Get number of line of word number X in file - bash

Question

Need to make a shell script that splits every csv file that uses \n as separator, the limit per file is the number of words and
I can't cut the line in half.
Finished script with the help of a wizard!
Example:
sh SliceByWords.sh 1000 .
Slices every file by 1000 words and put every part into subfolder
function has_number_number_of_words {
re='^[0-9]+$'
if ! [[ $1 =~ $re ]] ; then
echo "error: Not a number, please run the command with the number of words per file" >&2; exit 1
fi
}
#MAIN
has_number_number_of_words $1
declare -i WORDLIMIT=$1 # N of lines to part each file
subdir="Result"
mkdir $subdir
format=*.csv
for name in $format; do mv "$name" "${name// /___}"; done
for i in $format;
do
if [[ "$i" == "$format" ]]
then
echo "No Files"
else
( locali=$(echo $i | awk '{gsub(/ /,"\\ ");print}');
localword=$i;
FILENAMEWITHOUTEXTENSION="${localword%.*}" ;
subnoext=$subdir"/"$FILENAMEWITHOUTEXTENSION;
echo Processing file "$FILENAMEWITHOUTEXTENSION";
awk -v NOEXT=$subnoext -v wl=$WORDLIMIT -F" " 'BEGIN{fn=1}{c+=NF}{sv=NOEXT"_snd_"fn".csv";print $0>sv;}c>wl{c=0;++fn;close(sv);}' $localword;
)&
fi
done
wait #wait
for name in $format; do mv "$name" "${name//___/ }"; done
echo All files done.
Since i couldnt figure out how to enter awk files with spaces , im using
for name in $format; do mv "$name" "${name//___/ }"; done

Answer 1

I think this would be a lot easier to handle with awk:
awk -F" " 'BEGIN{filenumber=1}{counter+=NF}{print $0 > FILENAME"_part_"filenumber} counter>1000{counter=0;++filenumber}' yourinputfile
awk here is:
Splitting each line by space -F" "
Before processing the file set the filenumber variable to 1
Bump the counter variable by the number of fields in the line {counter+=NF}
Print out the line to the file, numbered by a variable. Using the FILENAME built-in variable here to pull through yourinputfile. {print $0 > FILENAME"_part_"filenumber}
If the counter has popped over 1000, then send it back to 0 and bump the filenumber variable by 1 counter>1000{counter=0;++filenumber}
Minimized a bit:
awk -F" " 'BEGIN{fn=1}{c+=NF}{print $0>FILENAME"_part_"fn}c>1000{c=0;++fn}' yourinputfile