I am interested on which is better in the sense of either being more flexible/general/extensible or faster or less error prone or uses less memory.
Snippet1:
grep '^+[^+]' /tmp/p0rn.lst | while read x;do
wget $x
done
Snippet2:
while read x;do
wget $x
done < <(grep '^+[^+]' /tmp/p0rn.lst)
The first uses a pipeline, the second process substitution. Process substitution is usually better.
Piping input to a loop means the loop runs in a subshell. Variable changes inside a subshell are lost when the subshell finishes, i.e. when the loop ends.
For example, if you wanted to count the number of URLs processed by incrementing a variable each iteration you'd have to use process substitution:
count=0
while read x; do
wget "$x"
((++count))
done < <(grep '^+[^+]' /tmp/p0rn.lst)
echo "processed $count urls"
If you used a pipeline it would always print "processed 0 urls":
count=0
grep '^+[^+]' /tmp/p0rn.lst | while read x; do
wget "$x"
((++count))
done
# Doesn't work!
echo "processed $count urls"
In addition to #john-kugelman 's answer I would like to point out that the bash holds a variable called PIPESTATUS which is an array of all the exit codes of the last pipe:
(exit 1) | (exit 2) | (exit 3) | (exit 4); echo "${PIPESTATUS[#]}"
This will print
1 2 3 4
There is no similar mechanism if this is rewritten using process substitutions:
(exit 4) < <(
(exit 3) < <(
(exit 2) < <(
(exit 1)
)
)
)
In this case, the inner exit codes are just lost, unless they are explicitly stored somehow (e. g. dumped in a file or similar).
The overall exit code of a pipe is the exit code of the last pipe element, on default, so true | false is like false. In many cases this is desirable, e. g.
if curl "$url" | grep -q "searchterm"
then
# do something in case the searchterm was found
In this usage the exit value of the grep clearly is what is wanted.
There are other uses, however, in which you would rather react on the exit value of the left element:
curl "$url" | sed 's/password.*/###/g' > x || { # incorrect usage!
echo "Curl failed." 1>&2
}
This will not work because the pipe's exit value is the exit value of sed (which in this case is not the relevant part). Moving the check deeper inside can solve the issue:
(
curl "$url" || echo "Curl failed." 1>&2
) | sed 's/password.*/###/g' > x
Or also:
sed 's/password.*/###/g' < <(
curl "$url" || echo "Curl failed." 1>&2
) > x
But neither allows e. g. exiting the surrounding shell properly (because the check is done in a nested scope).
You can, however, use the pipefail option of the shell in which case a pipe's exit value is the exit value of the rightmost non-zero exit value:
set -o pipefail
(exit 1) | (exit 2) | (exit 3) | (exit 0); echo $?
This will print 3 instead of 0. Applied to our last example:
set -o pipefail
if ! curl "$url" | sed 's/password.*/###/g' > x
then
echo "Curl failed (or sed)." 1>&2
# Now we can even exit this shell here if we like.
fi
(You might want to scope the pipefail option to avoid influencing the rest of the script.)
You can, however, achieve a similar thing using process substitutions for the output:
if ! curl "$url" > >(sed 's/password.*/###/g' > x)
then
echo "Curl failed." 1>&2
# Now we can even exit this shell here if we like.
fi
But this will ignore failures in the right commands of the pipe (sed in this case). Using pipefail you can react on failures in any of the piped commands. There is no (simple and recommendable) way of achieving this using process substitutions.
Related
The following script calls another program reading its output in a while loop (see Bash - How to pipe input to while loop and preserve variables after loop ends):
while read -r col0 col1; do
# [...]
done < <(other_program [args ...])
How can I check for the exit code of other_program to see if the loop was executed properly?
Note: ls -d / /nosuch is used as an example command below, because it fails (exit code 1) while still producing stdout output (/) (in addition to stderr output).
Bash v4.2+ solution:
ccarton's helpful answer works well in principle, but by default the while loop runs in a subshell, which means that any variables created or modified in the loop will not be visible to the current shell.
In Bash v4.2+, you can change this by turning the lastpipe option on, which makes the last segment of a pipeline run in the current shell;
as in ccarton's answer, the pipefail option must be set to have $? reflect the exit code of the first failing command in the pipeline:
shopt -s lastpipe # run the last segment of a pipeline in the current shell
shopt -so pipefail # reflect a pipeline's first failing command's exit code in $?
ls -d / /nosuch | while read -r line; do
result=$line
done
echo "result: [$result]; exit code: $?"
The above yields (stderr output omitted):
result: [/]; exit code: 1
As you can see, the $result variable, set in the while loop, is available, and the ls command's (nonzero) exit code is reflected in $?.
Bash v3+ solution:
ikkachu's helpful answer works well and shows advanced techniques, but it is a bit cumbersome.
Here is a simpler alternative:
while read -r line || { ec=$line && break; }; do # Note the `|| { ...; }` part.
result=$line
done < <(ls -d / /nosuch; printf $?) # Note the `; printf $?` part.
echo "result: [$result]; exit code: $ec"
By appending the value of $?, the ls command's exit code, to the output without a trailing \n (printf $?), read reads it in the last loop operation, but indicates failure (exit code 1), which would normally exit the loop.
We can detect this case with ||, and assign the exit code (that was still read into $line) to variable $ec and exit the loop then.
On the off chance that the command's output doesn't have a trailing \n, more work is needed:
while read -r line ||
{ [[ $line =~ ^(.*)/([0-9]+)$ ]] && ec=${BASH_REMATCH[2]} && line=${BASH_REMATCH[1]};
[[ -n $line ]]; }
do
result=$line
done < <(printf 'no trailing newline'; ls /nosuch; printf "/$?")
echo "result: [$result]; exit code: $ec"
The above yields (stderr output omitted):
result: [no trailing newline]; exit code: 1
At least one way would be to redirect the output of the background process through a named pipe. This would allow to pick up its PID and then get the exit status through waiting on the PID.
#!/bin/bash
mkfifo pipe || exit 1
(echo foo ; exit 19) > pipe &
pid=$!
while read x ; do echo "read: $x" ; done < pipe
wait $pid
echo "exit status of bg process: $?"
rm pipe
If you can use a direct pipe (i.e. don't mind the loop being run in a subshell), you could use Bash's PIPESTATUS, which contains the exit codes of all commands in the pipeline:
(echo foo ; exit 19) | while read x ; do
echo "read: $x" ; done;
echo "status: ${PIPESTATUS[0]}"
A simple way is to use the bash pipefail option to propagate the first error code from a pipeline.
set -o pipefail
other_program | while read x; do
echo "Read: $x"
done || echo "Error: $?"
Another way is to use coproc (requires 4.0+).
coproc other_program [args ...]
while read -r -u ${COPROC[0]} col0 col1; do
# [...]
done
wait $COPROC_PID || echo "Error exit status: $?"
coproc frees you from having to setup asynchronicity and stdin/stdout redirection that you'd otherwise need to do in an equivalent mkfifo.
Please explain to me why the very last echo statement is blank? I expect that XCODE is incremented in the while loop to a value of 1:
#!/bin/bash
OUTPUT="name1 ip ip status" # normally output of another command with multi line output
if [ -z "$OUTPUT" ]
then
echo "Status WARN: No messages from SMcli"
exit $STATE_WARNING
else
echo "$OUTPUT"|while read NAME IP1 IP2 STATUS
do
if [ "$STATUS" != "Optimal" ]
then
echo "CRIT: $NAME - $STATUS"
echo $((++XCODE))
else
echo "OK: $NAME - $STATUS"
fi
done
fi
echo $XCODE
I've tried using the following statement instead of the ++XCODE method
XCODE=`expr $XCODE + 1`
and it too won't print outside of the while statement. I think I'm missing something about variable scope here, but the ol' man page isn't showing it to me.
Because you're piping into the while loop, a sub-shell is created to run the while loop.
Now this child process has its own copy of the environment and can't pass any
variables back to its parent (as in any unix process).
Therefore you'll need to restructure so that you're not piping into the loop.
Alternatively you could run in a function, for example, and echo the value you
want returned from the sub-process.
http://tldp.org/LDP/abs/html/subshells.html#SUBSHELL
The problem is that processes put together with a pipe are executed in subshells (and therefore have their own environment). Whatever happens within the while does not affect anything outside of the pipe.
Your specific example can be solved by rewriting the pipe to
while ... do ... done <<< "$OUTPUT"
or perhaps
while ... do ... done < <(echo "$OUTPUT")
This should work as well (because echo and while are in same subshell):
#!/bin/bash
cat /tmp/randomFile | (while read line
do
LINE="$LINE $line"
done && echo $LINE )
One more option:
#!/bin/bash
cat /some/file | while read line
do
var="abc"
echo $var | xsel -i -p # redirect stdin to the X primary selection
done
var=$(xsel -o -p) # redirect back to stdout
echo $var
EDIT:
Here, xsel is a requirement (install it).
Alternatively, you can use xclip:
xclip -i -selection clipboard
instead of
xsel -i -p
I got around this when I was making my own little du:
ls -l | sed '/total/d ; s/ */\t/g' | cut -f 5 |
( SUM=0; while read SIZE; do SUM=$(($SUM+$SIZE)); done; echo "$(($SUM/1024/1024/1024))GB" )
The point is that I make a subshell with ( ) containing my SUM variable and the while, but I pipe into the whole ( ) instead of into the while itself, which avoids the gotcha.
#!/bin/bash
OUTPUT="name1 ip ip status"
+export XCODE=0;
if [ -z "$OUTPUT" ]
----
echo "CRIT: $NAME - $STATUS"
- echo $((++XCODE))
+ export XCODE=$(( $XCODE + 1 ))
else
echo $XCODE
see if those changes help
Another option is to output the results into a file from the subshell and then read it in the parent shell. something like
#!/bin/bash
EXPORTFILE=/tmp/exportfile${RANDOM}
cat /tmp/randomFile | while read line
do
LINE="$LINE $line"
echo $LINE > $EXPORTFILE
done
LINE=$(cat $EXPORTFILE)
I am new to shell scripting and stuck with a problem. In my shell method if I saw any validation issue then rest of the programm will not execute and will show user a message. Till validation it's done but when I used exit 0 then only it comes out of the validation loop not from full method.
config_wuigm_parameters () {
echo "Starting to config parameters for WUIGM....." | tee -a $log
prepare_wuigm_conf_file
echo "Configing WUIGM parameters....." | tee -a $log
local parafile=`dirname $0`/wuigm.conf
local pname=""
local pvalue=""
create_preference_template
cat ${parafile} |while read -r line;do
pname=`echo $line | egrep -e "^([^#]*)=(.*)" | cut -d '=' -f 1`
if [ -n "$pname" ] ; then
lsearch=`echo $line | grep "[<|>|\"]" `
if [ -n "$lsearch" ] ; then
echo validtion=$lsearch
echo "< or > character present , Replace < with < and > with >"
exit 1;
else
pvalue=`echo $line | egrep -e "^([^#]*)=(.*)" | cut -d '=' -f 2- `
echo "<entry key=\"$pname\" value=\"$pvalue\"/>" >> $prefs
echo "Configured : ${pname} = ${pvalue} " | tee -a $log
fi
fi
done
echo $validtion
echo "</map>" >> $prefs
# Copy the file to the original location
cp -f $prefs /root/.java/.userPrefs/com/ericsson/pgm/xwx
# removing the local temp file
rm -f $prefs
reboot_server
}
Any help would be great
It is because the construction
cat file | while read ...
starts a new (sub)shell.
In the next you can see the difference:
echoline() {
cat "$1" | while read -r line
do
echo ==$line==
exit 1
done
echo "Still here after the exit"
}
echoline $#
and compare with this
echoline() {
while read -r line
do
echo ==$line==
exit 1
done < "$1"
echo "This is not printed after the exit"
}
echoline $#
Using the return doesn't helps too, (because of subshell). The
echoline() {
cat "$1" | while read -r line
do
echo ==$line==
return 1
done
echo "Still here"
}
echoline $#
will still prints the "Still here".
So, if you want exit the script, use the
while read ...
do
...
done < input #this not starts a new subshell
if want exit just the method (return from it) must check the exit startus of the previous command, like:
echoline() {
cat "$1" | while read -r line
do
echo ==$line==
exit 1
done || return 1
echo "In case of exit (or return), this is not printed"
}
echoline $#
echo "After the function call"
Instead of || or you can use the
[ $? != 0 ] && return 1
just after the while.
You use the return instruction to exit a function with a value.
return [n]
Causes a function to exit with the return value specified by n. If n is omitted, the return status is that of the last command executed in the function body. If used outside a function, but during execution of a script by the . (source) command, it causes the shell to stop executing that script and return either n or the exit status of the last command executed within the script as the exit status of the script. If used out‐side a function and not during execution of a script by ., the return status is false. Any command associated with the RETURN trap is executed before execution resumes after the function or script.
If you want to exit a loop, use the break instruction instead:
break [n]
Exit from within a for, while, until, or select loop. If n is specified, break n levels. n must be ≥ 1. If n is greater than the number of enclosing loops, all enclosing loops are exited. The return value is 0 unless n is not greater than or equal to 1.
The exit instruction exits the current shell instead, so the current program as a whole. If you use sub-shells, code written between parenthesis, then only that sub-shell exits.
Consider I have following commandline: do-things arg1 arg2 | progress-meter "Doing things...";, where progress-meter is bash function I want to implement. It should print Doing things... before running do-things arg1 arg2 or in parallel (so, it will be printed anyway at the very beginning), and record stdout+stderr of do-things command, and check it's exit status. If exit status is 0, it should print [ OK ], otherwise it should print [FAIL] and dump recorded output.
Currently I have things done using progress-meter "Doing things..." "do-things arg1 arg2";, and evaluating second argument inside, which is clumsy and I don't like that and believe there is better solution.
The problem with pipe syntax is that I don't know how can I get do-things' exit status from inside the pipeline? $PIPESTATUS seems to be useful only after all commands in pipeline finished.
Maybe process substitution like progress-meter "Doing things..." <(do-things arg1 arg2); will be fine, but in this case I also don't know how can I get exit status of do-things.
I'll be happy to hear if there is some other neat syntax possible to achieve same task without escaping command to be executed like in my example.
I greatly hope for the help of community.
UPD1: As question seems not to be clear enough, I paraphrase it:
I want bash function that can be fed with command, that will execute in parallel to function, and bash function will receive it's stdout+stderr, wait for completion and get its exit status.
Example implementation using evals:
progress_meter() {
local output;
local errcode;
echo -n -e $1;
output=$( {
eval "${cmd}";
} 2>&1; );
errcode=$?;
if (( errcode )); then {
echo '[FAIL]';
echo "Output was: ${output}"
} else {
echo '[ OK ]';
}; fi;
}
So this can be used as progress_meter "Do things..." "do-things arg1 arg2". I want the same without eval.
Why eval things? Assuming you have one fixed argument to progress-meter, you can do something like:
#!/bin/bash
# progress meter
prompt="$1"
shift
echo "$prompt"
"$#" # this just executes a command made up of
# arguments 2, 3, ... of the script
# the real script should actually read its input,
# display progress meter etc.
and call it
$ progress-meter "Doing stuff" do-things arg1 arg2
If you insist on putting progress-meter in a pipeline, I'm afraid your best bet is something like
(do-things arg1 arg2 ; echo $?) | progress-meter "Doing stuff"
I'm not sure I understand what exactly you're trying to achieve,
but you could check the pipefail option:
pipefail
If set, the return value of a pipeline is the
value of the last (rightmost) command to exit
with a non-zero status, or zero if all commands
in the pipeline exit successfully. This option
is disabled by default.
For example:
bash-4.1 $ ls no_such_a_file 2>&- | : && echo ok: $? || echo ko: $?
ok: 0
bash-4.1 $ set -o pipefail
bash-4.1 $ ls no_such_a_file 2>&- | : && echo ok: $? || echo ko: $?
ko: 2
Edit: I just read your comment on the other post. Why don't you just handle the error?
bash-4.1 $ ls -d /tmp 2>&- || echo failed | while read; do [[ $REPLY == failed ]] && echo failed || echo "$REPLY"; done
/tmp
bash-4.1 $ ls -d /tmpp 2>&- || echo failed | while read; do [[ $REPLY == failed ]] && echo failed || echo "$REPLY"; done
failed
Have your scrips in the pipeline communicate by proxy (much like the Blackboard Pattern: some guy writes on the blackboard, another guy reads it):
Modify your do-things script so that it reports its exit status to a file somewhere.
Modify your progress-meter script to read that file, using command line switches if you like so as not to hardcode the name of the blackboard file, for reporting the exit status of the program that it is reporting the progress for.
I'd like to send the result of a series of commands to a variable:
variable=$(a | few | commands)
However, the command substitution resets PIPESTATUS, so I can't inspect where it went wrong after the fact. One solution would be to use mktemp and put the result there temporarily:
variable_file=$(mktemp) || exit 1
a | few | commands > $variable_file
exit_codes="${PIPESTATUS[*]}"
variable=$(<$variable_file)
Is there a more elegant solution?
Kinda hacky but I think you could fudge it like this.
variable=$(a | few | commands; echo ": ${PIPESTATUS[*]}")
PIPESTATUS=(${variable##*: })
variable=${variable%:*}
variable=${variable%$'\n'}
Building on ephemient's answer, if we need the output of the piped commands stored without them being mixed in with the pipestatus codes, but we don't really care what the exit codes themselves are (just that they all succeeded), we can do:
variable=$(a | few | commands; [[ ${PIPESTATUS[*]} == "0 0 0" ]])
This will check on the status of all the piped command status in the above example and if its exit code is not 0, will set $? to 1 (false)
If you want to exit with a different code instead of 1, you could capture the contents of PIPESTATUS[#], e.g. r_code=${PIPESTATUS[2]}, and then use (exit ${r_code[2]}) instead of false.
Below captures all the codes of PIPESTATUS, ensures they're all 0, and if not, sets the exit code to be the $? value of commands:
declare -a r_code
variable=$(a | few | commands
r_code=(${PIPESTATUS[#]})
[[ ${r_code[*]} == "0 0 0" ]] || (exit ${r_code[2]})
)
echo ${?} # echoes the exit code of `commands`
echo ${variable} # echoes only the output of a | few | commands