RS command not found - bash

I am doing a research on a number of subjects which requires that I submit my script to a supercomputer. My script was working fine on the individual subject, but I am getting this error when i submit it to the supercomputer.
rs command not found.
I am new to scripting but when i looked for this command in my terminal (type rs) it existed- but when i did the same in the supercomputer shell rs was not there.
Is there a way to download this specific command ?
THank you

Looks like your script does not include the details of $PATH variable when it gets executed.
To resolve this find the location of rs using which rs and include that location in the $PATH variable and export it inside the script. It would look something like this in your script:
export PATH=$PATH:`which rs`
NOTE: This might not work and you might have to replace the location of rs command explicitly instead of using it in a single command.
PS. Assuming you have rs extension installed in your system.

Related

Jenkins "forgets" parameters when executing a shell script in Build section

I encounter the issue that I have a parameterized project with several string parameters, e.g., "VARIABLE_A", and that Jenkins doesn't know them anymore when executing a shell script in the Build section, i.e., there is simply no value.
This is very bizarre and I am convinced this should work using a string parameter (variable) in these ways:
"echo $VARIABLE_A"
"python3 $PATH/abc.py $VARIABLE_A"
...
but there is no values anymore.
echo-command does not print anything and the Python script misses the value as VARIABLE_A is apparently empty.
Perhaps someone has an idea ?
Thanks
Rainer
PS
Jenkins version is "2.277.2".

Add Path to OSX to El Capitan

I am trying to learn UNIX.
I am using a book called “Wicked Cool Shell Scripts”.
I am told that .bash_profile contains my login for bash and that I can add paths to it so that commands I enter in Terminal will find the scripts I am writing.
The contents of my current bash_profile is:
export PATH=~/bin:$PATH
When I type echo $PATH I get:
/usr/local/opt/php#7.0/bin:/Library/Frameworks/Python.framework/Versions/3.6/bin:/Library/Frameworks/Python.framework/Versions/3.5/bin:/Library/Frameworks/Python.framework/Versions/3.5/bin:/Library/Frameworks/Python.framework/Versions/3.3/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/opt/X11/bin
I would like to add a path so that - as the book suggests - I can write scripts and refer to them directly from the command line, instead of having to constantly navigate to that directory to run them.
I have a file with a shebang. It runs fine when I type its name and am in the same directory. I have moved that file to the folder scripts, which is located under crg/Users/ (ie: Users/crg/scripts)
According to this book, I can now alter my $PATH to include that directory, so that when I type that filename, the program will run.
I cannot do this successfully.
I don’t know why.
After every edit, I quit terminal and reopen it, to ensure it is using the newly edited bash_profile.
As per the books instructions on page 5, I have tried entering this in my bash_profile:
export PATH=”/Users/crg/scripts/:$PATH”
I save my bash_profile, quit Terminal, reopen it and type echo $Path
This is the result:
”/Users/crg/scripts/:??
This is not right. In fact, it's wildly wrong. And it does not allow me to run scripts from the folder indicated. It also seems to completely overwrite whatever was in the bash_profile before this, so I cannot - after doing this 'simple edit' suggested by a 'professional' - run a php -version command from the Terminal.
I am at a complete loss as to why this is happening.
Why is there a quotation mark at the beginning of this line (but not at the end)?
What's with the colon and the 2 question marks at the end of this line?
How do I add/append a path to my bash_profile?
More questions:
When I try and solve this on my own using “the Internet”, I discover many interesting versions of this ‘simple’ process: Here’s one suggested by a ‘professional’:
export PATH="${PATH}:/path/to/program/inside/package"
This is very different from what the book says...
Here’s another version of ‘how to do it’ by ‘a professional’:
export PATH=$PATH:/usr/local/sbin/modemZapp
Notice that this one doesn’t even have quotes. In both, the PATH variable comes before the actual path.
Why are there so many 'versions' of how to perform this simple task?
Can someone please tell me how to add a path to my .bash_profile?
UPDATE: I have followed the advice here, (add it to etc/paths) but this does not work either.
I get the exact same thing when I type echo $PATH in a new Terminal:
/usr/local/opt/php#7.0/bin:/Library/Frameworks/Python.framework/Versions/3.6/bin:/Library/Frameworks/Python.framework/Versions/3.5/bin:/Library/Frameworks/Python.framework/Versions/3.5/bin:/Library/Frameworks/Python.framework/Versions/3.3/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr:/usr/local/share/npm/bin:/Users/fhb/scripts:/opt/X11/bin
I can't help but note a comment on that last page: "I have been through at least a dozen different methods for adding directories to $PATH. Why are there so many and why do so few of them work?"
To answer your first question if you look closely your quotes are ” instead of ". I'm guessing you edited either your bash_profile or this post in a rich text editor instead of a plain text one. I would recommend notepad for Windows or nano for *nix if you are writing code. To fix this issue, replace the ” with ".
To answer your second question, bash is quite forgiving and will allow you to set a string variable in multiple different ways, even without quotes. However you can run into issues when a string contains whitespace, for example: /Users/lilHenry/my scripts.
The "${PATH}" syntax is just another way to declare a string. It has the benefit that it allows you to interpolate variables into a string like so:
prefix="foo"
echo "${prefix}bar"
This will output foobar, whereas echo "$prefixbar" will not output anything as the variable prefixbar has not been set. I would suggest sticking with the export PATH="/Users/me/bin:$PATH" syntax.

Shell script error in UNIX but works in CentOS - source: not found

myconf.sh
setting1=val1
setting2=val2
export setting1
export setting2
Then I call this conf file in my runner.sh, but I get the error "runner.sh: source: not found". Initially I was using source myconf.sh when calling it inside and saw in some posts that I should be using "." instead of "source".
myrunner.sh
#!/bin/sh
. myconf.sh
echo "$setting1"
echo "$setting2"
I'm calling myrunner.sh through this command
sh myrunner.sh
Please let me know if I'm actually doing something wrong. I'm able to call it properly without errors in my CentOS image but when we execute it in a UNIX box I'm hitting the error.
Thanks!
What is your $PATH env var set to?
You may just need to include the current directory in your path or prefix the filename.
Example: source ./myconf.sh
ETA: As noted; putting the current directory . into your path may not be the most desirable thing. I suggested it simply to explain why your script may work on one system but not another.

Problem with input filter using doxygen 1.6.3 on windows XP

I am trying to use doxygen to generate documentation for some matlab classes I have written. I am using the doxygen-matlab package, which includes a perl script to kludge matlab .m files into c++ style commented files, so that doxygen can read them.
In my doxyfile, I have set (according to the instructions)
FILTER_PATTERNS = *m=C:/doxygenMatlab/m2cpp.pl
However, when the code runs, rather than running the script on the input files, it appears to just open the script using whatever the default windows setting for .pl is.
IE, if I associate .pl with notepad, the script is opened by notepad once for each input file doxygen is trying to parse. If I associate .pl with perl.exe, the script runs and throws the no argument error
Argument must contain filename -1 at C:\doxygenMatlab\m2cpp.pl line 4.
The doxygen documentation says
Doxygen will invoke the filter program by executing (via popen()) the command <filter> <input-file>
So I am wondering if there is some problem with popen() and windows that I could fix.
Could you try the workarounds I posted on the Matlab File Exchange regarding the doxygen package ?
Set the following variables in the Doxyfile :
INPUT_FILTER=perl m2cpp.pl
FILE_PATTERNS=*.m
If it doesn't work you should try to install ActivePerl : with this version of perl, everything is working fine.
I tried to reproduce the error using the Windows command prompt ("cmd") and noticed the following:
If you call "perl m2cpp.pl" you get error -1 because you did not specify a m-file to be translated into a cpp-file.
If you call "perl m2cpp.pl mfile" and the path of mfile contains spaces, you get error 1.
After I moved the mfile into a location which does not contain spaces, I got the desired output.
Now back to Doxygen. I tried what you suggested, Fabrice, without any luck. I read the doxygen help and found out that the INPUT_FILTER variable is only read and used if FILTER_PATTERNS is empty.
Therefore, I now use INPUT_FILTER = "C:\Programme\MATLAB\R2009a\sys\perl\win32\bin\perl U:\doxygen_matlab\m2cpp.pl" and an empty FILTER_PATTERNS variable. With this configuration, you can even leave the PERL_PATH variable empty. Moreover, there seems to be no issues with file names that contain spaces.
Unfortunately, all files are parsed with the above configuration, not only m-files. However, setting FILTER_PATTERNS to something like *.m=C:\Programme\MATLAB\R2009a\sys\perl\win32\bin\perl U:\doxygen_matlab\m2cpp.pl does not work because doxygen automatically adds the name of the filtered mfile and interprets the command as perl "m2cpp.pl mfile". Of course, the file "m2cpp.pl mfile" does not exist, because these are two files.
Maybe you can find a solution to this problem. In the meantime, I suggest the workaround above and that you keep your C-files away from the folder that contains the m-files.
write a simple batch file, e.g. mfilter.bat, which takes one argument from command line:
C:\Programme\MATLAB\R2009a\sys\perl\win32\bin\perl U:\doxygen_matlab\m2cpp.pl %1
Change setting in Doxyfile:
FILTER_PATTERNS = *.m=mfile.bat
This did it for me (on a Windows platform)
I think I solved this problem : it came from a bad association between .pl and the program to execute (maybe due to a bad installation of the perl shipped whith Matlab ?).
To correct this, you should change the association for the .pl files : in a Windows command prompt ("cmd"), just type de 2 following lines :
assoc .pl=PerlScript
ftype PerlScript=C:\Program Files\MATLAB\R20xx\sys\perl\win32\bin\perl.exe %1 %*
(the old installation forgot the %* at the end, the arguments were not passed to the m2cpp.pl script).
And then everything should be fine with the FILTER_PATTERNS set the usual way, for example FILTER_PATTERN=*m=C:\DoxygenMatlbab\m2cpp.pl
Could you tell me if this fixed your problem ?
According to the Doxygen forums, there is a difference in behavior between using INPUT_FILTER and FILTER_PATTERNS.
I found that if I do some extra (escaped) quoting, I can get FILTER_PATTERNS to work. For example, instead of:
FILTER_PATTERNS = "*.m=sed -e 's|%%|//!|'"
Try:
FILTER_PATTERNS = "*.m=\"sed -e 's|%%|//!|'\""
(All of my experimentation was done with doxygen version 1.8.6)

how to invoke ruby script containing system command with cron job?

I have a ruby script containing system command like http://gist.github.com/235833, while I ran this script from shell, it works correctly, but when I added it to my cron job list, it doesn't work any more, the cron job is like:
10/* * * * * cd /home/hekin; /usr/bin/ruby my_script.rb
any idea what's going wrong with what i've done? Thank you.
Thank you all for your answers.
It's my mistake.
Since I'm using ssh key forwarding on the local machine, while I executed the script from the shell, the ssh key forwarding related environment variables are all sitting there, but from cron job context, those environment variables are missing.
Try to separate the things that might go wrong. The ones I can think of are:
The cron syntax - is the time value given legal and fitting your shell?
Permissions - execute permissions and read permissions for the relevant directory and file
Quoting - what scope does cron cover? Does it run only the first command?
In order to dissect this, I suggest you first run a really simple cron job, like 'ls'. Next run a single-liner script. Next embed your commands in a shell-script file. Somewhere along these lines you should find the problem.
The problem is your environment. While testing in your shell its fully equipped and boosted by your shell environment. While running under cron its very, very stripped down.
Where is the destination "." for your script? I guess it will be "/" and may not "$HOME" thus your script won't be able to write at that location and fails. Try using an absolut path for the destination.

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