Having the issue when loading the cvs/create being return an error of;
My route file;
My CvController;
Application frames (1)
in your route
CvController#create
but in your CvController
public function cerate()
spellings mistake.
create != cerate
There is a spell mistake in your function
public function create() {
return view('cv.create');
}
Related
I have a named route with a parameter which looks like this...
Route::get('/profile/{user_id}', [ProfileController::class, 'profile'])->name('profile');
Now in one of my controller,
I have a function that calls this route like this
public function _myFunction($some_data) {
return redirect()->route('profile', [$some_data->user_id]);
}
and in my ProfileController's profile() function, I have this.
public function profile() {
return view('modules.profile.profile');
}
I've followed the documentation and some guides I found in SO, but I got the same error,
"Route [profile] not defined."
can somebody enlighten me on where I went wrong?
Here's what my routes/web.php looks like...
Route::middleware(['auth:web'])->group(function ($router) {
Route::get('/profile/{user_id}', [ProfileController::class, 'profile'])->name('profile');
});
When calling the route, you should pass the name of the attribute along with the value (as key vaue pairs). In this case, your route is expecting user_id so your route generation should look like this:
return redirect()->route('profile', ['user_id' => $some_data->user_id]);
Read more on Generating URLs To Named Routes in Laravel.
I solved the issue, and its really my bad for not providing a more specific case information and made you guys confused.
I was using socialite and called _myFunction() inside the third party's callback..
After all, the problem was the socialite's google callback, instead of placing the return redirect()->route('profile', [$user->id]) inside _myFunction(), what I did was transfer it to the callback function.
So it looked like this now...
private $to_pass_user_id;
public function handleGoogleCallback()
{
try {
$user = Socialite::driver('google')->user();
$this->_myFunction($user);
return redirect()->route('profile', [$this->to_pass_user_id]);
} catch (Exception $e) {
dd($e->getMessage());
}
}
public function _myFunction($some_data) {
... my logic here
$this->to_pass_user_id = $some_value_from_the_logic
}
I am trying to get the second argument from the route in laravel from the following code.
web.php
Route::get('users/{name}/forksnippets/{name2}','Forksnippet#viewforksnippet');
controller
public function viewforksnippet($slug){
dd($slug);
}
getting name here as result
Just add the second argument to the method of the controller.
public function viewforksnippet($slug, $name2)
{
dd($slug, $name2);
}
public function viewforksnippet($name, $name2)
{
dd($name2);
}
Please try this ex
I am thinking of any techniques of autoloading the view files according to url.
For example:
public function addProducts()
{
return view('admin.addProducts');
}
public function editProducts()
{
return view('admin.editProducts');
}
public function allProducts()
{
return view('admin.allProducts');
}
Here, the Controller's method name is identical to view file name. So, I am thinking, if it is possible to load the view files without writing same kind of method again and again.
Enlighten me.
If your route only needs to return a view, you may use the Route::view method.
For example:
Route::view('/welcome', 'welcome');
Route::view('/welcome', 'welcome', ['name' => 'Taylor']);
read more here
It's the call PHP magic, man. https://repl.it/#Piterden/PHP-call-magic?language=php
public function __call($method, $parameters)
{
if (str_contains($method, 'Product')) {
return view("admin.{$method}");
}
}
btw, it's not a good practice for controller.
The problem looks basic but it is really painful!
I'm using get method and getting value in controller and I want the same value to return in another view.
How can I do that???
Please help!!!
This is my function from controller:
public function guest(){
if (Input::get('Cash On Delivery')){
$get = Input::get('Cash On Delivery');
return Redirect::to('guest/guestview/'.$get);
}
Well, with regards to your answer, using $_REQUEST directly is not Laravel's way of doing things :(
I believe this is better
public function guest(Request $request)
{
if ($request->payment_method == ('Cash On Delivery'))
{
return view('guest/guestview', ['guest'=>$request->payment_method]);
}
}
Ok Guys, I figured it out,
Just do this below.
public function guest(Request $request){
if ($request->payment_method == ('Cash On Delivery')){
$get = $_REQUEST['payment_method'];
return view('guest/guestview', compact('get'));
}
I am just learning Laravel 5.1 framework, I find a puzzling problem.
First, I create a model named 'Page', then I create a controller named 'HomeController', the method code is following:
public function index()
{
return view('home')->withPages(Page::all());
}
I cannot find 'withPages()' function, so I find helper function view() return \Illuminate\View\View, so I find 'vendor/laravel/framework/src/Illuminate/View/View.php', there is a "__call()", so I get it.
But I try to delete this function, my site is still normal.
did I find the wrong place? I am very puzzled.
... there is a "__call()", so I get it. But I try to delete this function, my site is still normal. did I find the wrong place? I am very puzzled.
Probably.
Laravel 'compiles' all it's core classes into a single file as a performance optimisation.
Try running php artisan clear-compiled and your site should start failing.
This is how I would do it -
public function index()
{
return view()->with('pages', Page::all());
}
If you want to use withPages method, you need to have a variable $pages set in the method.
So your method would look like:
public function index()
{
pages = Page::all();
return view('home')->withPages($pages);
}
Other two options:
public function index()
{
return view('home')->with('pages', Page::all());
}
or
public function index()
{
pages = Page::all();
return view('home')->with(compact('pages));
}
You can use any of these methods.