Here is what I've done:
let rec l = function
| [] -> 0
| t::q -> 1 + l q
print_int(l ([1;2;3;4]))
The problem is that it's saying me :
It is applied to too many arguments; maybe you forgot a `;'.
When I put the double semicolon ;; at the end of the definition of l it works well, yet I've read that ;; is not useful at all if you are not coding in the REPL, so here I don't see why it's giving me this error.
The following
print_int(l [1;2;3;4])
is a toplevel expression. Such expression needs to be preceded by ;;:
;; print_int(l [1;2;3;4])
Another option is to make this toplevel expression a binding with
let () = print_int(l [1;2;3;4])
When parsing the code the parser advances until it hits l q. At this point there could be more arguments that should get applied to the function l. So the parser keeps going and the next thing it finds is the value print_int. Another argument to l. Which gives you your error.
The parser has no way of knowing that you had finished the code for the function l. In the top level the special token ;; is used to tell the parser that the input is finished and it should evaluate the code now. After that it starts paring the remaining input again.
Now why doesn't compiled code also have the ';;' token?
Simply because its not needed. In compiled code the line print_int(l [1;2;3;4]) is not valid input. That would be a statement you want to execute and functional languages have no such thing. Instead print_int(l [1;2;3;4]) is an expression that returns a value, () in this case, and you have to tell the compiler what to do with that value. A let () = tells the compiler to match it against (). And the let ... also tells the compiler that the previous let rec l ... has finished. So no special ;; token is needed.
Or think of it this way: In the top level there is an implicit let _ = if your input doesn't start with let. That way you can just type in some expression and see what it evaluates to without having to type let _ = every time. The ';;' token still means "evaluate now" though and is still needed.
Where can I find a list of Scala's "magic" functions, such as apply, unapply, update, +=, etc.?
By magic-functions I mean functions which are used by some syntactic sugar of the compiler, for example
o.update(x,y) <=> o(x) = y
I googled for some combination of scala magic and synonyms of functions, but I didn't find anything.
I'm not interested with the usage of magic functions in the standard library, but in which magic functions exists.
As far as I know:
Getters/setters related:
apply
update
identifier_=
Pattern matching:
unapply
unapplySeq
For-comprehensions:
map
flatMap
filter
withFilter
foreach
Prefixed operators:
unary_+
unary_-
unary_!
unary_~
Beyond that, any implicit from A to B. Scala will also convert A <op>= B into A = A <op> B, if the former operator isn't defined, "op" is not alphanumeric, and <op>= isn't !=, ==, <= or >=.
And I don't believe there's any single place where all of Scala's syntactic sugars are listed.
In addition to update and apply, there are also a number of unary operators which (I believe) qualify as magical:
unary_+
unary_-
unary_!
unary_~
Add to that the regular infix/suffix operators (which can be almost anything) and you've got yourself the complete package.
You really should take a look at the Scala Language Specification. It is the only authoritative source on this stuff. It's not that hard to read (as long as you're comfortable with context-free grammars), and very easily searchable. The only thing it doesn't specify well is the XML support.
Sorry if it's not exactly answering your question, but my favorite WTF moment so far is # as assignment operator inside pattern match. Thanks to soft copy of "Programming in Scala" I found out what it was pretty quickly.
Using # we can bind any part of a pattern to a variable, and if the pattern match succeeds, the variable will capture the value of the sub-pattern. Here's the example from Programming in Scala (Section 15.2 - Variable Binding):
expr match {
case UnOp("abs", e # UnOp("abs", _)) => e
case _ =>
}
If the entire pattern match succeeds,
then the portion that matched the
UnOp("abs", _) part is made available
as variable e.
And here's what Programming Scala says about it.
That link no longer works. Here is one that does.
I'll also add _* for pattern matching on an arbitrary number of parameters like
case x: A(_*)
And operator associativity rule, from Odersky-Spoon-Venners book:
The associativity of an operator in Scala is determined by its last
character. As mentioned on <...>, any method that ends
in a ‘:’ character is invoked on its right operand, passing in the
left operand. Methods that end in any other character are the other
way around. They are invoked on their left operand, passing in the
right operand. So a * b yields a.*(b), but a ::: b yields b.:::(a).
Maybe we should also mention syntactic desugaring of for expressions which can be found here
And (of course!), alternative syntax for pairs
a -> b //converted to (a, b), where a and b are instances
(as correctly pointed out, this one is just an implicit conversion done through a library, so it's probably not eligible, but I find it's a common puzzler for newcomers)
I'd like to add that there is also a "magic" trait - scala.Dynamic:
A marker trait that enables dynamic invocations. Instances x of this trait allow method invocations x.meth(args) for arbitrary method names meth and argument lists args as well as field accesses x.field for arbitrary field names field.
If a call is not natively supported by x (i.e. if type checking fails), it is rewritten according to the following rules:
foo.method("blah") ~~> foo.applyDynamic("method")("blah")
foo.method(x = "blah") ~~> foo.applyDynamicNamed("method")(("x", "blah"))
foo.method(x = 1, 2) ~~> foo.applyDynamicNamed("method")(("x", 1), ("", 2))
foo.field ~~> foo.selectDynamic("field")
foo.varia = 10 ~~> foo.updateDynamic("varia")(10)
foo.arr(10) = 13 ~~> foo.selectDynamic("arr").update(10, 13)
foo.arr(10) ~~> foo.applyDynamic("arr")(10)
As of Scala 2.10, defining direct or indirect subclasses of this trait is only possible if the language feature dynamics is enabled.
So you can do stuff like
import scala.language.dynamics
object Dyn extends Dynamic {
def applyDynamic(name: String)(a1: Int, a2: String) {
println("Invoked " + name + " on (" + a1 + "," + a2 + ")");
}
}
Dyn.foo(3, "x");
Dyn.bar(3, "y");
They are defined in the Scala Language Specification.
As far as I know, there are just three "magic" functions as you mentioned.
Scalas Getter and Setter may also relate to your "magic":
scala> class Magic {
| private var x :Int = _
| override def toString = "Magic(%d)".format(x)
| def member = x
| def member_=(m :Int){ x = m }
| }
defined class Magic
scala> val m = new Magic
m: Magic = Magic(0)
scala> m.member
res14: Int = 0
scala> m.member = 100
scala> m
res15: Magic = Magic(100)
scala> m.member += 99
scala> m
res17: Magic = Magic(199)
What are the precise rules for when you can omit (omit) parentheses, dots, braces, = (functions), etc.?
For example,
(service.findAllPresentations.get.first.votes.size) must be equalTo(2).
service is my object
def findAllPresentations: Option[List[Presentation]]
votes returns List[Vote]
must and be are both functions of specs
Why can't I go:
(service findAllPresentations get first votes size) must be equalTo(2)
?
The compiler error is:
"RestServicesSpecTest.this.service.findAllPresentations
of type
Option[List[com.sharca.Presentation]]
does not take parameters"
Why does it think I'm trying to pass in a parameter? Why must I use dots for every method call?
Why must (service.findAllPresentations get first votes size) be equalTo(2) result in:
"not found: value first"
Yet, the "must be equalTo 2" of
(service.findAllPresentations.get.first.votes.size) must be equalTo 2, that is, method chaining works fine? - object chain chain chain param.
I've looked through the Scala book and website and can't really find a comprehensive explanation.
Is it in fact, as Rob H explains in Stack Overflow question Which characters can I omit in Scala?, that the only valid use-case for omitting the '.' is for "operand operator operand" style operations, and not for method chaining?
You seem to have stumbled upon the answer. Anyway, I'll try to make it clear.
You can omit dot when using the prefix, infix and postfix notations -- the so called operator notation. While using the operator notation, and only then, you can omit the parenthesis if there is less than two parameters passed to the method.
Now, the operator notation is a notation for method-call, which means it can't be used in the absence of the object which is being called.
I'll briefly detail the notations.
Prefix:
Only ~, !, + and - can be used in prefix notation. This is the notation you are using when you write !flag or val liability = -debt.
Infix:
That's the notation where the method appears between an object and it's parameters. The arithmetic operators all fit here.
Postfix (also suffix):
That notation is used when the method follows an object and receives no parameters. For example, you can write list tail, and that's postfix notation.
You can chain infix notation calls without problem, as long as no method is curried. For example, I like to use the following style:
(list
filter (...)
map (...)
mkString ", "
)
That's the same thing as:
list filter (...) map (...) mkString ", "
Now, why am I using parenthesis here, if filter and map take a single parameter? It's because I'm passing anonymous functions to them. I can't mix anonymous functions definitions with infix style because I need a boundary for the end of my anonymous function. Also, the parameter definition of the anonymous function might be interpreted as the last parameter to the infix method.
You can use infix with multiple parameters:
string substring (start, end) map (_ toInt) mkString ("<", ", ", ">")
Curried functions are hard to use with infix notation. The folding functions are a clear example of that:
(0 /: list) ((cnt, string) => cnt + string.size)
(list foldLeft 0) ((cnt, string) => cnt + string.size)
You need to use parenthesis outside the infix call. I'm not sure the exact rules at play here.
Now, let's talk about postfix. Postfix can be hard to use, because it can never be used anywhere except the end of an expression. For example, you can't do the following:
list tail map (...)
Because tail does not appear at the end of the expression. You can't do this either:
list tail length
You could use infix notation by using parenthesis to mark end of expressions:
(list tail) map (...)
(list tail) length
Note that postfix notation is discouraged because it may be unsafe.
I hope this has cleared all the doubts. If not, just drop a comment and I'll see what I can do to improve it.
Class definitions:
val or var can be omitted from class parameters which will make the parameter private.
Adding var or val will cause it to be public (that is, method accessors and mutators are generated).
{} can be omitted if the class has no body, that is,
class EmptyClass
Class instantiation:
Generic parameters can be omitted if they can be inferred by the compiler. However note, if your types don't match, then the type parameter is always infered so that it matches. So without specifying the type, you may not get what you expect - that is, given
class D[T](val x:T, val y:T);
This will give you a type error (Int found, expected String)
var zz = new D[String]("Hi1", 1) // type error
Whereas this works fine:
var z = new D("Hi1", 1)
== D{def x: Any; def y: Any}
Because the type parameter, T, is inferred as the least common supertype of the two - Any.
Function definitions:
= can be dropped if the function returns Unit (nothing).
{} for the function body can be dropped if the function is a single statement, but only if the statement returns a value (you need the = sign), that is,
def returnAString = "Hi!"
but this doesn't work:
def returnAString "Hi!" // Compile error - '=' expected but string literal found."
The return type of the function can be omitted if it can be inferred (a recursive method must have its return type specified).
() can be dropped if the function doesn't take any arguments, that is,
def endOfString {
return "myDog".substring(2,1)
}
which by convention is reserved for methods which have no side effects - more on that later.
() isn't actually dropped per se when defining a pass by name paramenter, but it is actually a quite semantically different notation, that is,
def myOp(passByNameString: => String)
Says myOp takes a pass-by-name parameter, which results in a String (that is, it can be a code block which returns a string) as opposed to function parameters,
def myOp(functionParam: () => String)
which says myOp takes a function which has zero parameters and returns a String.
(Mind you, pass-by-name parameters get compiled into functions; it just makes the syntax nicer.)
() can be dropped in the function parameter definition if the function only takes one argument, for example:
def myOp2(passByNameString:(Int) => String) { .. } // - You can drop the ()
def myOp2(passByNameString:Int => String) { .. }
But if it takes more than one argument, you must include the ():
def myOp2(passByNameString:(Int, String) => String) { .. }
Statements:
. can be dropped to use operator notation, which can only be used for infix operators (operators of methods that take arguments). See Daniel's answer for more information.
. can also be dropped for postfix functions
list tail
() can be dropped for postfix operators
list.tail
() cannot be used with methods defined as:
def aMethod = "hi!" // Missing () on method definition
aMethod // Works
aMethod() // Compile error when calling method
Because this notation is reserved by convention for methods that have no side effects, like List#tail (that is, the invocation of a function with no side effects means that the function has no observable effect, except for its return value).
() can be dropped for operator notation when passing in a single argument
() may be required to use postfix operators which aren't at the end of a statement
() may be required to designate nested statements, ends of anonymous functions or for operators which take more than one parameter
When calling a function which takes a function, you cannot omit the () from the inner function definition, for example:
def myOp3(paramFunc0:() => String) {
println(paramFunc0)
}
myOp3(() => "myop3") // Works
myOp3(=> "myop3") // Doesn't work
When calling a function that takes a by-name parameter, you cannot specify the argument as a parameter-less anonymous function. For example, given:
def myOp2(passByNameString:Int => String) {
println(passByNameString)
}
You must call it as:
myOp("myop3")
or
myOp({
val source = sourceProvider.source
val p = myObject.findNameFromSource(source)
p
})
but not:
myOp(() => "myop3") // Doesn't work
IMO, overuse of dropping return types can be harmful for code to be re-used. Just look at specification for a good example of reduced readability due to lack of explicit information in the code. The number of levels of indirection to actually figure out what the type of a variable is can be nuts. Hopefully better tools can avert this problem and keep our code concise.
(OK, in the quest to compile a more complete, concise answer (if I've missed anything, or gotten something wrong/inaccurate please comment), I have added to the beginning of the answer. Please note this isn't a language specification, so I'm not trying to make it exactly academically correct - just more like a reference card.)
A collection of quotes giving insight into the various conditions...
Personally, I thought there'd be more in the specification. I'm sure there must be, I'm just not searching for the right words...
There are a couple of sources however, and I've collected them together, but nothing really complete / comprehensive / understandable / that explains the above problems to me...:
"If a method body has more than one
expression, you must surround it with
curly braces {…}. You can omit the
braces if the method body has just one
expression."
From chapter 2, "Type Less, Do More", of Programming Scala:
"The body of the upper method comes
after the equals sign ‘=’. Why an
equals sign? Why not just curly braces
{…}, like in Java? Because semicolons,
function return types, method
arguments lists, and even the curly
braces are sometimes omitted, using an
equals sign prevents several possible
parsing ambiguities. Using an equals
sign also reminds us that even
functions are values in Scala, which
is consistent with Scala’s support of
functional programming, described in
more detail in Chapter 8, Functional
Programming in Scala."
From chapter 1, "Zero to Sixty: Introducing Scala", of Programming Scala:
"A function with no parameters can be
declared without parentheses, in which
case it must be called with no
parentheses. This provides support for
the Uniform Access Principle, such
that the caller does not know if the
symbol is a variable or a function
with no parameters.
The function body is preceded by "="
if it returns a value (i.e. the return
type is something other than Unit),
but the return type and the "=" can be
omitted when the type is Unit (i.e. it
looks like a procedure as opposed to a
function).
Braces around the body are not
required (if the body is a single
expression); more precisely, the body
of a function is just an expression,
and any expression with multiple parts
must be enclosed in braces (an
expression with one part may
optionally be enclosed in braces)."
"Functions with zero or one argument
can be called without the dot and
parentheses. But any expression can
have parentheses around it, so you can
omit the dot and still use
parentheses.
And since you can use braces anywhere
you can use parentheses, you can omit
the dot and put in braces, which can
contain multiple statements.
Functions with no arguments can be
called without the parentheses. For
example, the length() function on
String can be invoked as "abc".length
rather than "abc".length(). If the
function is a Scala function defined
without parentheses, then the function
must be called without parentheses.
By convention, functions with no
arguments that have side effects, such
as println, are called with
parentheses; those without side
effects are called without
parentheses."
From blog post Scala Syntax Primer:
"A procedure definition is a function
definition where the result type and
the equals sign are omitted; its
defining expression must be a block.
E.g., def f (ps) {stats} is
equivalent to def f (ps): Unit =
{stats}.
Example 4.6.3 Here is a declaration
and a de?nition of a procedure named
write:
trait Writer {
def write(str: String)
}
object Terminal extends Writer {
def write(str: String) { System.out.println(str) }
}
The code above is implicitly completed
to the following code:
trait Writer {
def write(str: String): Unit
}
object Terminal extends Writer {
def write(str: String): Unit = { System.out.println(str) }
}"
From the language specification:
"With methods which only take a single
parameter, Scala allows the developer
to replace the . with a space and omit
the parentheses, enabling the operator
syntax shown in our insertion operator
example. This syntax is used in other
places in the Scala API, such as
constructing Range instances:
val firstTen:Range = 0 to 9
Here again, to(Int) is a vanilla
method declared inside a class
(there’s actually some more implicit
type conversions here, but you get the
drift)."
From Scala for Java Refugees Part 6: Getting Over Java:
"Now, when you try "m 0", Scala
discards it being a unary operator, on
the grounds of not being a valid one
(~, !, - and +). It finds that "m" is
a valid object -- it is a function,
not a method, and all functions are
objects.
As "0" is not a valid Scala
identifier, it cannot be neither an
infix nor a postfix operator.
Therefore, Scala complains that it
expected ";" -- which would separate
two (almost) valid expressions: "m"
and "0". If you inserted it, then it
would complain that m requires either
an argument, or, failing that, a "_"
to turn it into a partially applied
function."
"I believe the operator syntax style
works only when you've got an explicit
object on the left-hand side. The
syntax is intended to let you express
"operand operator operand" style
operations in a natural way."
Which characters can I omit in Scala?
But what also confuses me is this quote:
"There needs to be an object to
receive a method call. For instance,
you cannot do “println “Hello World!”"
as the println needs an object
recipient. You can do “Console
println “Hello World!”" which
satisfies the need."
Because as far as I can see, there is an object to receive the call...
I find it easier to follow this rule of thumb: in expressions spaces alternate between methods and parameters. In your example, (service.findAllPresentations.get.first.votes.size) must be equalTo(2) parses as (service.findAllPresentations.get.first.votes.size).must(be)(equalTo(2)). Note that the parentheses around the 2 have a higher associativity than the spaces. Dots also have higher associativity, so (service.findAllPresentations.get.first.votes.size) must be.equalTo(2)would parse as (service.findAllPresentations.get.first.votes.size).must(be.equalTo(2)).
service findAllPresentations get first votes size must be equalTo 2 parses as service.findAllPresentations(get).first(votes).size(must).be(equalTo).2.
Actually, on second reading, maybe this is the key:
With methods which only take a single
parameter, Scala allows the developer
to replace the . with a space and omit
the parentheses
As mentioned on the blog post: http://www.codecommit.com/blog/scala/scala-for-java-refugees-part-6 .
So perhaps this is actually a very strict "syntax sugar" which only works where you are effectively calling a method, on an object, which takes one parameter. e.g.
1 + 2
1.+(2)
And nothing else.
This would explain my examples in the question.
But as I said, if someone could point out to be exactly where in the language spec this is specified, would be great appreciated.
Ok, some nice fellow (paulp_ from #scala) has pointed out where in the language spec this information is:
6.12.3:
Precedence and associativity of
operators determine the grouping of
parts of an expression as follows.
If there are several infix operations in an expression, then
operators with higher precedence bind
more closely than operators with lower
precedence.
If there are consecutive infix operations e0 op1 e1 op2 . . .opn en
with operators op1, . . . , opn of the
same precedence, then all these
operators must have the same
associativity. If all operators are
left-associative, the sequence is
interpreted as (. . . (e0 op1 e1) op2
. . .) opn en. Otherwise, if all
operators are rightassociative, the
sequence is interpreted as e0 op1 (e1
op2 (. . .opn en) . . .).
Postfix operators always have lower precedence than infix operators. E.g.
e1 op1 e2 op2 is always equivalent to
(e1 op1 e2) op2.
The right-hand operand of a
left-associative operator may consist
of several arguments enclosed in
parentheses, e.g. e op (e1, . . .
,en). This expression is then
interpreted as e.op(e1, . . . ,en).
A left-associative binary operation e1
op e2 is interpreted as e1.op(e2). If
op is rightassociative, the same
operation is interpreted as { val
x=e1; e2.op(x ) }, where x is a fresh
name.
Hmm - to me it doesn't mesh with what I'm seeing or I just don't understand it ;)
There aren't any. You will likely receive advice around whether or not the function has side-effects. This is bogus. The correction is to not use side-effects to the reasonable extent permitted by Scala. To the extent that it cannot, then all bets are off. All bets. Using parentheses is an element of the set "all" and is superfluous. It does not provide any value once all bets are off.
This advice is essentially an attempt at an effect system that fails (not to be confused with: is less useful than other effect systems).
Try not to side-effect. After that, accept that all bets are off. Hiding behind a de facto syntactic notation for an effect system can and does, only cause harm.