This question already has an answer here:
golang how can I use struct name as map key
(1 answer)
Closed 9 months ago.
We have a following function:
func (h *Handler) Handle(message interface{}) error {
//here there is a switch for different messages
switch m := message.(type) {
}
}
This signature is given and can't be changed. There are around 20 different message types the handler processes.
Now, there are some of these messages (around 4) which need special post-processing. In a different package.
Thus, I am thinking to do this like this:
func (h *Handler) Handle(message interface{}) error {
//here there is a switch for different messages
switch m := message.(type) {
}
//only post-process if original message processing succeeds
postProcessorPkg.Process(message)
}
Now, in the Process function, I want to quickly lookup if the message type is indeed of the ones we need postprocessing for. I don't want to do a switch again here. There are many handlers, in different packages, with varying amount of message types, and it should be generic.
So I was thinking of registering the message type in the postprocessor and then just do a lookup:
func (p *Postprocessor) Register(msgtype interface{}) {
registeredTypes[msgtype] = msgtype
}
and then
func (p *Postprocessor) Process(msgtype interface{}) error {
if ok := registeredTypes[msgtype]; !ok {
return errors.New("Unsupported message type")
}
prop := GetProp(registeredTypes[msgtype])
doSmthWithProp(prop)
}
This will all not work now because I can only "register" instances of the message, not the message type itself, as far as I know. Thus the map would only match a specific instance of a message, not its type, which is what I need.
So I guess this needs redesign. I can completely ditch the registering and the map lookup, but
I can't change the Handle function to a specific type (signature will need to remain message interface{}
I would like to avoid to have to use reflect, just because I will have a hard time defending such a solution with some colleagues.
As there is no possibility to set a type as the map key, I finally decided to implement the following solution, which is based on #Chrono Kitsune 's solution:
type Postprocess interface {
NeedsPostprocess() bool
}
type MsgWithPostProcess struct {}
func (p *MsgWithPostProcess) NeedsPostprocess() bool {
return true
}
type Msg1 struct {
MsgWithPostProcess
//other stuff
}
type Msg2 struct {
MsgWithPostProcess
//other stuff
}
type Msg3 struct {
//no postprocessing needed
}
func (p *Postprocessor) Process(msgtype interface{}) error {
if _, ok := msgtype.(Postprocess); ok {
//do postprocessing
}
}
As of my simple test I did, only Msg1 and Msg2 will be postprocessed, but not Msg3, which is what I wanted.
This question was the first hit I found on Google but the title is somewhat misleading. So I'll leave this here to add some food for thought with the title of the question in mind.
First, the issue with maps is that its key must be a comparable value. This is why for example a slice cannot be used is a map key. A slice is not comparable and is therefore not allowed. You can use an array (fixed sized slice) but not a slice for the same reason.
Second, you have in the reflect.TypeOf(...).String()a way to get a canonical string representation for types. Though it is not unambiguous unless you include the package path, as you can see here.
package main
import (
"fmt"
s2 "go/scanner"
"reflect"
s1 "text/scanner"
)
type X struct{}
func main() {
fmt.Println(reflect.TypeOf(1).String())
fmt.Println(reflect.TypeOf(X{}).String())
fmt.Println(reflect.TypeOf(&X{}).String())
fmt.Println(reflect.TypeOf(s1.Scanner{}).String())
fmt.Println(reflect.TypeOf(s2.Scanner{}).String())
fmt.Println(reflect.TypeOf(s1.Scanner{}).PkgPath(), reflect.TypeOf(s1.Scanner{}).String())
fmt.Println(reflect.TypeOf(s2.Scanner{}).PkgPath(), reflect.TypeOf(s2.Scanner{}).String())
}
int
main.X
*main.X
scanner.Scanner
scanner.Scanner
text/scanner scanner.Scanner
go/scanner scanner.Scanner
https://play.golang.org/p/NLODZNdik6r
With this information, you can (if you feel so inclined) create a map which let's go from a reflect.Type to a key and back again, like this.
package main
import (
"fmt"
s2 "go/scanner"
"reflect"
s1 "text/scanner"
)
type TypeMap struct {
m []reflect.Type
}
func (m *TypeMap) Get(t reflect.Type) int {
for i, x := range m.m {
if x == t {
return i
}
}
m.m = append(m.m, t)
return len(m.m) - 1
}
func (m *TypeMap) Reverse(t int) reflect.Type {
return m.m[t]
}
type X struct{}
func main() {
var m TypeMap
fmt.Println(m.Get(reflect.TypeOf(1)))
fmt.Println(m.Reverse(0))
fmt.Println(m.Get(reflect.TypeOf(1)))
fmt.Println(m.Reverse(0))
fmt.Println(m.Get(reflect.TypeOf(1)))
fmt.Println(m.Reverse(0))
fmt.Println(m.Get(reflect.TypeOf(X{})))
fmt.Println(m.Reverse(1))
fmt.Println(m.Get(reflect.TypeOf(&X{})))
fmt.Println(m.Reverse(2))
fmt.Println(m.Get(reflect.TypeOf(s1.Scanner{})))
fmt.Println(m.Reverse(3).PkgPath(), m.Reverse(3))
fmt.Println(m.Get(reflect.TypeOf(s2.Scanner{})))
fmt.Println(m.Reverse(4).PkgPath(), m.Reverse(4))
}
0
int
0
int
0
int
1
main.X
2
*main.X
3
text/scanner scanner.Scanner
4
go/scanner scanner.Scanner
In the above case I'm assuming that N is small. Also note the use of the identity of reflect.TypeOf, it will return the same pointer for the same type on subsequent calls.
If N is not small, you may want to do something a bit more complex.
package main
import (
"fmt"
s2 "go/scanner"
"reflect"
s1 "text/scanner"
)
type PkgPathNum struct {
PkgPath string
Num int
}
type TypeMap struct {
m map[string][]PkgPathNum
r []reflect.Type
}
func (m *TypeMap) Get(t reflect.Type) int {
k := t.String()
xs := m.m[k]
pkgPath := t.PkgPath()
for _, x := range xs {
if x.PkgPath == pkgPath {
return x.Num
}
}
n := len(m.r)
m.r = append(m.r, t)
xs = append(xs, PkgPathNum{pkgPath, n})
if m.m == nil {
m.m = make(map[string][]PkgPathNum)
}
m.m[k] = xs
return n
}
func (m *TypeMap) Reverse(t int) reflect.Type {
return m.r[t]
}
type X struct{}
func main() {
var m TypeMap
fmt.Println(m.Get(reflect.TypeOf(1)))
fmt.Println(m.Reverse(0))
fmt.Println(m.Get(reflect.TypeOf(X{})))
fmt.Println(m.Reverse(1))
fmt.Println(m.Get(reflect.TypeOf(&X{})))
fmt.Println(m.Reverse(2))
fmt.Println(m.Get(reflect.TypeOf(s1.Scanner{})))
fmt.Println(m.Reverse(3).PkgPath(), m.Reverse(3))
fmt.Println(m.Get(reflect.TypeOf(s2.Scanner{})))
fmt.Println(m.Reverse(4).PkgPath(), m.Reverse(4))
}
0
int
1
main.X
2
*main.X
3
text/scanner scanner.Scanner
4
go/scanner scanner.Scanner
https://play.golang.org/p/2fiMZ8qCQtY
Note the subtitles of pointer to type, that, X and *X actually are different types.
Related
a := []int{1,2,3}
x, a := a[len(a)-1], a[:len(a)-1]
fmt.Println(a,x)
How to create a pop() function that will do the same for any type of an array?
Here is what I came up with so far:
func pop(a []*interface{}) interface{}{
x := a[len(a)-1]
a = a[:len(a)-1]
return x
}
func main(){
a := []int{1,2,3}
x = pop(a)
fmt.Println(a,x) // -> [1,2] 3
}
But I get cannot use a (type []int) as type []interface {}or other error messages if I try to tweak the code by trial and error.
package main
import (
"fmt"
"reflect"
)
func pop(a interface{}) interface{} {
v := reflect.ValueOf(a).Elem()
x := v.Index(v.Len() - 1)
v.SetLen(v.Len() - 1)
return x
}
func main() {
a := []int{1, 2, 3}
x := pop(&a)
fmt.Println(a, x) // -> [1,2] 3
}
Though this can be implemented, I still think that x, a = a[len(a)-1], a[:len(a)-1] should be better than a pop function.
The go type system doesn't allow you to cast from []type1 -> []type2. Even if it did interfaces are a struct containing a type id and pointer to the object, where normally you would just have the object. Because of this you need to take a interface{} and use reflect to do the slicing.
func pop(slice interface{}) (interface{}, interface{}) {
v := reflect.ValueOf(slice)
return v.Slice(0,v.Len()-1).Interface(), v.Index(v.Len()-1).Interface()
}
Go Playground
Note that this loses compile time type safety, because it must use an interface. Additionally, due to using interfaces the poped value may be allocated, creating extra GC pressure.
Common Go style typically recommends not writing a function like this, and just inlining the small amount of code manually.
After all that really good anwers using reflection I also want to add one answer which offers a more idiomatic Go solution. Like Rob Pike said in his great talk about Go Proverbs
interface{} says nothing
Reflection is never clear
So there should be also one answer showing the idiomatic Go way. This solution does not work for slices of standard types. But there the answer of cshu shows the best solution: x, a = a[len(a)-1], a[:len(a)-1]
For own defined types we have to define a Poper interface and the Pop function takes that as input and returns an empty interface.
type Poper interface {
Pop() interface{}
}
type MyType struct {
a []int
}
func (mt *MyType) Pop() interface{} {
x := mt.a[len(mt.a)-1]
mt.a = mt.a[:len(mt.a)-1]
return x
}
func Pop(p Poper) interface{} {
return p.Pop()
}
func main() {
a := &MyType{[]int{1, 2, 3}}
fmt.Println(Pop(a), a)
}
https://play.golang.org/p/UbDkoVYSMA
At all it is not a good idea to return an empty interface, because all following code has to support the interface{}.
The following code example does not work:
func main() {
a := &MyType{[]int{1, 2, 3}}
fmt.Println(Pop(a), a)
var b int
b = Pop(a)
}
https://play.golang.org/p/wg9__O44A8
The error says everything about that problem: cannot use Pop(a) (type interface {}) as type int in assignment: need type assertion
So the Pop() function does work by returning interface{} but the rest of the code using the result of that function needs to make a type assertion. So if you can avoid it you should search for another solution using types.
I have some different structs like Big with Small embedded at offset 0.
How can I access Small's structure fields from code, that doesn't know anything about Big type, but it is known that Small is at offset 0?
type Small struct {
val int
}
type Big struct {
Small
bigval int
}
var v interface{} = Big{}
// here i only know about 'Small' struct and i know that it is at the begining of variable
v.(Small).val // compile error
It seems that compiler is theoretically able to operate such expression, because it knows that Big type has Small type embedded at offset 0. Is there any way to do such things (maybe with unsafe.Pointer)?
While answer with reflection is working but it has performance penalties and is not idiomatic to Go.
I believe you should use interface. Like this
https://play.golang.org/p/OG1MPHjDlQ
package main
import (
"fmt"
)
type MySmall interface {
SmallVal() int
}
type Small struct {
val int
}
func (v Small) SmallVal() int {
return v.val
}
type Big struct {
Small
bigval int
}
func main() {
var v interface{} = Big{Small{val: 3}, 4}
fmt.Printf("Small val: %v", v.(MySmall).SmallVal())
}
Output:
Small val: 3
Avoid using unsafe whenever possible. The above task can be done using reflection (reflect package):
var v interface{} = Big{Small{1}, 2}
rf := reflect.ValueOf(v)
s := rf.FieldByName("Small").Interface()
fmt.Printf("%#v\n", s)
fmt.Printf("%#v\n", s.(Small).val)
Output (try it on the Go Playground):
main.Small{val:1}
1
Notes:
This works for any field, not just the first one (at "offset 0"). This also works for named fields too, not just for embedded fields. This doesn't work for unexported fields though.
type Small struct {
val int
}
type Big struct {
Small
bigval int
}
func main() {
var v = Big{Small{10},200}
print(v.val)
}
I've been trying to build a set of structs that have a base struct as their foundation and variants built on top of that. I've found, however, that there doesn't seem to be a way for the struct to identify itself when the common code is in the base struct. How should I be doing this?
package main
import (
"fmt"
)
type Base interface {
IsMe(other Base) bool
}
type Block struct {
}
func (b *Block) IsMe(other Base) bool {
return b == other
}
type Block2 struct {
Block
}
func main() {
b1 := &Block{}
b2 := &Block2{}
fmt.Printf("b1.IsMe(b1): %v\n", b1.IsMe(b1))
fmt.Printf("b1.IsMe(b2): %v\n", b1.IsMe(b2))
fmt.Printf("b2.IsMe(b1): %v\n", b2.IsMe(b1)) // Wrong result!
fmt.Printf("b2.IsMe(b2): %v\n", b2.IsMe(b2)) // Wrong result!
}
If you really want to do it the fake inheritance way then you can certainly do it the way you did it but it really only works with unsafe or reflect because the language is not designed for what you want to do.
Your problem starts with where x.IsMe comes from when using embedding. When you write
type Block struct {}
func (b *Block) IsMe(other Base) bool { return b == other }
type Block2 struct { Block }
the method IsMe is actually associated and bound to Block instead of Block2. So calling IsMe on an instance of Block2 is really only calling it on Block, in detail:
b2 := Block2{}
fmt.Println(b2.IsMe) // 0x21560
fmt.Println(b2.Block.IsMe) // 0x21560
Both methods have the same address. This shows that even though b2 has the method IsMe, that method is only propagated from Block to the outside of Block2 and not inherited. This in turn means that you are always running effectively this code:
b1 := Block{}
b2 := Block2{}
b2_embedded_block := b2.Block
b2_embedded_block.IsMe(b2)
b2_embedded_block.IsMe(b1)
// ...
which obviously cannot work since you are comparing two completely different instances.
What you really should do is to use some function outside of your embedding chain to decide equality. Example (On Play):
func IsEq(a,b Base) bool {
return a == b
}
This actually compares the right instances.
package main
import (
"fmt"
"reflect"
)
type Base interface {
IsMe(other Base) bool
}
type Block struct {
_ [1]byte // size of struct must be greater than zero
}
func (b *Block) IsMe(other Base) bool {
x := reflect.ValueOf(b)
y := reflect.ValueOf(other)
return x.Pointer() == y.Pointer()
}
type Block2 struct {
Block // "parent" needs to be first element
}
func main() {
b1 := &Block{}
b2 := &Block2{}
fmt.Printf("b1.IsMe(b1): %v\n", b1.IsMe(b1))
fmt.Printf("b1.IsMe(b2): %v\n", b1.IsMe(b2))
fmt.Printf("b2.IsMe(b1): %v\n", b2.IsMe(b1))
fmt.Printf("b2.IsMe(b2): %v\n", b2.IsMe(b2))
}
https://play.golang.org/p/Dx0Ze3euFY
I have several methods that I'm calling for some cases (like Add, Delete, etc..). However over time the number of cases is increasing and my switch-case is getting longer. So I thought I'd create a map of methods, like Go map of functions; here the mapping of functions is trivial. However, is it possible to create a map of methods in Go?
When we have a method:
func (f *Foo) Add(a string, b int) { }
The syntax below create compile-time error:
actions := map[string]func(a, b){
"add": f.Add(a,b),
}
Is it possible to create a map of methods in Go?
Yes. Currently:
actions := map[string]func(a string, b int){
"add": func(a string, b int) { f.Add(a, b) },
}
Later: see the go11func document guelfi mentioned.
There is currently no way to store both receiver and method in a single value (unless you store it in a struct). This is currently worked on and it may change with Go 1.1 (see http://golang.org/s/go11func).
You may, however, assign a method to a function value (without a receiver) and pass the receiver to the value later:
package main
import "fmt"
type Foo struct {
n int
}
func (f *Foo) Bar(m int) int {
return f.n + m
}
func main() {
foo := &Foo{2}
f := (*Foo).Bar
fmt.Printf("%T\n", f)
fmt.Println(f(foo, 42))
}
This value can be stored in a map like anything else.
I met with a similar question.
How can this be done today, 9 years later:
the thing is that the receiver must be passed to the method map as the first argument. Which is pretty unusual.
package main
import (
"fmt"
"log"
)
type mType struct {
str string
}
func (m *mType) getStr(s string) {
fmt.Println(s)
fmt.Println(m.str)
}
var (
testmap = make(map[string]func(m *mType, s string))
)
func main() {
test := &mType{
str: "Internal string",
}
testmap["GetSTR"] = (*mType).getStr
method, ok := testmap["GetSTR"]
if !ok {
log.Fatal("something goes wrong")
}
method(test, "External string")
}
https://go.dev/play/p/yy3aR_kMzHP
You can do this using Method Expressions:
https://golang.org/ref/spec#Method_expressions
However, this makes the function take the receiver as a first argument:
actions := map[string]func(Foo, string, int){
"add": Foo.Add
}
Similarly, you can get a function with the signature func(*Foo, string, int) using (*Foo).Add
If you want to use pointer to type Foo as receiver, like in:
func (f *Foo) Add(a string, b int) { }
then you can map string to function of (*Foo, string, int), like this:
var operations = map[string]func(*Foo, string, int){
"add": (*Foo).Add,
"delete": (*Foo).Delete,
}
Then you would use it as:
var foo Foo = ...
var op string = GetOp() // "add", "delete", ...
operations[op](&foo, a, b)
where GetOp() returns an operation as string, for example from a user input.
a and b are your string and int arguments to methods.
This assumes that all methods have the same signatures. They can also have return value(s), again of the same type(s).
It is also possible to do this with Foo as receiver instead of *Foo. In that case we don't have to de-reference it in the map, and we pass foo instead of &foo.
I have few C functions declared like this
CURLcode curl_wrapper_easy_setopt_long(CURL* curl, CURLoption option, long param);
CURLcode curl_wrapper_easy_setopt_str(CURL* curl, CURLoption option, char* param);
I would like to expose those as one Go function like this
func (e *Easy)SetOption(option Option, param interface{})
so I need to be able to check param type at runtime. How do I do that and is this good idea (if not what is good practice in this case)?
It seems that Go have special form of switch dedicate to this (it is called type switch):
func (e *Easy)SetOption(option Option, param interface{}) {
switch v := param.(type) {
default:
fmt.Printf("unexpected type %T", v)
case uint64:
e.code = Code(C.curl_wrapper_easy_setopt_long(e.curl, C.CURLoption(option), C.long(v)))
case string:
e.code = Code(C.curl_wrapper_easy_setopt_str(e.curl, C.CURLoption(option), C.CString(v)))
}
}
The answer by #Darius is the most idiomatic (and probably more performant) method. One limitation is that the type you are checking has to be of type interface{}. If you use a concrete type it will fail.
An alternative way to determine the type of something at run-time, including concrete types, is to use the Go reflect package. Chaining TypeOf(x).Kind() together you can get a reflect.Kind value which is a uint type: http://golang.org/pkg/reflect/#Kind
You can then do checks for types outside of a switch block, like so:
import (
"fmt"
"reflect"
)
// ....
x := 42
y := float32(43.3)
z := "hello"
xt := reflect.TypeOf(x).Kind()
yt := reflect.TypeOf(y).Kind()
zt := reflect.TypeOf(z).Kind()
fmt.Printf("%T: %s\n", xt, xt)
fmt.Printf("%T: %s\n", yt, yt)
fmt.Printf("%T: %s\n", zt, zt)
if xt == reflect.Int {
println(">> x is int")
}
if yt == reflect.Float32 {
println(">> y is float32")
}
if zt == reflect.String {
println(">> z is string")
}
Which prints outs:
reflect.Kind: int
reflect.Kind: float32
reflect.Kind: string
>> x is int
>> y is float32
>> z is string
Again, this is probably not the preferred way to do it, but it's good to know alternative options.
quux00's answer only tells about comparing basic types.
If you need to compare types you defined, you shouldn't use reflect.TypeOf(xxx). Instead, use reflect.TypeOf(xxx).Kind().
There are two categories of types:
direct types (the types you defined directly)
basic types (int, float64, struct, ...)
Here is a full example:
type MyFloat float64
type Vertex struct {
X, Y float64
}
type EmptyInterface interface {}
type Abser interface {
Abs() float64
}
func (v Vertex) Abs() float64 {
return math.Sqrt(v.X*v.X + v.Y*v.Y)
}
func (f MyFloat) Abs() float64 {
return math.Abs(float64(f))
}
var ia, ib Abser
ia = Vertex{1, 2}
ib = MyFloat(1)
fmt.Println(reflect.TypeOf(ia))
fmt.Println(reflect.TypeOf(ia).Kind())
fmt.Println(reflect.TypeOf(ib))
fmt.Println(reflect.TypeOf(ib).Kind())
if reflect.TypeOf(ia) != reflect.TypeOf(ib) {
fmt.Println("Not equal typeOf")
}
if reflect.TypeOf(ia).Kind() != reflect.TypeOf(ib).Kind() {
fmt.Println("Not equal kind")
}
ib = Vertex{3, 4}
if reflect.TypeOf(ia) == reflect.TypeOf(ib) {
fmt.Println("Equal typeOf")
}
if reflect.TypeOf(ia).Kind() == reflect.TypeOf(ib).Kind() {
fmt.Println("Equal kind")
}
The output would be:
main.Vertex
struct
main.MyFloat
float64
Not equal typeOf
Not equal kind
Equal typeOf
Equal kind
As you can see, reflect.TypeOf(xxx) returns the direct types which you might want to use, while reflect.TypeOf(xxx).Kind() returns the basic types.
Here's the conclusion. If you need to compare with basic types, use reflect.TypeOf(xxx).Kind(); and if you need to compare with self-defined types, use reflect.TypeOf(xxx).
if reflect.TypeOf(ia) == reflect.TypeOf(Vertex{}) {
fmt.Println("self-defined")
} else if reflect.TypeOf(ia).Kind() == reflect.Float64 {
fmt.Println("basic types")
}
See type assertions here:
http://golang.org/ref/spec#Type_assertions
I'd assert a sensible type (string, uint64) etc only and keep it as loose as possible, performing a conversion to the native type last.
func (e *Easy)SetOption(option Option, param interface{}) {
if s, ok := param.(string); ok {
// s is string here
}
// else...
}
What's wrong with
func (e *Easy)SetStringOption(option Option, param string)
func (e *Easy)SetLongOption(option Option, param long)
and so on?